// Proof of the Riemann hypothesis will not be said to because it will lead to defamation of oneself. Waiting for an unknown person to appear. Riemann hypothesis. s=1-s, s→1-s, s-1=s, If s=1/2+i , 1/2+i=1/2-i, or If s=1/2-i, 1/2-i=1/2+i, The real part becomes 1/2 and becomes super symmetry. This is the motive for the Riemann hypothesis. // The Riemann hypothesis is inevitably π=2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2 … and π is an infinite product of 2. Normal π=3.141592653589793…, this is from the I/O project. As long as you can get infinity on Critical Strip, you should be fine. This shouldn't be a problem. The infinite product representation of 2 corresponds to an infinite length straight line tangent to a circle. So if you draw a circle in the space of the curve, it will be π= 3.141592653589793… , Representing π/2 of Wallis. [Square of all even products] / [Square of all odd products] /π =[The infinite product of 2 ]/π =1/1 =1, so π=2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2 …, [The infinite product of 2 ]/π =1/1 =1, so π=2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2×2 …, When displayed as π=2×2×2×2×2×2×2×2×2×…, it corresponds to the circumference of the radius. And it corresponds to the length of an infinitely expanded semicircle arc. ⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️ Redisplay π/2 of Wallis. 2Π =π =Inf[2×] =2×2×2×2×2×2×2×2×2×2×…, 1/1=2Π/π=Inf[2×]/π, 1/2=2Π/2π=Π/π=Inf[2×]/2π, 1/3=2Π/3π=Inf[2×]/3π, 1/4 =Inf[2×]/4π =2Π/4π =4ΠΠ/16ππ =Π/2π =ΠΠ/4ππ, 1/5 =Inf[2×]/5π =2Π/5π, 1/6 =Inf[2×]/6π =2Π/6π =Π/3π, 1/7 =Inf[2×]/7π =2Π/7π, 1/8 =Inf[2×]/8π =2Π/8π =Π/4π, 1/9 =Inf[2×]/9π =2Π/9π, 1/10 =Inf[2×]/10π =2Π/10π =Π/5π, 1/11 =Inf[2×]/11π =2Π/11π, 1/12 =Inf[2×]/12π =2Π/12π =Π/6π, 1/13 =Inf[2×]/13π =2Π/13π, 1/14 =Inf[2×]/14π =2Π/14π =Π/7π, 1/15 =Inf[2×]/15π =2Π/15π, 1/16 =Inf[2×]/16π =2Π/16π =Π/8π, 1/17 =Inf[2×]/17π =2Π/17π, 1/18 =Inf[2×]/18π =2Π/18π =Π/9π, 1/19 =Inf[2×]/19π =2Π/19π, 1/20 =Inf[2×]/20π =2Π/20π =Π/10π, 1/21 =Inf[2×]/21π =2Π/21π, 1/22 =Inf[2×]/22π =2Π/22π =Π/11π, 1/23 =Inf[2×]/23π =2Π/23π, 1/24 =Inf[2×]/24π =2Π/24π =Π/12π, 1/25 =Inf[2×]/25π =2Π/25π, As a result of the Riemann hypothesis, π is an even number of infinite products of 2. When the radius is infinite, π is displayed as π=2×2×2×2×2×2×2×2×…. This occurs in an extreme undistorted space in the entire space. The predecessor, especially Euler, should have understood. However, it was too early for the times to accept it.