djdmath

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@yogurt150 Ай бұрын

Thank you!

@highlightmuseum8425 2 ай бұрын

This video did not help me at all.

@basudevbhattarai1939 2 ай бұрын

That's the calculator being stupid 😂

@user-kw4jn8od4z 3 ай бұрын

ITZ THE BEZT VIZEO IVE ZEEN FOR CAZALAN NUMBERZ.

@joeycar 6 ай бұрын

Goat

@Atharv.. 6 ай бұрын

TYSM YOU HELPED ME UNDERSTAND IT ❤

@mc.hammer 6 ай бұрын

thank you for this

@ANoteWeaver Жыл бұрын

Thank you

@rockingbadshah1848 Жыл бұрын

finally good stuff on counting

@meetamin7343 Жыл бұрын

Great explanation

@ijustcomment3533 2 жыл бұрын

Why did you stop?

@andrewchen861 2 жыл бұрын

Thank you for the episode!

@saw2005. 2 жыл бұрын

Your wonderful you saved my grade im thankful

@mardenge 2 жыл бұрын

Thank you!!

@VV-xt7fj 2 жыл бұрын

Thank you so much. This is the best explanation for catalan numbers that I have seen!

@leopoldopedersen1218 3 жыл бұрын

I like your video

@f5673-t1h 3 жыл бұрын

The Catalan numbers give you how many ways there are to parenthesize a sum, e.g. 2 ways of parenthesizing a+b+c as a+(b+c) or (a+b)+c. So how does this correspond with the above problem with paths? Well, at every step, the number U's must be <= the number of R's. This is the same thing as making sure that a sum is properly parenthesized when you're reading it from left to right: The number of right parentheses must be less than or equal to the number of left parentheses, and you can correspond a string of R's and U's with ('s and )'s, respectively.

@dolevdo 3 жыл бұрын

finnally i understand this topic thanks

@dolevdo 3 жыл бұрын

Great video. Extremely helpful

@debarghyakundu4094 3 жыл бұрын

nice explaination.

@EcoleLibre 3 жыл бұрын

Accent insupportable (nasal). Désolé. Pas capable.

@mk-ml4tn 3 жыл бұрын

What is the point of complementing rest of the path as we are ending at (4,6) not at (5,5)

@S_P_A_C_E_DD 3 жыл бұрын

Why does 10C4 represent every bad path though?

@fahyen6557 3 жыл бұрын

Who else is preparing for the AMC in Frebruary?

@fahyen6557 3 жыл бұрын

Ahh Ha. Interesting.

@fahyen6557 3 жыл бұрын

It gets more intuitive as I think about tho.

@fahyen6557 3 жыл бұрын

I have so many questions, that I don't how to ask.

@shubhamp. 3 жыл бұрын

0:42 he is an Indian not an Italian.

@djdmath Жыл бұрын

You are definitely correct, it was a slip of the tongue. Bhaskara was definitely Indian. Thank you for catching this.

@johng5295 4 жыл бұрын

Thanks in a million. Very well explained.A++

@박주호오늘은찐수학 4 жыл бұрын

What program do you use?

@poongodidhanasekaran8801 4 жыл бұрын

Example 3, does 'v' denote one in 'a,b..e' or operation? its used in both ways, bit confusing

@djdmath 4 жыл бұрын

I intend them to represent the variables a, b, c, and d. The first v will always represent a, the second v will always represent b. The close parentheses and e are, then, included to ensure that the algebraic syntax is valid. Notice that ppvvpv... => ((a*b)*(c... whereas ppvpvv.. => ((a*(b*c)...

@guslopez8760 4 жыл бұрын

First comment

@djdmath 4 жыл бұрын

Congratulations!

@abuyd4423 4 жыл бұрын

Is this possible without an equation for f?

@djdmath 4 жыл бұрын

You can still approximate the value of a derivative of a function without explicitly knowing the equation for f. The most common situation I have seen for AP Calculus AB (or college Calculus 1) is the case where you have a table of information. When trying to estimate the derivative, you simply move the two points as close as possible (even though you obviously cannot take the limit all the way to zero in this situation). e.g. Say that you know that the points (x, f(x)) contain (2, 4), (4, 16), (6, 64), (8, 256), and (10, 1024). If I wanted to approximate the derivative at x=3, I would simply find the average slope of the two points most closely bounding three: (2, 4) and (4, 16). This would lead to an approximate derivative value of (16-4)/(4-2)=6.

@yanhao9583 4 жыл бұрын

Amazing explanation!

@muhammadhattahakimkeren 5 жыл бұрын

thanks a lot for your video

@muhammadhattahakimkeren 5 жыл бұрын

Extra from me Proof for #of bad path = #of new path every new path has (n-1) Rs and (n+1) Us, therefore there is a point where #of Us > #of Rs so to every new path we can make one bad path, since bad path can only created one new path than function bad path to new path is bijection therefore #of bad path = #of new path

@djericwang 5 жыл бұрын

You’re a legend

@jaspreetkaur6745 5 жыл бұрын

How we can solve if there is another points are given like (2,3) to (4,7)?????????

@luojihencha 5 жыл бұрын

genius

@Gaer56 5 жыл бұрын

Im not sure what is right anymore, the lesson is easy but diffirent people present it diffirently , one above and one below line. There are also diffirent catalan number like in () examples

@kumarkrish1073 5 жыл бұрын

@woonsang 5 жыл бұрын

Great explanation!

@neslef3 5 жыл бұрын

If you have a sequence of R's and U's where it crosses the diagonal twice, there are two places where you can perform the 'flip' to get the U = R +2 result. (i.e. say for RUURRUUR you can perform the flip at RUU | RRUUR and get RUU | UURRU or you can perfom it at RUURRUU | R and get RUURRUU | R which both meet the desired requirements). Now if this is the case isn't it no longer a bijection and a one-to-one function and thus the proof is not longer valid? I know the function still works for determining the number of possible paths, but I don't see how we can validly get to that point. Please help

@lohe2499 5 жыл бұрын

why need to change R to U and U to R... somebody can explain?

@croraf 3 жыл бұрын

It is not very well explained here, nor in the other videos. I found the best explaination on english wikipedia (proof 2).

@neslef3 5 жыл бұрын

Great video. Extremely helpful. At about 15:30 when you are trying to prove the inverse from the U = R+2 set to the bad path set, for me it is much easier and convincing to go from the opposite direction and go from the back, looking for the first (and only) spot where there is 1 (and only 1) more U than R (and at least 1 R) and flip it from there. It is easier for me to prove/understand that the only way to from 6 U's and 4 R's is to flip it where there is 1 more U than R (and thus subtracting 1 U and adding 1 R). If this is wrong/ I made any wrong assumptions please Comment.

@samiahmadkhan2865 5 жыл бұрын

github.com/skhan75/CoderAid/blob/master/Techniques/Catalan%20Number/parentheses_combinations.py

@dannup25 5 жыл бұрын

Few videos explain as well as you. It is a shame that you have very few visits. Definitely not fair!

@hilafishman6339 5 жыл бұрын

Thank you!

@samchan2535 6 жыл бұрын

Clean and lucid explanation.

@cassandragonzalez7171 6 жыл бұрын

so awesome!!!!!.

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