Super sir

😍😍😍

Super Sir🥰❤

Super Sir🥰❤

Super sir.🎉😊

ಅರ್ಥ ಆಯ್ತು ಸಾರ್

❤

Nice explanation sir

Excellently Explained sir Third Problem can also be solved by using the following operations [X2, +1, X2, -1] with respect to individual column With respect to 1st column 5 X 2 = 10 => 10 + 1 = 11 11 X 2 = 22 => 22 - 1 = 21 With respect to 2nd column 8 X 2 = 16 => 16 + 1 = 17 17 X 2 = 34 => 34 - 1 = 33 With respect to 3rd column 7 X 2 = 14 => 14 + 1 = 15 15 X 2 = 30 => 30 - 1 = 29 Therefore the answer is 29

Dear Manu sir, After seeing the students response/interaction to the questions being asked shows that how effective and eminent teacher you are at delivering the concepts To be a great teacher in Mathematics, one must have excellent language and vocabulary skills. You are so good in both All these things happening for a good cause... Just keep going sir

Nice presentation ಮಾಮ್

Dear sir, Those students are very blessed to have such a wonderful mathematics teacher like you Each and every point has been excellently delivered

Explained very nicely sir As we know that a^(m-n) = a^m/a^n Suppose if m = n then the above expression becomes a^(n-n) = a^n/a^n a⁰ = 1

Nice explntn👌👌

👍

😊

👍

Good initiative sir

Suuper....good luck...

Super sir