Thank you

hi

both white triangles are similar . so 5/x = x/20 => x^2 = 100

we can also find cos 2a because we now cos a and sin a and write cosinus theory in given triangle and in this way we will be able to find ac

Fantastic answer 😍😍🤩

sorry for sound disturbing .....in next video it will not be repeated

it’s animation form is here kzbin.info/www/bejne/kKLbeaJ5qbprppo

Thankyou😊

Awesome explanation ❤️

🥰🥰

Thanks for sharing this video!!

Thanks for the problem!

From which country u are?

Math eager I have one more interesting questions for u plzz solve it but how can I send u a image of question

Nice

sorry for disturbing sound and wrong answer it is 73.....

I don't know, but the music is kinda disturbing to me so i turn off my sound. Good video anyway. Edit : correction 9/5 * 365/9 = 73

If you're gonna put music in a math video at least make it bearable

First

can we solve this problem only by pure geometrical methods other than trigonometry?

sin (30°) = 0.5

Straightforward solution

Area method is elegant

i did sin-theorm in ACE then in ABE ( angle B = alpha ) and fairly simple got tg(alpha)

Your solution is more elegant compared to mindyourdecisions.

Let area of triangle BQL = a. Area of triangle BRC = 9a. Since the triangles are similar And the scale factor is 3. Triangles BQL and CRM are congruent . So area of triangle BCM = 10a = 1/2 x3x1. Thus a = 3/20 Area of quad QRCL =8a =1.2 Area of PQRS = area of ANCL - area of QRCL x2 =6-2.4 = 3.6

Найти длину параболы на определённом участке декартовой системы координат - вот действительно "hard problem"

∆BCM=∆CDN=∆DAK=∆ABL=X X=b*h/2 X=3*1/2 X=3/2 ∆PQRS = ∆ABCD - 4(X) ∆PQRS = (3*3) - 4(3/2) ∆PQRS = 9 - 6 ∆PQRS = 3cm Lo resolví más fácil y sin presunción. Un saludo.

Very heard of Menelaus theorem... :(

Very hard. Thanks for sharing.

How do we know that A-F-C are collinear? I didn't understand

The triangles don't have to be equilateral. They can be random and still the result will be the same.

Great thanks but not hard at all

Nice idea thank you

Amazing.

Do we know that the squares are congruent?

Amazing.

105°

kzbin.info/www/bejne/rIbGf3ePoaenpcU

🤗🤗🤗🤗thank you for solution sir

Correct answer is 8.

Join A and R then <SRA and <SPA will be equal (standing on arc SA) then <BRA becomes 90⁰. and AB is a diameter. It is shortest way to solve that.

Tri angular ٠.any Nomber May be exist volum of large one =×. after That volume of second medium ×-(1/3.) = ×2 Finally third small volume. = ×2- (1/3) ٠

sorry it’s a huge mistake the area of isosceles triangle is mistake here in the video it’s actually b/4 root over( 4 (square of a)- square of b and doing this the area will be 1562.4....

very nice :)

podia-se multiplicar por 0,433x^2 na troca de 6

You can also use heron formula to solve for x

Mind your decision😂😂😂

Boler explain garya vaye jhan ramrari bujhinthyo..anyway thanks ,sir!