Glad I could help!

@@tiennamnguyen9942 I'm happy these videos are useful, thank you for the feedback!

Hi same a ơi

Thanks for watching!

Congrats on the 90%! I'm glad I could help. Thanks for watching!

Thanks for watching! I don't have a ti-84 plus, so I'm not sure, but you'll want to explore the math button to see if it's somewhere within that menu. Good luck!

Thank you for the feedback, I'm glad you enjoyed it! The Office is definitely one of my all-time favorites.

حرفيا 😂

I'm glad you find it useful! Thank you.

Hi Joe, thanks for watching! You might be thinking of a voltage divider here. When you have a voltage divider, the denominator is the sum of all resistances in series. But with the current divider, it is the numerator that is the total resistance of all the parallel paths you are dividing the current among. So in these problems, you'll see that the numerator is the combine resistance of all parallel paths, while the denominator is the resistance of the path in question, where the path we want the current for.

Thank you!

We can arbitrarily assign the direction of each current when beginning the problem. If the value for each current comes out positive, that means the direction we picked is correct. In this case, it might seem like the direction for I_3 should be reversed, at first glance. This current came out to be positive though, which means the polarity we initially selected is correct. Ultimately there is more current flowing from node A towards V2, than what is flowing out of V2 towards the node. So the final direction of the current is to the right.

Using superposition, you can determine that the current provided with only V1 in the circuit will be 652 mA, flowing from node A to V2. With only V2 in the circuit, 594 flows from V2 to Node A. This leads to a net current of 652 - 594 = 58 mA, flowing from Node A to V2. Therefore, the final direction of current I_3 is what is shown in the diagram. Does that make sense?

I don't have any at this time, but I might post some in the future!

@@profashleyevans then where i can find more videos about complex series and parallel rlc circiuts and also with power calculations like complex and others?

Hi, what kind of help do you need? What kind of circuit is it?

You can search through the component list to to find one - use the TTL group.

The voltage from terminal B to ground is the voltage across R2, which is also the voltage across X_L since they are in parallel. Since we have the current through I_C2, you can use that along with ohm's law to find the voltage across the parallel combination R2 // X_L, which would then be the voltage across each of those individual components.

It depends on what kind of calculator you have. For example, a TI-89 can automatically convert from rectangular to polar and you can type in the entire calculation in one step. If you don't have an advanced calculator, you would need to do each calculation in multiple steps on your calculator. This might mean first converting from rectangular to polar, or polar to rectangular depending on what value you're trying to find, and then doing additional combination of rectangular values or polar values. I go over the conversion from rectangular to polar, and polar to rectangular in an earlier video within the AC circuits playlist. If you need to see that information, look for the introduction to AC circuits video I posted.

@@profashleyevans ok thank you ill look for the video

Hi there, by definition the ASCII code for any character is 7 bits. We will always add leading zeros to any representation that isn't naturally 7 bits. Then, we're adding a partity but to the front (for a total of 8 bits) just to provide an example of how parity bits might be used with an ASCII message. Does that make sense?

@@profashleyevans Oh the 48 I was looking at was hex not decimal so in decimal it would be 72 which is what the binary you have is. Man this can get hard to keep things straight.

@@BenFreemanDC yes, number systems can be tricky! That's why I recommend always using a subscript when writing numbers related to digital systems. It's easy to confuse hex, decimal, binary, etc!!!

Glad it was helpful!

Glad I could help!

Thank you Dylon!

Thank you. I'm glad you found them helpful! I hope you enjoy my channel.

Hi Jon, thanks for the feedback! I'm glad you like the videos. I don't have any other videos with additional practice problems, but it's not hard to make up your own problems if you have a circuit design software such as multisim or pspice. You can use these programs to check your calculations. Or, grab a textbook similar to what we use in class, which is Principles of Electric Circuits, Conventional Current Version: Floyd, 10th Ed.

@@profashleyevans Good deal I seen that the book uses the TI-84 Ce and that’s actually the exact same calculator I use 😂💐 I think that’s God telling me to get the book thanks again Cheers

@rheigne maxxene maglente once you have the value for I_3 you plug that back into the equation that was derived for I_1. Look at the equation at 7:32. That's where you plug in I_3 to get I_1.

Hi there! Thanks for watching! I'm glad you find them helpful. Thanks for the heads up on the comments, what makes you think they're being deleted? I haven't noticed anything yet.

Well I noticed your response to a comment I had made from a video about AC Series-Parallel RC circuits ( I was just saying thanks for sharing since I’d just stumbled across your channel) but next time I pulled my phone out convo was gone but it is possible that I forgot to lock my screen and the conversation just got erased accidentally by me while my phone was shifting around in my pocket while I was raking leaves lol

@@jonramsey6348 okay, I'll be on the lookout! Thanks for letting me know.

@@profashleyevans 😊yes ma’am