Derivative of cos^2(x) - d/dx [cos^2(x)] - Chain Rule and Half Angle Formula
4:44
Derivative of cos^2(x) - d/dx [cos^2(x)] - Chain Rule and Half Angle Formula
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Integral Test for Convergence/Divergence of Infinite Series (How it Works)
16:56
Integral Test for Convergence/Divergence of Infinite Series (How it Works)
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Simple vs Compound Interest (Compound not much better?)
6:14
Simple vs Compound Interest (Compound not much better?)
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Limit of xe^x as x approaches -∞ (negative infinity) - L'Hospital's Rule
6:04
Limit of xe^x as x approaches -∞ (negative infinity) - L'Hospital's Rule
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Compound Interest: How much can you earn in 3 years at 9 per cent?
3:57
Compound Interest: How much can you earn in 3 years at 9 per cent?
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Harmonic Series: why it is Divergent
11:31
Harmonic Series: why it is Divergent
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Convergence and Divergence of Infinite Series with Example Problems
13:25
Convergence and Divergence of Infinite Series with Example Problems
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How to integrate ∫csc^3(x)dx - (Integration By Parts)
9:25
How to integrate ∫csc^3(x)dx - (Integration By Parts)
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Limit of (2 + h)^3 - 8 / h as h approaches 0
6:02
Limit of (2 + h)^3 - 8 / h as h approaches 0
3 жыл бұрын
What is the derivative of tan^2(x)? - d/dx[tan^2(x)]
2:38
What is the derivative of tan^2(x)? - d/dx[tan^2(x)]
3 жыл бұрын
Trig and Complex Numbers - Power Reduction Identities
14:32
Trig and Complex Numbers - Power Reduction Identities
3 жыл бұрын
Inverse hyperbolic cosine [cosh^-1(x)] as a logarithm
8:36
Inverse hyperbolic cosine [cosh^-1(x)] as a logarithm
3 жыл бұрын
How to evaluate the limit sqrt(1 + h) - 1 / h as x approaches 0
4:20
How to evaluate the limit sqrt(1 + h) - 1 / h as x approaches 0
3 жыл бұрын
Integral of ∫ sin(4x) / cos^4(x) dx
8:06
Integral of ∫ sin(4x) / cos^4(x) dx
3 жыл бұрын
Trig and Complex Numbers - Multiple Angle Identities
8:40
Trig and Complex Numbers - Multiple Angle Identities
3 жыл бұрын
Derivative of csc(x) - Reciprocal Rule
4:06
Derivative of csc(x) - Reciprocal Rule
3 жыл бұрын
Evaluating the Integral ∫ sqrt(x) / x^2 + x dx on the interval [1/3, 3]
8:39
Evaluating the Integral ∫ sqrt(x) / x^2 + x dx on the interval [1/3, 3]
3 жыл бұрын
Proof: Reciprocal Rule of Differentiation by First Principles
8:02
Proof: Reciprocal Rule of Differentiation by First Principles
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Limit of (x^2 + x - 6) / (x - 2) as x approaches 2
6:14
Limit of (x^2 + x - 6) / (x - 2) as x approaches 2
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How to Integrate ∫ log_a(x) dx
3:07
How to Integrate ∫ log_a(x) dx
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Derivative of arcsin(x) - d/dx [ sin^-1(x) ] - Inverse Sine function
4:22
Derivative of arcsin(x) - d/dx [ sin^-1(x) ] - Inverse Sine function
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How to Integrate ∫xsin^3(x)cos^4(x)dx
14:37
How to Integrate ∫xsin^3(x)cos^4(x)dx
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Integral of ∫ acos(x) / b + acos(x) dx with t = tan(x/2)
10:59
Integral of ∫ acos(x) / b + acos(x) dx with t = tan(x/2)
3 жыл бұрын
How to integrate ∫ dx / (a^2 + b^2x^2)
4:07
How to integrate ∫ dx / (a^2 + b^2x^2)
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How to Integrate ∫ a^x dx
3:25
How to Integrate ∫ a^x dx
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Find a and b for ax^3 - 8x^2 - 9x + b: Polynomial Remainder Theorem
11:20
Find a and b for ax^3 - 8x^2 - 9x + b: Polynomial Remainder Theorem
3 жыл бұрын
Integral of tan^4(x) = Integral of y^4/(y^2+1) ?? - Change of Variable
7:47
Integral of tan^4(x) = Integral of y^4/(y^2+1) ?? - Change of Variable
3 жыл бұрын
Proof: Limit as x approaches 0 of [tan(x) - x] / x^3 = 1/3 (L'Hospital's Rule)
7:35
Proof: Limit as x approaches 0 of [tan(x) - x] / x^3 = 1/3 (L'Hospital's Rule)
3 жыл бұрын
What is the derivative of sec^2(x)? - d/dx[sec^2(x)]
2:34
What is the derivative of sec^2(x)? - d/dx[sec^2(x)]
3 жыл бұрын
Пікірлер
@sanianadeem9487
@sanianadeem9487 2 күн бұрын
you made it seem so easy. thanks alot!
@Meowhoraga420
@Meowhoraga420 4 күн бұрын
ur overcomplicating it bruh
@angesilue983
@angesilue983 7 күн бұрын
Gg😂🎉
@HorizonTech_graphix
@HorizonTech_graphix 8 күн бұрын
@ 8:54 what happened there
@A.rKh.d
@A.rKh.d 9 күн бұрын
hard question
@r2891-z9j
@r2891-z9j 14 күн бұрын
helped me a lot, thanks.
@monisha2007-x8u
@monisha2007-x8u 15 күн бұрын
Thank you bro that's understandable
@heeberman
@heeberman 15 күн бұрын
What changes if the inflow and outflow rates are different?
@luuksemmekrot4509
@luuksemmekrot4509 16 күн бұрын
Very helpful video thank you!
@EvarstiHitimana
@EvarstiHitimana 19 күн бұрын
Ntabwo byumvikana
@georgen9755
@georgen9755 20 күн бұрын
Where lecturers cannot address vice presidents and presidents i wonder how such access is possible for lecturers such as me ......
@TonyTheShooter
@TonyTheShooter 26 күн бұрын
Im mexican, and I had homework with this integral, I didnt find it everywhere until I found this channel, its a gold mine
@bonniem1865
@bonniem1865 28 күн бұрын
thank you!
@RawanDiaaYoussef
@RawanDiaaYoussef Ай бұрын
As a pharmacy student from Egypt u very benefit me thank u sir ❤
@plushiyito
@plushiyito Ай бұрын
soo both final expressions are correct, but still by convention we use the positive one???
@user-youung.hyun26
@user-youung.hyun26 Ай бұрын
Oh my Jesus, thank you teacher Finally I understood what I have to do in nixing problem. I appreciate it.
@ethanluvisia8678
@ethanluvisia8678 Ай бұрын
This was amazing, thank you!
@chazadkins24
@chazadkins24 2 ай бұрын
Very helpful! Thank you greatly
@antoniocampos9721
@antoniocampos9721 2 ай бұрын
Thanks man....greetings from Brazil !
@umakako
@umakako 2 ай бұрын
Thank you!
@gelbkehlchen
@gelbkehlchen 2 ай бұрын
Solution: ∫(4x+3)/(x²+1)*dx = 2*∫2x/(x²+1)*dx+3*∫1/(x²+1)*dx = -------------- Substitution for the first integral: u = x²+1 du = 2x*dx dx = du/(2x) -------------- = 2*∫2x/u*du/(2x)+3*∫1/(x²+1)*dx = 2*∫1/u*du+3*∫1/(x²+1)*dx = 2*ln|u|+3*arctan(x)+C = 2*ln|x²+1|+3*arctan(x)+C Checking the result by deriving: [2*ln|x²+1|+3*arctan(x)+C]’ = 2*1/(x²+1)*2x+3*1/(x²+1) = (4x+3)/(x²+1) Everything okay!
@livvielov
@livvielov 2 ай бұрын
I picked the right u but took dv=sec^2x +1 and ended up with a right mess. Thanks for the proof
@Zxnoll-r4s
@Zxnoll-r4s 2 ай бұрын
GOOD VIDEO
@egemenyaln
@egemenyaln 2 ай бұрын
Amazing video 🎉
@jotisidhu6386
@jotisidhu6386 2 ай бұрын
Thanks a lot😊
@SreenidhiRamasahayam
@SreenidhiRamasahayam 2 ай бұрын
Thankyou from India💖
@ashishraje5712
@ashishraje5712 2 ай бұрын
Integral ln^2 (sin x) pls explain
@hamidmohaddes2774
@hamidmohaddes2774 2 ай бұрын
We can use lhopitalle rule
@TuyeniMeme
@TuyeniMeme 2 ай бұрын
Hmm......this was very helpful I now understand something that previously took me around three hours to understand 😊
@RayanShaikh-bf1gp
@RayanShaikh-bf1gp 3 ай бұрын
gracias
@klozzy1851
@klozzy1851 3 ай бұрын
thank u!!!
@thedeathofbirth0763
@thedeathofbirth0763 3 ай бұрын
Master indeed! Thank you!
@thedeathofbirth0763
@thedeathofbirth0763 3 ай бұрын
Beautifully explained! Thank you! Can not wait for more videos from you. Please don't stop, you have too much to offer...
@thedeathofbirth0763
@thedeathofbirth0763 3 ай бұрын
Excellent communication skills! Thank you for the time you took to make this video!
@Kzaman-yg5br
@Kzaman-yg5br 3 ай бұрын
6:50 can I apply L Hospital rules because it is now 0/0 form.
@dinofish3262
@dinofish3262 2 ай бұрын
U can do that but you would need to take the derivative of m and ln(1+m). The proof is using first principles, which means all the information u have is the limit definition and algebra.
@soured7967
@soured7967 3 ай бұрын
best explanation ever, tyvvvvm
@anasyounus8787
@anasyounus8787 3 ай бұрын
Real
@derickmweembela4248
@derickmweembela4248 4 ай бұрын
Still can't get it 😢😢😢.
@derickmweembela4248
@derickmweembela4248 4 ай бұрын
I got it now. Simple 😊
@harshvardhanmisal2255
@harshvardhanmisal2255 4 ай бұрын
I was solving a question and used th cos3x formula. I saw the answer and it was completely different than mine. Now, I have understood what they did. Thanks!
@yr9829
@yr9829 4 ай бұрын
What the fucj
@RahinatuUmarAdamu
@RahinatuUmarAdamu 4 ай бұрын
This method is the best
@NumbToons
@NumbToons 4 ай бұрын
What a beautiful video and presentation
@saravanarajeswaran2626
@saravanarajeswaran2626 4 ай бұрын
on the other side , any function say a^x , the derivative would become a^x times limit as h approaches 0 of a^h - 1/h , which gives some random irrational number (which ln a) , so we would ask , so is there any number ,so that we take derivative the limit becomes 0, yes that is e , so most likely it is one of e definition you can say from another persepective
@AsmaMirza-kr2hm
@AsmaMirza-kr2hm 5 ай бұрын
Thank you teacher ❤
@fsponj
@fsponj 5 ай бұрын
I always wondered why lim h→0 (aʰ-1)/h = ln a Thanks for explaining it
@extryxd1025
@extryxd1025 5 ай бұрын
Thank you! You helped me a lot!
@scientist23wannabe_23
@scientist23wannabe_23 5 ай бұрын
I do it with lim[(lnx-lnx0)/x-x0] x->x0. becomes limln(x/x0)/(x-x0) x->x0 Then i pose u=x/x0 and the limits becomes lim lnu/[x0(1-u)] that lim(lnu)/(u-1)=1 using N-L theorem and squezze theorem u->1
@LakshayKhatkar-ev8hw
@LakshayKhatkar-ev8hw 5 ай бұрын
Sir this lecture was osm ❤ I am preparing for jee advance and i want you to solve such problems ❤ love from india
@Eddygay-jx6md
@Eddygay-jx6md 5 ай бұрын
I have a question
@Braaibroodjie8
@Braaibroodjie8 6 ай бұрын
Extremely helpful, thank you!