Brother 1st unit lo e model okati chusukunta Chala jntua r20 tomorrow exam
@AbhishekCivilTech2 жыл бұрын
Also learn Unit Load Method. Procedure is almost same as that of Castiglianos Method. Only last one step changes
@AbhishekCivilTech2 жыл бұрын
All the best for your Exam
@anucreationsandanuarts99062 жыл бұрын
Ok sir thank u
@anucreationsandanuarts99062 жыл бұрын
Anna small help moment distribution problem lo stiffness.k formula ela thiskovali Anna intermediate support ki
@AbhishekCivilTech2 жыл бұрын
If far end is fixed, then K = I/L and If far end is hinged, then K = 0.75*I/L or (3/4)*(I/L)
@anucreationsandanuarts99062 жыл бұрын
Sir derivation is not ask or ask sir in exam please reply sir
@AbhishekCivilTech2 жыл бұрын
Mostly derivations are not asked in exams. You just focus more on numerical problems. And if you have time then go for derivations.
@ajaytete77512 жыл бұрын
6EI∆/l² is formula but in AB=10m you took 6EI∆/5 it should be 6EI∆/100
@AbhishekCivilTech2 жыл бұрын
I revisited the problem and found nothing wrong in it. All the values were substituted as per the formula. If you still not able to get clarity, please feel free to comment again with your doubt.
@ajaytete77512 жыл бұрын
@@AbhishekCivilTech ok
@CHERUKURIYUVARAJUA2 жыл бұрын
over all sa 2 syllabus was covered by your youtube channel thanks bro
@AbhishekCivilTech2 жыл бұрын
In SA-2 there are few more topics left like Suspension Bridges(Problems on Girders) and also matrix methods(Stiffness and Flexibility). Let me complete those as well
@CHERUKURIYUVARAJUA2 жыл бұрын
bro can you start ddrcs subject bro pls
@AbhishekCivilTech2 жыл бұрын
Super! I am also thinking to start the same subject that you are asking for. Coming soon!!
@CHERUKURIYUVARAJUA2 жыл бұрын
BRO very special thanks to you love from raghu engineering college vijayanagaram
@AbhishekCivilTech2 жыл бұрын
Glad to hear that from you
@saimanjunath49072 жыл бұрын
Sir in video 47.12 in member CF we calculated P forces last column, i think it is -0.5....could you please explain it......?
@AbhishekCivilTech2 жыл бұрын
If there are any calculation mistakes, ignore it and follow the procedure. Thanks for Watching
@saimanjunath49072 жыл бұрын
Bayya in33.47 please calculate p1forces also one video please Bayya
@AbhishekCivilTech2 жыл бұрын
I though of making those calculations as well. But video becomes much lengthy and it may go for 2 parts. So please follow the same procedure that was followed for P0 forces. Thanks for Watching
@saimanjunath49072 жыл бұрын
Sir please explain at horizontal force paf po forces as u said paf=20kn please explain it sir
@AbhishekCivilTech2 жыл бұрын
You can follow same process for that member as well
@saimanjunath49072 жыл бұрын
Brother I'm andhra...i recently discontinued my btech for some reasons....when i rejoined my btech I can't understand this subject....now I have an hope that I can pass my exam Thanking you sir 🤗😍
@AbhishekCivilTech2 жыл бұрын
So glad to hear that. All the best.
@SagarC--2 жыл бұрын
Bro by doing multiplication in finding length AC1 0.5×0.0625 we will get 0.03125 not 0.3125 bro
@AbhishekCivilTech2 жыл бұрын
If there are any calculation mistakes please ignore them and follow the procedure. Thanks for Watching.
@sarcastictrippy2 жыл бұрын
Bro how did you solved those 3 equations can you explain it
@AbhishekCivilTech2 жыл бұрын
If you want to solve manually, you can go for matrix methods like Matrix Inversion Method, Gauss Jordan Method, Cramers Method. or You can use scientific calculator and using mode option, selecting appropriate format of equation like ax+by+cz=d. You enter coefficient values. I will make a video soon you will get more clarity. Thanks for watching
@shortnotesforce13302 жыл бұрын
Excellent sir...sir please do more videos
@AbhishekCivilTech2 жыл бұрын
Thank you very much. I will certainly make more videos
@sivakrishna13332 жыл бұрын
Sir, in AB we have two point loads buts u have calculated only one load
@AbhishekCivilTech2 жыл бұрын
Yes, We should consider one load only. Because another load is acting on the joint, not on the member AB. If it is acting on the member then we should consider that as well. The load which is acting on the joint does not produce any moment because in first step we assume Joint B as Fixed Support. Hope your doubt got cleared. Thanks for Watching
@JayaPrakash_72 жыл бұрын
Bro can u pls explain about how to calculate P1 forces ... I don't know about it , I hope u understand bro
@AbhishekCivilTech2 жыл бұрын
Bro It is similar to the calculation of P0-Forces. I have explained calculation of P0-Forces joint by joint. Similarly take each joint separately and resolve them to get P1 forces in individual members. Nothing new in it.
@susanngatia82472 жыл бұрын
Very helpful Am grateful all the way from Kenya
@AbhishekCivilTech2 жыл бұрын
Thank you
@gnana20032 жыл бұрын
Super bro. It is easy for understanding fastly.
@AbhishekCivilTech2 жыл бұрын
Thank you so much 🙂
@premotube2 жыл бұрын
Nice and thanks 👍
@AbhishekCivilTech2 жыл бұрын
Welcome 😊
@vallicreations4082 жыл бұрын
If there is no load on member CD , in shear condition we have to write Mcd+Mdc /5 or not
@AbhishekCivilTech2 жыл бұрын
Yes. Because it is also a column and it is also subjected to sway
@violetakoth83602 жыл бұрын
Here i am again rewatching this video for my structure 2B thanks alot
@AbhishekCivilTech2 жыл бұрын
Thanks for Watching
@SandeepYadav-bj1zl2 жыл бұрын
Waaa you made my day .i dont knowing how to thank you so i am hiiting hard subscribe need more info from you💖💖💖💖💖💖💖💖💖
@AbhishekCivilTech2 жыл бұрын
So glad to help you. Thanks for Watching
@SandeepYadav-bj1zl2 жыл бұрын
Excellent explanation ji
@AbhishekCivilTech2 жыл бұрын
Thank you very much
@mohammadnaseeruddin76542 жыл бұрын
This problem SA 1 OR SA 2 paper.???
@AbhishekCivilTech2 жыл бұрын
SA2
@mohammadnaseeruddin76542 жыл бұрын
This problem sa 1 or sa 2...???
@AbhishekCivilTech2 жыл бұрын
SA-2
@mohammadnaseeruddin76543 жыл бұрын
This problems structute analysis paper 1 or paper 2 sa 2..???
@AbhishekCivilTech2 жыл бұрын
SA-2
@rajanasreeramaraju95693 жыл бұрын
Hey, for sigma PL/A you have taken value of sigma P1PL/A.
@AbhishekCivilTech3 жыл бұрын
While calculating redundant forces, we should consider combined action of P and P1 forces.
@sayyaparajujahanvi38093 жыл бұрын
I also got 8426.7,how you got 13920
@AbhishekCivilTech3 жыл бұрын
Its a calculation mistake. But the procedure is same. Thanks for Watching
@tejaavijay21983 жыл бұрын
Why don't we consider 80kn downward force for calculation of 'Ve' in P&F
@AbhishekCivilTech3 жыл бұрын
At point E, the vertical shear is 120KN. So we dont consider 80KN.
@Sh21ivA3 жыл бұрын
Excellent.....too much concepts in one vedio
@AbhishekCivilTech3 жыл бұрын
Thanks a lot
@amritkhatiwada78833 жыл бұрын
All good bro, but how about indication of signs ?? Are all BMD +Ve or what?
@AbhishekCivilTech3 жыл бұрын
At the supports or joints we will get -ve moments. At mid spans we will get +ve moments. Thanks for Watching.
@sharanukonchur90533 жыл бұрын
90 kn load. Is not considered
@AbhishekCivilTech3 жыл бұрын
There is no 90KN load in the frame. I think you are asking about 80KN load. That load is acting exactly on the joint. So we dont have any moment due to 80KN load. Thanks for Watching.
@sharanukonchur90533 жыл бұрын
Hlo sir
@AbhishekCivilTech3 жыл бұрын
Hello.
@saicharanjajula84933 жыл бұрын
Tq bro
@AbhishekCivilTech3 жыл бұрын
Thanks For Watching
@sajeelbilal36533 жыл бұрын
Sir how did you calculated the values of the equations with calculator?
@AbhishekCivilTech3 жыл бұрын
In scientific calculator you can solve the equations by entering the values of coefficients
@chintandiora95183 жыл бұрын
Bole toh salute karne ka man ho gya sir ji Make so easy sir 🤝👍😊💐
@AbhishekCivilTech3 жыл бұрын
Thanks for Watching
@dancingfelloww3 жыл бұрын
Thanks for the clear explanation bro..
@AbhishekCivilTech3 жыл бұрын
Thanks for Watching
@violetakoth83603 жыл бұрын
Legendary keep doing more of these 🤛
@AbhishekCivilTech3 жыл бұрын
Thank You very much and I will definitely try
@violetakoth83603 жыл бұрын
Thanks man that was life saving🤜
@AbhishekCivilTech3 жыл бұрын
Thanks for Watching
@suryas17493 жыл бұрын
This is cantilever truss ahh?
@AbhishekCivilTech3 жыл бұрын
No, because for Cantilever one end must be fixed. We are not having any fixed support in the given truss. Thanks for Watching
@cameraworldstudio3 жыл бұрын
Well explained 👍
@AbhishekCivilTech3 жыл бұрын
Glad it was helpful!
@srinidhijakku10743 жыл бұрын
Then how to draw shear force diagram to this
@AbhishekCivilTech3 жыл бұрын
1. Divide the frame into 3 members 2. Calculate the Reactions at each end based on given loads and calculated moments using equilibrium equations. 3. Then using the reactions calculate the shear forces at various points on that member 4. Then draw the Shear Force Diagram as usual like you draw for Simply Supported beam
@Yashu_malviya3 жыл бұрын
Nice lecture 😊
@AbhishekCivilTech3 жыл бұрын
Thanks a lot 😊
@soorajkumar74593 жыл бұрын
THANK YOU SO MUCH MAN..MY CONFUSN GONE...
@MIXED__CONTENT_113 жыл бұрын
Super 😘 thank sir .....
@AbhishekCivilTech3 жыл бұрын
Welcome
@namanjain83413 жыл бұрын
You explained it very easily.
@AbhishekCivilTech3 жыл бұрын
Thank You very much
@violetakoth83603 жыл бұрын
Great work thankyou
@AbhishekCivilTech3 жыл бұрын
So nice of you
@rezaahmadi85833 жыл бұрын
in the 14th minute of the video plz check once, 25*cos(53.13)=15. U have taken as 20.
@AbhishekCivilTech3 жыл бұрын
Yes, You are right. Its 15KN. Thank You for identifying the mistake. But procedure is more important in examination
@startengineering73943 жыл бұрын
big confusion solved in avery simple way...thankyou♥️
@AbhishekCivilTech3 жыл бұрын
Glad to hear that
@unluckyboy39283 жыл бұрын
Guruji you r great abhishek mahesh babu
@AbhishekCivilTech3 жыл бұрын
Sukhibava
@thechosenstudios3 жыл бұрын
HEART STOLEN EXPLINATION BLESS U BROTHER MORE TO COME FROM YOU