Im so grateful that the sound quality is adequate.

God, the audio is horrible. Couldn't they have gotten a mike up there by him?

Must have been an exciting summer !

Benedict Gross is a great teacher <3, much respect

Absolutely beautiful lecture! I wish there were more of Tate’s talks available to watch online.

I have a proof that doesn’t fit inside the comment box

Thanks for this fantastic lecture!

Beal conjuncture proof kzbin.info/www/bejne/Z6LCmIeAiNZkpsUsi=eQd_85xaFupL-CMN

Fantastic lecture

Look at this link to see simple proof of FERMAT'S Last Theorem

I have fermats last theorem simple proof how to publish or how to verify how much that true.

I was really hoping to get a lecture of Pascal's hexagrammum mysticum; particularly its relation to Pappus

13/8/2023. Ne pouvant sans cesse me répéter, veuillez vous reporter sur d'autres sites traitant du sujet où j'explique l'EQUATION UNIVERSELLE cachée et FACILE de FERMAT, enfin retrouvée, et la réfutation de sa conjecture. En plus, vous découvrirez que FERMAT s'est inspiré de PYTHAGORE puisque Z²= X² + Y² peut s'étendre à Zpuissance(N) = X² + Y² , +2 <= N < + infini .Depuis plus de 2.500 ans, ni Pythagore, ni aucuns mathématiciens n'ont vu cette merveille mathématique, cette pépite. Pour arriver à FERMAT, il faut avoir l'idée de passer par PYTHAGORE et non s'attaquer directement à la conjecture qui est la face NORD périlleuse de la montée vers la solution qui est difficile comme l'attestent les 129 pages de Monsieur WILES. La solution est tellement inattendue, courte et facile que PERSONNE depuis près de 4 siècles n'a pas trouvé l'astuce de départ du raisonnement de FERMAT, tout le monde cherchant une démonstration compliquée..

I like your smell....remember today 10th of August

4/8/2023. Afin de ne pas me répéter sans cesse, veuillez vous reporter sur d'autres sites traitant de ce sujet . Conjecture de FERMAT démontrée avec l'EQUATION UNIVERSELLE et sa jumelle , celle de Pythagore où Z² est égale et étendue à Zpuissance(N) avec 2 <= N < + infini. A noter que depuis plus de 2.500 ans ,ni Pythagore ni aucun mathématicien ne se sont aperçus de cette propriété et merveilleuse étendue de l'exposant à l'infini. Fermat étant un cas similaire. Pour (Z)puissance au cube, l'équation de Pythagore est jumelle de celle de FERMAT.

He kinda sucks at lecturing

thanks for the post

Love this man’s book on elliptic curves but his lectures are even more precise thank you so much for upload !

I don't know why there are not many views of these wonderful lectures?

great lecture, but difficult to hear what he says. And bad video quality as well

Thanks , obviously , holonomies are important to me , I would agree .

she is always alive

This is the kind of mathematician that are unable to teach their own work in simple words. No wonder why people are scare with mathematics with such person teaching.

جانم

💞💞

John Gave me another Full Life

I love math, and I love the way Tate talks about abelian varieties, it's as if it's completely obvious what's going on.

= THE GREAT! - THE GREATEST!!! Theorem of the 21st century! = !!!!!!!!!!!!!!!!!!!!! "- an equation of the form X**m + Y**n = Z**k , where m != n != k - any integer(unequal "!=") numbers greater than 2 , - INSOLVable! in integers". !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! /- open publication priority of 22/07/2022 / !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! /-Proven by me! minimum-less than 7-10 pp.

Ribet is a wonderfully clear and fluent speaker. Even his blackboard writing is clear! Amongst mathematicians talking about Fermat he seems to be quite unique in this respect.

So lovely mathematician!

as a highschooler i can tell you this makes very little sense. I'll be back here when i understand it

Thanks for sharing this !

Pretty cool stuff.

Thanks for this video lecture. Very enlightening.

ı cant read

That feeling when you realize the table of addition is the same as nim-addition... RIP, btw. He was one of the greatest mathematicians of all time and certainly my favourite one.

زیبا ترین زنی که هیچگاه ندیدمش و جهان هم بی بهره ماند

I proved on 09/14/2016 the ONLY POSSIBLE proof of the Great Fermat's Theorem (Fermata!). I can pronounce the formula for the proof of Fermath's great theorem: 1 - Fermath's great theorem NEVER! and nobody! NOT! HAS BEEN PROVEN !!! 2 - proven! THE ONLY POSSIBLE proof of Fermat's theorem 3 - Fermath's great theorem is proved universally-proven for all numbers 4 - Fermath's great theorem is proven in the requirements of himself! Fermata 1637 y. 5 - Fermath's great theorem proved in 2 pages of a notebook 6 - Fermath's great theorem is proved in the apparatus of Diophantus arithmetic 7 - the proof of the great Fermath theorem, as well as the formulation, is easy for a student of the 5th grade of the school to understand !!! 8 - Me! opened the GREAT! A GREAT Mystery! Fermath's theorem! (not "simple" - "mechanical" proof) !!!!- NO ONE! and NEVER! (except ME! .. of course!) and FOR NOTHING! NOT! will find a valid proof

August 1995

Absolutely amazing video!

مریم میرزاخانی برای ما زنان ایرانی هرگز نمی میرد و جزو بزرگترین الگو های زندگی ماست

Do the notes exist somewhere?

<My Proof of Fermat's Last Theorem> 모든 솟수 p에 대하여, x^p + y^p = z^p을 만족하는 자연수 쌍 (x, y, z)가 존재한다면... 페르마 소정리와 인수정리를 적용하여 반드시 다음과 같은 꼴임을 알 수 있다. (x, y, z) = (v+pk, w+pk, v + w + pk) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) p가 짝수 솟수일 때: p = 2이므로 (x, y, z) = (v+2k, w+2k, v + w + 2k)를 x^2 + y^2 = z^2에 대입하고 정리하면 다음과 같이 변형된 식을 얻게 된다. vw = 2k^2 k=1일 때, 최소해를 구해보자. vw = 2이므로 v=1, w=2를 부여하면 될 것이다. v=1, w=2, k=1을 (x, y, z) = (v+2k, w+2k, v + w + 2k)에 대입하면 최소해 (x, y, z) = (1+2, 2+2, 1+2+2) = (3, 4, 5) 이후... k=2일 때: 2(3, 4, 5)가 해로 나타나고 k=3일 때: 3(3, 4, 5)가 해로 나타나고 k=n일 때: n(3, 4, 5)가 해로 나타난다. 이것은 x^2 + y^2 = z^2이라면 (nx)^2 + (ny)^2 = (nz)^2 또한 성립함을 의미한다. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (2) p가 홀수 솟수일 때: (x, y, z) = (v+pk, w+pk, v + w + pk)를 x^p + y^p = z^p에 대입하면... (v+pk)^p + (w+pk)^p = (v+w+pk)^p (v+w+pk)^p - {(v+pk)^p + (w+pk)^p} = 0 (v+w+pk)^p - {(v+pk)^p + (w+pk)^p - (pk)^p} = (pk)^p 이제 좌변에 페르마 소정리와 인수정리를 적용하면 다음과 같이 변형된 식을 얻게 된다. vw(v+w+2pk)F(v, w, k) = p^(p-1) k^p k=1일 때 최소해를 구해보자. k=1일 때, 우변은 홀수이므로 좌변의 인수들 또한 모두 홀수이어야 한다. v=홀수, w=홀수, v+w+2pk=홀수, ... v, w를 각각 'v+w+2pk=홀수'에 대입하면 '짝수=홀수'라는 모순이 생기므로 최소해는 없다. 따라서 자연수 해 (x, y, z)는 존재하지 않는다. (증명 끝)..

<My Proof of Fermat's Last Theorem> 모든 솟수 p에 대하여, x^p + y^p = z^p을 만족하는 자연수 쌍 (x, y, z)가 존재한다면... 페르마 소정리와 인수정리를 적용하여 반드시 다음과 같은 꼴임을 알 수 있다. (x, y, z) = (v+pk, w+pk, v + w + pk) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) p가 짝수 솟수일 때: p = 2이므로 (x, y, z) = (v+2k, w+2k, v + w + 2k)를 x^2 + y^2 = z^2에 대입하고 정리하면 다음과 같이 변형된 식을 얻게 된다. vw = 2k^2 k=1일 때, 최소해를 구해보자. vw = 2이므로 v=1, w=2를 부여하면 될 것이다. v=1, w=2, k=1을 (x, y, z) = (v+2k, w+2k, v + w + 2k)에 대입하면 최소해 (x, y, z) = (1+2, 2+2, 1+2+2) = (3, 4, 5) 이후... k=2일 때: 2(3, 4, 5)가 해로 나타나고 k=3일 때: 3(3, 4, 5)가 해로 나타나고 k=n일 때: n(3, 4, 5)가 해로 나타난다. 이것은 x^2 + y^2 = z^2이라면 (nx)^2 + (ny)^2 = (nz)^2 또한 성립함을 의미한다. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (2) p가 홀수 솟수일 때: (x, y, z) = (v+pk, w+pk, v + w + pk)를 x^p + y^p = z^p에 대입하면... (v+pk)^p + (w+pk)^p = (v+w+pk)^p (v+w+pk)^p - {(v+pk)^p + (w+pk)^p} = 0 (v+w+pk)^p - {(v+pk)^p + (w+pk)^p - (pk)^p} = (pk)^p 이제 좌변에 페르마 소정리와 인수정리를 적용하면 다음과 같이 변형된 식을 얻게 된다. vw(v+w+2pk)F(v, w, k) = p^(p-1) k^p k=1일 때 최소해를 구해보자. k=1일 때, 우변은 홀수이므로 좌변의 인수들 또한 모두 홀수이어야 한다. v=홀수, w=홀수, v+w+2pk=홀수, ... v, w를 각각 'v+w+2pk=홀수'에 대입하면 '짝수=홀수'라는 모순이 생기므로 최소해는 없다. 따라서 자연수 해 (x, y, z)는 존재하지 않는다. (증명 끝).

<My Proof of Fermat's Last Theorem> 모든 솟수 p에 대하여, x^p + y^p = z^p을 만족하는 자연수 쌍 (x, y, z)가 존재한다면... 페르마 소정리와 인수정리를 적용하여 반드시 다음과 같은 꼴임을 알 수 있다. (x, y, z) = (v+pk, w+pk, v + w + pk) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) p가 짝수 솟수일 때: p = 2이므로 (x, y, z) = (v+2k, w+2k, v + w + 2k)를 x^2 + y^2 = z^2에 대입하고 정리하면 다음과 같이 변형된 식을 얻게 된다. vw = 2k^2 k=1일 때, 최소해를 구해보자. vw = 2이므로 v=1, w=2를 부여하면 될 것이다. v=1, w=2, k=1을 (x, y, z) = (v+2k, w+2k, v + w + 2k)에 대입하면 최소해 (x, y, z) = (1+2, 2+2, 1+2+2) = (3, 4, 5) 이후... k=2일 때: 2(3, 4, 5)가 해로 나타나고 k=3일 때: 3(3, 4, 5)가 해로 나타나고 k=n일 때: n(3, 4, 5)가 해로 나타난다. 이것은 x^2 + y^2 = z^2이라면 (nx)^2 + (ny)^2 = (nz)^2 또한 성립함을 의미한다. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (2) p가 홀수 솟수일 때: (x, y, z) = (v+pk, w+pk, v + w + pk)를 x^p + y^p = z^p에 대입하면... (v+pk)^p + (w+pk)^p = (v+w+pk)^p (v+w+pk)^p - {(v+pk)^p + (w+pk)^p} = 0 (v+w+pk)^p - {(v+pk)^p + (w+pk)^p - (pk)^p} = (pk)^p 이제 좌변에 페르마 소정리와 인수정리를 적용하면 다음과 같이 변형된 식을 얻게 된다. vw(v+w+2pk)F(v, w, k) = p^(p-1) k^p k=1일 때 최소해를 구해보자. k=1일 때, 우변은 홀수이므로 좌변의 인수들 또한 모두 홀수이어야 한다. v=홀수, w=홀수, v+w+2pk=홀수, ... v, w를 각각 'v+w+2pk=홀수'에 대입하면 '짝수=홀수'라는 모순이 생기므로 최소해는 없다. 따라서 자연수 해 (x, y, z)는 존재하지 않는다. (증명 끝)

When did Ribet deliver this talk? He looks young enough that it might have been right after Wiles's proof was announced. He speaks of the Taniyama-Shimura conjecture, which has for twenty years (since the proof of Wiles and others) been known as the modularity theorem.

Oh she,s death😰😔😢😢😢😢😭😭

Thank you professor , amazing lecture series I feel honored to be following them

Thank you professor

She was elected from God to be in God's team to do a better job in Heaven . We came from God and will go back to .she is in heaven .she lives for ever