@@sunkymathsclass No. I am being truthful here. Really, I don't have. Keep making more videos brother!
@sunkymathsclassКүн бұрын
@@singyestudio608okay bro
@patk5724Күн бұрын
Also we can have : logx(4) = 1/2 x^1/2 = 4 [ raise by 2 on each sides below x^1/2×2 = 4^2 x = 16 log2(x) Implies log2(16) = y 2^y = 16 2^y = 2^4 y = 4 Therefore log2(16) = 4
@sunkymathsclassКүн бұрын
Yeah it can be solve this way too but the topic is change of base in logarithm and I have to strictly be on that line of change in base of logarithm. So it's best you follow instructions.
@sunkymathsclass2 күн бұрын
Where are you watching from??
@sunkymathsclass4 күн бұрын
Where are you watching from?? Drop a comment
@singyestudio6085 күн бұрын
Thanks for wonderful video. Even if your view count is low, please don't stop. You are doing important job enlightening so many people. Someday, your hard work will be rewarded. You got a new sub!
@sunkymathsclass3 күн бұрын
Thanks so much for the encouragement bro. I promise to keep to this and not to relent.
@singyestudio6083 күн бұрын
@@sunkymathsclassSure! This is be valuable be someone sooner or later. I really enjoyed your video. I am also struggling for support but I am not giving up.
@okemefulachidera54407 күн бұрын
Well done sir I love ur teachings
@sunkymathsclass7 күн бұрын
You are welcome, kindly follow for more!!
@sunkymathsclass9 күн бұрын
Where are you watching from???
@raiyanzaman632710 күн бұрын
Walaikum assalam
@sunkymathsclass12 күн бұрын
Where are you watching from??
@sunkymathsclass18 күн бұрын
Where are you watching from???
@MayankPatil-l9g19 күн бұрын
Thankyou sir ❤
@sunkymathsclass18 күн бұрын
Uwlc
@sunkymathsclass23 күн бұрын
Where are you watching from??
@sunkymathsclass23 күн бұрын
Where are you watching from??
@sunkymathsclassАй бұрын
Where are you watching from??
@MayankPatil-l9g19 күн бұрын
India
@sunkymathsclass7 күн бұрын
Good
@sunkymathsclassАй бұрын
Leave a comment
@sunkymathsclassАй бұрын
Where are you watching from?? kzbin.info/www/bejne/b4uoo6l7g7mSjq8si=xuNqvTh7vIjvoG3p
@sunkymathsclassАй бұрын
Where are you watching from??
@TDSONLINEMATHSАй бұрын
Keep it up bro❤❤
@sunkymathsclassАй бұрын
Thanks bro
@TDSONLINEMATHSАй бұрын
You can also say exponential equation
@sunkymathsclassАй бұрын
Yes of course
@PrithwirajSen-nj6qqАй бұрын
First problem (125)^(-2/3) *15 =( 5^3)^(-2/3) *5*3 =5^(-2+1)*3 = 5^(-1)*3 = 3/5 Student may like the soi below (125)^(-2/3)*15 = 15/[(125)^(2/3) =15/ [5^3*(2/3)] =15/5^2 = 15/25 = 3/5 =
@kvngrichieraznash719Ай бұрын
Great job sir...👌👌
@sunkymathsclassАй бұрын
Thanks man
@AbimbolaElizabeth-b3dАй бұрын
Tutor Ola ,great tutor
@sunkymathsclassАй бұрын
Thanks dear
@AbimbolaElizabeth-b3dАй бұрын
Tutor Ola ,great tutor
@AbimbolaElizabeth-b3dАй бұрын
Welldone sir
@sunkymathsclass21 күн бұрын
Thanks
@amucheugwuanyi42172 ай бұрын
God protection sir
@sunkymathsclass2 ай бұрын
Thank you ma
@öğrenci-l4k2 ай бұрын
perfect . greetings from Türkiye
@sunkymathsclass3 ай бұрын
Yeah for you to check if your answer is correct. Just replace both values of x and y in any of the two equation and it must result back to 5 for equation 1 and 8 for equation 2.
@olamilekanraphael35563 ай бұрын
Thanks teacher But need to check if the answer is not correct by checking the values of x and y
@ArjunSwami-pj2el5 ай бұрын
Hlo sir
@sunkymathsclass5 ай бұрын
Hello...
@sunkymathsclass5 ай бұрын
You can chat me up.... 07089742232
@AkandeOyindamola5 ай бұрын
Great 👌
@sunkymathsclass5 ай бұрын
Thanks dear
@firstborn90155 ай бұрын
Great job
@sunkymathsclass5 ай бұрын
Thanks bro
@sunkymathsclass5 ай бұрын
Pls comment if this video is clearer from your end or not
@SirShadowTv6 ай бұрын
Keep it up sir. Let's spread the knowledge🎉
@sunkymathsclass6 ай бұрын
Thank you sir
@BukenyaAlex-em6hs6 ай бұрын
How to draw an elipse
@sunkymathsclass6 ай бұрын
Follow me on this channel, as every topic in maths will be covered by God's grace.
@ByHisStripesWeAreHealed-bs2id6 ай бұрын
❤
@ByHisStripesWeAreHealed-bs2id6 ай бұрын
❤
@fidela4una6 ай бұрын
Nice
@sunkymathsclass6 ай бұрын
Thanks
@firstborn90156 ай бұрын
Great effort… more grace
@sunkymathsclass6 ай бұрын
Thank you
@emmanuelpraiseministrytv46426 ай бұрын
Nice lesson
@sunkymathsclass6 ай бұрын
Thanks for watching
@sunkymathsclass6 ай бұрын
Pls watch till end..
@sunkymathsclass6 ай бұрын
And like this video
@Stra4urx6 ай бұрын
Professor ola... Keep on the good work
@sunkymathsclass6 ай бұрын
Thank you, I will by God's grace and also help me keep the momentum by sharing my channel link for more subscribers