3 ай бұрын
3 ай бұрын
3 ай бұрын
3 ай бұрын
Пікірлер
@dotard0075 Ай бұрын
14:40 is wrong. poly[imino(1-oxohexane-1,6-diyl)] is right
@ThePolymerScienceTutor Ай бұрын
I wanted to deliberately be consistent with the nomenclature provided in ‘Principles of Polymerization’ by Odian, according to which the name should be poly [imino(1-oxohexamethylene)] as mentioned in the video. The name you have written is also correct. Thanks for your comment.
@ThePolymerScienceTutor 2 ай бұрын
I received a request to post the solution to this question. Hope it is helpful.
@Syedtx 3 ай бұрын
Plz upload more video related to polymers it will help students especially in india Love from india
@시트러스-f4t 3 ай бұрын
Thank you!
@SumitChaudhary-u6w 5 ай бұрын
Amazing Thank you very much
@ThePolymerScienceTutor 11 ай бұрын
You’re right, Thanks for catching that. By correcting for Phi to be 2.5 x 10^21, r^2/M comes to 48.66 x 10^-18 cm2 mol g-1. Do you concur?
@lukemorgan3488 11 ай бұрын
When converting Phi's units from dl -> 100 cm^3, you reduced the exponent 10^21 -> 10^19. Wouldn't the exponent go from 10^21 -> 10^23, since we're multiplying by 100? Thank you for doing these!
@LucyOfAeonia Жыл бұрын
I have been given Extent of reaction vs time data. I have calculated the degree of polymerisation for every p value and the number average molecular weight. How could i calculate the remaining monomer concentration at a specific time? If i had concentration data then the intercept would be equal to 1/Ao^2 and i could calculate Ao. But intercept = 1 when using 1/(1-p)^2 = 2ktAo^2 + 1. How would i find Ao to then find A at time t
@ThePolymerScienceTutor Жыл бұрын
If you do not know the initial monomer concentration, but would like to know the concentration of monomer left at any time t, use [M] = [Mo] - [Mo.p] . so [M]/[Mo] = 1-p. Plug in the value of p since you know p at time t. If p= 0.5, at say time t1, then [M]/[Mo] = 1-0.5 = 0.5. So, half of the monomer concentration will remain at time t1. If p= 0.8 at a different time t2, then [M]/[Mo] = 1-0.8 = 0.2. So 20% of the initial monomer concentration remains at time t2. If the actual initial monomer concentration is not given, you can in this way determine the fraction of monomer concentration that will remain at any given time. Let me know if this answered your question.
@LucyOfAeonia Жыл бұрын
Yes thank you so much , this is exactly what i need to do. again thank you @@ThePolymerScienceTutor
@하하호호-s4b Жыл бұрын
Why not the statistical at second??
@ThePolymerScienceTutor Жыл бұрын
Since average “E” sequence length is significantly more than average “H” sequence length for the second case.
@abhisheksnayar4003 Жыл бұрын
Informative
@MuhammadSaad-xp7gp Жыл бұрын
Any lecture on how necleation occurs?
@ThePolymerScienceTutor Жыл бұрын
Will do.
@MuhammadSaad-xp7gp Жыл бұрын
Thankyou