Unit Conversions Using a Grid
7:37
5 жыл бұрын
Adding and Subtracting Vectors
8:24
5 жыл бұрын
Accelerated Motion WA Vectors
10:46
5 жыл бұрын
Free Body Diagrams
23:45
5 жыл бұрын
SAT Imaginary Numbers
9:26
5 жыл бұрын
Working with Trig
19:27
5 жыл бұрын
Working with Exponents
16:07
5 жыл бұрын
Finding Reaction Forces Simple Beam
9:36
Physics Interactions-Two Blocks
19:37
AP Physics C-Harmonic Motion Systems
21:52
Adding Vectors-Components Graphically
11:43
Adding Vectors-Components Graphically
11:47
AP Physics C Rolling Motion
12:32
7 жыл бұрын
Projectile Motion2-Vertical Only
9:50
Torque and Angular Acceleration
10:58
Torque on a Beam
5:12
7 жыл бұрын
Rotational Kinetic Energy-2 Problems
10:23
Rotational Kinematic Problem
12:54
7 жыл бұрын
Potential Energy Graphs and Stability
13:23
Пікірлер
@sachinrath219
@sachinrath219 9 ай бұрын
why the work done by torque not considered, thanks
@robertslayerofmonsters1302
@robertslayerofmonsters1302 9 ай бұрын
I think the answers for Fab and Fac given in the video are incorrect, since their vector sum is not even approximately equal to Fad, which is 294 N. For Fab and Fac, I get 163 N and 191 N, which on vector addition appropriately give SQRT(163^2+191^2+2(163)(191)cos(37 deg +31 deg)) = 294 N.
@DanielOConner-o6z
@DanielOConner-o6z Жыл бұрын
Thanks sirr
@lykojello7733
@lykojello7733 Жыл бұрын
2 equation 2 unknown
@alicia__8258
@alicia__8258 Жыл бұрын
THANK YOU!! this video gave me an amazing new insight
@guhunohu
@guhunohu Жыл бұрын
Thank you so much
@huytranvan2754
@huytranvan2754 2 жыл бұрын
You explained well. Thank you!
@abdallahhachimi6579
@abdallahhachimi6579 2 жыл бұрын
Hello I did it on calculator i got a différent answer
@gerard8591
@gerard8591 Жыл бұрын
That’s crazy
@gerard8591
@gerard8591 Жыл бұрын
Who asked
@drury2d8
@drury2d8 2 жыл бұрын
Brent, what if the beam is a fixed cantilever?
@piglet2633
@piglet2633 2 жыл бұрын
What the f***
@MrThesavage78
@MrThesavage78 2 жыл бұрын
You're calculating the moment, not torque...change the title!
@mrcomawhite6667
@mrcomawhite6667 2 жыл бұрын
You're amazing
@teoman4806
@teoman4806 2 жыл бұрын
Perfect thank you.
@L3RNA3AN
@L3RNA3AN 3 жыл бұрын
What equation did you use to calculate frictional torque? I couldn't make it out from the video.
@maxima4116
@maxima4116 3 жыл бұрын
Here are my answers (I used t1-Fab t2-Fac and t3-Fad) For t1= 272.25 N T2= 253.98N T3 = 294 N In your final answer, when i check it (all forces on the x-axis should be equal to 0), yours is laying on 1... something. Mine has a closer value to zero.
@rhuxxinator9071
@rhuxxinator9071 3 жыл бұрын
This is right but the larger unit should always get a 1
@shakibishraq7779
@shakibishraq7779 3 жыл бұрын
This was very helpful, thank you. Was stuck on a similar question for a while before watching the video.
@Constance-M.
@Constance-M. 3 жыл бұрын
My test is on a few hours but now I know I'm going to get a good grade. Thank you sir.
@ximenahernandezrebollar3136
@ximenahernandezrebollar3136 3 жыл бұрын
i don't understand
@tlotlisogladwinmore3603
@tlotlisogladwinmore3603 3 жыл бұрын
thank you so much. God bless you.
@leuoteletamati2936
@leuoteletamati2936 3 жыл бұрын
FAC=1.07FAB
@sravankumarjr
@sravankumarjr 3 жыл бұрын
@7:26 actually thats 1.114AC (you made addition mistake of 0.60+0.514=1.114)not 1.156 so that finally Tension in AC=263N
@marthanambeye9638
@marthanambeye9638 3 жыл бұрын
Center of mass for the Y coordinate should be 18/35 or maybe I could be wrong?
@v-niftytrickster4166
@v-niftytrickster4166 3 жыл бұрын
Did he switch fab and fac by accident when solving for fac?
@tjmartin8261
@tjmartin8261 3 жыл бұрын
I'm confused which one is the area? I don't know where you got the .0125 from
@stevenokoro1866
@stevenokoro1866 4 жыл бұрын
Um. I'm pretty sure it's. Fac = 1.07Fab. Not the other way around. But still, great explanation.
@TheGogo548
@TheGogo548 4 жыл бұрын
Hi sir... I liked your video. I want to know which tool or the application you have used for and which platform do you use iPad or computer anything? thank you
@ryanniedernhofer
@ryanniedernhofer 4 жыл бұрын
Well done, much appreciated
@ravenguirao9081
@ravenguirao9081 4 жыл бұрын
May i know what book this is?
@mubarakhussain436
@mubarakhussain436 4 жыл бұрын
😍😍😍
@truesolution6069
@truesolution6069 4 жыл бұрын
IF YOU LEAD ANYBODY LEAD HIM/HER PROPERLY. MUST BE YOU'RE LOSS. YOU NEED HELP.
@nickolasstrandine8855
@nickolasstrandine8855 4 жыл бұрын
What if the 10N was an unknown and a fulcrum point so you have tension unknown and the 10N unknown?
@eri-r3l
@eri-r3l 4 жыл бұрын
thanks brent, super helpful
@nuggets5787
@nuggets5787 4 жыл бұрын
This is a good video. Textbooks just keep making this energy topic hard. Thank you so much!!
@elmolavista1239
@elmolavista1239 4 жыл бұрын
4:48 why isn't the distance for the woman 6 meters?
@vrindaagarwal8716
@vrindaagarwal8716 2 жыл бұрын
When the woman is walking....boat is going backwards so as to not change the position of com because center of mass must have 0 displacement as there is not external force applied in x direction...so when woman is moving forward 6m she is not actually moving 6m....but some distance boat is also moving which we need to subtract
@darchy398
@darchy398 4 жыл бұрын
وينهم طلاب محمد نجم
@avneeshnathan4978
@avneeshnathan4978 4 жыл бұрын
excellent video but can you please tell the rule of geometry for that angle part?
@Mr02071961
@Mr02071961 5 жыл бұрын
Sphere should also have mom. of inertia around its center.
@mahsumoral4960
@mahsumoral4960 5 жыл бұрын
why did not you change the center of mass? While stucking the center of mass changes right?
@octavio2152
@octavio2152 5 жыл бұрын
It's more easy to apply Lamy's law.
@zeeeej10
@zeeeej10 5 жыл бұрын
Your computations are wrong. you should double check them.
@thandolwethukumalo2457
@thandolwethukumalo2457 5 жыл бұрын
where does the -80fab come from ??
@ThePCVortex
@ThePCVortex 5 жыл бұрын
more please
@jakebutler7016
@jakebutler7016 5 жыл бұрын
correct but it would be 2.4 kip feet
@jereere8181
@jereere8181 5 жыл бұрын
Sir why did you use sin 30, On 3.5 distance? What if you used cosin 30
@kuzuchi59
@kuzuchi59 5 жыл бұрын
Only the vertical component of the cable can cause a moment around A. Since the beam has no thickness the horizontal component of the cable (cosine of angle) cannot create a moment around A because it goes through point A. Hope this helps!
@jereere8181
@jereere8181 5 жыл бұрын
Oh !! Now i know haha, Thank you Dr. Holt, love your vids
@anonymousdude5895
@anonymousdude5895 5 жыл бұрын
hi. I wanna say thank you. this still helps me in 2019.
@JasonAlexzander1q47
@JasonAlexzander1q47 5 жыл бұрын
So on a 500' 65° decline..600plb weight..... Tree to tree guy wire. Using 5/8 braided cable. The tree at the top, the wire is attached 15' up. On the bottom tree, the wire is attached 20' up from the ground. The 600plb object is 8' long and 5+1/2' wide and 3' tall in height. Will be suspended by ropes and three equally spaced tandem pulley trolleys. Where as the top of the 600plb object leading to the bottom of the guy wire will be 9'. How do I know how tight the guy wire needs to be so that the object doesn't hit the ground but ends within 20' of the bottom tree and about 1+1/2' from the ground? Who is the math god?
@adosar7261
@adosar7261 5 жыл бұрын
How lower potential energy leads a molecule to greater stability? If PE goes down doesn't KE goes up so the molecule is less stable?
@adosar7261
@adosar7261 5 жыл бұрын
How lower potential energy leads a molecule to greater stability? If PE goes down doesn't KE goes up so the molecule is less stable?
@adayahokung9718
@adayahokung9718 5 жыл бұрын
if I did not go to school or had not learn this already I would have had no idea what was going on...more detailed explanations would be lovely