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@PRITAM-324shorts 9 күн бұрын

8....(d) answer

@JonaliRabha-t7d 12 күн бұрын

Sir amar gowalpara district r questions peper Kun district logt mil hoi plz Ripley koribo jururi hoi

@biranmandal5030 22 күн бұрын

Sir eman kio easy ahise aikhn paper..kintu amr Kamrup (R) bohut tan ahise science or paper😢😢.. matric or karne ami kenekoi pohrim 😢😢😢😢😢

@ranjusarmah9344 23 күн бұрын

Sir question number 29 is correct answer "D" Because alldihide suffix al =O

@RaiHanS2005 23 күн бұрын

Yes correct. Mur option tu tik korute mistake hoi gol same same j. Thank you

@DhrubojyotiBordoloi-q9y 23 күн бұрын

Sir dibrugarh dristic r question pepar 😢plz

@Nishitadas-g7r 23 күн бұрын

sir plz plz long bur u debo

@aboutcricket5274 23 күн бұрын

Why there is no question of 13rd chapter

@UtpalSmriti 23 күн бұрын

Thanks you so much for this helpful video ❤

@Ankitanath6831 23 күн бұрын

Thank you

@jubaidul_x_0_1 23 күн бұрын

Kamrup (R) or match or question kot?

@iam---mahmadulislam 23 күн бұрын

Thank you Kali amar Science or exam ase

@RaiHanS2005 25 күн бұрын

Bhul soborei hobo pare muru exam soli ase so tar pora time ulai soln upload korisu keitaman bhul huwar karone sorry hokoluke baki moiu manuh bhul hoboi pare. I hope you gyuz understand ❤

@RaiHanS2005 25 күн бұрын

Correction:- Q.25 Ans C Q.28 Ans D

@MDIMRANHUSSAIN-zm6rb 26 күн бұрын

24 and 25 c

@majiborali1678 26 күн бұрын

Question 39 answer option a. 3:06

@RaiHanS2005 25 күн бұрын

Bhalke sai luwa sun

@majiborali1678 26 күн бұрын

Question 28 answer option d 1:59

@majiborali1678 26 күн бұрын

24 carect answer option C 1:40

@ujawalmishra2730 26 күн бұрын

I think that 24and 25 no. will be option c

@kamalkattel7041 26 күн бұрын

6th ka v galat he k20 hota he 🤦🏻‍♀️

@Abhishek_edits-d8v 26 күн бұрын

When potassium metal combusts in air, it reacts with oxygen to form **potassium oxide**. The specific product depends on the conditions of the reaction: 1. **Main product**: Potassium reacts with oxygen to form **potassium superoxide (KO₂)** in excess oxygen: \[ \text{K (s) + O₂ (g) → KO₂ (s)} \] 2. **Alternative product**: In limited oxygen, potassium forms **potassium oxide (K₂O)** or **potassium peroxide (K₂O₂)**: - Formation of potassium oxide: \[ 4\text{K (s)} + \text{O₂ (g)} → 2\text{K₂O (s)} \] - Formation of potassium peroxide: \[ 2\text{K (s)} + \text{O₂ (g)} → \text{K₂O₂ (s)} \] Under normal combustion conditions in air, **potassium superoxide (KO₂)** is the most common product because potassium has a strong affinity for oxygen and readily forms superoxides.