If a^2+b^2+c^2+1/a^2+1/b^2 +1/c^2=6 then, a+b+c =? | Algebra
4:01
If a^2+b^2+c^2+1/a^2+1/b^2 +1/c^2=6 then, a+b+c =? | Algebra
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If one root of the equation ax^2+bx+c=0 is 3 times the other then b^2:ac | Quadratic Equations|
4:09
If one root of the equation ax^2+bx+c=0 is 3 times the other then b^2:ac | Quadratic Equations|
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INTRO
0:18
INTRO
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When 2^256 is divided by 17 the remainder would be.| Remainder Theorem l
3:49
When 2^256 is divided by 17 the remainder would be.| Remainder Theorem l
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A number lies between 300 and 400. Playing with numbers|
8:18
A number lies between 300 and 400. Playing with numbers|
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If N is the sum of first 13,986 prime numbers, then N is always divisible by..| Number system
5:00
If N is the sum of first 13,986 prime numbers, then N is always divisible by..| Number system
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if the sum of n terms of two APs are in the Ratio 3n+5 : 5n+7 |Arithmetic Progression | Class 10
6:33
if the sum of n terms of two APs are in the Ratio 3n+5 : 5n+7 |Arithmetic Progression | Class 10
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The sum of two numbers is 1215 and their HCF is 81. How many pairs of such numbers can be formed? |
5:59
The sum of two numbers is 1215 and their HCF is 81. How many pairs of such numbers can be formed? |
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NUMBER SYSTEM| CLASS -9 RD Sharma MCQs| fully solved with explanation| CBSE
22:20
NUMBER SYSTEM| CLASS -9 RD Sharma MCQs| fully solved with explanation| CBSE
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x=(√(a+1)+√(a-1))/(√(a+1)-√(a-1)) ,show that x^2-2ax+1=0| Application of Componendo-Dividendo
5:54
x=(√(a+1)+√(a-1))/(√(a+1)-√(a-1)) ,show that x^2-2ax+1=0| Application of Componendo-Dividendo
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The peacock and the snake problem | CBSE | ICSE
5:13
The peacock and the snake problem | CBSE | ICSE
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COMPONENDO-DIVIDENDO
9:10
COMPONENDO-DIVIDENDO
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if 5^(-p)=4^(-q)=(20 )^r then show that: 1/p+1/q+1/r=0 |EXPONENTS | CBSE | ICSE
2:52
if 5^(-p)=4^(-q)=(20 )^r then show that: 1/p+1/q+1/r=0 |EXPONENTS | CBSE | ICSE
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if a^x=bc,b^y=ab and c^z=ab then xyz=8.| EXPONENTS |CBSE|ICSE
6:37
if a^x=bc,b^y=ab and c^z=ab then xyz=8.| EXPONENTS |CBSE|ICSE
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mathosol
0:30
mathosol
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