Reciprocal Trignometry ratios
3:16
Inverse Trignometry
2:20
Ай бұрын
SSS Similarity Theorem
8:44
3 ай бұрын
Trignometry:Similar Triangles
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Пікірлер
@NAGESHWARREDDYTUMMALA
@NAGESHWARREDDYTUMMALA 20 күн бұрын
Nice
@NAGESHWARREDDYTUMMALA
@NAGESHWARREDDYTUMMALA 20 күн бұрын
Nice
@Lorne-u2h
@Lorne-u2h 5 ай бұрын
That could be totally fake and I wouldn't know. All those years of watching The Big Bang Theory wasted.
@mathophilechirag
@mathophilechirag 8 ай бұрын
kzbin.infoDNnzG6ypnvY?si=qid9ycUv6SKPT1xM Maths Olympiad Question
@cizzle2054
@cizzle2054 8 ай бұрын
Are those x's?
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Yes! The variable is 'X'.
@ANTILGBT707
@ANTILGBT707 8 ай бұрын
No se de que país seas y pues si lo traduces espero que tengas más éxito en todo y bueno no será mucho pero ojalá que te valla bien amiga
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Thankyou so much!
@aprendiz4
@aprendiz4 8 ай бұрын
Let the result be seen for more than one millisecond please
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Sure!
@josephwaters2792
@josephwaters2792 8 ай бұрын
The other instructional videos aren't much better right side up. Things are more described rather than explained. Performing is not teaching. Rethink your approach and rework it. Good luck!
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Thankyou for the suggestion. I will try best next time.
@FatimetouMedlemine-bp3gv
@FatimetouMedlemine-bp3gv 8 ай бұрын
🫡👏👏👏
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Thankyou!😊
@tet876
@tet876 8 ай бұрын
or just 2×36
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Yes
@ChiefHitemBong
@ChiefHitemBong 8 ай бұрын
Wait...I thought any number divided by itself is 1..?
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Yes,number divided by itself is 1. Here,in this problem for 1÷3(sqrt(10)) Sqrt(10) is irrational number. So, I am Multiplying with sqrt(10) for both numerator and denominator so that sqrt(10)×sqrt(10)=sqrt(10^2)=10. So, in this way, we made denominator as a whole number 10 from irrational number sqrt(10). So, by Multiplying both numerator and denominator with sqrt(10 ) we converted it from irrational to whole number. Thus, we rationalized the denominator.
@ГошаЛайв
@ГошаЛайв 8 ай бұрын
Теорема виетта
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Yes! Nice For standard quadratic equation :ax^2+bx+c=0 Vietta's theorem: Sum of roots=-b÷a Product of roots=c÷a Sum of Roots=-6+-3=-9=-b÷a=-9÷1=-9 Product of roots=-6×-3=18=c÷a=18÷1=18
@ГошаЛайв
@ГошаЛайв 8 ай бұрын
Эээ, просто 400*2
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
👍
@srikanthraavi
@srikanthraavi 8 ай бұрын
Great short
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Thankyou!
@Jeffreydafox
@Jeffreydafox 8 ай бұрын
School: Please Excuse My Dear Aunt Sally Me: Please Eat My Dear Awesome Soup
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Thankyou for the idea for PEMDAS!
@johnroache32
@johnroache32 8 ай бұрын
And don't forget… We will all use this in every day life !
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Nice!
@Onenonlyprincess
@Onenonlyprincess 8 ай бұрын
Damn, that is some beautiful handwriting
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Thankyou!
@totalsoupsloud
@totalsoupsloud 8 ай бұрын
Please connect your x's!!!
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Yes, added correct value of x greater than 14 in the description and comments section. Sorry for the confusion and Thankyou for correcting it!
@kankri99
@kankri99 8 ай бұрын
At Math Academy: x > -14; On KZbin Comment: x > 14
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
Sorry,it's X>14.
@c4yourself319
@c4yourself319 8 ай бұрын
Where did the 3 and 4 go that were before X?
@ATMathAcademy
@ATMathAcademy 8 ай бұрын
In the inequality of: (X-5)÷3>(X-2)÷4 We do cross multiplication So, 4(X-5)>3(X-2) 4X-20>3X-6 Then, moving variables on one side and constants on the other side of the inequality. We get, 4X-3X>-6+20 X>14
@surajsahu8851
@surajsahu8851 9 ай бұрын
Wait isnt iota square 1
@ATMathAcademy
@ATMathAcademy 9 ай бұрын
I is an imaginary number. For example: To solve x^2+1=0 X^2=-1 x=squareroot of -1 So, for solving such equations the value of squaroot of -1 is named as an imaginary number called "i". So, as i=-1 Hence the value of i^2=(squaroot of -1)×(squaroot of -1) Which is i^2=-1. Thankyou!
@rleroygordon
@rleroygordon 10 ай бұрын
You can also do it as 18 + 21 - 5 = 39 - 5 = 34
@ATMathAcademy
@ATMathAcademy 9 ай бұрын
Yes! Absolutely