JCCCmath

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@RanBlakePiano 21 күн бұрын

Can t hear u well

@Abhishek_9570 22 күн бұрын

Watching One day before exam 😢

@minchodos 22 күн бұрын

Excellent illustration of test. Question: could someone please explain the “green” equation that plots the green line in Desmos showing the distance btw actual and error as n increases? Trying to understand how the professor constructed it: (b, t(a) + (1-t)f(a))

@alialbrega5007 27 күн бұрын

Which book did you use?

@JCCCmath 25 күн бұрын

At the time of these videos, I was using Thomas' 14th Edition.

@karamk321 Ай бұрын

How did the -x^3/3 became -x^3/6

@YsoGame Ай бұрын

Sir lec was W :)!!

@johnleandrepermison7175 Ай бұрын

Nice Vid!

@__-cm7ob Ай бұрын

nice video

@virajchaudhary243 2 ай бұрын

VERY HELPFULL

@zzym4107 2 ай бұрын

thank you!!

@jacobsandy8539 3 ай бұрын

How tall are you

@thisukainol 5 ай бұрын

thanks

@rizwanapatel3568 6 ай бұрын

Plz help me to solve integral minus infinty to infinity e-2/x/dx

@djarda2803 6 ай бұрын

nice explanation than these idiot indians

@ClassicalContrarian 7 ай бұрын

This is an awesome video!

@superfreiheit1 8 ай бұрын

After I saw this video I finaly get it, wonderful teacher

@milan1039 9 ай бұрын

Legend❤

@abdullahrahat1578 9 ай бұрын

thank you so much for explaining so well. <3

@weewoo3023 10 ай бұрын

I have no memory of doing this

@user-vg4rq4qw5o 11 ай бұрын

Thank you very much indeed this is really easy to follow and well explained

@gr3967 11 ай бұрын

Thanks ❤❤

@thatsfantastic313 11 ай бұрын

beautiful explanation♥ love from pakistan

@anthonysigns1075 Жыл бұрын

#CALC242

@samarpanjha5491 Жыл бұрын

Tnnx sir love from india

@Paulovrish7334 Жыл бұрын

Clean explanation

@walinut6443 Жыл бұрын

Thank you so much! I have a calculus 2 test in a few days, and a similar question appeared on my review. The teacher's method of solving was too difficult, but you made things so much more easier! May you live a long, healthy life!

@JCCCmath Жыл бұрын

Glad I could help.

@sujitmhadesar5246 Жыл бұрын

Tysm for this video....helped a lot!

@JCCCmath Жыл бұрын

You're welcome 😊

@aldobehrens5300 Жыл бұрын

Amazing

@JCCCmath Жыл бұрын

Thank you! Cheers!

@enzoys Жыл бұрын

THIS IS IT! this was the explanation I needed for helping me with vector calculus and I'm so happy I found your video!! thx

@JCCCmath Жыл бұрын

Great to hear!

@mujtabaahmadi7960 Жыл бұрын

Great explanation. Thanks!

@JCCCmath Жыл бұрын

Glad it was helpful!

@noodle7788 8 ай бұрын

@@JCCCmath What is theorem 5?

@JCCCmath 8 ай бұрын

@@noodle7788 , in the Calc II course these videos are used in, we use the Thomas Calculus book and Theorem 5 is just a list of 6 frequently used limits. This allows the students to just quote the theorem as opposed to re proving them every time.

@noodle7788 8 ай бұрын

@@JCCCmath I'm curious what the proof shows? does it just use the fact that the factorial function in the denominator grows much faster than the numerator. Or is there some way to better show limits with a factorial denominator goes to zero

@kingat8056 Жыл бұрын

Thank you, it's very helpful

@JCCCmath Жыл бұрын

You are welcome!

@snowcave4417 Жыл бұрын

Great stuff

@agnesnyambura334 Жыл бұрын

Thank you

@JCCCmath Жыл бұрын

You're welcome

@jwad21s91 Жыл бұрын

He got right to the point, something you rarely see

@bcnubynby4056 Жыл бұрын

The function f(x)=x/x+2 is increasing as shown by its derivative for all x>0. Graphing on Desmos verifies this as well. Therefore, condition two is met. All of this is beside the point because condition three fails and therefore an approach other than AST is needed. The video presentation is wonderful and goes beyond by showing "to error is human". Thanks for your fine teaching.

@izzygrandic Жыл бұрын

This is a great video and you are a great teacher.

@JCCCmath Жыл бұрын

Thank you. Glad you liked it.

@matokurin Жыл бұрын

Great

@matokurin Жыл бұрын

Great

@abdulrafay42240 Жыл бұрын

We do not take r<0 values, because it shows the reflection in polar coordinate?

@JCCCmath Жыл бұрын

We do allow for r<0 typically and interpret it as a reflection through the origin.

@kartik303 2 жыл бұрын

Thank you sir

@billwindsor4224 2 жыл бұрын

Excellent explanation, sir, *Thank You!*

@henryglenn534 2 жыл бұрын

LET'S GOOOO!

@letumilechocho231 2 жыл бұрын

Thank you!!!🌸

@JCCCmath Жыл бұрын

You are Welcome

@ee7692 2 жыл бұрын

ib exam tomorrow thanks king saving lives

@yahya-yl3rd 2 жыл бұрын

great video!

@hoaquach7684 2 жыл бұрын

Great job

@dhiaelhakrouabah8663 2 жыл бұрын

I just dont understand why the c is in between a and x0 (the point of our intrest) given that we're intrested in x0 then f^(n+1)(x) is supposed to be evaluated at x0 ...and other points of x are simply irrelavent . I understand that error bound should be as large as it can be by taking into account the worst case scenario and this is how we can bound it ..but x is supposed to be between a and x0 instead of c=x0 which is where we wanna know value of our approximation . What am i missing here?

@fullfungo Жыл бұрын

Realistically, you don’t need to write the error term as f(c)…, it has other forms as well. For example, “if |f^(n+1) (x)| < M on [a,b], then |R_n(b)| < M |b-a|^(n+1)/(n+1)!” In this formulation you just use the same bound. But if the function is continuous, then it has a point “c” where f^(n+1) (c) = M. So the form used in the video really only helps if f^(n+1) is continuous.

@dhiaelhakrouabah8663 Жыл бұрын

@@fullfungo thanks for commenting im still struggling with that concept . Like i understand that term is bounded by some number M bcuz we dont really know real value so we want to know how big it can get . But we assume c to be in between a and x0 ... like why exactly ? I didnt come across any justification and i dont quite get why they its not simply right at the point of evaluation x0? It just doesnt make sense to me

@fullfungo Жыл бұрын

@@dhiaelhakrouabah8663 en.wikipedia.org/wiki/Extreme_value_theorem?wprov=sfti1

@lolmnater101 2 жыл бұрын

Why is 2 < e < 3?

@michieldolfing Жыл бұрын

Because e~2.7182

@JCCCmath Жыл бұрын

In the course that this video is for, the students prove that by finding upper and lower bounds on the integral of (1/x) from 1 to 2 and 1 to 3, respectively. This, lead to concluding that there is a location between 2 and 3 where ln(x)=1, therefore 2<e<3.

@sanketmourya5136 2 жыл бұрын

Thank you sir

@saeedm3095 2 жыл бұрын

Thank you !

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