I think there is a fault in 47:00 as yb' = ys '* cos (o)

Saandar Zabardast

In the problem 3.c. we find out the steady state error for different kinds of disturbance inputs including the step disturbance. Now when I solve it, the errors are zero for impulse, step and ramp disturbances. It seems to have only a finite value when an acceleration disturbance is provided. In fact the value comes out to be J/(Hy.Kp). Now I might be wrong here, which I often am. So I'd like other learners to clarify this point if they can.

Thank you to the whole team of NPTEL for creating the videos, editing them and making it public so the people like me who weren't able to go to such prestigious university can still gain this prestigious knowledge from top professors in the country.

Respected sir, can you make a lecture on concept of MPC?

23:52 its not S=S0, its S=-S0

outstanding contents and outstanding teaching 👍🙏.

@15:18 the Laplace transform of the impulse function should come as 1/s and not 1

It was great. I found the answer to my questions that I was looking for. Thank you so much

ONE OF THE GREATEST COURSES

how did the equation come at 36:18

wonderful professor

Thanks

Very weak audio in the first few minutes.

What a gravelly voice!

Bring some more energy into your lectures. Your voice is barely audible even at full volume. This is an Indian taxpayer writing; I want better value for my money.

very good lecture

22:02 i think here derivative should be of polynomial function......not polynomial equation. Although stability will not be affected by it.

very good exp. but why 25 at s0 28:57

can you place one tablet of vicks and make your voice bit clear. it will make us easier to understand.

Thank you sir....🙏🙏 Thank you NPTEL....🙏🙏

. So, as we saw that the that the lead compensator was used to improve the transient response 1:18 ,lag was for the steady-state and in case we want to improve both, we use a lead-lag compensator

For revision is it possible to material or pdf of all the sessions ...

Now this brings us to some kind of approximation of this PID controllers which are in text 24:02 referred to as lead and lag compensation

The chalk is super.

36:11 Encirclement of poles.

37:57 Control systems are usually low pass filters, Gain Margin and phase margins are stability margins.41:46

12.58 it a doubt , order is closed loop poles , why sir has written different.

Write a few lines of code and demo this.

rules based on just just these these 2 things right, and slowly you’ll realize that what we 4:29 do in the rest of the course or most of the course which is pending from now on is just analyze complex numbers, nothing much. So, a system with the loop transfer function of

Writing on the slide is very small. Print is okay

Why 10 gain is taken as 7.5 in first example?

34:00 that is the doubt I also had. That is the advantage of studying control system in electrical engineering way.

excellent lectures

Thank you very much for your video... I learnt entire control system subject from your video sir. It explained very neatly 🙏🙏🙏🙏

Subtitles are hiding the information please remove or make it small

EXCELLANT LECTURE

You are my icon Sir

construction rule -3 is not valid in every case. So dont follow it

Wow

great lecture! Explanations were very clear and concise. I was trying to find a good resource to learn state-space control theory for my masters course on controls since I didn't learn that in my undergrad. Thank you so much!

Can we get this pdf?

what nonsense is he saying 19:40?

At 24:00 how can the deer population, H(t), ever start out being negative??

At 1:02:14 it would make no sense to define your output as the sum of the voltage across C and the current across L. What in the world would that even mean? They don't have the same units. I think that what you actually want to do is make a separate measurement of Vc and of IL. To that end the y1 = IL and y2 = Vc and the C matrix is simply the 2X2 identity matrix.

There's an algebraic error at 27:45. The controllability matrix has zero determinant only if R = sqrt(L/C) not R = sqrt(L*C).

There's an error in calculating the poles at 43:29. It should be 1 + k1 = 1 or k1 = 0. If k1 = -2 then the poles are at -2.4 and 0.4 not at -1.

Could you please share the slides?

What is meant by steady-state in a capacitive circuit subject to a sinusoidal voltage input? A sinewave depicts movements in the form of waves. It has a datum, rapid, slowing and steady growth in one direction for a quarter cycle with reference to a datum (a reference), and then slow and faster decay in one direction for the next quarter cycle, and all these elements again in the opposite direction (reversal) of the forward movement for the next half-cycle. It has peaks and valleys. In essence, the sinewave is a perfect embodiment of oscillatory movements like springs and quantities like voltage. It retains its waveshape when added to another sinewave of the same frequency and arbitrary phase and is the only periodic waveform which has this property. Imagine that you and your friend are playing a game of “swing”. When your friend sits on a stationary swing and you begin pushing it, it will take a few hard pushes initially to overcome inertia when the swing moves with a small displacement. You then synchronize your pushes by progressively moving slightly away from the stationary position of the swing, initially, pushing gently, and then pushing harder as you move away from the central stationary position of the swing. The point of pushing the swing is usually at the top of the swing cycle at one end. It takes a while of pushing before you are able to establish a rhythmic swing. The period before the rhythmic swing is established is the “transient”, and the rhythmic swing that is established after the few transient cycles elapse is the “steady-state”. This is analogous to establishing the steady-state in a capacitive circuit subject to a sinusoidal input. The capacitor being initially uncharged, will cause the current during the transient period to assume a value that will be quite different from that at the same voltage angle after steady-state is established. Electrostatics and circuits belong to one science, not two. These are discussed usually separately in textbooks and science and engineering courses. It is not possible to discuss the circuit processes which produce a sinusoidal current when a sinusoidal voltage is applied to a capacitor….the changing rates of change of the applied voltage ….the surface charge set up changing at every instant….the applied field changing in the wires ….and the current at each and every instant in time. Watch the two videos listed below to learn about current and the conduction process and surface charges (using a unified approach to electrostatics and circuits at a fundamental level). 1. kzbin.info/www/bejne/iHbWiJeabJukrsU 2. kzbin.info/www/bejne/bnO0fpKurJeFnNE The last frame of video #1 lists textbook 4 which discusses the sinusoidal steady-state in capacitors and inductors with the help of sequential diagrams and animated power-point presentations of the varying field components in the circuit elements in more detail.

In a series RLC circuit, can we choose inductor voltage as a state in state space modelling?