(0 1) is uncountable|(0,1) is uncountable proof|countable uncountable sets|uncountable set proof

  Рет қаралды 51,433

Rahul Mapari

Rahul Mapari

Күн бұрын

Пікірлер: 87
@prof.lalitkumarpachori8508
@prof.lalitkumarpachori8508 4 жыл бұрын
माझ्या वडिलांचे जगणे माझे आहे, परंतु माझे वडील चांगले आहेत. आपण आम्हाला शिक्षित करण्यासाठी जी मेहनत आणि प्रयत्न केले त्याबद्दल आम्ही नेहमीच आभारी आहोत मी तुमच्यासारखा गुरु मिळालो याबद्दल मी भाग्यवान होतो. प्रिय शिक्षक, मला नेहमीच पाठिंबा दिल्याबद्दल आणि माझे मार्गदर्शन केल्याबद्दल धन्यवाद. जर मला तुमचा आशीर्वाद नेहमी मिळाला असता तर मी यशस्वी झालो असतो. 😍
@prof.lalitkumarpachori8508
@prof.lalitkumarpachori8508 4 жыл бұрын
The Cantor set is an example of an uncountable set of Lebesgue measure 0 which is not of strong measure zero. Borel's conjecture states that every strong measure zero set is countable. ... A set A ⊆ R has strong measure zero if and only if A + M ≠ R for every meagre set M ⊆ R.
@aniketpal9629
@aniketpal9629 3 жыл бұрын
Darunnnn sirrr. Khub sundarrrr bojhalen sir .
@jadekan72
@jadekan72 2 жыл бұрын
Great! I didn't understand the way my teacher in the school doing this proof. But here I got hjelp! Thanks so much!
@Kalpanadubey11
@Kalpanadubey11 4 жыл бұрын
Sir apke pdane ka trika bhut accha hai please keep it
@generalhcross
@generalhcross 11 ай бұрын
This is the first explanation that I was able to understand. Thank you!!
@MdMahafuzurRahman-y3o
@MdMahafuzurRahman-y3o 2 ай бұрын
Thank you so much sir..My concept is clear now..Please take love💌
@mansafabrar6872
@mansafabrar6872 3 жыл бұрын
Best proof for R to be uncountable. 👍
@floatingmoose
@floatingmoose 2 жыл бұрын
Thank you for making this video. It made the arguments clear and easy to understand!
@inovexa4039
@inovexa4039 3 жыл бұрын
This is excellent sir!! Much love from Sri Lanka. The best explanation I've seen so far...
@gavinhyde2849
@gavinhyde2849 2 жыл бұрын
Great video. Straight to the point and easy to understand.
@devanshpandya3818
@devanshpandya3818 Жыл бұрын
Natural lite is good concept Yaa Ur explanation is also
@benedictkongyir1899
@benedictkongyir1899 3 жыл бұрын
May God bless you for your work
@devadathan6620
@devadathan6620 3 жыл бұрын
easy to understand. Very useful .❤️👍
@kousei8411
@kousei8411 Жыл бұрын
Simple and easy explanatiion
@reactionboy4437
@reactionboy4437 4 жыл бұрын
Sir,I learned many things from this lecture
@subhopal1760
@subhopal1760 4 жыл бұрын
Thnk sir....plzz sir upload vedios for csir net...
@diejodomison4249
@diejodomison4249 11 ай бұрын
Amazing video sir
@cut143
@cut143 4 жыл бұрын
Sir Topology questions and answers video daliye please
@priyanqajha4838
@priyanqajha4838 2 жыл бұрын
Finally crystal clear
@sridharreddy4162
@sridharreddy4162 2 жыл бұрын
Well explanation sir
@pradhumansinghchouhan9237
@pradhumansinghchouhan9237 Жыл бұрын
great video
@mathematicsmind8648
@mathematicsmind8648 4 жыл бұрын
It's simply awesome.. 🙏
@MathematicalMinds
@MathematicalMinds 2 жыл бұрын
Sir Please define uncountable union & countable union of sets
@bilalmusharraf9321
@bilalmusharraf9321 3 жыл бұрын
Sir plz make a complete series of important topics for IIT jam
@soniyasharma3406
@soniyasharma3406 4 жыл бұрын
Very beautifully explained, sir. I got it but I've a question, we have let that B, what if this assumption is wrong????? What if there doesn't exist such B. Maths is mysterious!!
@greatisnothing
@greatisnothing 4 жыл бұрын
There exist such B, just as we define it. It's Because we can proof that there is one element such as B exist that is not listed, it proves that its uncountable.
@soniyasharma3406
@soniyasharma3406 4 жыл бұрын
@@greatisnothing , yes. Got your point.
@kaushalkumar-oz3eh
@kaushalkumar-oz3eh 4 жыл бұрын
Sir please upload some lecture Riemann integral 🙏🙏🙏
@sabindragaurinteresting7126
@sabindragaurinteresting7126 2 жыл бұрын
Watch gajendra purohit videos
@sahayam80
@sahayam80 4 жыл бұрын
good explanation. thank you
@Chysrh
@Chysrh 2 жыл бұрын
Nyc expl.
@ranjithkumar-vl8mq
@ranjithkumar-vl8mq 4 жыл бұрын
Thank u sir..to teaching in english...
@vlog_vihar
@vlog_vihar 2 жыл бұрын
Sir good explanation but Hindi me bolte to or achha samajh ata. Thankyou sir
@michaelbachmann457
@michaelbachmann457 4 жыл бұрын
very lovely explained thank you :)
@Dream16780
@Dream16780 3 жыл бұрын
Bahut hard
@Dream16780
@Dream16780 3 жыл бұрын
And sir..you are really a good teacher..thanks for your lecture.
@dollykashyap4665
@dollykashyap4665 2 жыл бұрын
thnks sir u re the best 🥰
@indugupta6081
@indugupta6081 3 жыл бұрын
Thanks Sir
@lucienchu9649
@lucienchu9649 Жыл бұрын
Sorry sir, I am pretty confused, say a11 = 7, then b1 = 8. Isn't that we can always find a number in the list such that it starts with 0.8 then bla bla bla which will ultimately match the number B?
@saskiarymkiewicz260
@saskiarymkiewicz260 4 жыл бұрын
thank you, this really helped me
@ethangrubelich1305
@ethangrubelich1305 3 жыл бұрын
KING. THANK YOU.
@boxman_ninja0819
@boxman_ninja0819 3 жыл бұрын
Why can we not apply this proof to the set of rational numbers?
@soniyasharma3406
@soniyasharma3406 4 жыл бұрын
I'm so happy that i got it. I'm so bad with proofs. Any suggestions to improve it???
@sarojghosh7916
@sarojghosh7916 4 жыл бұрын
Any connected metric space with atleast two elements must be uncountable .
@tit-bits6197
@tit-bits6197 4 жыл бұрын
Killing a mosquito with a Canon?
@baisarinku2340
@baisarinku2340 4 жыл бұрын
Sir aap unacadamy app pr class kyu nhi le rhe.....??
@monoramamandal4941
@monoramamandal4941 4 жыл бұрын
Thank you so much ..
@D_i_n_e_s_562
@D_i_n_e_s_562 4 жыл бұрын
Thanq sir...
@ganeshmapari1576
@ganeshmapari1576 4 жыл бұрын
Like Classic girukul,like that, thanks
@ganeshmapari1576
@ganeshmapari1576 4 жыл бұрын
Gurukul
@RahulMapariBasicMaths
@RahulMapariBasicMaths 4 жыл бұрын
Oh. Thank you so much brother.
@alizach.3708
@alizach.3708 Жыл бұрын
Sir agr ic ki jaga (0,5) is uncountable prove karna hoto same aise hi hoga??
@RahulMapariBasicMaths
@RahulMapariBasicMaths Жыл бұрын
Yes
@alizach.3708
@alizach.3708 Жыл бұрын
​@@RahulMapariBasicMaths thankss sir
@poojaingole416
@poojaingole416 4 жыл бұрын
Thank you sir...
@radhikasavalam6696
@radhikasavalam6696 4 жыл бұрын
Thank you Sir
@akhileshkumarojha9301
@akhileshkumarojha9301 3 жыл бұрын
Thank you so much sir 🙏🙏
@mathsclub1903
@mathsclub1903 4 жыл бұрын
what is the condition of b1 not equal to a11
@ieltscuecard467
@ieltscuecard467 2 жыл бұрын
Why nonmeasurable set is uncountable????
@AjaySingh-bk6lk
@AjaySingh-bk6lk 4 жыл бұрын
Sir isko cator set ki help se prove kr saktay h kiya
@ananddanodiya2324
@ananddanodiya2324 4 жыл бұрын
Thank sir
@amandeep9930
@amandeep9930 4 жыл бұрын
A countable set has measure zero. Since measure of (0,1) is 1,it must be uncountable.
@RahulMapariBasicMaths
@RahulMapariBasicMaths 4 жыл бұрын
Very good. But we have some examples that a set is Uncountable but measure is zero.
@amandeep9930
@amandeep9930 4 жыл бұрын
@@RahulMapariBasicMaths Yes Sir, the most well known example is Cantor Set. Sir, I watch your videos regularly. Thank You for helping us.
@mansafabrar6872
@mansafabrar6872 3 жыл бұрын
Could u please explain measure zero concept?
@aniketpal9629
@aniketpal9629 3 жыл бұрын
I am now reading in 6th sem b.sc . And i was unable to understand the proof of this thm. untill watching the proof u provided it sir
@IAF-Lover001
@IAF-Lover001 Жыл бұрын
Studying 📚✏✔
@gandhamprasanthi7035
@gandhamprasanthi7035 4 жыл бұрын
Thank u sir
@AB_K96
@AB_K96 4 жыл бұрын
Thanks you sir 😇
@nileshgangurde4893
@nileshgangurde4893 3 жыл бұрын
aii not equal to bi Aise assumption krna hi q he Agar aise assumption nhi krenge to countable ho jayega na
@ايمانعلي-ظ6ت
@ايمانعلي-ظ6ت 2 жыл бұрын
Please help me in the theorem (0,1) is countable
@RahulMapariBasicMaths
@RahulMapariBasicMaths 2 жыл бұрын
(0,1) is uncomfortable.
@ايمانعلي-ظ6ت
@ايمانعلي-ظ6ت 2 жыл бұрын
@@RahulMapariBasicMaths I have solution or the proof that Is not countable
@osmaniavenky4874
@osmaniavenky4874 4 жыл бұрын
Super sir
@danielzhu4487
@danielzhu4487 2 жыл бұрын
Preciate it
@exol4229
@exol4229 2 жыл бұрын
Thankyou!
@s.p6482
@s.p6482 4 жыл бұрын
💖 from West Bengal
@saisameer5842
@saisameer5842 3 жыл бұрын
👌👌👌❤
@zahidrasoolkhan2277
@zahidrasoolkhan2277 4 жыл бұрын
Love from kashmir
@lakshakumarlariya6821
@lakshakumarlariya6821 4 ай бұрын
❤❤❤❤❤❤
@jeffjo8732
@jeffjo8732 Жыл бұрын
1) The interval [0,1] is indeed uncountable. (Note that you did not exclude 0.0000... or 0.11111... from the set you used, so the set is [0,1], not (0,1).) 2) Cantor's Diagonal Argument proves it. 3) This video is not a correct demonstration of CDA, and does not prove it. It is close, but incomplete. In fact, most expositions of CDA fail this way. It fails because you can't just say "we assume this list is complete" and then, when you show it is missing a number, claim a proof by contradiction. You have to actually use the assumed fact in the proof that leads to the missing number. All you really assumed is a list of some real numbers in that interval. What is shown in the video, is that if you have a list of any subset of [0,1], then that subset does not include the number B. This is the first part of CDA (actually, it is about strings, not numbers, but it does work with numbers). Only once this *_lemma_* is proven, directly and not by contradiction, does Cantor assume that the full set can be listed. Then we get the contradiction that B is in the listed set (since it includes all) but also not in the set (by the lemma). In other words, the contradiction is about B, not the interval.
@RahulMapariBasicMaths
@RahulMapariBasicMaths Жыл бұрын
Thank you so much for this information.
@aakritibhuriya1484
@aakritibhuriya1484 Жыл бұрын
thank you sir !
@sushmithabts229
@sushmithabts229 3 жыл бұрын
Thank you so much sir
@barasharanidas7265
@barasharanidas7265 4 жыл бұрын
Thank you sir....
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