03 Arrangements with restrictions

[@quinamasarira2116]

You have no idea how helpful this was! Thank you!

[@LMKMaths]

Glad it was helpful!

[@mmokengmabote9001]

Thank youu so much,I feel ready for my test.This video helped me

[@IdowuOluwatosinDonny]

Well explained 👍

[@chinonsookpara7877]

I love you for this wonderful explanation ❤

[@mohammedhafiz1349]

How many different teams of four people can be chosen from a group of 9?(1)if there are no restrictions (2)if one particular person must be included (3)if one particular person must be excluded

[@parthdatar9359]

Really helpful! Thank you for this.

[@rickasinghbhoola8719]

In your final questio e) since vowels can come 1st then consonants & then consonants & then vowels will the number of arrangements not be doubled ie. 288+288=576 ?

[@LMKMaths]

Hi! In the question, I do double the value to account for this. The number of ways to have the vowels first and the consonants second is 3! × 4! =144, and the number of ways to have the consonants first and the vowels second is 4! x 3!=144. Adding these together gives 144 + 144 =288. I did this as one calculation: 3! × 4! × 2 = 288. You don't need to double it for a second time.

[@rickasinghbhoola8719]

Thank you very much for the quick response.

[@chinonsookpara7877]

I love you for this wonderful explanation ❤