I am having trouble with you designating V2 as 5V. 5V is the volts DROPPED by the 30 ohm resistor. It seems like the large essential node across the top would be 40V, obtained by 60Vs minus the 20V drop across the 40ohm resistor.

Excellent video

Hi sir, can i know what happen to the 70ohm and 40ohm?

You jumped around too much. So things got confusing.

You should have defined what dB is and how to calculate it. All you said is -3dB and you left it up in the air.

Your pointer is important, and you use it often. So you need to make it easier to find ! I suggest you use a new color for your pointer, like red or green. .

Shitty xplainer

no one is searching for simplification of these extremely easy networks

What a g👏

thank you so much

If I have an 2amp 12volt supply how will this affect the amperage output if I take the voltage down to 6volt . All DC of course.

if you have two voltage sources, would you need to put two grounds? im srry if this is dumb question.

good

And,?, so? Theres more.

Great video!

thankyou for not having an indian accent

After 5 years , Better than my professor , THANKS !

You're amazing 👏

man i can't thanks u enough that was really helpful thanks a lot ^^

I personally think this circuit you drew here is a high pass filter, if you swap the capacitor with the resistor then I think it is a low pass filter.

Life saver, found this right before my midterm. Keep doing what your doing 😊👍

nice man!! helped me alot

why you calculate i1 instead of i2.

thank you

sir your exaplanation is very good.Thank you.

Good job

Due to a fundamental misperception of the movement of electric charge during the time that we can remember of our collective first studying electricity, the poles were actually mislabeled such that the electric current is actually from negative to positive. Given the absolute value of the math that is used to understand electricity as well as the absolute value of the work extractable from any given system is unchanged by this error, the fact that electron flow is actually from the anode to the cathode, which happen to have been mistakenly reverse-labeled to be possibly the only contradiction to the otherwise correct (outside of quantum theory, so in a more "classical" sense) saying: science always flows from highs to lows, the error per se is practically inconsequential. If not for a potential future consequence that may only be outside of our cognitive ability to even know how and that it can be looked for presently, my clarification might otherwise seem pedantic.

Thanks from Germany. It helped a lot!

The analysis for i2 is confusing when explained, but you achieved the correct answer. For those who found it hard to follow, I will try to help explain below... Since we know the current going into the node 1 is 0.5A, we can redraw the circuit using 0.5A as the current source and combine 50R + 10R (series) = 60R. 0.5A (Is = Current Source) --> 20R || 30R || 60R i1 i2 i3 We want to find the the current across the 30R = (i2). **** But first, let's find current across 20R or i1. 30R || 60R = 20R NEW Circuit: 0.5A (Is) --> 20R || 20R i1 (i2 || i3) = ix Current Division: Is * ( ix / ( i1 + ix ) ) i1 = 0.5A ( 20R / (20R + 20R) ) = 0.25A <--- This is current across 20R or i1 (First Resistor) * Remember, the opposite resistor is applied in the numerator * Now we can re-draw the circuit utilizing *new* Current Source starting at node 2: 0.25 (Is) --> 30R || 60R (w/ i2 across 30R and i3 across 60R) i2 i3 Current Division: Is * ( i3 / ( i2 + i3 ) ) i2 = 0.25A (60R / (30R + 60R) = 0.1667A i3 = 0.5A - 0.25A - 0.1667A = 0.0833 Is i1 i2 i3 Check: KCL Rule 0.5A = 0.25A + 0.1667A + 0.0833A Is = i1 + i2 + i3 0.5A = 0.5A (GooD) Hope this helps :-)

❤️

really helped freshened my head for by gen test coming up thanks!!

great video this explained it very well. haven't seen a video this concise yet I appreciate it

Sorry I don't quite understand why you used the value of current i1 to find the value of the voltage at i2...plz anyone with idea plz reply

Very helpful, thanks.

Why did you stop uploading videos? I prefer this channel over the more popular ones!

I thought the formula was V1= (R2/(R1+R2))* Vs Also, what would the formula be if you know V1, Vs and R2 and are solving for R1? And for if you know V1, Vs and R1 and are solving for R2?

Question: How do you get 15 ohms from 20||60? shouldn't it be a third? Edit: I just realized u were adding the resistance in fractions. 1/20 + 1/60 = 1/15 ohms nvm!

Thank you!

At least get the man's name right it's pronounced as (KIRK-KHOF).

Sir, my question is, there are many resistors there. How are you going to know that, this one is R1,R2??

You should keep making these lectures about electric. God bless you man.

Good job

Thanks a lot man. I have worked in flask and am learning ruby on rails. Your vid helped a lot to understand the basics .

whats the shortcut you used to add '<%= ' and '%>'?

congratulations, your video has officially made its way into a high-school physics lesson! your comment section will eventually be filled with angsty students saying "*insert class subject here* sucks or "*insert name* was here". have fun! :D

Increase Sound volume plz

Another good vídeo but I wish you had included a practical example with numbers, and possibly an application.

In the formula for series capacitors you wrote +C3 instead of +1/C3 Otherwise I found the video very helpful, thank you.

Thanks spot on

hello, it does not ask me whether to overwrite or not the controoler after adding bikes gears and services. it directly displays this message "The name 'WelcomeController' is either already used in your application or reserved by Ruby on Rails. Please choose an alternative or use --force to skip this check and run this generator again.". what can i do