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One of the best lectures that i took thank u

Great MashAllah ... Allah Jaza dy apko

Best Teacher for MTH601 Highly recommended.

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G00d..very effective lectures

AOA: Sir ur method of teaching is so good; please agr y notes ap shair kr sktyn to kindly zaror kr dyn.

Masha Allah ♥️ brilliant way of teaching

thank you mam good lecture

Very informative May Allah Pak bless you Ameen 🤲🏻

mam ye highlighted handouts provide kr dein

maam jo ap ny apny short notes bana rakhy usy share to ker dain plz

16 lecture hen just mam 17 to 22 lectures ni hen recorded Kia?? If hen to plz mjy link bej den your way of teaching so impressive thank you so much

thanks mam g teaching method are good

Plz share this handout

Is website py upload NAHI hui assignment ,, mn ny check kra Hy

Thnku sooo much sir

1st waly question ki diagram correct ha??

Is it correct solution ?

Ye apne ghalt solve kia es assignment ka asnwer announcement maim h

Thanks ❤

thanks

Its not mth601 assignment

2nd question me formula as per book kar len

Muhammad Nadeem ka sol bi kar de solve

Sir plz mth631 ka ssignment solution upload kr dein

Thankooooooooooooooooo

Sir 2nd question ka And wrong haa calculate kary too

sir math 403 ka solution bta dy please

Newton -Raphson ka formula wrong ha bahi

Thanks sir

sir newton waly formula main - ata hy +ke jga

Sir ye isi question file py solve kr k submit krwani h ya vesy khud sy bna k kr skty upload

Question no 1 ka answer wrong hai formula's thk hn lakin answer's thk nhi ahy calculate kar ka dekhain

Danish zaidi ki bba dein please

question # 1: iteration 2 f(1.3478)=(1.3478)^3−1.3478−1≈2.4484−1.3478−1=0.1006 yeh correct hai ap ka answer 0.1786 thk nhi h

MTH603 Assignment solution required. Inchrage: Ms.Danish Zaidi

Sir ye isi question file py solve kr k submit krwani h ya vesy khud sy bna k kr skty upload Kindly guide me

MTH603 Assignment solution required. Inchrage: Ms.Danish Zaidi

MTH603 Assignment solution required. Inchrage: Ms.Danish Zaidi

Thank u Soo Much Sir ye Solution kal sy mai Dhoond rahi thii...

danish zaidi ke bhe kr dain

AOA sir G mth403 Ki assignment ka solution bhi upload krdei plz section in-charge arooba Fatima plz sir G

❤

Bhai Jaan, Please Danish Zaidi Ka Bhi Solution Upload Kaar Dain.

Mis arooba Fatima

Sir in-charge Arooba Fatima ka bi solution upload krdy

MTH401 - Differential Equations Assignment No.1 Solution Section In charge: Zulfiqar Ahmad Noor Question # 1 Consider the following differential equation: (2𝑥𝑦 + 3)𝑑𝑥 + (𝑥2 + 4𝑦)𝑦 = 0 (a) Verify whether this differential equation is exact. (Show steps) (b) If it is exact, find the general solution of the given differential equation _________________________________________________________ Solution: (a) Verify whether this differential equation is exact. (Show steps) A differential equation of the form M (x , y) dx + N (x , y) dy = 0 is exact if ∂M/∂y=∂N/∂x For our equation: M(x,y) = 2xy + 3 N(x,y) = x2 + 4y Find ∂M/∂y: ∂M/∂y = ∂/∂y (2xy + 3) = 2x Find ∂N/∂x: ∂N/∂x=∂/∂x(x2+4y) = 2x Since ∂M/∂y=∂N/∂x = 2x, the differential equation is exact. (b) The general solution: To find the general solution we need to find S and T then solution is S+T=C S = ∫ Mdx = ∫ (2xy + 3)dx S = ∫ Mdx = ∫ (2xy) dx + 3 ∫ dx S = 2y x^2/2 + 3x S = x^2 y + 3x T = Integrate that portion of N w.r.t y that is free from x T = ∫ (4y) dy T = 4 ∫y dy T = 4 y^2/2 = 2y2 the general solution of the differential equation is: S +T = C x2y + 3x + 2y2 = C Where C is a constant. Question # 2: For each of the differential equations in the given table: a) Identify the type of differential equation and state the method you would use to solve it. b) Solve any one differential equation of your choice from the table. Sr # Differential Equations Suggested Method 1 dy/dx = xy2 2 (3x2+y)dx + (x+ 4y3)dy =0 3 y’ - 2/3y = x2 4 dy/dx + y = ex 5 dy/dx + y = y3x 6 (2x + 3y) dx + (3x + 4y)dy = 0 7 dy/dx - y/x = x3 8 y’+ y = cos x 9 dy/dx + 3y = y2 cos x _________________________________________________________ Solution: Sr # Differential Equations type of differential equation Suggested Method 1 dy/dx = xy2 Separable Separate variables and integrate both sides 2 (3x2+y)dx + (x+ 4y3)dy =0 Potentially Exact Check for exactness if exact, solve by finding a potential function; if not exact, find an integrating factor 3 y’ - 2/3y = x2 First-order linear Use integrating factor e∫-2/3 dx 4 dy/dx + y = ex First-order linear Use integrating factor e∫xdx 5 dy/dx + y = y3x Bernoulli equation Convert by setting v = y-2 and solve as a linear equation 6 (2x + 3y) dx + (3x + 4y)dy = 0 Potentially Exact Check for exactness if exact, solve by finding a potential function; if not exact, find an integrating factor 7 dy/dx - y/x = x3 First-order linear Use integrating factor e∫-1/x dx=1/x 8 y’+ y = cos x First-order linear Use integrating factor e∫xdx=ex 9 dy/dx + 3y = y2 cos x Bernoulli equation Convert by setting v = y-1 and solve as a linear equation Solution of self-chosen equation: Let's solve equation #4: dy/dx + y = ex This is a first-order linear differential equation. The standard form of a linear first-order differential equation is: dy/dx + P(x)y = Q(x) In our case: P(x) =1 Q(x) = ex Step 1: Find the integrating factor For a linear equation dy/dx + P(x)y = Q(x) the integrating factor is: μ(x)=e∫P(x)dx Here, P(x) = 1, so we have: μ(x) = e∫1dx = ex Step 2: Multiply the entire differential equation by the integrating factor Multiply both sides of the equation dy/dx + y = ex by ex: ex. dy/dx + ex .y = ex . ex Simplifying: ex dy/dx + exy = e2x Step 3: Observe the left-hand side The left-hand side of the equation is the derivative of y⋅μ(x)y \cdot \mu(x)y⋅μ(x), where μ(x)=ex\mu(x) = e^xμ(x)=ex. This can be written as: d/dx (exy) = e2x Step 4: Integrate both sides Now, integrate both sides with respect to x: ∫ d/dx (ex.y)dx = ∫e2x dx On the left-hand side, the integral is straightforward: exy = 1/2.e2x + C Where C is the constant of integration. Step 5: Solve for y Now, solve for y by dividing both sides by ex: y = e2x/2ex + C/ex Simplify the expression: y = ex/2 + Ce-x Final Solution: The general solution to the differential equation is: y = ex/2 + Ce-x Where C is the constant of integration. The end

thank you so much sir