Basics of Waves | A-level Physics
19:14
Forces in Mechanics - A-level Physics
11:10
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@austinahne3754
@austinahne3754 6 күн бұрын
great stuff, you deserve more views
@ForestLearn
@ForestLearn 6 күн бұрын
Thanks for watching and your very kind comment :)
@shairaanjuman3806
@shairaanjuman3806 11 күн бұрын
this saved me, thanks so much!!!
@ForestLearn
@ForestLearn 11 күн бұрын
Glad to hear that :)
@AhmedKhaleelAhmedAhmed
@AhmedKhaleelAhmedAhmed 16 күн бұрын
thank yoou
@ForestLearn
@ForestLearn 16 күн бұрын
You are welcome :)
@niwanthakaweragoda9480
@niwanthakaweragoda9480 18 күн бұрын
Saved me from a lot of stress. thank you so much
@ForestLearn
@ForestLearn 18 күн бұрын
Glad to hear that :)
@kinggp9823
@kinggp9823 21 күн бұрын
test on this in about 2 hours thanks lol
@ForestLearn
@ForestLearn 21 күн бұрын
Good luck :)
@MichaelK.-xl2qk
@MichaelK.-xl2qk 22 күн бұрын
So then why does the copper disc still generate current when the magnet is not stationary, but is attached to it and rotates at the same speed as it does?
@erinwallborg2290
@erinwallborg2290 26 күн бұрын
Can this help calculating the resonance peaks in for example - In Ear Earphones? As the ear canal is a form of a tube, can I predict the interactions of waves frequency-wise?
@ForestLearn
@ForestLearn 23 күн бұрын
Interesting question! Yes, I think so - it'd be a nice exercise to calculate the harmonic (resonant) frequencies of an ear canal and to compare that with the resonance peaks.
@tessney-filomeno1378
@tessney-filomeno1378 Ай бұрын
Thank you so much! these are definitely my top mistakes!
@ForestLearn
@ForestLearn Ай бұрын
Glad the vid helped - fingers crossed those mistakes are a thing of the past now :)
@overunityinventor
@overunityinventor Ай бұрын
when u raise a magnet weighing 100 grams upto a hieght of 100 meters, u put 100 joules of energy into it, when u drop that 100 grams magnet through the coil, the magnet fall takes 2 seconds and the coil generates 50 joules of energy. is there a way to generate more energy from the falling magnet of same weight from same hieght? yes, just increase the winding on the coil, now the coil has 4 times winding than it was before, now raising the magnet to same hieght takes the same amount of energy (=100 joules), but dropping the same magnet through the coil of bigger winding now generates more energy, and the fall of magnet takes more time (let's say 8 seconds) because of more back emf because of more current in coil. can you make and show graph and calculations of this situation please?
@LuckyDies
@LuckyDies Ай бұрын
thanks bro
@ForestLearn
@ForestLearn Ай бұрын
:)
@niccybeth572
@niccybeth572 2 ай бұрын
Extremely helpful! Thank you very much for this video.
@ForestLearn
@ForestLearn 2 ай бұрын
You're welcome, glad you found it useful :)
@cameronchambers2907
@cameronchambers2907 2 ай бұрын
The magnetic force on the sector that is resisting the change in direction , is this where and why there is back emf on motors ?
@ForestLearn
@ForestLearn 2 ай бұрын
Hi, great observation! The cutting of field lines gives rise to a magnetic force which is responsible for the induced emf + current in the Faraday dynamo. In a motor, again, the cutting of field lines gives rise to a magnetic force. But this force now opposes the motion of the electrons i.e. reduces the current; remember the current is present in the first place due to an applied/external emf across the motor. Thus, the overall emf is reduced by an amount known as the 'back emf' (the word 'back' implying opposition/reduction). [Note: the back emf is usually referred to as an induced emf, but I'm not sure that's helpful terminology.] Anyway, hope the above made some sense, hope to do a vid on back emf one of these days. In the meantime let me know if you have any further questions!
@mrpicky1868
@mrpicky1868 2 ай бұрын
wrong. forget the magnetic lines as they dont exist. it's all about dynamic induction. so you can get currrent from this even if both disc and magnet stationary and outside contact stays at same distance from center. kzbin.info/www/bejne/nZXYiqKKbtiAl6csi=0WdL6ZkCtSz2XE2X
@drudayanelumdeniyambbsdchm9852
@drudayanelumdeniyambbsdchm9852 2 ай бұрын
This is absolutely incredible simplification of physics. Thanks
@ForestLearn
@ForestLearn 2 ай бұрын
Thanks for your kind words!
@erica_99ig
@erica_99ig 2 ай бұрын
i am really grateful..been trying to understand this since 4 days but couldnt get it..this made me understand within minutes. thank you so much!!the visual representation really helped!
@ForestLearn
@ForestLearn 2 ай бұрын
You're welcome, really glad to hear that it helped :)
@helloHELLO-xc1bg
@helloHELLO-xc1bg 3 ай бұрын
Sir, I really appreciate your video. It rescued me from the deep struggle of not understanding what physics is talking about. I wish you to have a wonderful day!
@ForestLearn
@ForestLearn 3 ай бұрын
Very happy to hear that! Your comment made my day :)
@alanx4121
@alanx4121 3 ай бұрын
is there a current density distribution considering that the speed of the charge from inside to outside radius increases?
@ForestLearn
@ForestLearn 2 ай бұрын
Hi, thanks for your question and apologies for the late reply! Yes - you're correct :)
@jayantachoudhury4397
@jayantachoudhury4397 3 ай бұрын
I'm going to university of Leeds on this September as an undergrad in theoretical physics.
@ForestLearn
@ForestLearn 3 ай бұрын
Congratulations! You'll no doubt bump into Jiannis there :)
@jayantachoudhury4397
@jayantachoudhury4397 3 ай бұрын
@@ForestLearn I'm eager to meet him 🤩
@ForestLearn
@ForestLearn 3 ай бұрын
@@jayantachoudhury4397 Of course :) Mention this interview to him when you do!
@jayantachoudhury4397
@jayantachoudhury4397 3 ай бұрын
@@ForestLearn I'll for sure!
@ForestLearn
@ForestLearn 3 ай бұрын
@@jayantachoudhury4397 :) Hope you have a great time there!
@Geri_crs
@Geri_crs 4 ай бұрын
What would happen if you use a YBCO disc at 65°K ?
@Geri_crs
@Geri_crs 4 ай бұрын
*with-rotation axile inline crystal structure
@cantis3156
@cantis3156 4 ай бұрын
thank you so much bro these videos have been a massive help.
@ForestLearn
@ForestLearn 4 ай бұрын
My pleasure, really glad to hear that :)
@abhayganti8662
@abhayganti8662 5 ай бұрын
amazing video and thanks! How can i work out the results if I connect the falling bar magnet through a spring so it falls and rises continuously?
@ForestLearn
@ForestLearn 5 ай бұрын
Glad it was helpful! Sounds like an interesting investigation - do the experiment and then try to explain the results using your theoretical understanding :)
@mharsha3516
@mharsha3516 5 ай бұрын
thankyou, was very clear with the simulation and helped me understanding of the stationary waves.
@ForestLearn
@ForestLearn 5 ай бұрын
You're welcome :)
@ramens
@ramens 5 ай бұрын
thanks
@ForestLearn
@ForestLearn 5 ай бұрын
My pleasure :)
@444unknownuser
@444unknownuser 5 ай бұрын
youre acc the best
@ForestLearn
@ForestLearn 5 ай бұрын
You're way too kind :)
@ri0jeroen
@ri0jeroen 5 ай бұрын
Thanks for the video! I have one question: When exactly do the peaks happen? Is it when the middle of the magnet enters the coil, when the bottom of the magnet enters the coil or something else entirely?
@ForestLearn
@ForestLearn 5 ай бұрын
Thanks for watching :) The peak and trough occur when the magnet is fairly close to the coil, but not inside the coil (see the magnet positions at 3:00 in the vid, for example). At these positions, the rate of change of flux linkage is greatest, corresponding to max values of induced emf. As I discuss for the second question in the vid, when the middle of the magnet passes through the coil, the induced emf vanishes for an instant. Hope this helps - let me know if you have any further questions.
@b_dog_piano
@b_dog_piano 6 ай бұрын
Cheers boss, watching this in my physics class rn bro! :) Very helpful and my teacher said you're the best physics youtuber out there. I have a question, why does the bar magnet repel, and is lenzs law similar to lechatliers principle in chemistry?
@ForestLearn
@ForestLearn 6 ай бұрын
Thanks for watching and both your teacher's and your own awfully kind comments :) Regarding your question about repulsion, if you revisit the video between 1:00 - 2:00 this should provide the answers - let me know if not though, I'll be happy to address any specific issues. That's a v. interesting observation re the similarity of Lenz's law and Le Chatelier's principle! It seems that at a very high/general level they both involve systems the respond to counteract a change/disturbance to preserve the status quo (to keep things as they were). But one is a consequence of an equation of electromagnetism while the other is to do with chemical thermodynamics, so I'm not aware of there being any deeper connection between the two. Hope that helps!
@ibrahimfaisal1292
@ibrahimfaisal1292 6 ай бұрын
Amazing video! Answered every question that i was unsure of!
@ForestLearn
@ForestLearn 6 ай бұрын
Thanks, great to hear that :)
@tahabashir9405
@tahabashir9405 6 ай бұрын
damn the british. They ruled us till 1947, take valuable foreign exchange amouting to Rs 42 billion (120052506 pound sterling) every year for the CIE exams, and even their explanations are better.
@ForestLearn
@ForestLearn 6 ай бұрын
:|
@d_i_a_v_l_o3827
@d_i_a_v_l_o3827 6 ай бұрын
saving my a levels fr durham here we come 🔥🔥🔥
@ForestLearn
@ForestLearn 6 ай бұрын
Good luck - you can do it!
@charliecooper7458
@charliecooper7458 5 ай бұрын
Im going durham too, DURHAM HERE WE COME
@ForestLearn
@ForestLearn 5 ай бұрын
​@@charliecooper7458 Is the Durham physics dept ready for this many people with such a firm grasp of induction? 😂
@frosty2535
@frosty2535 6 ай бұрын
i rarely leave comments but i wanted to let you know how good these videos are. i never got induction (even after hours of trying to get it). now i actually get what's going on. massive thanks
@ForestLearn
@ForestLearn 6 ай бұрын
Well done for taking the time/effort to watch the vids to improve your understanding, and thank you for your incredibly kind comment! It means a great deal to me :)
@phoebeli4999
@phoebeli4999 6 ай бұрын
Thanks for separating the induction into three types! That is really helpful for understanding.☺️ btw is that means the hall voltage is actually an induced voltage of type I(the ‘cutting field lines’)?
@ForestLearn
@ForestLearn 6 ай бұрын
My pleasure :) The Hall effect/voltage appears similar to type I induced emfs (both involve the magnetic or Lorentz force for their explanation), but try not to mix them up. In the Hall effect, the conductor is stationary and doesn't 'cut field lines' - we don't refer to the Hall voltage as an induced emf. Induced emfs are reserved for induction phenomena. Hope this helps!
@m1062002
@m1062002 6 ай бұрын
brilliant explanation for all videos of the sereis
@ForestLearn
@ForestLearn 6 ай бұрын
Thanks so much for your kind comment, I'm glad they've been helpful to you :)
@sirlimonada2
@sirlimonada2 6 ай бұрын
is there any function that fits the curve and brings any data about the magnetic field passing through?
@ForestLearn
@ForestLearn 6 ай бұрын
Thanks for your question! I'm unaware of a function that fits the curve - in principle, you could simulate what's going on here computationally (i.e. code the equations of motion etc) and arrive at the induced emf graph. You could then numerically (computationally) integrate the induced emf with respect to time to arrive at how the flux linkage changes with time. Hope this helps!
@sirlimonada2
@sirlimonada2 6 ай бұрын
@@ForestLearn Thanks, luckily someone already did the math in physics forum, if anyone needs it , tittle of the post is "how to model a magnet falling through solenoid"
@ForestLearn
@ForestLearn 6 ай бұрын
@@sirlimonada2 Many thanks for sharing this!
@francoismukagaga
@francoismukagaga 6 ай бұрын
Hmmm, in a previous comment i mentioned" comments" when i ment " links " ! But don't bother, eventualy i'll find a way when necesary 🙂. Still, great video's & animations which i will relook and relook till i understand the fysics and the equations behind it...imbed in my brain 🤔🙂👍☘️14/4/24 FM
@ForestLearn
@ForestLearn 6 ай бұрын
Many thanks :)
@francoismukagaga
@francoismukagaga 6 ай бұрын
Because of the publicity underneath your video's it's imposible the see the comments, grrr! Great job! Great animations ! Thank you for sharing !👍🍀🍀14/4/24 FM👋
@ForestLearn
@ForestLearn 6 ай бұрын
You're most welcome, thanks for watching!
@emmayang-qq2ji
@emmayang-qq2ji 6 ай бұрын
what's the app that products the two waves?
@ForestLearn
@ForestLearn 6 ай бұрын
phet.colorado.edu/en/simulations/wave-on-a-string
@commenter3840
@commenter3840 6 ай бұрын
THANK YOU, your way of explaining things is 10/10
@ForestLearn
@ForestLearn 6 ай бұрын
Thank you for watching and your very kind comment :)
@sadkayyy
@sadkayyy 7 ай бұрын
Since the applied and magnetic force act in opposite directions and have the same magnitude, does this imply it is impossible to accelerate a conductor (in a closed circuit) when it is cutting across magnetic field lines?
@ForestLearn
@ForestLearn 7 ай бұрын
No - one only needs to increase the applied force, which will lead to a resultant upward force and thus an acceleration. This will not exist indefinitely - a higher speed will lead to a greater induced emf (Faraday's law) and greater induced current, which will result in an increased downward magnetic force which will counter-balance the applied force. Hope this helps!
@sadkayyy
@sadkayyy 7 ай бұрын
I've read that when the electrons in the wire accumlulate as shown in 2:50, they form an electric field which eventually becomes large enough to provide an electric force that balances the magnetic force, causing the electrons to stop moving, which in turn forms a potential difference. Apparently, by using magnetic force = electric force, magnetic force = BQv and electric force = QE = QV/d, the equation in 4:23 can be derived. What does this electric field look like, and how does it provide an electric force that acts opposite to the magnetic force? Also, is all of this just a really roundabout way of phrasing what you've mentioned in 2:50?
@ForestLearn
@ForestLearn 7 ай бұрын
Thanks for your question! The derivation you mention is covered by me in this vid (and addresses your queries): kzbin.info/www/bejne/bn3Fh3ltnbh2jck Hopefully, this should clear things up - if not, let me know and I'll be happy to help :)
@yusraawan8014
@yusraawan8014 7 ай бұрын
hello, was just watching the magnetic fields videos and I can't seem to find the vids on the type 3 scenario, only type 1 and 2, also do you have a video on RMS? I find it super confusing, thank you!!
@ForestLearn
@ForestLearn 7 ай бұрын
Thanks for watching and your comment! Hope to have a type 3 vid up shortly and will try to get round to RMS asap :)
@ForestLearn
@ForestLearn 7 ай бұрын
@yusraawan8014 Type 3 video is up now: kzbin.info/www/bejne/nXSnkmalo9B0bbc Hope it's useful!
@shubhamjoshi9624
@shubhamjoshi9624 7 ай бұрын
Very good video
@ForestLearn
@ForestLearn 7 ай бұрын
Many thanks :)
@imran4935
@imran4935 7 ай бұрын
You're amazing. That was a wonderful video. I've learned more in these 14 minutes than I did in my university lectures. Thanks a lot.
@ForestLearn
@ForestLearn 7 ай бұрын
That's awfully kind of you, glad it helped :)
@ForestLearn
@ForestLearn 7 ай бұрын
Answer to question posed at 8:59 (please try to figure it out yourself before taking a look!): To understand why the current alternates viewed through the lens of Lenz's law (!), it's helpful to recall the informal version of the law (for changes in flux) discussed in this vid [ kzbin.info/www/bejne/r2PGZGmNbrabsKc ]: 'The coil/loop tries to *oppose* any *changes* in magnetic flux (linkage).' As the north pole of the rotating magnet approaches the coil, the coil tries to oppose the changing flux linkage by developing a magnetic North pole on the left side - this thus repels the rotating magnet. Viewing the coil 'head on' from the left, the conventional current would be flowing aNti-clockwise [see this for further clarification: kzbin.info/www/bejne/qJe7emumdriYqKc ]. As the north pole of the rotating magnet moves away from the coil, the coil tries to oppose the changing flux linkage by developing a magnetic South pole on the left side - this thus attracts the rotating magnet. Viewing the coil 'head on' from the left, the conventional current would be flowing clockwiSe. And so on.
@StudywithmeinPakistan
@StudywithmeinPakistan 7 ай бұрын
Good explaination . I explained these topics in Urdu few days back. Which is mostly spoken in Pakistan(Asia).
@ForestLearn
@ForestLearn 7 ай бұрын
Thanks, that's great to hear! I am aware that Urdu is spoken in Pakistan :)
@StudywithmeinPakistan
@StudywithmeinPakistan 7 ай бұрын
@@ForestLearn Thanks. 👍
@pratichidas1579
@pratichidas1579 8 ай бұрын
Thank you!The animation helped a lot😊
@ForestLearn
@ForestLearn 8 ай бұрын
:)
@pratichidas1579
@pratichidas1579 8 ай бұрын
Thank you!The animation helped a lot😊
@ForestLearn
@ForestLearn 8 ай бұрын
:)
@BradleyPeacock-or8lr
@BradleyPeacock-or8lr 8 ай бұрын
Heres a derivation of the formula at 8:00 : Velocity varies with radius (v=ωr) so we consider de and dr instead of e and l in the original formula (e =Blv). de= vBdr, de = ωrBdr, de/dr = ωrB. Integrate this with limits 0 and R to get e = (ωBR^2)/2.
@ForestLearn
@ForestLearn 8 ай бұрын
Exactly, thanks for sharing this!
@زينالعابدينماجدمحمد
@زينالعابدينماجدمحمد 8 ай бұрын
❤❤❤❤❤
@ForestLearn
@ForestLearn 8 ай бұрын
:)
@h7opolo
@h7opolo 8 ай бұрын
your mouth noises fail to qualify as spoken English. Trying to learn while deciphering your thick accent is too cumbersome a chore at this early morning hour.
@JudeWeraduwage
@JudeWeraduwage 9 ай бұрын
A very nice video, though I wish I knew why the "misconceptions" were wrong...
@ForestLearn
@ForestLearn 8 ай бұрын
Thanks for watching and the kind words :) If you've met circular motion, you can check out the following vid which deals with some of the misconceptions I raised: kzbin.info/www/bejne/jXnImoB4Ytxjprc . Otherwise, let me know what you're struggling to understand in particular and I'll be happy to help.
@JudeWeraduwage
@JudeWeraduwage 8 ай бұрын
@@ForestLearn Wow, thank you for making & sharing that video, it really helped a lot!! Really love all of your stuff, keep up the great work!!!
@ForestLearn
@ForestLearn 8 ай бұрын
@@JudeWeraduwage My pleasure, really glad to hear that!