Just wanted to say that the multiplication "⚫" keeps tricking me into thinking it's a decimal point. Makes the math wildly confusing for a moment!
@surinetso83462 күн бұрын
√84+√49/√84-√49 = -1
@asiman9995 күн бұрын
9×4=36 3+6=9 396
@ManojkantSamal5 күн бұрын
Respected Sir, Good afternoon.....
@ManojkantSamal5 күн бұрын
*=read as square root ^=read as to the power As per question *{5+*(21)}=? Now simplify 5+*(21) Multiply 2 in both numerator and denomiator So the following Will happen. 2{5+*(21)}/2 ={10+2.*(21)}/2 ={3+7+2.*(21)}/2 ={(*3)^2+(*7)^2+2.*(21)}/(*2)^2 =(*3+*7)^2/(*2)^2 ={(*3+*7)/*2}^2 So the given question can be written as *{(*3+*7)/*2}^2 =(*3+*7)/*2 =*2(*3+*7)/(*2×*2) =(*6+*14)/2 =(1/2)×(*6+*14)
@shahlasomeban98966 күн бұрын
396
@SabitriSingh-e5m7 күн бұрын
396😊😊
@ralph_65798 күн бұрын
(√84+7)²/(84-49) =(133+28√21)/35 =(19+4√21)/5
@asiman9999 күн бұрын
1086
@ІраМострянська10 күн бұрын
10816
@sie_khoentjoeng488612 күн бұрын
Let A=√84 and B=√49 and A^2=84, B^2=49 (√84+√49) /(√84-√49) =(A+B) /(A-B) ={A+B) /(A-B) ×(A+B) /(A+B) =(A^2+2AB+B^2) /(A^2-B^2) =(84+2√84√49+49) /(84-49) =(133+2√84×7) /35 =(133+14√84) /35 =(19+2√84) /5
@VincentSimmons-j4w12 күн бұрын
2/21+7 2/22-7
@Ignoranceisbliss-i2e13 күн бұрын
Using the look and see method it's clear x = 16...