M108 H1.5-6 Q3
1:50
3 ай бұрын
M108 H1.5-6 Q2
3:31
3 ай бұрын
M108 H1.5-6 Q1
2:33
3 ай бұрын
How to Prove: Fermat's Theorem
2:39
Comparable Series
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How to Prove Quotient Rule
3:00
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2:10
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How to Prove Chain Rule
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6:22
Пікірлер
@moustafaelallati2856
@moustafaelallati2856 Сағат бұрын
Bedankt man! Duidelijke uitleg en een antwoord op mijn vraag. Ik ben blij om de honderdste like te kunnen geven. 👍
@zsky1543
@zsky1543 10 күн бұрын
Wow thank you so much! I had this exact problem on my exam and could not figure it out for the life of me. Thank you this video really helped me out 👍
@wishizuk
@wishizuk 10 күн бұрын
Glad to hear! My pleasure!
@vafkamat
@vafkamat 15 күн бұрын
Partial Converse: If a and b are greater 0, and if there exist integers x and y such that ax + by = 1 then gcd(a,b) = 1 Prf: Let d = gcd(a,b) If 1 = bx + ay then 1 = d( b/d)x + d ( a/d)y or 1 = d( xb/d + ay/d) The quantity in brackets is an integer for b/d and a/d are integer; this tells us that d|1 or d=1 so that gcd(a,b) = 1
@wishizuk
@wishizuk 10 күн бұрын
Thank you for posting this comment!
@sissibabyjane
@sissibabyjane 19 күн бұрын
Very helpful and well explained!
@wishizuk
@wishizuk 18 күн бұрын
Glad to hear! Thanks for your kind words!
@YotbePremium
@YotbePremium 20 күн бұрын
Hi, may I know how to know when to stop reiterating in numerical methods if I am also asked to solve for percentage difference?
@wishizuk
@wishizuk 18 күн бұрын
If you have a specified correct decimal places, you can stop when those digits stop changing. I would guess that the percentage difference of the zero x and x_n is: 100|(x-x_n)/x|, assuming that x is not zero.
@YotbePremium
@YotbePremium 20 күн бұрын
How do I know if it is analytic or not? Please explain in simple words.
@wishizuk
@wishizuk 20 күн бұрын
It means that it can be expressed as a power series.
@YotbePremium
@YotbePremium 20 күн бұрын
@@wishizuk got it! Thank you, your videos are vv helpful!
@wishizuk
@wishizuk 20 күн бұрын
​@@YotbePremiumMy pleasure!
@roberttomi8800
@roberttomi8800 23 күн бұрын
thanks
@wishizuk
@wishizuk 21 күн бұрын
My pleasure!
@qinzirui
@qinzirui 24 күн бұрын
ty so much ,but i wonder why im(a) is not (2 0 -1)T, (4 0 2)T, (-1 0 3)T . since those three vectors are linearly independent
@wishizuk
@wishizuk 21 күн бұрын
Those three vectors are NOT linearly independent since (-7/4)(2,0,-1) + (5/8)(4,0,2) = (-1,0,3).
@IannisRamírezFloropoulos
@IannisRamírezFloropoulos 24 күн бұрын
Where did the I (imaginary part) go when you raised it to the square root??
@wishizuk
@wishizuk 21 күн бұрын
|a+bi| = sqrt(a^2+b^2), so it is always a real number.
@531tt1e
@531tt1e Ай бұрын
i love you wishizukunde
@wishizuk
@wishizuk Ай бұрын
Thanks for your kind words!
@idontknow1630
@idontknow1630 Ай бұрын
ive watched a couple videos on these and it clicked for me finally from this video, thank you so much! i subbed :)
@wishizuk
@wishizuk Ай бұрын
Glad to hear that! I hooe that you enjoy my other videos!
@bladez8589
@bladez8589 Ай бұрын
Life saver. Hope everything is all well for you and thank you for the tremendous help!
@wishizuk
@wishizuk Ай бұрын
Glad to hear that you found the video helpful! My pleasure!
@KaidenWanna
@KaidenWanna Ай бұрын
Never explained where the 2x came from
@wishizuk
@wishizuk Ай бұрын
2 comes from "twice".
@WogariKenate
@WogariKenate Ай бұрын
wow its nice study
@wishizuk
@wishizuk Ай бұрын
Thanks for your kind words!
@FridayF8
@FridayF8 Ай бұрын
HOLY $H1T IS THAT RAMIEL-
@wishizuk
@wishizuk Ай бұрын
Interesting!
@MathematicianOrMagician
@MathematicianOrMagician Ай бұрын
Thank you, surprising no one said that to you in 4 years!
@wishizuk
@wishizuk Ай бұрын
My pleasure! That is okay! I am glad that you found it!
@valeriaquinto4171
@valeriaquinto4171 Ай бұрын
why 1/N+1 and -1/N+2 approaches to 0?
@wishizuk
@wishizuk Ай бұрын
1 divided by a larger and larger number gets closer and closer to 0.
@meslah1637
@meslah1637 Ай бұрын
i appreciate it
@wishizuk
@wishizuk Ай бұрын
My pleasure!
@NicaKasende
@NicaKasende Ай бұрын
❤❤❤
@wishizuk
@wishizuk Ай бұрын
Thanks for the hearts!
@TaofiqueMK
@TaofiqueMK Ай бұрын
Look like kidney force to see like a heart 😂😅
@wishizuk
@wishizuk Ай бұрын
Kidneyoid
@asmatamiri1614
@asmatamiri1614 Ай бұрын
Good boy that’s what I like
@wishizuk
@wishizuk Ай бұрын
Glad to hear!
@kipweit9634
@kipweit9634 Ай бұрын
Hi, do we actually end up getting the same value for area element as if it wasn't actually rectangular, because you say that we have to pretend that it's rectangular.
@wishizuk
@wishizuk Ай бұрын
This video gives an alternative view of area elements: kzbin.info/www/bejne/m5PTan1pq816qac
@almscurium
@almscurium 2 ай бұрын
Great video :)
@wishizuk
@wishizuk 2 ай бұрын
Thanks for your kind words!
@epharedam
@epharedam 2 ай бұрын
thank you so much...
@wishizuk
@wishizuk 2 ай бұрын
My pleasure!
@16_siska85
@16_siska85 2 ай бұрын
Thank you sir
@wishizuk
@wishizuk 2 ай бұрын
My pleasure!
@limtseren5694
@limtseren5694 2 ай бұрын
thanks for such clarity
@wishizuk
@wishizuk 2 ай бұрын
My pleasure!
@MisaAmane-jy8nm
@MisaAmane-jy8nm 2 ай бұрын
You are very underrated!! Very helpful thank you
@wishizuk
@wishizuk 2 ай бұрын
Thanks for your kind words! I hope that you will also enjoy my other videos.
@ln_cript
@ln_cript 3 ай бұрын
beautifully and simply explained!
@wishizuk
@wishizuk 3 ай бұрын
Thanks for your kind words!
@NurbolBekbossin
@NurbolBekbossin 3 ай бұрын
I couldn't understand Theorem 1.6 from Apostol's book, I believe this is a lot more clear. Not sure why Apostol chose such a convoluted way of proving the theorem, only way I could think of is that he assumed reader/student doesn't know two assisting theorems on the video that would help advance further more efficiently.
@wishizuk
@wishizuk 3 ай бұрын
I am glad to hear! I hope that you will enjoy my other videos!
@Artux_X
@Artux_X 3 ай бұрын
I LOVE YOU SO MUCHHHH TYPE SHII
@wishizuk
@wishizuk 3 ай бұрын
Thanks for your kind words!
@stephenlepage
@stephenlepage 3 ай бұрын
Easy to follow derivation by first principles, well described, well animated. No mucking around. Solid video.
@wishizuk
@wishizuk 3 ай бұрын
Thanks for your kind words! I hope that you will enjoy my other videos!
@anamitam7113
@anamitam7113 3 ай бұрын
thanks
@wishizuk
@wishizuk 3 ай бұрын
My pleasure!
@leonardopaes2494
@leonardopaes2494 3 ай бұрын
Great and neat proof! I learned a lot, specially regarding the well-ordering principle!
@wishizuk
@wishizuk 3 ай бұрын
Glad to hear that! I hope that you will enjoy my other videos!
@sudhanyadutta3175
@sudhanyadutta3175 3 ай бұрын
thanks 😃
@wishizuk
@wishizuk 3 ай бұрын
My pleasure!
@apostrophe07
@apostrophe07 3 ай бұрын
Holy hell this was insanely helpful. Thanks a ton sir
@wishizuk
@wishizuk 3 ай бұрын
My pleasure!
@apostrophe07
@apostrophe07 3 ай бұрын
Thanks a lot good sir!
@wishizuk
@wishizuk 3 ай бұрын
You are welcome!
@Anonymous_MC
@Anonymous_MC 3 ай бұрын
i like how this guy writes everything in logical statements
@wishizuk
@wishizuk 3 ай бұрын
Thanks for your kind words!
@dabeerahmed4802
@dabeerahmed4802 4 ай бұрын
Can i not just say that a_n converges to a, so the choice of Epsilon in N2, can be |b_n - b| < 0.5E/|a|?
@wishizuk
@wishizuk 3 ай бұрын
Since I did not worry about the case where |a| = 0, I replaced with |a| + 1.
@vishalverma5280
@vishalverma5280 4 ай бұрын
Finally a kind kind of cool breeze in baking sun. ❤❤ You are my hero ❤❤❤
@wishizuk
@wishizuk 3 ай бұрын
Thanks for your kind words!
@jean-kiara
@jean-kiara 4 ай бұрын
one video and I understand everything. you are a GOAT. (greatest of all time)
@wishizuk
@wishizuk 4 ай бұрын
Youn are too kind, but thanks!
@janusium
@janusium 4 ай бұрын
Where did all the numbers go
@wishizuk
@wishizuk 4 ай бұрын
Who needs numbers?
@epic_editz_x
@epic_editz_x 4 ай бұрын
The best explanation so far ❤
@wishizuk
@wishizuk 4 ай бұрын
Thanks for your kind words!
@laminedjiba2034
@laminedjiba2034 4 ай бұрын
merci
@wishizuk
@wishizuk 4 ай бұрын
You are very welcome!
@MichaelJamesActually
@MichaelJamesActually 4 ай бұрын
thank you for posting this! I've been testing root-finding methods in geogebra. do you know of a way to implement something like secant method where you are looking at the previous two points? generating a table is possibly straightforward, not sure if it is possible in a script or Iteration function.
@wishizuk
@wishizuk 4 ай бұрын
Glad to hear that!
@krumpy8259
@krumpy8259 4 ай бұрын
There we go, that’s fantastic thank you.
@wishizuk
@wishizuk 4 ай бұрын
My pleasure! I appreciate your kind words!
@Channel-zb1fi
@Channel-zb1fi 4 ай бұрын
Thank you, this was immensely helpful for reinforcing my idea of, what it means to prove something by induction.
@Channel-zb1fi
@Channel-zb1fi 4 ай бұрын
Oh, and a few other proofs refused to handle the induction process diligently by skipping the assuming of P(n), and transforming that into P(n+1), and just started at P(n+1) without explaining how they arrived at the P(n+1) from P(n), thereby disregarding the entire idea of an implication.
@wishizuk
@wishizuk 4 ай бұрын
Thanks for your kind words! It is indeed a neat technique.
@Sooo_Seen
@Sooo_Seen 4 ай бұрын
thaaank you that was helpful and super clear!!
@wishizuk
@wishizuk 4 ай бұрын
Thanks, but I don't know how else I explain partitions of sets.
@kartheekpattigilli2759
@kartheekpattigilli2759 4 ай бұрын
🎉🎉🎉🎉thanks
@wishizuk
@wishizuk 4 ай бұрын
My pleasure!
@princeakpabli7988
@princeakpabli7988 5 ай бұрын
thank you very much for the video. but please what happened to the "B" in the case 3? i thought it will be the coefficient of the sine function
@wishizuk
@wishizuk 5 ай бұрын
We typically do not include the constant in front of an eigenfunction.
@Linhkinhbrods
@Linhkinhbrods 5 ай бұрын
isn't it that when gcd(a,b)|(ax+by) then gcd(a,b) = ax + by already because of well ordering principle and the gcd itself let's say when gcd(4,6) = 2 then we have 2|ax+by hence ax + by must be equal to 2.
@wishizuk
@wishizuk 5 ай бұрын
Being divisible by 2 does not mean being equal to 2.
@Linhkinhbrods
@Linhkinhbrods 5 ай бұрын
@@wishizuk what?
@wishizuk
@wishizuk 5 ай бұрын
@@Linhkinhbrods 2|(ax+by) does not imply ax+by=2.
@Linhkinhbrods
@Linhkinhbrods 5 ай бұрын
@@wishizuk why not
@wishizuk
@wishizuk 5 ай бұрын
@@Linhkinhbrods 2 divides 4, but 4 is not 2.