This seems to be the lecture my professors are using as a template for teaching in class. I am excited to finish the 60 lectures asap!
@aerodynamico64276 ай бұрын
Teaching is much better if you don't slow down everybody by your writing speed. Edit the video to fast forward when you are writing. See some of the excellently produced lecture videos from the U.S.A.
@HuneMan-f8z6 ай бұрын
Please sent to me as PDF formHydrogen at 15 ºC and a pressure of 1 atm. is flowing along a flat plate at a velocity of 3 m/s. If the plate is 0.3 m wide and at 71 ºC, calculate the following quantities at x = 0.3 m and at the distance corresponding to the transition point, i.e., Rex = 5 x 105 (take properties at 43ºC) (a) Hydrodynamic boundary layer thickness, in cm, (b) Local friction coefficient, (c) Average friction coefficient, (d) Drag force, in N, (e) Thickness of thermal boundary layer, in cm, (f) Local convective-heat-transfer coefficient, in W/m2-ºC, (g) Average convective-heat-transfer coefficient, in W/m2.ºC, and (h) Rate of heat transfer, in W. Consider a 15-cm x 20-cm printed circuit board (PCB) that has electronic components on one side. The board is placed in a room at 20°C. The heat loss from the back surface of the board is negligible. If the circuit board is dissipating 8 W of power in steady operation, determine the average temperature of the hot surface of the board, assuming the board is (a) vertical, (b) horizontal with hot surface facing up, and (c) horizontal with hot surface facing down. Take the emissivity of the surface of the board to be 0.8 and assume the surrounding surfaces to be at the same temperature as the air in the room. A shell-and-tube heat exchanger with 2-shell passes and 8-tube passes is used to heat ethyl alcohol (Cp = 2670 J/kg · °C) in the tubes from 25°C to 70°C at a rate of 2.1 kg/s. The heating is to be done by water (Cp = 4190 J/kg · °C) that enters the shell side at 95°C and leaves at 45°C. If the overall heat transfer coefficient is 950 W/m2 · °C, determine the heat transfer surface area of the heat exchanger.
@hongsethya49326 ай бұрын
thank you so much step indian
@Hariharan-d6s7 ай бұрын
Can anyone explain how sir wrote the accumulation term?
@HACKER-we8lb10 ай бұрын
old is gold
@kutraleeshwaranb2595 Жыл бұрын
pls give mathematical derivation or concept links for past few lectures(bessel's function,orthogonality condition,etc) as most of them don't have same mathematical prerequisites required for solving heat transfer problems. i have heat transfer in this semester but math required for heat transfer is in upcoming semesters.
@Kamlesh_mechdestiny Жыл бұрын
Awesome sir
@Shin123-f5j Жыл бұрын
It was very good!
@naan_manithan Жыл бұрын
Why the centre of symmetrical heat profile consider as adiabatic sir? Practical explanation please sir!!
@naan_manithan Жыл бұрын
Sir while seeing plane wall with generation u said that "when we have heat generation we can't use resistance model concept " And then in example sum u used the resistance concept to find T1? while we have heat generation at slab A how we can use resistance concept sir
@pritom7298 Жыл бұрын
best sir
@pritom7298 Жыл бұрын
Thank you for the great helping tools you have delivered, sir.
@mandarivenkatesh517 Жыл бұрын
One of the best lectures in my life. Thank you Professor. If possible please provide lectures of mass transfer and thermodynamics
@KakarotM99 Жыл бұрын
This was one of the best Heat Transfer Course I've seen. Apart from having a brilliant mind, Prof Ganesh is an excellent communicator. He breaks down such complex concepts into understandable and digestible bits. His coverage on Convection and Radiation is absolutely brilliant, people make these topics so complex, yet Prof is able to break them down into simple intuitive chunks.
@thepiyushparihar3463 Жыл бұрын
THODA HIGH LEVEL HO GYA SIR
@aryanthakur9995 Жыл бұрын
Why did we have to stick the thermocouple at x=0? Any other point would have worked just as well, right?
@VarunSrinivas4 ай бұрын
that is because we have to cancel the x^2/L^2 term in the bracket, to give a simple equation. it would have worked anywhere yes.
@neonroy1431 Жыл бұрын
Thank you so much sir for such a vivid explanation.
@neonroy1431 Жыл бұрын
Thank you sir for explaining in such a better way.
@yashprajapati7699 Жыл бұрын
who hired this cameraman
@PawanVerma-jj1iy2 жыл бұрын
The board is not visible properly
@krishnakhandelwal2882 жыл бұрын
Appreciable explanation
@krishnakhandelwal2882 жыл бұрын
It was a phenomenal explanation
@sahilpani86102 жыл бұрын
Poor videography
@sairahul41822 жыл бұрын
Outstanding Explanation!
@shijilan75542 жыл бұрын
helped a lot for my ct prep . tq sir
@NAYAN-t3e2 жыл бұрын
This Tamil professor is so perfect to teach tough subject in a very lucrative way. ❤️
@khollgyrddr38202 жыл бұрын
thank sir for giving such very passionate lecture of heat transfer
@ChemicalengineerVlogs2 жыл бұрын
Tq you sir love u a lot❤❤
@sahilgajbhiye06562 жыл бұрын
ty very much sir
@umeshjasawat12643 жыл бұрын
3:40
@NAYAN-t3e3 жыл бұрын
The explanation of the concepts is not up to the mark as compared with IIT Kharagpur or Madras lectures.....
@ChemicalengineerVlogs2 жыл бұрын
This is not good ,first complete the course then you will realize it is good
@umeshjasawat12643 жыл бұрын
10:00
@ganeshviswanathan10353 жыл бұрын
Typo: The term indicated at 22:09 in Rohsenow correlation should be raised to the power "3".
@israilisrail44133 жыл бұрын
Thanks sir
@SasiKumar-xs1yn3 жыл бұрын
How did you calculate T1
@vishwaroop1431 Жыл бұрын
calculate overall resistance network and put value of q.