Math Man Dr. Sam

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@wasimvillidad3000 Ай бұрын

Fun fact: When a polynomial, p(x), is divided by (x - a)² the remainder is the equation of the tangent at x = a.

@aniketbailwal-h3y Ай бұрын

thank you so much for these pratice qustions

@jayy1688 Ай бұрын

Appreciate it sir.

@PentiiSniper Ай бұрын

I love you so much sir please don't die !!!!

@footcareer_ult Ай бұрын

Just wondering, does this appear as foundation or higher level?

@vascobishop3359 2 ай бұрын

A good quality lesson. By the way where are all these geniuses coming from?

@Milk.Steak. 2 ай бұрын

very helpful thank you!

@theresfel7065 2 ай бұрын

how do you know where to put the -3, -4, 3, and 4s into the coordinates after you already sub into your

@Deevige 2 ай бұрын

Very good teaching 🎉🎉❤ From deevige classes pvt ltd malleswaram bangalore

@AhmaadBamaas 2 ай бұрын

YOU ARE THE BESSSSSSSSSSSST 😊😃

@sykevfx 3 ай бұрын

Why do you not talk about the after 0.1 seconds it starts to spread? I took 6s away from my 4.27 minutes but I’m not sure if that’s right

@GpsChittaurkhal 3 ай бұрын

Good

@wasimvillidad3000 3 ай бұрын

IMO: The difference should be |x₁ - x₂| = |8/p| = 8/|p|

@45fgdryp86 3 ай бұрын

she lies after lies

@ZXODGAMING 4 ай бұрын

Kyu itna mehnat kar rehe hao

@ZXODGAMING 4 ай бұрын

View nahi jayga

@charlesokuom8747 5 ай бұрын

Well solved

@Space_Void 5 ай бұрын

🧌

@СмирновМаксим-б2ч 5 ай бұрын

Initial picture is wrong. Lower isosceles triangle has bigger base than the upper one. In order for it to have the same base its vertex angle should be 2arcsin(sin(50)/4), which is approximately 22 degrees instead of 50

@mathmandrsam 5 ай бұрын

Correct. As described in monologue in these vids... Pix are not to scale. Metrics are inaccurate and these do not work. Purpose of vid is only to demo strats for solving as if they did exist, nothing more.

@johnspathonis1078 5 ай бұрын

Sorry to inform you Dr Sam but your diagram is impossible to construct. The bottom angle is not 50 degrees but is equal to 22.08 degrees. It may be possible to calculate these things but if the diagram is not correct then the answer is not correct. This is a great example to students of what not to do. Don't assume that the information given to you is correct. Cheers John

@mathmandrsam 5 ай бұрын

@johnspathonis1078 5 ай бұрын

@@mathmandrsam Thank you for the reply. I understand your intention. However you are setting a dangerous prescedent. It would have just as easy to do it correctly the first time. After all you are using an electronic calculator where one number is just as valid as any another. I was in charge of a mechanical design office for 17 years and workshops so I know how things can go off track. Mathematics may be your forte but building things in the real world for over 50 years is mine. Cheers

@mathmandrsam 5 ай бұрын

@@johnspathonis1078 In the words of the great Austin Powers "I like to live dangerously". But, I am also evil. My students all know this and that I leave many mistakes for them to find and correct.

@mathmandrsam 5 ай бұрын

@@johnspathonis1078 However, I note your point. And, if one if my 12-year old students applies for a job at your place of work... don't put them in charge of any important mechanical design project.

@johnspathonis1078 5 ай бұрын

@@mathmandrsam I am truly sorry but your students would not pass the entry test. I had the opposite upbringing. About 55 years ago -- my Grade 12 Maths II teacher wrote the text book used by all of Queensland. I answered a question in class and I made a fatal error!!! I disobeyed Isaac Newton’s third law…..“For every action there is an equal but opposite reaction”. For my sins, I had to stand up in class and bow my head in one minute of total silence. May I say one minute is a very long time. I never made that mistake ever again. The problem was this - 10 frictionless identical cylinders (each weight = W) were layered horizontally in a frictionless box. Four (4) cylinders were placed in the bottom layer 1. These cylinders were a close fit inside the box. In layer 2, three (3) cylinders were placed horizontally on top of the four cylinders in layer 1. In layer 3, two cylinders were placed horizontally on top of layer 2. In layer 4, the remaining single cylinder was laid horizontally. So the layers were 4-3-2-1 to form a pyramid shape. The problem is this - In terms of W, calculate all reactions on every cylinder. In summary, I am the product of my environment. As a teacher what sort of environment are you creating? Cheers

@EvelynNani-w4h 6 ай бұрын

Do simultaneuous equation please ♥️

@scottmitchell2757 7 ай бұрын

So square roots have functions.. It's not just a rudimentary repeated exercise.. Thia surprises more people than you would think

@rajeshkumar-fv6ws 7 ай бұрын

Hello respected Sir Dr. Sam 🙏 I am also a maths teacher. I like your way of teaching ❤❤ Thank you sir 🙏

@civwar64bob77 8 ай бұрын

LOL I would have used a larger piece of graph paper and a finer pencil for a better estimate, but just looking at your graph, the X intercept of the bottom line is at about +6.25 so slope of rise/run = -7/6.25 = -1.12. As we say in the USA, close enough for government work.

@IainDavies-z2l 8 ай бұрын

Just keep hitting triple 20 and you are well on the way to winning.

@ns-sj7gi 9 ай бұрын

Is this year 10 or year 4 😂

@anni2815 9 ай бұрын

Thank you so much! I finally understand this now, I have been struggling forever!!!! Keep up these videos I have learned so much!! 😁😁👍👍

@danielbain1927 10 ай бұрын

Hi Sir, I am just a little confused with Q4b in between the second to last and last step at how (2x^2/3 - 1)/5 became (2/5)x^1/3? Should it not be (2/5)x^-1/3?

@iyakintv5144 10 ай бұрын

This is finding the Azimuths. In my Surveying class, Bearings cannot be more than 90 degrees.

@kevincrotty9475 2 ай бұрын

Correct - these are Azimuths, im studying for my professional engineering exam right now, and guessing this is just how they survey in other parts of the world

@golddddus 10 ай бұрын

√6 is only +√6. To avoid abracadabra with a plus-minus sign, a different approach is needed. One is (x-3)^2 - 6 = (x-3)^2 - (√6)^2 = (x-2 + √6)*(x-2 - √6)=0. The second is, if you have to use the unlucky plus minus sign. √((x-2)^2) = | x-2 |. Then | x-2 | = √6 and solution can bi written as x-2 = ±√6

@lashahmed7422 10 ай бұрын

Thanks brother

@JoyceNkatiko Жыл бұрын

Sir, how did you find 262?

@GerrardKasanzale-bx5wk Жыл бұрын

Super ducks

@learnwithchristianekpo6005 Жыл бұрын

You made a mistake in Ex 15.06 x(a+b+c+d) = ax +bx + cx + dx

@mathmandrsam Жыл бұрын

Good call - will fix when I get a moment 🙂

@chronvisal8898 Жыл бұрын

Thanks teacher

@huckfinn301 Жыл бұрын

Where do you get the 3 in the first place? To this student it appears you say when x is zero the constant is 3. Where did that come from? Thanks

@OttoGlassV Жыл бұрын

The constant C is arbitrary since there are a infinite number of curves that would fit the solution. Now in practice you measure it as your initial conditions. For math exercises they give you a point on the desired curve like his example "x=0, f(x)=3."

@huckfinn301 Жыл бұрын

@@OttoGlassV thank you