So then why does the copper disc still generate current when the magnet is not stationary, but is attached to it and rotates at the same speed as it does?
@erinwallborg229026 күн бұрын
Can this help calculating the resonance peaks in for example - In Ear Earphones? As the ear canal is a form of a tube, can I predict the interactions of waves frequency-wise?
@ForestLearn23 күн бұрын
Interesting question! Yes, I think so - it'd be a nice exercise to calculate the harmonic (resonant) frequencies of an ear canal and to compare that with the resonance peaks.
@tessney-filomeno1378Ай бұрын
Thank you so much! these are definitely my top mistakes!
@ForestLearnАй бұрын
Glad the vid helped - fingers crossed those mistakes are a thing of the past now :)
@overunityinventorАй бұрын
when u raise a magnet weighing 100 grams upto a hieght of 100 meters, u put 100 joules of energy into it, when u drop that 100 grams magnet through the coil, the magnet fall takes 2 seconds and the coil generates 50 joules of energy. is there a way to generate more energy from the falling magnet of same weight from same hieght? yes, just increase the winding on the coil, now the coil has 4 times winding than it was before, now raising the magnet to same hieght takes the same amount of energy (=100 joules), but dropping the same magnet through the coil of bigger winding now generates more energy, and the fall of magnet takes more time (let's say 8 seconds) because of more back emf because of more current in coil. can you make and show graph and calculations of this situation please?
@LuckyDiesАй бұрын
thanks bro
@ForestLearnАй бұрын
:)
@niccybeth5722 ай бұрын
Extremely helpful! Thank you very much for this video.
@ForestLearn2 ай бұрын
You're welcome, glad you found it useful :)
@cameronchambers29072 ай бұрын
The magnetic force on the sector that is resisting the change in direction , is this where and why there is back emf on motors ?
@ForestLearn2 ай бұрын
Hi, great observation! The cutting of field lines gives rise to a magnetic force which is responsible for the induced emf + current in the Faraday dynamo. In a motor, again, the cutting of field lines gives rise to a magnetic force. But this force now opposes the motion of the electrons i.e. reduces the current; remember the current is present in the first place due to an applied/external emf across the motor. Thus, the overall emf is reduced by an amount known as the 'back emf' (the word 'back' implying opposition/reduction). [Note: the back emf is usually referred to as an induced emf, but I'm not sure that's helpful terminology.] Anyway, hope the above made some sense, hope to do a vid on back emf one of these days. In the meantime let me know if you have any further questions!
@mrpicky18682 ай бұрын
wrong. forget the magnetic lines as they dont exist. it's all about dynamic induction. so you can get currrent from this even if both disc and magnet stationary and outside contact stays at same distance from center. kzbin.info/www/bejne/nZXYiqKKbtiAl6csi=0WdL6ZkCtSz2XE2X
@drudayanelumdeniyambbsdchm98522 ай бұрын
This is absolutely incredible simplification of physics. Thanks
@ForestLearn2 ай бұрын
Thanks for your kind words!
@erica_99ig2 ай бұрын
i am really grateful..been trying to understand this since 4 days but couldnt get it..this made me understand within minutes. thank you so much!!the visual representation really helped!
@ForestLearn2 ай бұрын
You're welcome, really glad to hear that it helped :)
@helloHELLO-xc1bg3 ай бұрын
Sir, I really appreciate your video. It rescued me from the deep struggle of not understanding what physics is talking about. I wish you to have a wonderful day!
@ForestLearn3 ай бұрын
Very happy to hear that! Your comment made my day :)
@alanx41213 ай бұрын
is there a current density distribution considering that the speed of the charge from inside to outside radius increases?
@ForestLearn2 ай бұрын
Hi, thanks for your question and apologies for the late reply! Yes - you're correct :)
@jayantachoudhury43973 ай бұрын
I'm going to university of Leeds on this September as an undergrad in theoretical physics.
@ForestLearn3 ай бұрын
Congratulations! You'll no doubt bump into Jiannis there :)
@jayantachoudhury43973 ай бұрын
@@ForestLearn I'm eager to meet him 🤩
@ForestLearn3 ай бұрын
@@jayantachoudhury4397 Of course :) Mention this interview to him when you do!
@jayantachoudhury43973 ай бұрын
@@ForestLearn I'll for sure!
@ForestLearn3 ай бұрын
@@jayantachoudhury4397 :) Hope you have a great time there!
@Geri_crs4 ай бұрын
What would happen if you use a YBCO disc at 65°K ?
@Geri_crs4 ай бұрын
*with-rotation axile inline crystal structure
@cantis31564 ай бұрын
thank you so much bro these videos have been a massive help.
@ForestLearn4 ай бұрын
My pleasure, really glad to hear that :)
@abhayganti86625 ай бұрын
amazing video and thanks! How can i work out the results if I connect the falling bar magnet through a spring so it falls and rises continuously?
@ForestLearn5 ай бұрын
Glad it was helpful! Sounds like an interesting investigation - do the experiment and then try to explain the results using your theoretical understanding :)
@mharsha35165 ай бұрын
thankyou, was very clear with the simulation and helped me understanding of the stationary waves.
@ForestLearn5 ай бұрын
You're welcome :)
@ramens5 ай бұрын
thanks
@ForestLearn5 ай бұрын
My pleasure :)
@444unknownuser5 ай бұрын
youre acc the best
@ForestLearn5 ай бұрын
You're way too kind :)
@ri0jeroen5 ай бұрын
Thanks for the video! I have one question: When exactly do the peaks happen? Is it when the middle of the magnet enters the coil, when the bottom of the magnet enters the coil or something else entirely?
@ForestLearn5 ай бұрын
Thanks for watching :) The peak and trough occur when the magnet is fairly close to the coil, but not inside the coil (see the magnet positions at 3:00 in the vid, for example). At these positions, the rate of change of flux linkage is greatest, corresponding to max values of induced emf. As I discuss for the second question in the vid, when the middle of the magnet passes through the coil, the induced emf vanishes for an instant. Hope this helps - let me know if you have any further questions.
@b_dog_piano6 ай бұрын
Cheers boss, watching this in my physics class rn bro! :) Very helpful and my teacher said you're the best physics youtuber out there. I have a question, why does the bar magnet repel, and is lenzs law similar to lechatliers principle in chemistry?
@ForestLearn6 ай бұрын
Thanks for watching and both your teacher's and your own awfully kind comments :) Regarding your question about repulsion, if you revisit the video between 1:00 - 2:00 this should provide the answers - let me know if not though, I'll be happy to address any specific issues. That's a v. interesting observation re the similarity of Lenz's law and Le Chatelier's principle! It seems that at a very high/general level they both involve systems the respond to counteract a change/disturbance to preserve the status quo (to keep things as they were). But one is a consequence of an equation of electromagnetism while the other is to do with chemical thermodynamics, so I'm not aware of there being any deeper connection between the two. Hope that helps!
@ibrahimfaisal12926 ай бұрын
Amazing video! Answered every question that i was unsure of!
@ForestLearn6 ай бұрын
Thanks, great to hear that :)
@tahabashir94056 ай бұрын
damn the british. They ruled us till 1947, take valuable foreign exchange amouting to Rs 42 billion (120052506 pound sterling) every year for the CIE exams, and even their explanations are better.
@ForestLearn6 ай бұрын
:|
@d_i_a_v_l_o38276 ай бұрын
saving my a levels fr durham here we come 🔥🔥🔥
@ForestLearn6 ай бұрын
Good luck - you can do it!
@charliecooper74585 ай бұрын
Im going durham too, DURHAM HERE WE COME
@ForestLearn5 ай бұрын
@@charliecooper7458 Is the Durham physics dept ready for this many people with such a firm grasp of induction? 😂
@frosty25356 ай бұрын
i rarely leave comments but i wanted to let you know how good these videos are. i never got induction (even after hours of trying to get it). now i actually get what's going on. massive thanks
@ForestLearn6 ай бұрын
Well done for taking the time/effort to watch the vids to improve your understanding, and thank you for your incredibly kind comment! It means a great deal to me :)
@phoebeli49996 ай бұрын
Thanks for separating the induction into three types! That is really helpful for understanding.☺️ btw is that means the hall voltage is actually an induced voltage of type I(the ‘cutting field lines’)?
@ForestLearn6 ай бұрын
My pleasure :) The Hall effect/voltage appears similar to type I induced emfs (both involve the magnetic or Lorentz force for their explanation), but try not to mix them up. In the Hall effect, the conductor is stationary and doesn't 'cut field lines' - we don't refer to the Hall voltage as an induced emf. Induced emfs are reserved for induction phenomena. Hope this helps!
@m10620026 ай бұрын
brilliant explanation for all videos of the sereis
@ForestLearn6 ай бұрын
Thanks so much for your kind comment, I'm glad they've been helpful to you :)
@sirlimonada26 ай бұрын
is there any function that fits the curve and brings any data about the magnetic field passing through?
@ForestLearn6 ай бұрын
Thanks for your question! I'm unaware of a function that fits the curve - in principle, you could simulate what's going on here computationally (i.e. code the equations of motion etc) and arrive at the induced emf graph. You could then numerically (computationally) integrate the induced emf with respect to time to arrive at how the flux linkage changes with time. Hope this helps!
@sirlimonada26 ай бұрын
@@ForestLearn Thanks, luckily someone already did the math in physics forum, if anyone needs it , tittle of the post is "how to model a magnet falling through solenoid"
@ForestLearn6 ай бұрын
@@sirlimonada2 Many thanks for sharing this!
@francoismukagaga6 ай бұрын
Hmmm, in a previous comment i mentioned" comments" when i ment " links " ! But don't bother, eventualy i'll find a way when necesary 🙂. Still, great video's & animations which i will relook and relook till i understand the fysics and the equations behind it...imbed in my brain 🤔🙂👍☘️14/4/24 FM
@ForestLearn6 ай бұрын
Many thanks :)
@francoismukagaga6 ай бұрын
Because of the publicity underneath your video's it's imposible the see the comments, grrr! Great job! Great animations ! Thank you for sharing !👍🍀🍀14/4/24 FM👋
@ForestLearn6 ай бұрын
You're most welcome, thanks for watching!
@emmayang-qq2ji6 ай бұрын
what's the app that products the two waves?
@ForestLearn6 ай бұрын
phet.colorado.edu/en/simulations/wave-on-a-string
@commenter38406 ай бұрын
THANK YOU, your way of explaining things is 10/10
@ForestLearn6 ай бұрын
Thank you for watching and your very kind comment :)
@sadkayyy7 ай бұрын
Since the applied and magnetic force act in opposite directions and have the same magnitude, does this imply it is impossible to accelerate a conductor (in a closed circuit) when it is cutting across magnetic field lines?
@ForestLearn7 ай бұрын
No - one only needs to increase the applied force, which will lead to a resultant upward force and thus an acceleration. This will not exist indefinitely - a higher speed will lead to a greater induced emf (Faraday's law) and greater induced current, which will result in an increased downward magnetic force which will counter-balance the applied force. Hope this helps!
@sadkayyy7 ай бұрын
I've read that when the electrons in the wire accumlulate as shown in 2:50, they form an electric field which eventually becomes large enough to provide an electric force that balances the magnetic force, causing the electrons to stop moving, which in turn forms a potential difference. Apparently, by using magnetic force = electric force, magnetic force = BQv and electric force = QE = QV/d, the equation in 4:23 can be derived. What does this electric field look like, and how does it provide an electric force that acts opposite to the magnetic force? Also, is all of this just a really roundabout way of phrasing what you've mentioned in 2:50?
@ForestLearn7 ай бұрын
Thanks for your question! The derivation you mention is covered by me in this vid (and addresses your queries): kzbin.info/www/bejne/bn3Fh3ltnbh2jck Hopefully, this should clear things up - if not, let me know and I'll be happy to help :)
@yusraawan80147 ай бұрын
hello, was just watching the magnetic fields videos and I can't seem to find the vids on the type 3 scenario, only type 1 and 2, also do you have a video on RMS? I find it super confusing, thank you!!
@ForestLearn7 ай бұрын
Thanks for watching and your comment! Hope to have a type 3 vid up shortly and will try to get round to RMS asap :)
@ForestLearn7 ай бұрын
@yusraawan8014 Type 3 video is up now: kzbin.info/www/bejne/nXSnkmalo9B0bbc Hope it's useful!
@shubhamjoshi96247 ай бұрын
Very good video
@ForestLearn7 ай бұрын
Many thanks :)
@imran49357 ай бұрын
You're amazing. That was a wonderful video. I've learned more in these 14 minutes than I did in my university lectures. Thanks a lot.
@ForestLearn7 ай бұрын
That's awfully kind of you, glad it helped :)
@ForestLearn7 ай бұрын
Answer to question posed at 8:59 (please try to figure it out yourself before taking a look!): To understand why the current alternates viewed through the lens of Lenz's law (!), it's helpful to recall the informal version of the law (for changes in flux) discussed in this vid [ kzbin.info/www/bejne/r2PGZGmNbrabsKc ]: 'The coil/loop tries to *oppose* any *changes* in magnetic flux (linkage).' As the north pole of the rotating magnet approaches the coil, the coil tries to oppose the changing flux linkage by developing a magnetic North pole on the left side - this thus repels the rotating magnet. Viewing the coil 'head on' from the left, the conventional current would be flowing aNti-clockwise [see this for further clarification: kzbin.info/www/bejne/qJe7emumdriYqKc ]. As the north pole of the rotating magnet moves away from the coil, the coil tries to oppose the changing flux linkage by developing a magnetic South pole on the left side - this thus attracts the rotating magnet. Viewing the coil 'head on' from the left, the conventional current would be flowing clockwiSe. And so on.
@StudywithmeinPakistan7 ай бұрын
Good explaination . I explained these topics in Urdu few days back. Which is mostly spoken in Pakistan(Asia).
@ForestLearn7 ай бұрын
Thanks, that's great to hear! I am aware that Urdu is spoken in Pakistan :)
@StudywithmeinPakistan7 ай бұрын
@@ForestLearn Thanks. 👍
@pratichidas15798 ай бұрын
Thank you!The animation helped a lot😊
@ForestLearn8 ай бұрын
:)
@pratichidas15798 ай бұрын
Thank you!The animation helped a lot😊
@ForestLearn8 ай бұрын
:)
@BradleyPeacock-or8lr8 ай бұрын
Heres a derivation of the formula at 8:00 : Velocity varies with radius (v=ωr) so we consider de and dr instead of e and l in the original formula (e =Blv). de= vBdr, de = ωrBdr, de/dr = ωrB. Integrate this with limits 0 and R to get e = (ωBR^2)/2.
@ForestLearn8 ай бұрын
Exactly, thanks for sharing this!
@زينالعابدينماجدمحمد8 ай бұрын
❤❤❤❤❤
@ForestLearn8 ай бұрын
:)
@h7opolo8 ай бұрын
your mouth noises fail to qualify as spoken English. Trying to learn while deciphering your thick accent is too cumbersome a chore at this early morning hour.
@JudeWeraduwage9 ай бұрын
A very nice video, though I wish I knew why the "misconceptions" were wrong...
@ForestLearn8 ай бұрын
Thanks for watching and the kind words :) If you've met circular motion, you can check out the following vid which deals with some of the misconceptions I raised: kzbin.info/www/bejne/jXnImoB4Ytxjprc . Otherwise, let me know what you're struggling to understand in particular and I'll be happy to help.
@JudeWeraduwage8 ай бұрын
@@ForestLearn Wow, thank you for making & sharing that video, it really helped a lot!! Really love all of your stuff, keep up the great work!!!
@ForestLearn8 ай бұрын
@@JudeWeraduwage My pleasure, really glad to hear that!