Пікірлер
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 9 сағат бұрын
Eta should be SIR CONDUCTIVITY.J=nEwhere n= conductivity & J is the current density
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 9 сағат бұрын
Shorter area straw having less resistance to flow of liquid so easy to suck which means in short duration of time we can suck grater amount of liquid.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 9 сағат бұрын
R = nl/A
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 сағат бұрын
For parallel plate capacitor should have capacitance C=eA/d
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 22 сағат бұрын
Dielectric constant
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 22 сағат бұрын
E= 1/2 CV^2
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 22 сағат бұрын
Unit of charge is define by considering test charge qi with parent charge Q so untill the ELECTRIC FIELD E= 1/4πe0 Q/r^ 2 as F =qiE untill this value not given constant value then for the specific of charge for that F= qi E = Constant then such test charge is define as unit charge.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 Күн бұрын
STRESS f= F/A= n v /l= ML^-1T^-1 LT^-1 L^-1= MLT^-2L^-2= MLT^+2/A= F/A Hence viscous stress f= nv/l where v is the terminal velocity
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 Күн бұрын
Due to above less potential like ground potential like that avilable at TOP.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 Күн бұрын
Last five years the ocean having raised temprature 1° C. So this is supporting statement that in each day about 4500 cm^2 area received heat energy in 1 second 675 JOULE then estimation suggest this statement.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 Күн бұрын
PACIFIC MEANS PEACEFUL
@MukyaLema
@MukyaLema Күн бұрын
I love you, you instruct us very well. Your lecture is more helpful to me.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 2 күн бұрын
e=2.718
@dr.lennartlichtenstein4298
@dr.lennartlichtenstein4298 3 күн бұрын
43:53 = who's ganna care I care about my Salary by the end of month
@ilkindnziyev5650
@ilkindnziyev5650 3 күн бұрын
41:34 junior😂
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 5 күн бұрын
As P= constant/V so, P Vs V should be rectangular high parabola.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 5 күн бұрын
PRASNHANTA MAHASAGAR PECIFIC
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 5 күн бұрын
Rubber band is basically PVC (C2H4)n
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 5 күн бұрын
Sir, you are more than 6 feet
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 6 күн бұрын
l2=l1 [1+a(t2-t1)] where a is the coefficient of linear expansion having in relation a= b/2 = y/3 where b is surface expansion & y is the volume coefficient of expansion respective ly
@mortezagolestanyfar710
@mortezagolestanyfar710 8 күн бұрын
❤❤
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 9 күн бұрын
Look with regards
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 9 күн бұрын
Equivalent Capacitance C= C1+C2
@Leon-om1lg
@Leon-om1lg 10 күн бұрын
Nice problems. However, in the last problem, why was the volume of the lake immediately rounded off? Shouldn't the rounding off be done at the last part of the calculation? This would lead to 6*10^5 kg (631508.1681 kg) instead of 7*10^5 if my calculations are correct.
@krishnakootala6196
@krishnakootala6196 10 күн бұрын
cameraman rlly wants us to not learn this by not showing us half what what he's talking about
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 10 күн бұрын
A BLACK BODY RADIATES IN ONE DAY ABOUT 5 JOULE
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
For run pulse beat enhance so blood flows in rapid stage hence Bood Pressure expected way grater.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
4πr^2= Surface area of sphere
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
Hence when blood flows by volume is greater then BLOOD PRESSURE should be expected way more according to the formula V = P π r^4 / 8 nl
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
SPIGHNOMANOMETER
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
Volume of blood flows per second ~Internal blood pressure
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
On vertical opposite the blood flows expected way greater.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 11 күн бұрын
Systolic= 80+Age of individual,where Diastolic=80 mm of Hg
@lawron2
@lawron2 12 күн бұрын
This is by far the most clear and precise lecture ever. Salute 🫡
@VIPINDIAPolytechnic
@VIPINDIAPolytechnic 12 күн бұрын
Nice examples sir ,thank you
@karelkohout
@karelkohout 12 күн бұрын
We can't eliminate that hydrogen, because that would be sin :-)
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 13 күн бұрын
For scalar product is estimated as DOT PRODUCT we have to consider
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 13 күн бұрын
∆p/∆t= Force = Momentum loss
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 13 күн бұрын
Frequency nue n= 1/T collision
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 13 күн бұрын
Work done in bringing a unit charge from INFINITY to a PARTICULAR POINT is define as POTENTIAL r W= $ F •dl= 1/4πeo $ (q×1)x^-2 dx Infinity r V(r) = - q/4πeo [x^-1] Infinity V(r)= -(9×10^11 q)/r 27:31 30:56
@Gartenzoe
@Gartenzoe 14 күн бұрын
DEVIL!!!!
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 14 күн бұрын
Due to Burnoulies theorem SPPED of AIR is less so AIR PRESSURE is high so to balance the equation v^2/2g +P/dg = Constant So due to high air pressure exist at the middle the white golf ball can not fly more .It is the CAUSE
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 15 күн бұрын
Q/t= KAdT/dx
@markbrightwell3536
@markbrightwell3536 15 күн бұрын
I believe the professor’s explanation of the argon tank problem can’t be correct. A quasistatic process would require slowly changing the external pressure from high to low, i.e., from P1 to P2. Furthermore, if the temperature is constant through the whole process, then the ideal gas law would require PV = constant. Thus, the pressure of the argon would decrease as the volume increases.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
COLLISION
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
P = 1/3 mnc^2 Now 1/2 mc^2~KT So PV= 2/3 KT
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
Random motion
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
Brwonian movement
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
AIR INSERTED LIKE DIFFUSION THROUGH AIR BALOON MEMBRANE .
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
6.023 ×10^23 molecules or proton or electron means stand for 1 mole.If 1 gm molecular weight any solute dissolved in 1000 cm^ 3 then 1 Mole solution is made . Genrally at NTP ,1 gm molecular substance any gas having volume 22.4 liters and having number of molecules of gas should be AVEGADRO NUMBER that one 6.023 × 10^ 23 molecules.If one gm equivalent any solute dissolved in 1000 cm^ 3 distilled water then solution made is 1 N solution read as 1 Normal solution.
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
PV= mRT
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
22.4 liters ,1 mole means AVEGADRO NUMBER 6.023 × 10^ 23 MOLECULES
@subirkumarbandyopadhyay9757
@subirkumarbandyopadhyay9757 16 күн бұрын
If one molecular weight solute dissolved in 1000 cm^3 dissolved then 1 Mole solution is observed.