Thank you, I was confused on what to do when there was a self biasing resistor.
@blackcohn2 ай бұрын
Is it not the capacitors treated as open circuit in small signal model?
@arashyusefi18895 ай бұрын
Thanks 😊👍🙏💯
@tiagofalcao81618 ай бұрын
Great video, cheers!
@AdamScheuring10 ай бұрын
Can you please edit this video. You made a mistake at 3:06.
@qemmm1111 ай бұрын
Much appreciated Sir 😊 MOSFET drain feedback bias One minute A: Id=k(vd-vt)^2 15-vd/15=0.25(vd-1.5)^2 Too lazy to solve the value of ax2+bx+c=0 vd gm=2k(vgs-vt)^2=2k*(id/k)^1/2=2*(k*id)^1/2 (Id/k)^1/2=vgs-vt B: vo=-u*vi*(rl'/ro+rl') vo/vi=41.2*(3.75/(68.75+3.75))=154.5/71.5=-21.6v/v C: Rin=rg/(1-A)=10/22.6=3.164M ohm Ro=ro//rd//RL//(rg/(1-1/av))=~
@Emma-dd1fc Жыл бұрын
What really is the Va? I dont see where that is or what it means 😢
@Emma-dd1fc Жыл бұрын
I think it's like lambda = 0.02?
@ManivannanS-u6u Жыл бұрын
inverse of lamda@@Emma-dd1fc
@ds4056 Жыл бұрын
@@Emma-dd1fc Va = 1/lambda
@phengyang2639 Жыл бұрын
Va is the Early voltage. Analyzing the ID and VDE characteristic graph, the point of intersection from all the relationship curves correspond to some Early trans-conductance which is ID/VA where VA is the value of VDE at the point of intersection.
@Emma-dd1fc Жыл бұрын
Wow! Thanks for this 🙏
@muhammadazeem502 Жыл бұрын
in the small signal model you are missing the Rs, you seem to directly connect the source to ground.
@Kevin-sl8bw Жыл бұрын
this is incredible video, hope you can make more video of solid state device.
@moody83112 жыл бұрын
Thank you, Finally clicked for me.
@giuseppecautero50572 жыл бұрын
I have only one comment on the beautiful presentation (thanks!): In the first few minutes the instructor begins by saying: when photons arrive then we measure a current. Is flawless. But then he tells me that positive charges move together with negative ones. But this does NOT generate current !!! I also have some questions: it is said that they move together. Good. Then we arrive at the result that the mobility is that of minority charges. Great, but mobility is a positive number. Then: what is the direction, particularly in the case I create positive and negative charges in an intrinsic semiconductor? (Where the concept of minority charges makes no sense). That is: does ambipolar transport only concern doped semiconductors in the presence of an external electric field?
@etiennejansenvanvuuren2 жыл бұрын
Good day sir, is there any chance you may have more videos on advanced electronics? This playlist really helped me during the first half of my semester.
@dongxiawei9442 жыл бұрын
The video is helpful
@philliphollingsworth66013 жыл бұрын
At the “3:06” mark into the video, should “j2” times “1/2” be “j” instead of “1”
@jCh20193 жыл бұрын
what a fantastic Video, thanks for this math explain ,really extremely helpful 🥰
@scriptkiddie74853 жыл бұрын
Loved the vid, super helpful
@adnanashraf90024 жыл бұрын
I like your channel please send me your watsapp number or group link.for help
@peterzhang21024 жыл бұрын
Fantastic video, thank you for the information!
@jigarfaria4 жыл бұрын
What will happen to the ambipolar mobility at high level injection? Since Δn=Δp, will it be zero? But how does this exaplin the carrier flow if the mobility is zero? PS: At 8:56 you didn't write the derivative on left side of the equation.