8 ай бұрын
8 ай бұрын
Пікірлер
@shubham.1729 3 күн бұрын
Are you wolowitz from big bang theory???
@christopherbarile2539 2 күн бұрын
Perhaps in a different life
@shubham.1729 2 күн бұрын
@christopherbarile2539 yeah 😅 thank you for the explanation
@kevincardenas6629 10 күн бұрын
ty
@christopherbarile2539 10 күн бұрын
You are welcome!
@ali_shz2233 20 күн бұрын
Could you draw Mo for ethylene too and describe why two of 2s combination of carbon with 1s of hydrogens aren't allowed based on molecular orbital symmetry?
@duterran 21 күн бұрын
Very useful video for a graduate student, thanks a lot!!!
@christopherbarile2539 20 күн бұрын
Glad it was helpful!
@jamesbond-nx2ns Ай бұрын
great I understood
@christopherbarile2539 Ай бұрын
Glad to hear that!
@PieMaru Ай бұрын
thank you so much for the video!!
@christopherbarile2539 Ай бұрын
Glad it was helpful!
@peterqiu2674 Ай бұрын
Hi, could you please do a video on how to calculate ECSA using the integral of reduction current from a CV?
@neemishbadole9126 Ай бұрын
Thanks chrisopher
@christopherbarile2539 Ай бұрын
You're welcome!
@SantiagoGonzalez-d4y Ай бұрын
This video is really helpful! Thank you for explaining it in simple and different ways
@christopherbarile2539 Ай бұрын
Glad it was helpful!
@Imdaniferreirag Ай бұрын
Hi, the plot of current vs scan rate is with the peak anodic currents of the CV? Thank you so much!
@christopherbarile2539 Ай бұрын
You can use either the anodic or cathodic peak currents in principle for this analysis.
@karnikabassi9619 Ай бұрын
I don't understand a thing
@christopherbarile2539 Ай бұрын
Sorry! I suggest starting with some of the introduction to character table videos.
@Michaelxx245 Ай бұрын
Why are you adding double bonds to the carbons in the cyclic ring instead of just adding hydrogens? This is for the example at five minutes...
@christopherbarile2539 Ай бұрын
C must have an octet, so to satisfy the octet rule if there are no lone pairs on C, C must form 4 bonds.
@ChinemeremChristian-Iwuagwu 2 ай бұрын
whats the name of the formula you used to find all the possible microstates
@christopherbarile2539 2 ай бұрын
I do not believe it has a name, but it is based on combinations and permutations.
@oneaboveall9280 2 ай бұрын
Why does it have to be so difficult?
@christopherbarile2539 2 ай бұрын
The universe is complex.
@KavinTeenakul 2 ай бұрын
Can the capacitance be calculated from EIS data? WHen fitting the EIS circuit, there will be the capacitor component.
@christopherbarile2539 2 ай бұрын
Yes
@heeralalsoni9307 2 ай бұрын
Excellent demonstration. Please upload more videos .
@christopherbarile2539 2 ай бұрын
Are there particular topics you are interested in?
@heeralalsoni9307 2 ай бұрын
brilliant explanation so far,
@christopherbarile2539 2 ай бұрын
Thanks!
@akashsarkar8888 2 ай бұрын
is there any forbidden transitions.
@christopherbarile2539 2 ай бұрын
Those that are not spin-allowed are spin-forbidden.
@akashsarkar8888 2 ай бұрын
@@christopherbarile2539 a2g to eg is not allowed……we get a shoulder peak at uv but it will be not allowed and we calculate neu 2/neu3 without considering this transition….
@anurajbhattacharya6278 3 ай бұрын
You're a lifesaver, sir. Thank you for this crystal clear yet simplistic explanation.
@christopherbarile2539 2 ай бұрын
Glad it helped!
@Pamela-r7f 3 ай бұрын
You're the best at explaining
@christopherbarile2539 3 ай бұрын
Glad it is helpful!
@heatherpartlow2674 3 ай бұрын
thank you!
@christopherbarile2539 3 ай бұрын
Glad you found it helpful
@heeralalsoni9307 3 ай бұрын
excellent description
@christopherbarile2539 3 ай бұрын
Glad you think so!
@heeralalsoni9307 3 ай бұрын
very useful
@christopherbarile2539 3 ай бұрын
Glad to hear that
@k.s.satheeshkumar4117 3 ай бұрын
Nicely explained. thank you
@christopherbarile2539 3 ай бұрын
You are welcome
@전선민-v8o 3 ай бұрын
Thank you for fundamentally explaining what the difference is between chronopotentiometry and chronoamperometry (kinetic, thermodynamic).
@christopherbarile2539 3 ай бұрын
Glad it was helpful!
@Kylitovibes 4 ай бұрын
I am trying to apply the rotation of a hexagons six points using matrices. It reminds me of the Cn you show but I want to understand why. I am having trouble.
@Kylitovibes 4 ай бұрын
I'm understand it's a rotation but the sin cos part.
@alikaperdue 4 ай бұрын
Hi Christopher. I found the D3h multiplication table when I was manipulating triangles on a complex plane. Is it established that D3h is just the symmetry of similar triangles having fixed side? You know way more, so do you know what I am talking about?
@alikaperdue 4 ай бұрын
code results: E C₃¹ C₃² Ov Ov¹ Ov¹¹ Oh S₃ S₃⁵ C₂ C₂¹ C₂¹¹ E E C₃¹ C₃² Ov Ov¹ Ov¹¹ Oh S₃ S₃⁵ C₂ C₂¹ C₂¹¹ C₃¹ C₃¹ C₃² E Ov¹ Ov¹¹ Ov S₃ S₃⁵ Oh C₂¹ C₂¹¹ C₂ C₃² C₃² E C₃¹ Ov¹¹ Ov Ov¹ S₃⁵ Oh S₃ C₂¹¹ C₂ C₂¹ Ov Ov Ov¹¹ Ov¹ E C₃² C₃¹ C₂ C₂¹¹ C₂¹ Oh S₃⁵ S₃ Ov¹ Ov¹ Ov Ov¹¹ C₃¹ E C₃² C₂¹ C₂ C₂¹¹ S₃ Oh S₃⁵ Ov¹¹ Ov¹¹ Ov¹ Ov C₃² C₃¹ E C₂¹¹ C₂¹ C₂ S₃⁵ S₃ Oh Oh Oh S₃ S₃⁵ C₂ C₂¹ C₂¹¹ E C₃¹ C₃² Ov Ov¹ Ov¹¹ S₃ S₃ S₃⁵ Oh C₂¹ C₂¹¹ C₂ C₃¹ C₃² E Ov¹ Ov¹¹ Ov S₃⁵ S₃⁵ Oh S₃ C₂¹¹ C₂ C₂¹ C₃² E C₃¹ Ov¹¹ Ov Ov¹ C₂ C₂ C₂¹¹ C₂¹ Oh S₃⁵ S₃ Ov Ov¹¹ Ov¹ E C₃² C₃¹ C₂¹ C₂¹ C₂ C₂¹¹ S₃ Oh S₃⁵ Ov¹ Ov Ov¹¹ C₃¹ E C₃² C₂¹¹ C₂¹¹ C₂¹ C₂ S₃⁵ S₃ Oh Ov¹¹ Ov¹ Ov C₃² C₃¹ E
@alikaperdue 4 ай бұрын
Code results: E C₃¹ C₃² Ov Ov¹ Ov¹¹ Oh S₃ S₃⁵ C₂ C₂¹ C₂¹¹ E E C₃¹ C₃² Ov Ov¹ Ov¹¹ Oh S₃ S₃⁵ C₂ C₂¹ C₂¹¹ C₃¹ C₃¹ C₃² E Ov¹ Ov¹¹ Ov S₃ S₃⁵ Oh C₂¹ C₂¹¹ C₂ C₃² C₃² E C₃¹ Ov¹¹ Ov Ov¹ S₃⁵ Oh S₃ C₂¹¹ C₂ C₂¹ Ov Ov Ov¹¹ Ov¹ E C₃² C₃¹ C₂ C₂¹¹ C₂¹ Oh S₃⁵ S₃ Ov¹ Ov¹ Ov Ov¹¹ C₃¹ E C₃² C₂¹ C₂ C₂¹¹ S₃ Oh S₃⁵ Ov¹¹ Ov¹¹ Ov¹ Ov C₃² C₃¹ E C₂¹¹ C₂¹ C₂ S₃⁵ S₃ Oh Oh Oh S₃ S₃⁵ C₂ C₂¹ C₂¹¹ E C₃¹ C₃² Ov Ov¹ Ov¹¹ S₃ S₃ S₃⁵ Oh C₂¹ C₂¹¹ C₂ C₃¹ C₃² E Ov¹ Ov¹¹ Ov S₃⁵ S₃⁵ Oh S₃ C₂¹¹ C₂ C₂¹ C₃² E C₃¹ Ov¹¹ Ov Ov¹ C₂ C₂ C₂¹¹ C₂¹ Oh S₃⁵ S₃ Ov Ov¹¹ Ov¹ E C₃² C₃¹ C₂¹ C₂¹ C₂ C₂¹¹ S₃ Oh S₃⁵ Ov¹ Ov Ov¹¹ C₃¹ E C₃² C₂¹¹ C₂¹¹ C₂¹ C₂ S₃⁵ S₃ Oh Ov¹¹ Ov¹ Ov C₃² C₃¹ E
@alikaperdue 4 ай бұрын
Python code: #!/usr/bin/python3 import pandas as pd from math import isclose def r1(z): return (z-3)/(z+1) def r2(z): return (z+3)/(-z+1) def E(z): return z def C31(z): return r1(z) def C32(z): return r2(z) def OV(z): return -r2(z).conjugate() def OV1(z): return -r1(z).conjugate() def OV11(z): return -z.conjugate() def OH(z): return z.conjugate() def S3(z): return r1(z).conjugate() def S35(z): return r2(z).conjugate() def C2(z): return -r2(z) def C21(z): return -r1(z) def C211(z): return -z funcs = { 'E' :E, 'C₃¹':C31, 'C₃²' :C32, 'Ov':OV, 'Ov¹':OV1, 'Ov¹¹':OV11, 'Oh':OH, 'S₃' :S3, 'S₃⁵' :S35, 'C₂':C2, 'C₂¹':C21, 'C₂¹¹':C211, } prec = 0.0000001 z = 1+1j res = [] for f1 in funcs.keys(): row = [] for f2 in funcs.keys(): r = funcs[f1](funcs[f2](z)) for rf in funcs.keys(): if abs(r-funcs[rf](z)) < prec: break row.append(rf) res.append(row) df = pd.DataFrame(res,columns=funcs.keys(),index=funcs.keys()) print(df)
@mattiadarioli774 5 ай бұрын
really great videos, thank u s much
@christopherbarile2539 4 ай бұрын
Glad you like them!
@BlackRose.Arises 5 ай бұрын
Thank you so much for these lectures. I finally understand this topic. I appreciate it 😊🙏
@christopherbarile2539 4 ай бұрын
Glad to hear that
@keithyoung7349 5 ай бұрын
please keep doing what you are doing
@keithyoung7349 5 ай бұрын
Best explanation! prepping me for finals :)
@christopherbarile2539 4 ай бұрын
Good luck!!
@edwinloveson2203 5 ай бұрын
Wft+???
@aizadmokhtar7049 5 ай бұрын
By equalling the slope of i vs v^1/2 and 2.69x10^5 n ^3/2 A D^1/2 C, we can get the surface area (A). To do that, do I need to make the intercept = 0 or not?
@joekerrigan8473 5 ай бұрын
It’s hard to find high level, useful echem info like this in an easily digestible form. Thanks
@christopherbarile2539 4 ай бұрын
Glad it was helpful!
@EliasAyine 5 ай бұрын
give examples of inversion center clearly?
@leidydanielalermagarcia9063 6 ай бұрын
You explained this in such an understandable way, thanks a lot
@christopherbarile2539 5 ай бұрын
Glad it was helpful!
@marziyehjoda9015 6 ай бұрын
Dear professor Christopher Barile Thank you so much for your attached video , but I do not understand why γredz /γoxy is equal is it possible to clear me. I understand γ represents the charge transfer coefficients of the redox reactions. Specifically, γred represents the charge transfer coefficient of the reduction reaction, while γoxy represents the charge transfer coefficient of the oxidation reaction. In many cases, such as in some symmetric systems or when the electrode process is reversible, the charge transfer coefficients of the reduction and oxidation reactions are equal. Mathematically, this is represented as γred = γoxy. This equality implies that the rate of the forward (oxidation) reaction is equal to the rate of the backward (reduction) reaction, and the overall process is reversible. When γred = γoxy, it simplifies certain electrochemical equations and allows for easier analysis of the system. However, it's important to note that in some cases, the charge transfer coefficients may not be equal, especially in asymmetric systems or when the electrode process is not fully reversible. Is it correct my attitude from your attached video. Marzieh
@Elxa-fb5gv 6 ай бұрын
Helpful
@christopherbarile2539 5 ай бұрын
Glad to hear that
@lara8012 6 ай бұрын
i've been using this playlist to revise content for my summer exams as a fresher from the uk and i just wanted to say i've never had physical and inorganic chemistry explained to me in such a way that i can understand so well. thank you so much for these videos!
@christopherbarile2539 6 ай бұрын
I'm so glad!
@norapryor5432 6 ай бұрын
This is a great video and helped me out a lot in my inorganic chemistry class! Thank you!
@christopherbarile2539 6 ай бұрын
Glad it helped!
@tavvykuzba3743 6 ай бұрын
Thank you so much you made it so clear !!
@christopherbarile2539 6 ай бұрын
You're very welcome!
@akashsarkar8888 6 ай бұрын
in higher study hit and trial method get more importance😒😒
@dillonbaker9761 6 ай бұрын
Extremely helpful. Thanks
@christopherbarile2539 6 ай бұрын
Glad it was helpful!
@lavahawk 6 ай бұрын
Thanks this was very useful.
@christopherbarile2539 6 ай бұрын
Glad it was helpful!
@Loots1 6 ай бұрын
∫∫∫dzdydx = (abc/6) z from 0 to c[1-(y/b)-(x/a)] y from 0 to b[1-(x/a)] x from 0 to a 32mins vs 32seconds
@satnammattu7156 7 ай бұрын
can u plz share the title of the research ppr u shared in this video
@NaeemShahzadArshad 6 ай бұрын
same question
@christopherbarile2539 6 ай бұрын
The title of the paper is "Four-Electron Electrocatalytic O2 Reduction by a Ferrocene-modified Glutathione Complex of Cu" published in 2021 in ACS Applied Energy Materials.
@marieltecson752 7 ай бұрын
Thank you!!
@christopherbarile2539 7 ай бұрын
You're welcome!
@marieltecson752 7 ай бұрын
@@christopherbarile2539 I am a Ph.D. student and I have an exam which is crucial in my degree. I initially looked into the books available for inorganic chemistry and even looked at google. Fortunately, I saw your videos and you really explained the concept very well unlike in books that made me frustrated. I enjoyed your lectures and learned a lot from it. Thank you!
@maggie9399 7 ай бұрын
THANK YOU
@christopherbarile2539 7 ай бұрын
Glad it helped
@arghyadeepde1718 7 ай бұрын
Really crisp explanation!! loved it
@christopherbarile2539 7 ай бұрын
Glad you liked it
@anntrii_2403 7 ай бұрын
May I ask for the presentation?