Intuimation

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@apoorvvyas52 13 күн бұрын

Beautiful

@hawkinlock 15 күн бұрын

Now do the solution with O(n) runtime and O(1) space complexity.

@ansklfnaskidfhn-hi6zg 17 күн бұрын

no audio?

@sakshampokhrel42 19 күн бұрын

Are you from nepal? If not then where are you from?

@intuimation.314 18 күн бұрын

Yes I am, but I live in the United States🇺🇸

@sakshampokhrel42 16 күн бұрын

@@intuimation.314 as i though man the education system here is trash even torwards acedimic subjects like mathematics i want to leave as soon as i can so i can persuite my dream of being a mathematician one more question were you born there is the us or born here and later went there.

@shankar........... 29 күн бұрын

software used in this video for teaching >????

@intuimation.314 29 күн бұрын

It's not a software actually. To make animations I use Python Library called the MANIM. But yeah I use video editing software to combine my animations and voice

@intuimation.314 Ай бұрын

Something I'd like to highlight is that I didn't mention how does the sum transform into an integral as n → ∞? The key idea comes from the concept of a Riemann sum, which approximates the integral of a function by summing its values at discrete points and multiplying by the width of the subintervals. As the number of intervals increases, the width of each subinterval becomes smaller, and the Riemann sum becomes a more accurate approximation of the integral. If you'd like to see the detailed explanation with LaTeX code for this transformation, you can check out the document here: www.overleaf.com/read/fxrswmhfmpws#6671bf Also, if you want a full video explaining Riemann sums and how they transform into integrals, feel free to let me know in the comments, and I can make a dedicated video on that topic!

@jakeaustria5445 Ай бұрын

Thank You ❤

@braineaterzombie3981 Ай бұрын

Audio isn't smooth. If you don't have good setup, you can use ai voice. There are many free tools available. Also work done is way less with them However animations and other things are fantastic

@intuimation.314 Ай бұрын

It's definitely something I'm working on improving. I'll also look into using AI voices.

@crimsnblade8555 26 күн бұрын

please no ai voice, I like my maths videos human

@JohnSmall314 Ай бұрын

Very interesting and very well done. I subscribed

@recklessvelociraptor2579 Ай бұрын

3:26 in rearranged formula we using f'(x0) which uses x1, but how we calculate x1 to begin with?

@recklessvelociraptor2579 Ай бұрын

is there a full version? it seems cut

@intuimation.314 Ай бұрын

Yeah please check out: kzbin.info/www/bejne/mKmoZoqPlq6nirssi=22BN48-NBsWXazvs

@recklessvelociraptor2579 Ай бұрын

how graph even created without a being specified? f(x) only have 1 variable, so a must be specified right?

@recklessvelociraptor2579 Ай бұрын

and in this example we finding root of a, correct?

@nortonsm Ай бұрын

Great video! Appreciate the hard work in putting these together. One small comment on the proof that I had to “prove” to myself and maybe others might be interested. I worried that there could be some n where the denominator would go to zero in that expression for the geometric expansion ( either the real or imaginary part of the denominator since it’s complex, i.e 1 - exp(2*pi*i/n) ) and therefore would not make the proof general for all n integers > 1. But then, it occurred to me that the denominator represents a vector from a point in the complex unit circle to 1 on the real-axis and other than n=1, the trivial case, this will never be zero in the real or imaginary component. Anyways, thanks for pointing out this proof and letting me have some math fun!

@intuimation.314 Ай бұрын

Thanks for sharing your thoughts and for taking the time to dive deeper into the proof. You're absolutely right-if you picture the vectors on the complex plane, it becomes clear that the denominator will only go to 0 if the imaginary part is 0, which happens only for the 0th vector. No other vector is purely real, so the imaginary part is never 0 elsewhere. Glad you enjoyed exploring this proof!

@nartoomeon9378 Ай бұрын

We can also use rotational symmetry - if you myltiply every vector from given set by *exp(i*2π/n)* , the set does not change and vector sum(Σ) too: *Σ=Σ×exp(i×2π/n)=Σx* This equation works for any *Σ* if the coefficient on the right side = 1, but *exp(i×2π/n)* ≠ 1 ! So, only possible solution is Σ=0. But we need to know that *x* coefficient is not (left/right) zero divisor. If so, we get more than one solution.. which breaks vector sum as function. But complex numbers form a number field, any non-zero complex number is not a zero divisor. The answer was right - *Σ=0* ✅

@intuimation.314 Ай бұрын

The rotational symmetry approach is a really cool way to think about it. I hadn’t thought about the role of zero divisors in the complex field like that-great point! Appreciate you taking the time to share this!

@nartoomeon9378 Ай бұрын

@@intuimation.314 Im sorry, but my point of view was not so clear and full. Equation Σ=Σx for x≠1 has more than one solution not only if x is zero divizor, but if x preserve Σ under multiplication in another way. Such case is possible in rings, for example: 7*2=2 (mod 12) [Z/12 commutative ring]. But wait, we can use properties of the ring and rewrite our equation in the next way: Σ=Σx => Σ-Σx=0 => Σ(1-x)=0. Now, we can see how to solve it.(zero divizors wins) We don't need "preserving" property, multiple solutions possible Only if Σ or (1-x) is one-side zero divizor , or one of them two-sided... Anyway, my intuition was not so bad. All of these is my self-critique, but I think it useful for you too.

@recklessvelociraptor2579 Ай бұрын

how is root at y=0? Of which x root we finding?

@intuimation.314 Ай бұрын

To find square root using Newton Raphson Method, we take a special function y = x^2-a, which has its root at x=a. Mathematically speaking, function y=0 at x=a

@recklessvelociraptor2579 Ай бұрын

@intuimation.314 you mean at x^2=a

@recklessvelociraptor2579 Ай бұрын

@@intuimation.314 but what is a formula that represents drawing a tangent?

@SEE2080jp Ай бұрын

Do you animate all scene and voice over

@intuimation.314 Ай бұрын

Yeah👍

@SEE2080jp Ай бұрын

How do you make the voice + visuals

@intuimation.314 Ай бұрын

I start by writing a script for the video. Then, I animate the visuals using MANIM. For the voiceover, I record it on my mobile phone. Finally, I use video editing tools to combine the animations and voice seamlessly.

@AbhishekJohn-g5y Ай бұрын

👍

@antormosabbir4750 Ай бұрын

Souns Bangladeshi 🤔

@intuimation.314 Ай бұрын

😂Really. I am from south Asia though.

@antormosabbir4750 Ай бұрын

Yes brother! We speak in this accent, not like Indian accent

@pizzarickk333 Ай бұрын

I remember learning about this proof when I was first introduced to complex numbers. Nice video.

@intuimation.314 Ай бұрын

Thanks! I love how elegant this proof is.

@benhernandez Ай бұрын

This is awesome,thank you. Im learning higher level math later in life and this fills my curiosity of why things work like they do and how. It was interested that you included code, this is something i want to try out

@intuimation.314 Ай бұрын

I'm happy you enjoyed the code - feel free to play around with it!

@fernandopauli49 Ай бұрын

Beautiful!

@shreejalbhattarai4635 Ай бұрын

Here are my observations from this video: 1) This might be your best video so far; 10/10 for the concept. The animations have been a lot better. I've noticed that the explanation time and the time consumed by each frame match precisely. The length of the video is fantastic as well. One thing I'd suggest is revising the script once you finalize everything because minor mistakes can make the soup sour for critiques. In 11.41, there is a small spelling mistake, again, which I admit should be the least of concern, but I've included it for your retrospection. 2) I like how you connect a simple thing, like the vector sum of symmetric discrete vectors to zero, with electric field intensity and the fact that you were able to generalize your conclusion to continuous value systems. Excellent work on that. 3) I know that videos like these take a lot of time to prepare, and putting consistent work into these requires a great deal of work and dedication. I'd suggest putting the same work on your vocals as well. Try to pronounce the words a bit clearer and practice the script beforehand. I'd also suggest you record this audio in parts. Again, in no way should my suggestions be among the main takeaways from the audience's reaction, but I tried to sum it up as a well-wisher of this channel.

@intuimation.314 Ай бұрын

Thank you so much Shreejal for the detailed feedback! I'll take your suggestions to heart and make the necessary improvements.

@marcus2558 Ай бұрын

Thank you this helped me understand this!

@intuimation.314 Ай бұрын

Glad it helped!

@mapleigue Ай бұрын

Are you using manim?

@intuimation.314 Ай бұрын

Yeah the community version

@scifi2sci Ай бұрын

Great work! The microphone and voice could be better, but overall really great.

@woaitsbren Ай бұрын

agreed, enjoyed the visuals a lot, would have prefered clearer microphone quality

@intuimation.314 Ай бұрын

Thank you! It's recorded in Mobile. I'll try to improve the audio quality in future videos.

@edwardgongsky8540 2 ай бұрын

You didn't show the general formula, scam video.

@intuimation.314 Ай бұрын

I am sorry but I intended to show the Gaussian Summation here. For general proof you can checkout full video on arithmetic series: kzbin.info/www/bejne/r4eufnWqfMd9aKcsi=vmgkfQWoy5rJAw8K

@dhdhdh98 3 ай бұрын

this video is so much helpful than reading 30 minutes i can just write down code after watch that animation 🤣

@intuimation.314 Ай бұрын

Glad that you find it helpful!

@dhdhdh98 3 ай бұрын

hello, just curiosity why you did right-- when left and right height are both 8? is there no possibility approaching left side will have more volume?

@intuimation.314 3 ай бұрын

Yes, you could have moved the left pointer instead of the right pointer when both heights are the same (both 8 in this case), and it would still work. The algorithm usually moves the right pointer, but you could move the left pointer instead. It's just a choice, and it doesn't change the result because the width will get smaller either way.

@dhdhdh98 3 ай бұрын

@mathsimplified.2258 thank you I really appreciate 🫡

@dr.mikelitoris 3 ай бұрын

Great Video

@mmoonman13 3 ай бұрын

That's the French flag. Dutch flag has horizontal stripes.

@intuimation.314 3 ай бұрын

Thanks for your comment! The colors in the Dutch National Flag algorithm don’t actually represent the Dutch flag. They’re just three categories (like 0, 1, and 2) used to sort items in an array. The algorithm's name comes from the idea of sorting things into three groups, similar to the colors on a flag, but it doesn’t mean the colors match the real flag.

@dr.mikelitoris 3 ай бұрын

Let me know if you want some leetcode coaching lil bro you clearly do not know ball

@LightYagami-js1ee 3 ай бұрын

nice video! Thanks for your hard work! but your github repo seems not updating, can you update it? thx

@intuimation.314 3 ай бұрын

Ah, Procrastination is definitely my problem! But don’t worry, I’ll be updating the GitHub repo soon. Let me know if there's anything specific you'd like to add there!

@brownie2006 3 ай бұрын

Was it hard to learn manim?

@intuimation.314 3 ай бұрын

Learning MANIM can be a bit challenging at first, but there are tutorials that make it easier. You can even write a good prompt and let ChatGPT help generate the code-it might not be perfect, but you can always debug and make adjustments!

@sloan00 3 ай бұрын

I think this video visualizes well how this solution works. It would be better if you also add why this solution works.

@intuimation.314 3 ай бұрын

Thank you for the feedback! The purpose of this playlist is to visualize the dry run of these algorithms. I'll definitely consider making videos explaining why they work as well. Stay tuned!"

@japneetrajput6721 3 ай бұрын

Did you make this visualisation using MANIM Library?

@intuimation.314 3 ай бұрын

Yes. It's a cool library to make animations!

@MarcdeGennes 3 ай бұрын

Great visualization. Another comment : isn t it weird that your approximation of tan x is above the actual tan x curve for large x after the x^7 term ? Wouldn't you only add more positive terms afterwards, making it even further away from the red curve ?

@mzlmtn 3 ай бұрын

yes it is weird and probably wrong

@intuimation.314 3 ай бұрын

My bad. I wrote down a general expression for the tan(x) expansion in code, but I think that's more complicated than I thought. Sorry for the logical error. However, the terms on the bottom are correct. I'm really glad that you're paying attention to the details, and I appreciate the feedback!

@spacelover4106 3 ай бұрын

Looks really cool! I love it! But one small mistake: the function shown on the bottom left is one term behind the function plotted on the graph

@intuimation.314 3 ай бұрын

Thanks so much for pointing that out! I really appreciate your attention to detail. I'll make a note of it for future videos. Glad you enjoyed the rest of it!

@sporkcunt8100 4 ай бұрын

I don’t know why I’m watching this I failed pre algebra

@SampleroftheMultiverse 6 ай бұрын

12 “U” Shape Waves kzbin.info/www/bejne/raOlpKSfepWpfZYsi=waT8lY2iX-wJdjO3 Thanks for your informative and well produced video. You and your viewers might find the quantum-like analog interesting and useful. I have been trying to describe the “U” shape wave that is produced in my amateur science mechanical model in the video link. Summing all wave function before transition, is that like Over-lap all the waves together using Fournier Transforms? This model makes a “U” shape or square wave. Is this a similar representation Feynman Path Integrals? In the model, “U” shape waves are produced as the loading increases and just before the wave-like function shifts to the next higher energy level. You might be interested in seeing the load verse deflection graph in white paper found elsewhere on my KZbin channel. You can actually replicating it with a sheet of clear folder plastic and tape and seeing it first hand is worth the effort.