Greatest Video I've ever had the honor to lay my eyes upon. 🥲
@diamondfire2114 күн бұрын
I completely agree👍
@thomasseeley81242 ай бұрын
Carefull. This mixture should not be stored. Mix and use
@mustafosafarov92222 ай бұрын
Thank you very much for your teaching❤
@noodles70763 ай бұрын
Well I definitely bombed that question😅, that one was so tricky
@sadiewilke60793 ай бұрын
Guys, I am in college and I am watching this video at 12:45 a.m. to help me study. Mr. Ayton is the best. Like and subscribe
@theshadowking_59813 ай бұрын
1d is so ambiguous man like I put increasing, but the argument for decreasing makes sense too such as comparing the first derivative with the second
@ambareeshbudaraju46843 ай бұрын
who is here before tomorrow LOL
@cjaden3 ай бұрын
fr
@iamdyslexic35403 ай бұрын
Do you want to mention like a value like 50% distilled water or it is just mentioning adding some Di h2o for the second step
@Maria-mh1jp3 ай бұрын
Would 3900 instead of 3940 be accepted ? Thank you
@Maria-mh1jp3 ай бұрын
Hi, would you know whether the point is given for a correct (demonstrated) approach but incorrect answer ? I’m scared I lost a lot of points because of typing mistakes in a rush (eg. I typed for example 0.0144 instead of 0.0114 into my calculator for one of them) 😖
@brodysigler81933 ай бұрын
GOAT teacher !
@jamsstats17003 ай бұрын
Would it be fine to use electronegativity on bii? It implies that the n state is lower
@MrAyton123 ай бұрын
No electronegativity for bii. Sorry.
@suryakridhey14753 ай бұрын
For the one about atomic structure, i just said that there are more valence electron shells so there would be a larger radius. Would i get the point
@MrAyton123 ай бұрын
I think you will get a point there!
@_hydrxngea_55563 ай бұрын
yep, i messed up
@melloby_by3 ай бұрын
I just got HUMBLED
@JP-np8fj3 ай бұрын
@Mr. Ayton How close do numbers have to be? If I show my work and make a dumb mistake(use the wrong number) can you still earn points? Thank you!
@MrAyton123 ай бұрын
It really depends on what type of problem.
@JP-np8fj3 ай бұрын
@@MrAyton12 how would it differ? I'm referring to the 54 Kj problem
@haydenb89883 ай бұрын
i didn’t have any of these questions on my frqs? did i have a different form than these frqs?
@melloby_by3 ай бұрын
Did you have form O? Did you take the test in the US or internationally?
@haydenb89883 ай бұрын
@@melloby_by not sure which form i had, i took the test in the us
@bozowald4383 ай бұрын
I flipped the top equation but I had everything right just backwards 😔😔
@MrAyton123 ай бұрын
This will be a tough one to grade for students that did that. Unfortunately, I don't think that they will award any consistency points for part (d).
@aryanvenishetty183 ай бұрын
For part d, aren't solids and liquids excluded from the net ionic equation?
@xiaomi60353 ай бұрын
no
@Elijah-um8ve3 ай бұрын
You’re thinking about Kc (equilibrium) in which you would exclude all solids and liquids from the calculation. Net ionic gets rid of spectator ions and emphasizes compounds that are active during the reaction. You basically split apart aqueous things and cross out ions which are on both sides of the chemical equation.
@MrAyton123 ай бұрын
Sorry, no. Those substances are changing charges and therefore need to be in the net ionic.
@hoopiskey36613 ай бұрын
I said around 4.0 for pka of lactic acid, will I get it correct?
@MrAyton123 ай бұрын
I think you will be totally fine for that. Just having 4 is no good but having two sig figs on this is vital.
@cj.56323 ай бұрын
@@MrAyton12if this isn’t the sig fig point then will saying “4” Be okay? Also considering the titration curve has pH plotted as whole numbers
@rohilpat3 ай бұрын
did we have to explain anything when it said hypothesize
@MrAyton123 ай бұрын
You do not have to justify your hypothesized experiment.
@cryptidprince6663 ай бұрын
For part e I put 2688 J (forgot sig figs) and calculated -53.76 for ii), will I lose both of those points?
@MrAyton123 ай бұрын
I think you may be ok, but I'm not totally sure. It is all whether this is the sig figs problem they decide to be sticklers about. I honestly think you will be alright.
@rohilpat3 ай бұрын
part f and g only two sig figs no?
@MrAyton123 ай бұрын
You will be fine with 2 or 3 since there are no measured values. It is confusing since the Ka is report with 2 and the pH in (g) has 3.
@jussin683 ай бұрын
Would it be enough to say that for part d, more gas particles would be produced over the course of the reaction or would I need to explain further why those particles increase the entropy? Also, would it be okay if in part e I explained that since H is positive it can be greater than (T x S), making G positive, without mentioning the temperatures that would make G positive?
@MrAyton123 ай бұрын
For part (d), it will be worth one total point. If you did not discuss the particles, then you would not get that point. You have to state about the dispersion of particles or number of arrangements increasing. For part (e), you have to refute the student's claim about all temperatures somehow. I think the way you explained it above would get you that point since you stated that the enthalpy could make the overall G positive.
@kiminokao31523 ай бұрын
for the net ionic equation, what If I only labeled the solids for states of matter and didn't label any of the aqueous and liquids? would the entire thing be wrong?
@mayanktiku99003 ай бұрын
states don't rlly matter. im pretty sure in scoring guides like it always says states not req
@MrAyton123 ай бұрын
You do not need to label states of matter, just atoms and charges balanced.
@sikegirls3 ай бұрын
For c, would we add the masses of the water and the metal cube for q=mCAT?
@rivka0073 ай бұрын
Unfortunately, no :(. The q gained by the water is equal to the q lost by the metal cube. It is asking us to solve specific heat capacity of the metal cube, so you have to use the mass of the metal cube only, which is 98.1 g.
@MrAyton123 ай бұрын
Sorry, no for that one. They gave you the heat transferred and were specifically looking for the metal.
@thinkinghashim3 ай бұрын
Is there only one possible answer for the second question?
@MrAyton123 ай бұрын
Those are the general answers that would need to be present to get two points overall for (b)
@Maria-mh1jp3 ай бұрын
Hi - Would you get the point if you drew the arrows with greater magnitude but in the same direction as the initial picture ? Thanks
@alexanderengelhaupt72013 ай бұрын
I think yes
@MrAyton123 ай бұрын
Totally good - they are simply looking for (on average) longer arrows.
@sikegirls3 ай бұрын
Quick question, for part g, if you stated that the ratios of the conjugate base/ acid was 15:2 or 15/2, would that be correct, although unsimplified?
@MrAyton123 ай бұрын
I think the scorers would love that answer. It is the ratio - whether simplified to 8.5 to 1 or 15:2. Love it!
@JamesRios-cd2ir3 ай бұрын
Wait is number one not gas so it would be parenthesis not brackets
@MrAyton123 ай бұрын
No Kp, it was a Kc expression. Brackets for molarity.
@Maria-mh1jp3 ай бұрын
For the pH question, is the mark on the graph awarded regardless of your following explanation ? Also, if I based my answer off the ratio and that it will appear at 1/3rd of the volume to the equivalence point (similar to how 1/2 of the acid is neutralized at 1/2 the volume of the titration point “the half equivalence point”) - would this be accepted / is it correct judgement? Thank you
@MrAyton123 ай бұрын
Yes, you would get one point for the mark on the graph (probably being before 1/2 way to the equivalence point). For the second point, you will simply have to compare the ratio of conjugate base to weak acid. Stating that there are more moles of acid and therefore the pH < pKa will get you that second point.
@HaydenSoule3 ай бұрын
Is it possible to get the point on d ii by identifying one correct answer(adding more H2 or I2), but also saying one wrong answer (increasing the temperature)?
@MrAyton123 ай бұрын
Boy that is a tough one. They may give you a point for the adding of H2 or I2, which would result in more moles of HI
@clix63563 ай бұрын
For part b, i put the right answer, but i was thinking during the test (and still am), i remembered i heard something about how u need to standardize NaOH rather than weighting a mass and putting it into a solution because it is hydroscopic as it would give an artificially high molarity value than actual, is that true in this case, or is there an exception im missing.
@MrAyton123 ай бұрын
NaOH is hydroscopic but that is over time from the water in the air. They are assuming anhydrous NaOH here.
@kazehh68663 ай бұрын
I have a question, for the X on titration curve. What if you put above it ?
@MrAyton123 ай бұрын
Sorry, if the X was at a pH and volume greater than the pKa, that would be incorrect.
@kavin43883 ай бұрын
Did you have to say the retention factor for the last part (is that the key word they were looking for)? I said that the solvent will move about half the way up in that half the time, meaning the distance between X and Y will roughly halve.
@MrAyton123 ай бұрын
You will be good with that explanation!
@phalanx85973 ай бұрын
Hi, what if I put 9:1 for the ratio instead of 8.5:1. I rounded to 9:1 but since it’s one sig fig off would they accept ( I showed the correct work).
@MrAyton123 ай бұрын
I think they will give a little bit of wiggle room on this one. I think you may be good with 9:1 ratio
@Noooooooooooooooooooooo03 ай бұрын
Did you need to say use the pipet to fill to 100.00ml cuz I just said add water until it reads 100.00ml 😂
@humandavey3 ай бұрын
same
@MrAyton123 ай бұрын
I honestly think you will be fine.
@Noooooooooooooooooooooo03 ай бұрын
Did we need to talk about hybridization for why the angles were different or could you say that the lone electron repels the oxygens, giving it a bent shape whereas the cation is linear and therefore 180
@vinnygoatt3 ай бұрын
that’s what i said, i didn’t mention any angles or shapes. i just mentioned the fact that the lone electron pushes against the other parts
@MrAyton123 ай бұрын
You will be totally cool with that explanation. As long as you specify one reason for the difference in bond angles, you are great!
@MrAyton123 ай бұрын
@@vinnygoatt Perfect!
@man743_plays_da_games93 ай бұрын
I did 2688 instead of 2690 am I fine
@rileycain65893 ай бұрын
I think it should have two sig figs, based on the specific heat (4.2)
@JungGeumbi3 ай бұрын
@@rileycain6589that is what I’m sayin’
@MrAyton123 ай бұрын
I think you will be fine on this problem. I don't think this will be the sig fig stickler problem.
@MrAyton123 ай бұрын
@@rileycain6589 The specific heat is not a measured number, all the measurements are three sig figs, so you want to round to 3. You will be fine with rounding to 2 on this problem though.
@rileycain65893 ай бұрын
@@MrAyton12 ok, thank you for clearing that up
@Noooooooooooooooooooooo03 ай бұрын
By the way thank you for making these 👍
@man743_plays_da_games93 ай бұрын
I had 38.5 but changed it to 38.49 is that still fine??
@pianopanda90573 ай бұрын
Probably not given that was more than likely the question where they were testing sig figs, meaning you had to have an estimation in the tenth place, so going out the hundredths will probably lose you the point. But if it wasn’t the sig fig question your probably fine but in past years questions like that where they have you read an instrument they expect you to and only to estimate past one sig fig from the precision of the instrument.
@MrAyton123 ай бұрын
You won't get that point. You need only one estimated digit.
@Noooooooooooooooooooooo03 ай бұрын
Do you think I would have needed to explain my answer for why decreasing heat would result in more moles of HI? I just wrote “decrease temp of reaction vessel”
@Noooooooooooooooooooooo03 ай бұрын
The question just says to “hypothesize an experimental procedure” but college board is sometimes picky so idk let me know what you think
@MrAyton123 ай бұрын
You will be good. They just asked you to hypothesize an experiment, not justify that hypothesis.
@clix63563 ай бұрын
How many frqs can you mess up and still be in a guaranteed 5 range if someone where to get at least a 45/50 on the mcq (so far from watching all the parts of your videos i got at least 4 points off on the frq)
@_rosiexmilks_96893 ай бұрын
4 points off is super good, pretty sure you can like get a 30/60 on mcq and still pass with a 5
@fatcatz4053 ай бұрын
did you need calculations to justify for c or could you just talk about the data
@MrAyton123 ай бұрын
You will need some calculation to support your explanation.
@_rosiexmilks_96893 ай бұрын
If I said bond angle is around 120 (bc bent, i didnt realize it was more than 120) but i also metioned other one was 180 and linear, does that still count?
@MrAyton123 ай бұрын
You will be totally fine. Just specifying bent/linear or hybridization or lone electron/no unshared pairs on central atoms will get you that point.
@jasperdavdson3 ай бұрын
If I just said for the last part that the distance would be lesser between the two because compound Y was moving faster and had less time to widen the gap between it and Compound X and I screwed for that point.
@rileycain65893 ай бұрын
Omg I said that too, I really hope the reader likes that response. Hopefully just mentioning the rates they are moving at is enough
@MrAyton123 ай бұрын
You will be good with that! You are explaning the migration of the two compounds.
@thereliable1david3 ай бұрын
Hello there Mr. Ayton, thanks for the videos. If I said the pKa was 3.9 in part c, would that be acceptable? Then, if I used 3.9 for the Henderson Hasselbalch equation in part d and got a pH of 3.6 instead of 3.5 and put the X at right around 6mL of base added, would I lose any points? Appreciate it!
@vphoenix1963 ай бұрын
You wouldn’t lose any points as the calculation has to be within +/- 0.1. Then, using 3.9 for the equation would count as a consistent calculation based off your previous answer. Hope this helps!
@thereliable1david3 ай бұрын
Yes it does, thanks. I’m just wondering if putting the point at 6ml of base added is too far away from the actual point. Like even if I used pH 3.6, I think I was looking at it wrong, and it crosses 3.6 at around 5mL of base added. So would this lose me any points? Just the distance from the point they might be looking for? Thanks
@MrAyton123 ай бұрын
That is totally cool. All you need is 3.# with that number being an estimated digit. Therefore 3.8, 3.7, 3.9 - these would all work. Some students were saying their teachers were saying 4 would work...that would not. And since you were consistent, no lost points - all points awarded to you! Great job!
@thedarklord8293 ай бұрын
for ii, i said decrease temperature by cooling it down will shift rigth and produce more hI. will that work?
@MrAyton123 ай бұрын
Beautiful!
@ArkCordova213 ай бұрын
Would a catalyst work for ii?
@theshadowking_59813 ай бұрын
now im thinking about it prolly not cause it just speeds up the reaction
@MrAyton123 ай бұрын
Sorry, no. A catalyst speeds up the forward and the reverse reactions.
@yushisetlur63183 ай бұрын
For part C, I was able to interpret using the data which one was the limiting reactant and explained, but did not calculate anything. Do you think that will be fine?
@rohilpat3 ай бұрын
yeah thats what i did. i just proposed the idea that increasing the mass of sodium bicarbonate would have no effect on the moles of carbon dioxide produced if the other thing were the limiting reactant.
@MrAyton123 ай бұрын
You would need some kind of calculation in order to justify the answer.