this is the best channel to learn QM, I don't even know how to begin to thank you Professor. Truly amazing work what y'all do. You def inspire me!
@Gayth-v3i2 күн бұрын
Great Video. I am starting to fear though that you gave up on us, since there are no more updates.
@kisho26792 күн бұрын
How is artificial intelligence being used currently to calculate the eigenvalues and eigenfunctions of the 14 Lanthanides chemical elements of the periodic table?
@phonon16 күн бұрын
I am trained in math (no physics). I love that these video can be understood for a broader audience.
@hannesneutze15817 күн бұрын
I would be really useful if you had a slide for like 3 seconds before the proof started where you showed what notation you used. I'm used to different notation and it was hard to follow because I had to spend time figuring out what the symbols actually meant
@youngphilosophy61789 күн бұрын
I think it’s easier to define a pure state and a mixed state in the following way. A pure state is just a state where we can define a fixed phase between the states. For example, in the superposition pure state there is interference term that carries a phase for both u1 and u2. The same can’t be said about mixed states. The mixed state doesn’t have a fixed phase. Mixed states are just classical statistical ensembles. I hope this helps someone. 😊
@koushiksaikia10 күн бұрын
At 1.01 is it necessarily a position eigen state, or any arbitrary state?
@bijitmoish808612 күн бұрын
Hey, I have watched your videos on rigorous QM, and I really liked how intuitively the concepts were explained. Thanks for making these videos. I am trying to find a book on QM that is based on the modern state space formalism and covers a wide range of concepts and applications of QM. But it seems that most books either heavily overuse wave mechanics and/or use a weird hybrid between wave mechanics and state space formalism that I cannot make good sense out of. Is there any book, which uses the modern formalism strictly, and covers a wide array of QM topics?
@nikhilmalik517814 күн бұрын
Please get a nice mic
@pdelong4215 күн бұрын
I didn't quite follow the bit at 4:30, when you said the commutator of A and a general function of B, is equal to the commutator of A and B, times the derivative of the function of B (with respect to what? to time? to B?). Did I miss the justification of this statement? Was it covered in an earlier video? By the way, I just discovered this channel, and I like it so much I'm starting from its beginning. Thank you for putting this out there.
@sandippaul46817 күн бұрын
Always a life-saver
@KSV369218 күн бұрын
Wonderful explanation dear madam. I need all the topics from Quantum Mechanics from Ur Class.
@gorporpio18 күн бұрын
In geophysics this is used to determine whether the core is hot because of the pressure due to the weight above. It's not. Its radioactive decay. My ta said there's a book that tells how to do spherical harmonics . It was so easy when the teacher showed us. But the example was a potentially infinite series of integrals.
@yeast452923 күн бұрын
Brilliant video. So clear and well structured
@ProfessorMdoesScience18 күн бұрын
Glad you like it!
@sinaasadiyan23 күн бұрын
great explanation
@ProfessorMdoesScience18 күн бұрын
Glad you think so!
@berkaysuer729725 күн бұрын
perfect
@ProfessorMdoesScience18 күн бұрын
Thanks!
@sebastiangudino937725 күн бұрын
Where do these operator come from?
@Imran52Feb25 күн бұрын
What are L plus and L Minus operators? Rest I understood. Thanks Professor madam.
@HarshitKmwt26 күн бұрын
At 11:17 you added the terms for ni=0, instead you could have subtracted those two terms and would have obtained the result that the commutator is 1 instead of anticommutator [because (ci dagger ci) gives 0, so it doesn't matter if we add or subtract we get the same RHS but LHS would be different giving both commutator and anticommutator equals to 1]. Same for ni=1 case. Can you please answer this query.
@kisho267928 күн бұрын
which are the eigenfunctions for the other 117 chemical elements (hydrogen, etc.)?
@ProfessorMdoesScience18 күн бұрын
The energy eigenfunctions of all other elements can only be calculated approximately because the electron-electron interaction makes an analytical solution essentially impossible. We will cover some of those when we discuss approximation methods, so stay tuned! :)
@sebastiangudino937728 күн бұрын
I don't get how one could represent things like position and momentum here. Those are continuous basis. Energy is fine, just a really long unit vector of coefficients for all posible energies. Do we just work in discrete basis like in matrix mechanics? If so, whats the form the hamiltonian will take in matrix form in the energy basis? What about the position operator in the energy basis? (To calculate useful properties like the expectations value)
@RykeZarr29 күн бұрын
Great explanation!
@ProfessorMdoesScience18 күн бұрын
Glad you like it!
@gnrwashere5997Ай бұрын
Thanks for this awesome video,the best explanation that i could possibly get,thank you so much!!!!
@ProfessorMdoesScience18 күн бұрын
Glad it helped!!
@TeachwellesАй бұрын
What is the recommended viewing sequence of the 95 videos. Is it suggested by viewing them from oldest to newest? Each video I have viewed refers to other videos. I find these very helpful in my learning quest!!!
@ProfessorMdoesScience18 күн бұрын
Glad you like the videos! A good way to view them is to follow the playlists, and for those the order could be: 1. The postulates (basic mathematical tools of QM): kzbin.info/aero/PL8W2boV7eVfmMcKF-ljTvAJQ2z-vILSxb 2. The quantum harmonic oscillator (a good illustration of the use of the postulates): kzbin.info/aero/PL8W2boV7eVfmdWs3CsaGfoITHURXvHOGm 3. Angular momentum (from 1D to 3D): kzbin.info/aero/PL8W2boV7eVfmm5SZRjbhOKNziRXy6yIvI 4. Central potentials (a good illustration of 3D QM): kzbin.info/aero/PL8W2boV7eVfkqnDmcAJTKwCQTsFQk1Air 5. Hydrogen atom (the culmination of single-particle QM): kzbin.info/aero/PL8W2boV7eVfnJbLf-p3-_7d51tskA0-Sa These are a good starting point that are roughly equivalent to an introductory course on quantum mechanics. Beyond that, other topics of interest are quantum mechanics of many particles, density matrices, etc. I hope this helps!
@Meow_yjАй бұрын
I wish I had discovered you earlier; then I wouldn't have failed quantum mechanics :' ) Thank you for these high-quality lectures!
@ProfessorMdoesScience18 күн бұрын
Glad you like our videos, and glad you found us! :)
@user-sr6yt6os4zАй бұрын
Can you make video about momentum angular momentum and spin for electromagnetic field
@ProfessorMdoesScience18 күн бұрын
Thanks for the suggestion!
@haoqinggenius4335Ай бұрын
May i clarify my understanding for this lecture here? So what u mean is that different values of alpha and beta can represent a same physical state, since exchanging identical particles should not change anything. Right? And we should expect that the probability of measuring |up, up> remains the same, or rather be independent of alpha and beta. Am i right? But then, upon calculation, results completely contradicted this idea and thus we need to dismiss exchange degeneracy? Just like that?
@clemcaramel42Ай бұрын
Hello, for the proof that [A,B^n]=n[A,B]B^(n-1) if [A,[A,B]]=0 and [B,[A,B]]=0 ( 15:39 ), I don’t understand why we need [A,[A,B]]=0 ??? It seems we do not use this condition, so does it works if we only suppose [B,[A,B]]=0 ? Thanks for yours videos, those are great!
@fabio_air4230Ай бұрын
Great video, like all of yours! One question: Would NOT dropping the anti-commutator term make the inequality tighter (i.e. raise the lower bound)?
@ProfessorMdoesScience18 күн бұрын
Yes!
@fabio_air4230Ай бұрын
Thanks!
@ProfessorMdoesScience18 күн бұрын
Wow, thanks!
@mathewvincent692Ай бұрын
Which all books do you recommend, Ma'am?
@vrendus522Ай бұрын
Great stuff, thank you. Dan
@ProfessorMdoesScienceАй бұрын
Glad you like it!
@rithin4538Ай бұрын
Thankyou so much for the videos 🙏 They helped a lot
@ProfessorMdoesScienceАй бұрын
Glad they were helpful!!
@mathewvincent692Ай бұрын
Thank You soo much , your videos are the best for the topic in YT, I regained my interest in theoretical physics because of you :))
@ProfessorMdoesScienceАй бұрын
This is great to hear!
@user-rv2qx9yy9xАй бұрын
Thanks - I do have an issue though with the notation towards the end; how can g_{ijkl} be dependent on a specific pair (q,q') when we have eliminated the sum over (space) indices? Shouldn't the expression for $g_{ijkl}$ be free of the q,q' just like the $f_{ik}$ and $h_{jl}$ at the top of the page?
@ronaldjorgensen6839Ай бұрын
thank ytou
@ProfessorMdoesScienceАй бұрын
Thanks for watching!
@ronaldjorgensen6839Ай бұрын
thank you
@ProfessorMdoesScienceАй бұрын
Hope you liked it!
@smkolinsАй бұрын
what sbout mass equivalence with energy? does this set a relationship between mass and time?!
@ProfessorMdoesScienceАй бұрын
Interesting question, we are currently looking at non-relativistic quantum mechanics, but we do hope to cover relativistic QM in the future. We are in fact building towards that with our series on quantum field operators :)
@ronaldjorgensen6839Ай бұрын
use inertia/momentum as void mass gravitation variable any variable isolated spedds operation of solve for AI chip unit
@user-to3fx2do4d2 ай бұрын
Hallo sir ! Unfortunately, in general, neither symmetric nor ant-isymmetric wavefunctions can be said to be eigenfunctions of the Hamiltonian. The wave function for an electron in a hydrogen-like atom with atomic number Z in the ground state is RZ(r)=2(Z/a0)^(3/2)*exp(-Zr/a0). RZ(r) is an eigenfunction of HZ=1/(2m)*p^2-Ze^2/(4πε0r). But RZ(r) is not an eigenfunction of HZ'=1/(2m)*p^2-Z'e^2/(4πε0r), Z'≠Z. Let us consider the case where a hydrogen-type atom with atomic number Z and a hydrogen-type atom with atomic number Z' are sufficiently separated from each other. And each electron in each atom is in the ground state. The anti-symmetric wave function Ψ={RZ(r1)RZ'(r2)-RZ(r2)RZ'(r1)}/2^(1/2) is not an eigenfunction of the Hamiltonian H=1/(2m)*p1^2-Ze^2/(4πε0r1)+1/(2m)*p2^2-Z'e^2/(4πε0r2). It should be an ironclad rule of quantum mechanics that the wave function is an eigenfunction of the Hamiltonian.
@fernandojimenezmotte20242 ай бұрын
Thank You professor M does Science for your wonderful series course in Quantum Mechanics. I am a scientist , that comes from Electrical Enginering course work/career and my final metamorphosis dream is to fully mutate to a mix of Teoretical Physics + Computational Mathematics scientist
@ProfessorMdoesScienceАй бұрын
Glad you like our series, and fully support your aspiration! :)
@BM-pu5eu2 ай бұрын
very nice video
@ProfessorMdoesScienceАй бұрын
Thanks!
@goulchat12 ай бұрын
Nice!
@ProfessorMdoesScienceАй бұрын
Thanks!
@fabio_air42302 ай бұрын
Thanks!
@ProfessorMdoesScienceАй бұрын
Oh wow, thank you!!
@hugom63882 ай бұрын
Would it be correct that at higher energy levels the kinetic energy of the electron decreases as potential energy increases?
@ProfessorMdoesScienceАй бұрын
The kinetic energy is associated with the curvature of the wave function. You can qualitatively understand this by considering that, in the position representation, the kinetic energy operator is the second derivative with respect to position. In this context, the more "wiggly" the wave function, the higher the kinetic energy. If you look at the higher excited states of hydrogen, you will see that they do become increasingly "wiggly" (the number of nodes increases, and therefore so does the curvature). As a result, the kinetic energy grows with the excited state. I hope this helps!
@user-rv2qx9yy9x2 ай бұрын
Very clear, thanks!
@ProfessorMdoesScienceАй бұрын
Glad it was helpful!
@user-rv2qx9yy9x2 ай бұрын
Very clear and concise, thank you! Looking forward to the Quantum Field Operators problems and solutions - any idea when that might be available? 🙂
@ProfessorMdoesScienceАй бұрын
We are working on them! We have two videos left for the series, and we hope to publish the problems simultaneously with the last video :)
@user-rv2qx9yy9xАй бұрын
@@ProfessorMdoesScience Thanks - look forward to them!
@rahulshastri92782 ай бұрын
Never seen this derivation of transformation function between x and p basis. Usually it is directly introduced by Fourier coefficient.
@ProfessorMdoesScienceАй бұрын
I hope you still found it interesting!
@fernandojimenezmotte20242 ай бұрын
Thank You professor M does Science for your wonderful channel in Quantum Mechanics
@ProfessorMdoesScience2 ай бұрын
Thanks for your kind words!
@fatemehsoltani54572 ай бұрын
thank you for the videos. is there any difference between the eigenfunctions and eigenstates for the quantum harmonic oscillators?
@ProfessorMdoesScience2 ай бұрын
The eigenfunctions are the position representation of the eigenstates, so they do describe the same thing. You can check out our videos on wave functions to explore the relationship between wave functions and more abstract states here: kzbin.info/www/bejne/aJ3VZJR3aduUeNU I hope this helps!