AKA…Bernoulli’s Principal

Pls which textbook do you use for this

This is a very limited (only one) example of the many ways that siphons can be/are used: partial/inverted/self-starting/capillary/bubbling/barometer/... PS: 'vacuum' is nearly possible above about 32' (a function of barometric/atmospheric pressure), near which the water near the apex will be boiling and the column will collapse.

I got drunk asf and had to know this thanks for the video

Actually Cohesive force also comes into action, as this air pressure theory is already debunked.

What happens when the lengths of pipe boths before and after the bend vary?

just amazing

Fab explanation, thanks :)

Make this experiment with very fine particle inkjet printer or in fair of science find dye that is exactly in size or water molecule and is not transparent, yes such particle don't exist but that is point of scientist Brownian motion 10^14 hz collisions observed pollen particles of flowers jiggles 1000 smaller paint (dye) particles of potassium permanganate jiggles faster mixing of layers is much faster, no stratification of layers of laminar flow exist. 1:40 Your camera showing only 1/3 length of total pipe but even here you see that already intensity of dye are mixing, no even flow layers stratification. Not forget fact that water molecules compare to dye particles are 10000 times smaller, inject printer dye have smallest particle compare to water 1000 times bigger than individual water molecule. Take very long pipe and use see than no laminar flow exist. What you can see that Brownian mixing follows sinusoidal pattern Kármán vortex street. Of course which is behaviors of Brownian motion of mixing not flow regime of laminar or turbulent. Reject Brownian motion of molecules is rejecting all atomist model of matter, according to Reynolds flow is perfect layers of continuous flow that sometimes moves in vortices and eddies if flow is high (turbulent). And we stuck with this interpretation to this day.

First for laminar flow which is parabolic continuity rule of flow rate cannot be applied in parabolic laminar flow maximum velocity is in center and zero at surface of channel. That is first indicator laminar and turbulent is invalid definition together with Re number. Second perform experiment in transparent tube with potassium permanganate which dissolves in water and with inject printer ink which very fine particles, but still are 100 times bigger than water molecules but you see that at Re<2000 paint mixes perfectly because of Brownian motion in liquid 10^14 Hz collision rate of molecules no such thing as laminar flow. To solve velocity loss deltaw need initial maximum flow w0 and geometrical parameters of channel (pipe) (L, d, epsilon). reason why Regula heat exchangers is 30% less efficient and uses 2 times more metal is because Reynolds and Prandtl, Nusselt numbers who are nonsense, why exploit inanimate devices if workers can work for free and exploit humans is better choice.

What are the dimensions of your flume? And that is 10mm acrylic? Correct.

I am here because the brief explanation of "how a bore evacuator works" just doesn't cut it for me.

how do we open the fuel tank of car with out vehicle key or without destroying the opening?

Great video, I'm building a financial model template for a hydro power dam and this was the first piece of content on the entire internet that made sense. I was able to use the calcs and it makes sense! Thanks.

Nice one Practically,is 'n' and 's' will be given If not,what are conditions or code to get those values if not given Or are they constant values

Past three immediately when I went to you-tube I understand everything ❤ so thank

Can tell you me more about manometer

Thanks you for your explanation sir

Explain everything throughly sir as i cant understand... Plz give a reason for everything u write and give a good reason.. Also this part 4:05 remake da video 4:28 here too pi... Unable to understand... Understood very little😢😢😢😢😢 4:53

0.00255m2 (at 9.49mins) is 0.00255 square metres. IT IS NOT, AS YOU SAY 0.00255 METRES SQUARED! GRRRRRR.....

You say metres cubed when you mean cubic metres! 8m3, for instance, is 8 cubic metres. 8 metres cubed is 8x8x8 which is 512 cubic metres - bit of a difference!!

Saving my neck the day before the exam. Very straightforward and clear. Bless you

Nice explanation! One very minor point: the letter h is pronounced aitch- it doesn’t actually have an h at the start of itself.

My guy never disappointed when come to his fields of expertise. Thank you once again and Keep it up, I'm the biggest consumer of your materials.

Thanks ❤

The best fluid mechanics videos I’ve ever seen and I’ve seen a lot haha.

excellent video! life saver

Thanks helpfull

Another fantastic example. Love it.

I don't khow well I can appreciate the works you put in delivering astonishing concepts behind pump'head. A topic that was vaguely covered and hard to grasped during my 2nd year at University. Once, I greatly appreciated your input and dedication to the subject itself.

Dude thanks but I'm confused of the 2 you divided in area.

Remember democrats were historically the most racist & notably supported the Klans. They’re also the ones who call everyone against them fascist and justify any wrong doing towards said person, ironically.

👍nice

I was wondering about what is the pressure at end B based on a requirement that the flow velocity through the pipe is 1m/s and flow rate is 100l/s. Say there is no requirement for delivery pressure at B, length of pipe is L metres, B is higher than A in height. By using bernoulli's theorem, pressure/head required to pump water from A to be B will be = Head loss due to friction + Potential head due to height difference between A and B. Does this mean that water pressure at point B will be zero? appreciate an answer. thank you!

Math makes me feel dumb.

Thanks for this video! I just wanted to clarify something. I tried applying the formula where you simply do 1/3 or 2/3 times the length of the gate to find the location of the equivilent point load of the triangular load from the water but it is not giving me 2.643m like you got using L'=I/AL + L... Like 0.75/3 is not equal to 3-2.643 if that makes sense. I realize this is because the formula I used doesn't account for the fact that there is water above the height of the gate and the distance between the height of the water and centroid of the gate is important but is there a way to use my method to solve this problem (i.e., maybe doing a weighted average of the location of the point load based on the height of water and the location of the point load based on the height of the gate)?

Thanks alot very beneficial explanation 🙏it helps !

If the pipe was not open to the environment, say it was a closed pipe, would we still be able to apply Bernoulli's equation to solve for pressure at Point 2. With point 1 still being at the top of the reservoir and a given flowrate

so tedious, so stupid, waste of time

Isn’t the pressure at the bottom of the tank much higher than the pressure at the top of the tank? I would assume the pressure would not depend on the hight of the tank but rather just the hight until where the tube is inside the tank

I didn't understand the total force is the pressure time the perpendicular area which is 10.6*1...sin45 nahnah

Say flow (Q) knows is 100 lit/sec.

If flow (Q) is given or known what is the formula to calculate cross sectional area for a concrete channel. Kindly answer. Thank you.

really helpful

Thank you for your simplified explanation. I have a question: How did you calculate the volume for the tank under your flume based on what is coming in (flume outlet) and what goes out?

0.044 what is this i mean is this answer in bars or in which unit? or if the answer is in meters then kindly can you clear that what is 0.044 ?

Thanks mate. Great video.

Isn't N/m square Pascals

❤❤❤

Im happy to be confident after your video clips lectures