I’ve been aiming for like 10-15 problems a day the past month. Seeing my speed improve a lot so just need to perform on these interviews. Godspeed
@OmoruyiOmofonmwan7 күн бұрын
Gonna subscribe. You can do it my man
@KoustavSeth-n9z7 күн бұрын
I'll be checking everyday Can ask me anything if you want i recently recieved 2 job offers
@andygarcia65937 күн бұрын
Good shit bro, I’m on the Leetcode grind too. Wish you luck brother🗣️🗣️‼️‼️🫡
@walkoss4608 күн бұрын
Hello, I suggest you to solve this one without any string manipulation and casting.
@naveenairani9 күн бұрын
Im also doing leetcode still learning and will learn till i land a job, hope you work well with taking care of your health and joy at the same time. Im with you brother.
@keremleoyna36429 күн бұрын
Basınnnnnn türkler gelsin bu adama baskın türkler
@roshanchauhan11239 күн бұрын
Bro is awesome, I can solve this sum in 5 mins
@saroman325moon29 күн бұрын
keep grinding bro, im just starting too hopefullly we'll land perfect jobs why not at FAANG
@Poopooman69010 күн бұрын
Bro I'm doing leetcode too. I hope we make it. Bless
@codestreakwithleo10 күн бұрын
Let's make it together 💪🏼
@sangamgyawali229910 күн бұрын
HOW OLD ARE YOU?
@Micha-mx8ii10 күн бұрын
What about this? Does this comply with the requirements? result = [] for k in range(len(nums)): if nums[k] in nums[:k]: result.append(nums[k]) return result
@udaykiran242710 күн бұрын
No, will give a TLE as it's O(n^2)
@daniyalhodekar568011 күн бұрын
while doing binary search inside rotated sorted array its guaranteed one half will always be sorted, use this fact to your advantage
@pritkanani433811 күн бұрын
I didn't watched the whole video but I think if you could do like first overlapped and do k-1 so it will increase again to k and recheck again , i guess.😊
@amishgupta10211 күн бұрын
so cool
@yutongzhu942211 күн бұрын
bro does not feel like wearing clothes
@mickmoon68879 күн бұрын
too comfortable with own skin
@MusammaSultan12 күн бұрын
Why r u trying so hard to end up a slave in corporate? U seem intelligent, u can do greater things. Just saying.
@idkname712 күн бұрын
I'm gonna follow you , because I wanna do this too , currently studying dsa.
@5foreign34612 күн бұрын
this uses O(n) space not constant
@SagarSingh-wj4pn12 күн бұрын
correct! my guy mistook linear for constant space
@codestreakwithleo12 күн бұрын
Thanks for pointing it out, I missed the O(1) space complexity condition there. Had a further look at the problem again, and it looks like doing the nums[abs(nums[i]) - 1] < 0 approach should work