0.06

3 power 11=3 power k,then k=11

Second way is better

No need for taking log ,3 power k =9 power 1/3=3 power 2/3 since 9=3 power 2 So k=2/3

Could you not simplify it to 27 to the power x = 9 as a first step?

Very nice @MATHS TUTORIAL ( BL SAHU)

КОМУ ЗАДАЧКА, НАХРЕНА ТАКОЙ ЧУЩЬЮ ИНТЕРНЕТ ЗАСОРЯТЬ

Save you a little trouble: X = 11. 3^10 x 3^1 = 3^(10 + 1) = 3^11.

You are making a mountain of a mole hill. Chutia

X=11

It's easy 3¹⁰+3¹⁰+3¹⁰ =3¹⁰(1+1+1) =3¹⁰×3 =3¹⁰×3¹ =3¹¹ So,3^x=3¹¹ or,x=11. I am eight standerd. I did it in 5 seconds. I am from India.🇮🇳🇮🇳🇮🇳 Thank you.

x=0.667

Questo è il quadrato di un binomio sotto radice. È= al quadrato del 1° + il quadrato del 2° +/- il doppio prodotto del 1°x 2°

(x.x^1/2)^1/2 = 3.3^1/2 (x^3/2)^1/2= 3^3/2 x^3/2 = 3^6/2 x^3 = 3^6 = (3^2)^3 = 9^3 x= 9

I know a lot of people weren't paying attention and immediately said "x = 3"

Am I the only one triggered by how this person writes?

Very beautifull solution

Watched to the end ❤ great solutions my fellow Mathematician ❤❤

Nice trick, but you still have 31 roots to solve for. A more general solution might be: X = 1/e^[W(-ln2/32)], where W is the Lambert W function..

A1, b0 , c2.

16^(1/2+1/4+1/8)^16 =16^(7/8)^16 =16^14 or 2^56

=[(9)^7/8]^4 =[ (3^2)^7/8]^4 =( 3^2)^28/8 = (3)^56/8 = (3)^7./

Math ok. How about spelling? Substitute not subsitute.

Method 3 Start at the inside: √(16) = 4, then √(16×4) = 8, then √(16×8) = 2^(7/2), then [2^(7/2)]^16 = 2^56

Nice video, please speak in next one, no worries! :)

10^X×3=600 10^X=600/3=200 X×log10=log200 X×1=log(2×100) X=log2+2

Too many steps, just apply the definition of logarithm: it is the exponent to be given to the base to obtain the argument, so x= Log 200, x=3.010...

X = log 333/log 9 = 2.643 (approx)

Х=3

80(9^x-1)=20 9^x-1=1/4 3^(2x-2)=2^(-2) 2x-2=-2log_3(2) x=1-log_3(2) x~= 1- log2/log3 = 1-0.301/0.477 =0.176/0.477 about 0.4

Wtf? It has to be 81, doesn't it?

1+ log 37/ log 9

a=3 b=0 это на вскидку посмотрим, что получится в итоге.😅

I woud add the first and the third equation and subtract the second equation.. Tht gives 2=2 i.e. a=1. With this informtion,we cn get from the first equation b=0 and from the third equation c=2. I think, my soutionis easier than the one in the video ...

a=1 b=0 c=2 Ez 10 seconds mai answer soch liya maine

9^(n+1)-9^(n-1)=20 9•9ⁿ-[(9ⁿ)/9]=20 81•9ⁿ-9ⁿ=20 80•9ⁿ=20 9ⁿ=¼ 9ⁿ=4^-1 3²ⁿ=4^-1 2n=log_3(4^-1) 2n=log_3(2^-2) 2n=-2[log_3(2)] n=-log_3(2) ❤

Adding (1)+(2)+(3) is unnecessary. Why make it so complicated? (1)-(2)=> a-c=-1 (5) (3)+(5)=> 2a = 2 => a= 1 subs a=1 into (1) => b=0 subs a=1 into (3) => b=2

A= 1 B =0 C = 2

A-1, B-0, C-2

√15√√15√√√15=225^k 15^1/2 .15^1/4. 15^1/8=(15^2)^k 15^1/2+1/4+1/8=15^2k 15^7/8 = 15^2k Since bases are equal, powers are also equal. 2k=7/8 K = 7/16

√5√√5√√√5=125^k 5^1/2 .5^1/4. 5^1/8 =125^k 5^7/8 = (5^3)^k 5^7/8=5^3k 3k = 7/8 K= 7/24

Your 'x' is 45, '2' easy!

Deviam habituar-se a desenhar SEMPRE primeiro o traço de fração e depois o numerador e o denominador para assim ficar tudo alinhado

Messed up twice.. learn before you try to teach. -multiplication and division are equal. You go left to right, so you start with 4/2 -even if multiplication was to go first, 2(1/2)≠5/2 (which I genuinely have no f***ing clue on how you got to), 2(1/2)=2/2=1 Solution: 4/2(1/2)=? 2(1/2)=? 2/2=? ?=1

2

35 is not 7.5

bird noise is irritating