Если 3^х=2, почему не логарифмировать по основанию 3? В чём смысл логарифмировать по основанию 10?
@MarcAdelinet14 күн бұрын
x=0.36......
@ToanPham-wr7xe15 күн бұрын
😮
@naveenkumar-fb3fn15 күн бұрын
Why you not learnt math seriously You say if x=-1 then 3^x^3 =3^-1 which is impossible. You always forget the base 3^-1^3= 3^-3 You should solve it as below 3^x^3+3^x^3+3^x^3 = 1 3(3^x^3)=1 , 3^x^3= 1/3 3^3x = 3^-1 3x=-1, x=-1/3 Now 3^x^3 =3^{-1/3)^3 =3^{(-1/3)×3} =3^{-3/3} =3^-1 =1/3 Now 3^x^3=1/3 then 3^x^3+ 3^x^3 +3^x^3 =1/3+1/3+1/3 =3/3 =1
@naveenkumar-fb3fn15 күн бұрын
It's wrong. The basic is 8 not 5. Exponential formula says a^m^n=a^mn Now if you put x=0 then 8^4^5^x=8^(4×5×0)=8^0=1 Correct answer is x=1/5 /Learn simple mathematics formula first before posting any video
@cosmolbfu6717 күн бұрын
a<b<c
@shaheenamobin472117 күн бұрын
Nice equation
@jagadiswarchakraborty29517 күн бұрын
Splitting -130 into -125-5 is good.
@BruceLee-io9by21 күн бұрын
A nice math exercise.
@vineyanand-ed7hg21 күн бұрын
X=2 , 2 sec question!
@Ashish_IISc21 күн бұрын
Badhiya 😂😂😂😂😂😂😂😂
@sadanandamishra626921 күн бұрын
Excellent solving. Thanks for your presentation. 🙏
@Mathinhood21 күн бұрын
Welcome
@user-sh3fe4vc8s22 күн бұрын
You don't need to proof that match to solve the question. Directly spilt 258 as sum of power of 6. You will get 1,2,3 as a,b,c
@sadanandamishra626921 күн бұрын
If possible please explain your idea so that we can learn.
@user-sh3fe4vc8s21 күн бұрын
@@sadanandamishra6269 Write 258 in terms of table of 6 i.e 258 = 6 x 43 = 6 x ( 42 + 1 ) = (6 x 42) + (6 x 1) = (6 x 6 x 7) + 6 = { (6^2) x (6 + 1) } + 6 = { 6^3 + 6^2 + 6^1 } While solving such questions, mindset should be converting the number on the right side in the form of number on the left side.
@shaheenamobin472123 күн бұрын
God bless you
@Mathinhood22 күн бұрын
Thank You
@shyamsingh972823 күн бұрын
samjhane ka tarika gajab ka h God bless u
@Mathinhood23 күн бұрын
thank you
@cypher_xd656425 күн бұрын
Oral question, no need to use even pen n paper :)
@harrymatabal844825 күн бұрын
Excellent presentation. Youust be from india. I am a south African indian
@rajeshvyas93428 күн бұрын
X=4/7
@user-dp6gt3qp4nАй бұрын
Aap nakal ( copy ) Kar Rahe ho . Originality nahi ha , aapme. It is not slip of pen .
@shaheenamobin4721Ай бұрын
Shandar
@JohnAmbruzАй бұрын
Plodding beyond belief...
@BruceLee-io9byАй бұрын
Great explanation.
@williamhuang4970Ай бұрын
X = 6 4 /2 5才對
@rajeshvyas934Ай бұрын
-1
@Hari4Me2408Ай бұрын
x=-1/3 is possible think!
@adb012Ай бұрын
That would be one solution IF what you had was (4^x)^3, but 4^x^3 means 4^(x^3) so no, x=-1/3 doesn't solve it because you would have 4^(-1/27)=1/[27th.root](4), added 4 times.
@rajendraameta7993Ай бұрын
65x1=65 is rejected?
@pjaj43Ай бұрын
GCSE maybe, hardly "Olympiad"
@Babu-kd4jeАй бұрын
Copy paste question from other channel. Don't do this, we are not foolish
@shrunushrivastava3424Ай бұрын
from which channel?
@syedmdabid7191Ай бұрын
Rootus de equatio est ---1 vel 3 responsum.
@shivanandaaithal4818Ай бұрын
X=3/8
@jaggisaram4914Ай бұрын
16
@jaggisaram4914Ай бұрын
3/8
@solace_seeker7734Ай бұрын
Bahut badhiya ❤
@rajanmaths5Ай бұрын
Aapka channel moatize ho gaya please reply me
@mahmoudibra5822Ай бұрын
Thanks
@walterwen2975Ай бұрын
A Nice Radical Equation Math Olympiad: ¹⁸√x = ˣ√3; x = ? (¹⁸√x)¹⁸ˣ = (ˣ√3)¹⁸ˣ, xˣ = 3¹⁸ = (3²)⁹ = 9⁹; x = 9 Answer check: ¹⁸√x = ¹⁸√9 = 3²⸍¹⁸ = ⁹√3 = ˣ√3; Confirmed Final answer: x = 9