Bedankt man! Duidelijke uitleg en een antwoord op mijn vraag. Ik ben blij om de honderdste like te kunnen geven. 👍
@zsky154310 күн бұрын
Wow thank you so much! I had this exact problem on my exam and could not figure it out for the life of me. Thank you this video really helped me out 👍
@wishizuk10 күн бұрын
Glad to hear! My pleasure!
@vafkamat15 күн бұрын
Partial Converse: If a and b are greater 0, and if there exist integers x and y such that ax + by = 1 then gcd(a,b) = 1 Prf: Let d = gcd(a,b) If 1 = bx + ay then 1 = d( b/d)x + d ( a/d)y or 1 = d( xb/d + ay/d) The quantity in brackets is an integer for b/d and a/d are integer; this tells us that d|1 or d=1 so that gcd(a,b) = 1
@wishizuk10 күн бұрын
Thank you for posting this comment!
@sissibabyjane19 күн бұрын
Very helpful and well explained!
@wishizuk18 күн бұрын
Glad to hear! Thanks for your kind words!
@YotbePremium20 күн бұрын
Hi, may I know how to know when to stop reiterating in numerical methods if I am also asked to solve for percentage difference?
@wishizuk18 күн бұрын
If you have a specified correct decimal places, you can stop when those digits stop changing. I would guess that the percentage difference of the zero x and x_n is: 100|(x-x_n)/x|, assuming that x is not zero.
@YotbePremium20 күн бұрын
How do I know if it is analytic or not? Please explain in simple words.
@wishizuk20 күн бұрын
It means that it can be expressed as a power series.
@YotbePremium20 күн бұрын
@@wishizuk got it! Thank you, your videos are vv helpful!
@wishizuk20 күн бұрын
@@YotbePremiumMy pleasure!
@roberttomi880023 күн бұрын
thanks
@wishizuk21 күн бұрын
My pleasure!
@qinzirui24 күн бұрын
ty so much ,but i wonder why im(a) is not (2 0 -1)T, (4 0 2)T, (-1 0 3)T . since those three vectors are linearly independent
@wishizuk21 күн бұрын
Those three vectors are NOT linearly independent since (-7/4)(2,0,-1) + (5/8)(4,0,2) = (-1,0,3).
@IannisRamírezFloropoulos24 күн бұрын
Where did the I (imaginary part) go when you raised it to the square root??
@wishizuk21 күн бұрын
|a+bi| = sqrt(a^2+b^2), so it is always a real number.
@531tt1eАй бұрын
i love you wishizukunde
@wishizukАй бұрын
Thanks for your kind words!
@idontknow1630Ай бұрын
ive watched a couple videos on these and it clicked for me finally from this video, thank you so much! i subbed :)
@wishizukАй бұрын
Glad to hear that! I hooe that you enjoy my other videos!
@bladez8589Ай бұрын
Life saver. Hope everything is all well for you and thank you for the tremendous help!
@wishizukАй бұрын
Glad to hear that you found the video helpful! My pleasure!
@KaidenWannaАй бұрын
Never explained where the 2x came from
@wishizukАй бұрын
2 comes from "twice".
@WogariKenateАй бұрын
wow its nice study
@wishizukАй бұрын
Thanks for your kind words!
@FridayF8Ай бұрын
HOLY $H1T IS THAT RAMIEL-
@wishizukАй бұрын
Interesting!
@MathematicianOrMagicianАй бұрын
Thank you, surprising no one said that to you in 4 years!
@wishizukАй бұрын
My pleasure! That is okay! I am glad that you found it!
@valeriaquinto4171Ай бұрын
why 1/N+1 and -1/N+2 approaches to 0?
@wishizukАй бұрын
1 divided by a larger and larger number gets closer and closer to 0.
@meslah1637Ай бұрын
i appreciate it
@wishizukАй бұрын
My pleasure!
@NicaKasendeАй бұрын
❤❤❤
@wishizukАй бұрын
Thanks for the hearts!
@TaofiqueMKАй бұрын
Look like kidney force to see like a heart 😂😅
@wishizukАй бұрын
Kidneyoid
@asmatamiri1614Ай бұрын
Good boy that’s what I like
@wishizukАй бұрын
Glad to hear!
@kipweit9634Ай бұрын
Hi, do we actually end up getting the same value for area element as if it wasn't actually rectangular, because you say that we have to pretend that it's rectangular.
@wishizukАй бұрын
This video gives an alternative view of area elements: kzbin.info/www/bejne/m5PTan1pq816qac
@almscurium2 ай бұрын
Great video :)
@wishizuk2 ай бұрын
Thanks for your kind words!
@epharedam2 ай бұрын
thank you so much...
@wishizuk2 ай бұрын
My pleasure!
@16_siska852 ай бұрын
Thank you sir
@wishizuk2 ай бұрын
My pleasure!
@limtseren56942 ай бұрын
thanks for such clarity
@wishizuk2 ай бұрын
My pleasure!
@MisaAmane-jy8nm2 ай бұрын
You are very underrated!! Very helpful thank you
@wishizuk2 ай бұрын
Thanks for your kind words! I hope that you will also enjoy my other videos.
@ln_cript3 ай бұрын
beautifully and simply explained!
@wishizuk3 ай бұрын
Thanks for your kind words!
@NurbolBekbossin3 ай бұрын
I couldn't understand Theorem 1.6 from Apostol's book, I believe this is a lot more clear. Not sure why Apostol chose such a convoluted way of proving the theorem, only way I could think of is that he assumed reader/student doesn't know two assisting theorems on the video that would help advance further more efficiently.
@wishizuk3 ай бұрын
I am glad to hear! I hope that you will enjoy my other videos!
@Artux_X3 ай бұрын
I LOVE YOU SO MUCHHHH TYPE SHII
@wishizuk3 ай бұрын
Thanks for your kind words!
@stephenlepage3 ай бұрын
Easy to follow derivation by first principles, well described, well animated. No mucking around. Solid video.
@wishizuk3 ай бұрын
Thanks for your kind words! I hope that you will enjoy my other videos!
@anamitam71133 ай бұрын
thanks
@wishizuk3 ай бұрын
My pleasure!
@leonardopaes24943 ай бұрын
Great and neat proof! I learned a lot, specially regarding the well-ordering principle!
@wishizuk3 ай бұрын
Glad to hear that! I hope that you will enjoy my other videos!
@sudhanyadutta31753 ай бұрын
thanks 😃
@wishizuk3 ай бұрын
My pleasure!
@apostrophe073 ай бұрын
Holy hell this was insanely helpful. Thanks a ton sir
@wishizuk3 ай бұрын
My pleasure!
@apostrophe073 ай бұрын
Thanks a lot good sir!
@wishizuk3 ай бұрын
You are welcome!
@Anonymous_MC3 ай бұрын
i like how this guy writes everything in logical statements
@wishizuk3 ай бұрын
Thanks for your kind words!
@dabeerahmed48024 ай бұрын
Can i not just say that a_n converges to a, so the choice of Epsilon in N2, can be |b_n - b| < 0.5E/|a|?
@wishizuk3 ай бұрын
Since I did not worry about the case where |a| = 0, I replaced with |a| + 1.
@vishalverma52804 ай бұрын
Finally a kind kind of cool breeze in baking sun. ❤❤ You are my hero ❤❤❤
@wishizuk3 ай бұрын
Thanks for your kind words!
@jean-kiara4 ай бұрын
one video and I understand everything. you are a GOAT. (greatest of all time)
@wishizuk4 ай бұрын
Youn are too kind, but thanks!
@janusium4 ай бұрын
Where did all the numbers go
@wishizuk4 ай бұрын
Who needs numbers?
@epic_editz_x4 ай бұрын
The best explanation so far ❤
@wishizuk4 ай бұрын
Thanks for your kind words!
@laminedjiba20344 ай бұрын
merci
@wishizuk4 ай бұрын
You are very welcome!
@MichaelJamesActually4 ай бұрын
thank you for posting this! I've been testing root-finding methods in geogebra. do you know of a way to implement something like secant method where you are looking at the previous two points? generating a table is possibly straightforward, not sure if it is possible in a script or Iteration function.
@wishizuk4 ай бұрын
Glad to hear that!
@krumpy82594 ай бұрын
There we go, that’s fantastic thank you.
@wishizuk4 ай бұрын
My pleasure! I appreciate your kind words!
@Channel-zb1fi4 ай бұрын
Thank you, this was immensely helpful for reinforcing my idea of, what it means to prove something by induction.
@Channel-zb1fi4 ай бұрын
Oh, and a few other proofs refused to handle the induction process diligently by skipping the assuming of P(n), and transforming that into P(n+1), and just started at P(n+1) without explaining how they arrived at the P(n+1) from P(n), thereby disregarding the entire idea of an implication.
@wishizuk4 ай бұрын
Thanks for your kind words! It is indeed a neat technique.
@Sooo_Seen4 ай бұрын
thaaank you that was helpful and super clear!!
@wishizuk4 ай бұрын
Thanks, but I don't know how else I explain partitions of sets.
@kartheekpattigilli27594 ай бұрын
🎉🎉🎉🎉thanks
@wishizuk4 ай бұрын
My pleasure!
@princeakpabli79885 ай бұрын
thank you very much for the video. but please what happened to the "B" in the case 3? i thought it will be the coefficient of the sine function
@wishizuk5 ай бұрын
We typically do not include the constant in front of an eigenfunction.
@Linhkinhbrods5 ай бұрын
isn't it that when gcd(a,b)|(ax+by) then gcd(a,b) = ax + by already because of well ordering principle and the gcd itself let's say when gcd(4,6) = 2 then we have 2|ax+by hence ax + by must be equal to 2.
@wishizuk5 ай бұрын
Being divisible by 2 does not mean being equal to 2.