this is not how proofs work, and your evaluation is also incorrect. downvoted
@RealMesaMikeАй бұрын
Precedence of operations. You have to take the square roots first before you can multiply i.e. √a × √b ≠ √(ab) in general, as that violates operator precedence. It's a nice shortcut when a and b are both positive reals though, since it gives the same answer as if you had followed proper operator precedence.
@adorianburanko1234Ай бұрын
Good video, but √36 is ±6, so √-9 * √-4 = √36 = -6
@anshuyadavexplainsАй бұрын
@@adorianburanko1234 if any variable then root 36 = +-6
@RealMesaMikeАй бұрын
No, square root symbol is defined as giving the Principal Square Root.
@AaravNaiduORIGINALАй бұрын
0
@ThetSu-e3uАй бұрын
C
@muteebrasool3411Ай бұрын
D
@kovacicchelsea3826Ай бұрын
-2
@takshmakwana3040Ай бұрын
19•19•19=6859
@anshuyadavexplainsАй бұрын
@@takshmakwana3040 ✅️
@daddykhalil909Ай бұрын
1:43 on top of the horrible handwriting you are using a thick pen. Totally Aweful
@anshuyadavexplainsАй бұрын
@@daddykhalil909 okkk I will try❤️
@LentaroToneАй бұрын
nice proof, but you misspelled breaking in the title. You said "braking", as in like pressing the brakes.
@anshuyadavexplainsАй бұрын
Oh thanks❤
@melaomelao8689Ай бұрын
The trick is this: a^2 + b^2 -2ab = (a-b)^2 = (b-a)^2; in the left side you choose (b-a)^2 while in the right side you choose (a-b)^2. The initial choice of diferences are then treated as two squares from which roots are extrated which returns four solutions of which only one is consistent.
@darlenesmith5690Ай бұрын
Not quite. He picked a-b both times. The problem is when he took the square roots. Square roots result in 2 roots, not 1. ((4-5)^2)^1/2 = (4-5) = -1 or -(4-5) = 1. He selected -1. ((6-5)^2)^1/2 = (6-5) = 1 or -(6-5) = -1. He selected 1. If 1 is selected both times, then -(4-5) = (6-5) and the two 5s cannot cancel out. If -1 is selected both times, then (4-5) = -(6-5) and the two 5s cannot cancel out.