This is class 8th question

Write "x =", not "a =". FAIL.

A. B isn't a math operator that I am familiar with.

Failed? This exercise? Better stay away from maths physics engineering and all the rest !

(a+b)^2=a^2+b^2 +2ab 400=a^2+b^2+88 a^2+b^2=312 (a-b)^2=a^2+b^2-2ab (a-b)^2=312-88=224 a-b=4✓14 a+b=20 2a=20+4✓14 a=10+2✓14 b=20-10-2✓14 b=10-2✓14

I used another way. a+b = 20, so a^2+2ab+b^2=400, but ab=44 so a^2+b^2=400-88=312. (a-b)^2=a^2-2ab+b^2, so (a-b)^2=312-88=224. a-b=+-sqrt(224)=+-4sq(14). Since a+b=20. 2a+b-b=20+-4sqrt(14). a=10+-2sqrt(14) and b=20-a for each case.

y = x - 65. sqrt(y) = 13 - sqrt(x). Squaring and using the above equation x - 65 = y = 169 - 26sqrt(x) + x. Simplifying 26sqrt(x) = 234, sqrt(x) = 9. Squaring, x = 81. So, y = 81 - 65 = 16. Checking, the answer is correct. Thus, x + y = 97.

why 5^x = 2 = 1?

You’ve lost roots in case a=b. It’s (1+-sqrt(293))/2

-2

? = 8. Keterangannya= 8.9.4=8+4=12-3=9 7.13.9=7+9=16-3=13 6.?.5=6+5=11-3=8

15/6 - 1/2 = 15/6 - 3/6 = 12/6 = 2

A=13 B=19 C=25 A+B+C=57

10

10

92

57

13+18+26=57

63

13+6+38=57

Don't make track all of wrong be thoughtful.

92.

(x + y)² = 49 => x + y = ±7 x² - y² = 7 (x + y)/(x - y) = 7 x + y = 7 x - y = 1 x = 4 => y = 3 => xy = 12 x + y = -7 x - y = -1 x = -4 => y = -3 => xy = 12 *xy = 12* ANOTHER WAY (x + y)² = 49 x² - y² = 7 (x + y)/(x - y) = 7 => x + y = 7(x - y) (x + y)² = 49(x - y)² 49 = 49(x - 1)² => (x - y)² = 1 (x + y)² = 49 (x - y)² = 1 4xy = 48 => *xy = 12*

_x² + xy = 28_ ... ① _y² + xy = 21_ ... ② Subtracting ② from ① _x² - y² = (x + y)(x - y) = 7_ ... ③ Adding ① and ② _x² + y² + 2xy = (x + y)² = 49_ ⇒ _x + y = ±7_ Substituting into ③ _±7(x - y) = 7_ ⇒ _(x - y) = ±1_ But _x + y = ±7_ ∴ _x = ±4, y = ±3_ ⇒ *_xy = 12_*

Wrong doings

14 correct answer

55

This works only with special numbers because there are some funy things in the mathematics! Make it with sqr(10) or sqr(36) or sqr(121)!

Its 14

It is all wrong doings.

Окей, посчитай корень из 3600

G❤❤

The imaginary solution cannot be accepted because only real values are admitted.

??😢

X=-7

C,=-7

x=-7

If a, b are the real numbers a² - b² = 49 (a+b)(a-b) = 7² a+b = 7 a-b = 7 --------- + 2a = 14 a = 7 --> b = 0 ============ a+b = 7 a-b = 7 --------- - 2b = 0 b = 0 --> a = 7 ============ a² - b² = 49 (a+b)(a-b) = 1*49 a+b = 1 a-b = 49 --------- + 2a = 50 a = 25 --> b = -24 =============== a² - b² = 49 (a+b)(a-b) = 49*1 a+b = 49 a-b = 1 --------- + 2a = 50 a = 25 --> b = 24 ============== (a,b) = (7,0),(25,24)(25, -24) 5:39 You've missed 1 value 🤗🤗🤗

392 = 2³7² = 7²(7 + 1) = 7³ + 7² x² - x³ = 7³ + 7² (x³ + 7³) - (x² - 7²) = 0 (x + 7)(x² - 7x + 7²) - (x + 7)(x - 7) = 0 (x + 7)(x² - 8x + 56) = 0 *x = -7* x² - 8x + 56 = 0 => complex roots

❤

?????

how did you establish the equations for a and b at 2:40?

3^x + 3^x = 90 2*3^x = 90 3^x = 45 3^x = 3²*5 log 3^x = log 3² + log 5 x log 3 = 2 log 3 + log 5 x = 2 + log 5/log 3 x = 2 + ³log 5

Other root is imaginary...so that must be discarded by saying this root cannot exist.

Best part of the solution was when a fly landed on log 3/log 3 at 3.50.

This guy will solve all the problems in the world. Go outside, get some fresh air.

Why go past log45 / log 3 ?????

Please one equal sign only once in your solution not twice. Each equation will have only one equal sign.

wow very daNgerous😇😇

𝘑𝘶𝘴𝘵 𝘢 𝘸𝘢𝘴𝘵𝘢𝘨𝘦 𝘰𝘧 𝘵𝘪𝘮𝘦 𝘪𝘧 𝘺𝘰𝘶 𝘨𝘪𝘷𝘦 𝘵𝘩𝘪𝘴 𝘱𝘶𝘻𝘻𝘭𝘦 𝘵𝘰 𝘢𝘯𝘺𝘰𝘯𝘦 𝘧𝘰𝘳 𝘴𝘰𝘭𝘷𝘪𝘯𝘨.... 🙏