excellent explanation sir 💯💯

Thank you handsome sir ☺️

Thanks a lot sir

Thanks sir

s = 0 tha na

🤩🤩

at the end the video : tsin(at)-Cos(at)/2a -(0-Cos(-at)/2a)= tsin(at)-cos(at)/2a-Cos(at)/2a ? please help me to solve the correct ans

Thank you so much sir ❤

Helpful

Thanks sir

deserve a subscriber

underrated sir

wow superb explanation, I was struggling with this question and now all cleared

Thanks sir

thank you sir

I like your teaching style. ..Thank you✨

Very nice explanation 👍👍

Excellent solutions very helpful for me Please aise hi video or baniye or jyada questions solving video bnaiye

nice explanation

This is not trick😅

could have been much easier if you had noticed it was nothing but the differentiation of -1/(s^2+s-2)

Sir asla em balee

11/2 kaise

why canot we do this using imaginary part method sir

Thank u ❤

Jazakilah ❤

-f(0) kaha gaya bhai

Thank you sir

Multiply and divide by 2, then it is laplace inverse of F'(s)= -tf(t), Where F(s) is, -1/(s^2+4s+5)

Thank you sir

Thankyou sir 😊

Thanku sir

Thank you sir

Thank you for your good explanation sir

ek question ek din me ho paya

Thank u sir I'm Tamilnadu

pehle step mei e^(-t) common lia toh bracket mei andar 1 - e^(-2t) kaise bacha? 1 - e^3 bachna chaiye thaaaa

♾️×0= indeterminate form not zero please give a detail explanation about it.......🙏🙏🙏🙏

aaj danish bhai zinda hote na.....

Aap bahut handsome ho sir ji😊

To boring class

❤❤❤❤

Voice is not clear

❤love you 🤟 sir i subscribed your channel but plese take care of your body also....lol so thin

Find inverse laplace of [1/(s^3+1)s^3]

Great video sir thank alot

sir isme e^2ix = sin2x ni lege? and e^2ix= cos2x+ isin2x

Super sirr❤ good explanation

thanks🇳🇵

thanks from 🇳🇵