did not understand

Please avoid trying to overdo your pronunciation. Instead, embrace your natural local accent in English and proceed confidently as you are.

Your accents are very good 👍🏻

You are amazing. Gained a subscriber.

y are u faking accent .

much love from Greece!! when you come here i will be more than welcomed to have you to my house and spend time together coding in C language

very very poor explanation

I found this gem 💎 very late

You are trying so hard to hide your Bengali accent with as much American as possible, I could not focus on your approach :)

bhai normal english me bol le, foreign excent boche me dal...

#@urtheshit_1 @allycatsssh @al.ex8156 @elusive @dukeoriginal

speak in your original accent it makes things more easily understandable

NICE SUPER EXCELLENT MOTIVATED

REALLY GREAT EXPLANATION - THANK YOU SO MUCHHHH

Thanks🎉

how about these arrays: [0,2,1] and [0,2,1]. I dont think your code work??

Thanks for sharing this video, I finally understand the levenshtein algorithm

Man you are amazing

bro u dont have to do the accent man...

Hi, I have a quesiton. Did you figure it out yourself that (R-L)/2 will cause overflow? Is this something everybody knows from Computer Science? Thanks! It is a very good explanation you have, more clear than others.

NICE SUPER EXCELLENT MOTIVATED

Bhai accent kyu badal raha hai.

Thanks.

The way he said Thirty Two 🥴

Not efficient, use mask to swap without using loop

Good explanation and resolution code 👌

VERY CLEAR

Subscribed!!! Best solution of this question on youtube

What happened to your accent lol

Bhai aise awaaz mai pure video kaise bol lete ho? Hume bhi tips do please.

BC jabardasti kyun accent change kar raha hai bhai?? Gareebo ka Angrez BC

you have to slightly change the code because this code doesn't work for string = "aa" , pattern = "*"; modified code for (int i = 0; i <= s_len; i++) { for (int j = 0; j <= p_len; j++) { if (i == 0 && j == 0) { dp[i][j] = true; } else if (i == 0) { if (dp[i][j-1] == true && p.charAt(j-1) == '*') { dp[i][j] = true; } else { dp[i][j] = false; } } else if (i != 0 && j == 0) { dp[i][j] = false; } else if (s.charAt(i-1) == p.charAt(j-1) || p.charAt(j-1) == '?') { dp[i][j] = dp[i-1][j-1]; } else if (p.charAt(j-1) == '*'){ dp[i][j] = dp[i][j-1] || dp[i-1][j]; } } }

what if the input is [ 3, 3, 2, -1 ]

Videos like these make people fall for "Tutorial Hell" - No intuition - No thought process - Why stack ??????? - Why traverse from back of the array ???? Waste of time.

Best Logic I found .... Thanks for the content.

nice explanation

Hello, can you help me understanding this one here? I have a mask of 0xFFFFFFFF and an input of 0x7FFFFFFF when I extract the value I do "0x7FFFFFFF & 0xFFFFFFFF" wich gives me the full input. But when I have the input and I try to apply the mask I do "0x7FFFFFFF | 0xFFFFFFFF" wich of course it does not give me the full input like the mask does. What am I doing wrong? Thanks in advance 👍.

superb bro....i saw other O(n) solutions but they were very confusing . Your approach is best among all i saw thank you.

Thank you!

after watching so many explanation videos, this one finally makes sense to me!

I'm so disappointed that I didn't come up with great solutions like this..

best and simple ..

Excellent explanation bro.....🙌🙌🙌

paan thook ke baat kar lodu! fake accent#$%^&

If you want views say it in indian accent. Learn to pronounce properly.

rey pandina kodaka. oora kukka aapara.

Hi sir, can you please provide any discount for your udemy course

Superb explanation!

great explanation..thank you

Really good