R. Paul Singh

Пікірлер

@fathimarahim227 10 күн бұрын

Perfect..thanks sir

@saritajackelineromanivasqu1852 Ай бұрын

Thanks for the explanations

@zechijoy9787 Ай бұрын

Thanks so mucg

@thermo.kesfet Ай бұрын

Thank you so much

@ChinyereLawrence-u4o Ай бұрын

Thank you sir your video has helped my daughter God bless you 🙏 ❤️ 😘 🎉

@Bromotologist 2 ай бұрын

Clear explanation

@Nice-dk6ky 2 ай бұрын

Thank you for explaining so well

@yawakowuah-addo6659 2 ай бұрын

Explanation excellent keep it up

@engsherif4657 2 ай бұрын

Good lecatcher thank you

@muhammedanas823 2 ай бұрын

Wow😮❤

@ekkrana01 2 ай бұрын

Wow lecture

@FredrikOlaussen 3 ай бұрын

Thank you for a very helpful tutorial. I'm confused by the enthalpy chart used. The one I use and others I compare to, I get much higher Enthalpy values at these conditions. H1 = 250kJ/kg, H2 = 400kJ/kg and H3 = 430kJ/kg

@RPaulSingh 3 ай бұрын

Thank you for your observation! Please note that enthalpy charts (and tables) available from different organizations may have used different reference datum. The charts, I have used, are based on 100 kJ/kg at 0 C for saturated liquid as a datum. You may find other charts available with a datum reference as 200 kJ/kg at 0 C. You can check these numbers by reading the enthalpy value at 0 C for the saturated liquid state. The different datum values do not influence our calculations because we are always determining the difference between two enthalpy values; and the chosen datum does not impact the difference (only the absolute enthalpy value at that temperature may be different depending upon the chart one uses).

@brighttooth3592 4 ай бұрын

Thank you

@ineshenriques4561 4 ай бұрын

thank you so much

@Maddiverse6300 4 ай бұрын

Very helpful sir

@litingrui 5 ай бұрын

Very useful teaching video. If you can give an example to calculate it will be better.

@ghassansiregar1376 5 ай бұрын

Thankyou sir!

@radioaydn 6 ай бұрын

thank you so much for the short and educative video :)

@sukhmanpreetsingh4732 6 ай бұрын

Thnku sir ❤❤

@christianmontenegroaraya1888 6 ай бұрын

Congratulations for the simplicity and for the amazing explanation!

@suheladesilva2933 6 ай бұрын

Great video, thanks

@ChenellybrightIum 7 ай бұрын

Download

@زهراء-ي4س 7 ай бұрын

شكرا عاشت ايدك ❤😊

@muhammadganji1529 7 ай бұрын

🎉🎉❤❤

@muhammadganji1529 7 ай бұрын

🎉🎉🎉🎉

@muhammadganji1529 7 ай бұрын

🎉🎉

@muhammadganji1529 7 ай бұрын

It very useful for me 🎉🎉🎉🎉

@JAVIERALEJANDROSOTOPONCE 8 ай бұрын

Thanks a lot. Very good and nice explanation. so didactic

@warriorsfg 8 ай бұрын

Thank you!

@alessandrabyrrorodrigues9311 8 ай бұрын

Hi. In line 6) two elbows of 90 degrees are 2*0.75 instead of 2*1.5. The result in line 6) should be 3.5. So, in line 8) your total friction loss is 213.9 J/kg. Am I correct?

@RPaulSingh 8 ай бұрын

The friction loss for a regular 90 degrees threaded elbow is 1.5, therefore, for two elbows it is 2*1.5. The calculation shown in the video is correct!