1-Bit Full Adder using Multiplexer

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Neso Academy

Neso Academy

Күн бұрын

Пікірлер: 213
@APC9906
@APC9906 7 жыл бұрын
For question at the end: To get 1 for i3, the shaded region that satisfies A=1 & B=1 shows that there are two 1s, if you group them, you can see that Ci changes from 1 to 0, making the answer 1; to help you more, take each 1 alone (generally bad idea), you'll realize you have Ci+Ci' which is equal to 1
@siddhantmeshram4092
@siddhantmeshram4092 3 жыл бұрын
I don't know who you are or where you live but thank you thank you !
@starkendeavours7072
@starkendeavours7072 3 жыл бұрын
Tysm.
@bhouyem2315
@bhouyem2315 2 жыл бұрын
thank u sm
@rishavyadav9438
@rishavyadav9438 2 жыл бұрын
Thank you
@satyampatel3244
@satyampatel3244 2 жыл бұрын
tqsm
@tacoz4429
@tacoz4429 8 жыл бұрын
Thank you. You have pretty much saved me from failing the course. :') There is still hope.
@malikhamza2285
@malikhamza2285 6 жыл бұрын
sir you are the only one reason behind my DLD interest.thanks alot for your service.stay blessed
@abhiramanne9649
@abhiramanne9649 4 жыл бұрын
I will be frank I feel like my lecturer for digital electronics is literally following neso academy.
@ranjeet5806
@ranjeet5806 3 жыл бұрын
Probably your teacher is the one who's running neso academy.
@saimyousuf2108
@saimyousuf2108 5 жыл бұрын
Best channel to learn digital logic
@reona3713
@reona3713 5 жыл бұрын
your explanations are better than my prof. Good job
@josuezalazar
@josuezalazar 3 жыл бұрын
The logic to use the full Adder carry output is: i0 = 0, i1 = Cin, i2 = Cin, i3 = 1.
@nandinisharma3360
@nandinisharma3360 2 жыл бұрын
Can you explain me how i3 come 1 it's very confused me 😶
@josuezalazar
@josuezalazar 2 жыл бұрын
@@nandinisharma3360 hey, it's been a while since I studied this. I've just checked it out and I think that i3 = 1 because in the Kmap when A = 1 & B = 1 there're two posible answers. And those answers would be written as Ci or Ci' which equals to 1.
@nandinisharma3360
@nandinisharma3360 2 жыл бұрын
@@josuezalazar then why we written i2 = Ci, why not 1 ?😶
@josuezalazar
@josuezalazar 2 жыл бұрын
@@nandinisharma3360 because in i2 is when A=1 & B=0 and as you can see we have two options. One of them is 0 and the other is 1. We use the option that's 1, and that option occurs when Ci is 1, or in other words, i2 = Ci
@nandinisharma3360
@nandinisharma3360 2 жыл бұрын
@@josuezalazar sorry bt it's very confusing me😶😶😞
@hotaru6765
@hotaru6765 7 жыл бұрын
wow! you made my subject DCD interesting.
@kilarisreenivasprasad8030
@kilarisreenivasprasad8030 3 жыл бұрын
Sir,you are my true and best inspiration.................
@sameerthor11
@sameerthor11 Жыл бұрын
sir you are a living legend hats off sir
@tabassumhebbalkar
@tabassumhebbalkar 8 жыл бұрын
Thanks a ton! your videos are so helpful :)
@alekdanser
@alekdanser 9 жыл бұрын
Thanks a lot for the videos they're really helpful! Would You mind making one on static hazards and iterative circuits? I find it hard to find a good explanatation regarding those 2 topics anywhere.Thanks again
@mohammadnaseer5413
@mohammadnaseer5413 Жыл бұрын
Good and easy explanation 👍🏻
@johncena8336
@johncena8336 9 жыл бұрын
great stuff man! keep up the good work.
@ajayjadhav-vc5wg
@ajayjadhav-vc5wg 8 жыл бұрын
great series of lectures!you are doing good job!
@HaidarTcm
@HaidarTcm 8 ай бұрын
Thanks legend, really if i have any course i need help i foud this channel to be the support❤
@xXAIvaNOosXx
@xXAIvaNOosXx 6 жыл бұрын
you can compare cin with both s and Co , if they cin equals to S or Co then you right the value of I = cin if Cin different with S or Co then you give the value of I C'in. thanks you so much my hero
@mssahin1572
@mssahin1572 9 жыл бұрын
Thanks for uploading these videos. They helped me a lot. I have a question. When A = 1 and B =1, how can Cout equal to 1?
@sukhdeepsaini1108
@sukhdeepsaini1108 5 жыл бұрын
we are talking about carry
@hitengupta5793
@hitengupta5793 5 жыл бұрын
Because when a=1 and when b=1 it gives C & C bar . So there is nothing common so we take it as one.
@mvssguptajagadesh3269
@mvssguptajagadesh3269 4 жыл бұрын
@@hitengupta5793 it should be Ci + Complement of Ci = 1. (Ci + Ci' = 1).... That's why it is one .
@goldenSpearton16
@goldenSpearton16 4 жыл бұрын
@@mvssguptajagadesh3269 tqs brother...!!!
@deepakkumrawat8312
@deepakkumrawat8312 7 жыл бұрын
Thank u a lot.. these videos are very helpful
@priyajitmondal6661
@priyajitmondal6661 8 ай бұрын
Thank you much sir❤
@sorryfornoname2157
@sorryfornoname2157 3 жыл бұрын
Fuck me. this guy explains this better than the teacher at college where i pay to study (the current education system works guys)
@nitishkumarprajapati6096
@nitishkumarprajapati6096 3 жыл бұрын
Thanks Sir😀😀
@riseabovehate9476
@riseabovehate9476 7 жыл бұрын
In an xor gates IC there are four exor gates so output of a xor b can be fed to input of 2nd xor gate with c in the same IC, so in this case also only one IC is required
@legolas433
@legolas433 3 жыл бұрын
all videos are great man thx
@samal-satyajit
@samal-satyajit Жыл бұрын
Today is my exam after couple of hours and am watching it now
@pratyushsingh2809
@pratyushsingh2809 7 жыл бұрын
when we use b and c as select lines. Den what will be the inputs in terms of A?
@WELLINGTONSIBANDA-t1t
@WELLINGTONSIBANDA-t1t 8 ай бұрын
what should I consider in choosing a MUX for implementing a particular Boolean function
@hyphenpointhyphen
@hyphenpointhyphen 9 жыл бұрын
I wondered till your solution of the hw problem how to derive the value of Ci, so input (last variable) decides what function is used, 00-> 0,11-> 1, Ci Ci'. Thanks for clearing that up.
@DoubleL_Leo
@DoubleL_Leo 2 жыл бұрын
Thank you sir
@sandeepanbhattacharyya828
@sandeepanbhattacharyya828 5 жыл бұрын
can we consider S1 and S2 to be B and Cin respectively
@tarunmarisetty2839
@tarunmarisetty2839 7 жыл бұрын
awesome explaination
@duanoor2767
@duanoor2767 2 күн бұрын
When implementing 1 bit full adder using 8X1 mux then in that case we would have three selection lines so we comsider a=s0 and b=s1 and cin =s2 so our output that we calculate from k map would be whole of expression like we will consider threee of the variables?like in 4X1 MUX WE WHEN SELECTION LINES WERE AB then we didnt conder ab and gave output while observing the behaviour of cin..Please,help me to clarify my logic ...am i going on straight direction?
@rishavkashyap325
@rishavkashyap325 7 жыл бұрын
do we need to connect the select lines of one mux to other ???
@vishwarajendran1483
@vishwarajendran1483 6 жыл бұрын
For Carry output, inputs are 0,Ci,Ci,1.
@kuldeeptiwari3424
@kuldeeptiwari3424 6 жыл бұрын
Kaisa Bhai . Mera nhi aaraha h
@vijayanethala4973
@vijayanethala4973 5 жыл бұрын
How did u get that...I got x,ci,ci,x bcz when A=0,B=0 ci changes from 0 to 1
@sadhanasavkare7662
@sadhanasavkare7662 5 жыл бұрын
@@vijayanethala4973 then ci=1.but in video its ci=0.correction is needed.
@ShaanThor
@ShaanThor Ай бұрын
​@kuldeeptiwari3424 bhai easy he batau?
@SomiMm-q1g
@SomiMm-q1g 11 ай бұрын
Thank you
@joshitapapareddy9845
@joshitapapareddy9845 7 жыл бұрын
Hello sir, How should we apply the same using 8:1 multiplexer? Please reply as soon as possible, thank you!
@sanjukansal8206
@sanjukansal8206 7 жыл бұрын
What if we have to do it by 8×1 MUX? As it contains 3 selectors.
@rohitsayandip6741
@rohitsayandip6741 9 жыл бұрын
Thanks a lot man.
@Zuwwar
@Zuwwar 10 жыл бұрын
Dear Nesco, i have a question which is that u said that in case of (4:1 multiplexer) your input would b the Cin and A,B would be your select lines. Now in case of (8:1 multiplexer), i would have 3 select lines that is A,B,Cin. so what would be my input then in case of (8:1 MUX)? Because in this case Cin is also considered as a select line.
@chandumistimer8406
@chandumistimer8406 7 жыл бұрын
Zuwwar Khan Jadoon we can directly give sum as input den
@mukulmohal7492
@mukulmohal7492 9 жыл бұрын
why we have used only A and B as S0 & S1 can we use Cin in place of either A or B
@kunalkadian6792
@kunalkadian6792 6 жыл бұрын
why we dont use bc as select line and then just use A and Acomp as input
@renuka8372
@renuka8372 Жыл бұрын
@ShivaKumar-xq8yk
@ShivaKumar-xq8yk 6 жыл бұрын
Sir how to implemente the same question with 2 by 1 MUX.....?
@tiboosters9668
@tiboosters9668 5 жыл бұрын
why not make it with one 8x1 MUX, instead of two 4x1 MUX ?
@tharindukrishan6789
@tharindukrishan6789 6 жыл бұрын
Thanks a lot!
@letsbehelpinghands246
@letsbehelpinghands246 8 жыл бұрын
thank you so much..
@utkarshshukla231
@utkarshshukla231 5 жыл бұрын
Suppose s1 = 0 and s0 = 0 for sum then how will Ci's value be taken ... As 1 or as 0 as TT has both at m0 and m1
@khaldounal-nuaimi3594
@khaldounal-nuaimi3594 5 жыл бұрын
Thank you!
@Caraval
@Caraval 8 жыл бұрын
why the last input for the second mux is 1, can you explain it? thanks
@vaibhavahuja4001
@vaibhavahuja4001 7 жыл бұрын
see the k map, when A and B both are 1, the shaded area has both of the squares as 1, hence I3 is 1.
@deepaksahoo9336
@deepaksahoo9336 6 жыл бұрын
Vedprakash Meena thanks dude
@akashdubey9132
@akashdubey9132 6 жыл бұрын
@Vedprakash Meenalooking for the answer. This is the correct one.
@saurabhraj8477
@saurabhraj8477 6 жыл бұрын
As Ci+~Ci=1
@AshranBaig
@AshranBaig 7 жыл бұрын
how 1 will be there in the input of carry MUX?
@ravimaurya9674
@ravimaurya9674 4 жыл бұрын
Because its Ci + Ci(bar) = 1
@NATANSHROCKS
@NATANSHROCKS 8 жыл бұрын
Sir could you please tell me the answer of the homework question. Thanks
@_cxc_8198
@_cxc_8198 7 жыл бұрын
thank you so much :D
@sanjanadogga3856
@sanjanadogga3856 6 жыл бұрын
Implement a multiplexer using 36 input lines , how many selection lines are needed?
@jackdanksterdawson112
@jackdanksterdawson112 7 жыл бұрын
How do u determine the select line variables y did u take a and b why not b and cin
@jackdanksterdawson112
@jackdanksterdawson112 7 жыл бұрын
Vedprakash Meena my xams over!!
@yugayadav5906
@yugayadav5906 3 жыл бұрын
THANKS YOU FOR SUPORTING
@thesorcerer111
@thesorcerer111 9 жыл бұрын
Sir I'm a big fan of your videos, but could you please make one on "the implementation of a full adder using 2 4x1 mux". That'd be very helpful.
@thesorcerer111
@thesorcerer111 9 жыл бұрын
+Neso Academy Thanks!!
@abudriaz9678
@abudriaz9678 8 жыл бұрын
but there are already 2 4×1 mux in it 😐
@utsavprabhakar5072
@utsavprabhakar5072 6 жыл бұрын
What am i missing? This has 2 4*1 mux and this is a full adder? +thesorcerer111 mate did you find the answer?
@chiluvurideepthi6822
@chiluvurideepthi6822 4 жыл бұрын
For the 2nd MUX(For carry) , when A=1,B=1 ,then how the output is 1,by k-map...? And thank you for the video.
@sainadhrahul4450
@sainadhrahul4450 3 жыл бұрын
Since Both Minterms are present I3= Ci + Ci ' which is Equal to 1
@_zerox_X
@_zerox_X 2 жыл бұрын
How should we know which mux should we use like here he used 4 x 1 mux
@bhawika902
@bhawika902 5 жыл бұрын
Thank u
@bjornnct8809
@bjornnct8809 5 жыл бұрын
Hey how do you design a 1 bit full adder using exnor gates and a mux ? Please respond... I need help
@RadixElektra
@RadixElektra 7 жыл бұрын
ctrl C, for copy ctrl V, for paste,
@studentcommenter5858
@studentcommenter5858 6 жыл бұрын
Did you just assume him to be using a keyboard? He may be using a touchpad and mouse.
@NaveenSword
@NaveenSword 6 жыл бұрын
@@studentcommenter5858 he uses wacom tablet and wacom digital pen.
@justinrosario3053
@justinrosario3053 5 жыл бұрын
god bless you sir
@VC-kj9yx
@VC-kj9yx 9 жыл бұрын
what if there is a dont care in k-map
@aqibshafique8671
@aqibshafique8671 8 жыл бұрын
Can we also add Enable in Full adder using Multiplexer ? And enable in in 2:1 Multiplexer ? Why we use Enable in 4:1 Mux special case ? Kindly solve my problem Thanks
@ShubhamSingh-bj3ms
@ShubhamSingh-bj3ms 8 жыл бұрын
HAFIZ Aqib Shiekh what u want
@shahzaibishaque
@shahzaibishaque 6 жыл бұрын
Enable is somrthing we use when we want our MUX to give 0 output or 1 by our choice. It is helpful in certain cases e.g in case of 8*1 MUX using 4*1 MUX we use enable to off our one of the two 4*1 MUX
@anastariq8464
@anastariq8464 Жыл бұрын
what about the i0.....there is no 1 in shaded region when a and b both are zero
@ajaysrivastav5412
@ajaysrivastav5412 8 жыл бұрын
Can you please tell why I3=1 for "carry" in Kmap ?
@explorewithvikas3019
@explorewithvikas3019 4 жыл бұрын
Explain??
@adhishravi20
@adhishravi20 5 жыл бұрын
B and ci are the selector variable??
@yugeshvemula8044
@yugeshvemula8044 7 жыл бұрын
plz explain about 2 to 1 multiplexer by using 74LS150
@jaswanthsai1917
@jaswanthsai1917 5 жыл бұрын
For the last two cases A=1,B=1 then why do we get different ie., Ci, 1
@madhavsaha962
@madhavsaha962 8 жыл бұрын
please solve the Boolean function using 8*1 mux please.. thank you.
@gouravmanchanda9301
@gouravmanchanda9301 9 жыл бұрын
this playlist does not include videos of multiplexer...please upload those videos...
@rebihamounder2185
@rebihamounder2185 8 жыл бұрын
thnx it help full
@sureshdudyala2589
@sureshdudyala2589 6 жыл бұрын
Down part is not visible
@ashibindal6644
@ashibindal6644 9 жыл бұрын
sir can u plz explain how to design 32*1 mux using 8*1 and 4*1 mux
@alagarhari9410
@alagarhari9410 4 жыл бұрын
Can we select selector variables as per our wish
@ANIKETKUMAR-su1kf
@ANIKETKUMAR-su1kf 8 жыл бұрын
please solve implement of full adder using using 4:1 mux
@Naveenkumar-qu9lk
@Naveenkumar-qu9lk 4 жыл бұрын
Sir...if we take select lines different is there any change in answer...?
@aravindosarkar341
@aravindosarkar341 7 жыл бұрын
Pls make a video that shows how to implement a 4 variable Sop or pos expression using a 8:1 Mux. Suppose the expression is Y(A, B, C, D) = Summation of m(0,2,3,6,8,9,12,14)
@santoshodeyar9736
@santoshodeyar9736 2 жыл бұрын
I did that bro
@SahaabMansha
@SahaabMansha Жыл бұрын
sir can we use one 8x1 to make 1 bit full adder
@ankit4376
@ankit4376 6 жыл бұрын
How to determine I3 for carry
@gunduboinadileep9523
@gunduboinadileep9523 Жыл бұрын
if we take BC as selectors it will be more easy I think
@AKJOSHI28
@AKJOSHI28 4 жыл бұрын
Sir, how the value of I4=1 in the case of Carry ???
@Zuwwar
@Zuwwar 10 жыл бұрын
i mean in 8:1 MUX... A,B,Cin these all are your select lines, so what would be your input then?
@Zuwwar
@Zuwwar 10 жыл бұрын
***** So when would it be "0" and when would it be "1" ?
@Zuwwar
@Zuwwar 10 жыл бұрын
***** thanks :)
@TheShahzebrizvi
@TheShahzebrizvi 5 жыл бұрын
Can you do a video on ALU
@jamestoh8853
@jamestoh8853 9 жыл бұрын
How do you get 1 and 0 as the answer?
@Vishtory
@Vishtory 8 жыл бұрын
+Jason Ramia sir, as for i3 c iz changed from 1 to zero then how could we can take it as 1 ...if smthng changes we dnt take it in account. please explain.
@gunar3939
@gunar3939 7 жыл бұрын
I need to know for last c whose value is 1
@arslanmalik6151
@arslanmalik6151 8 жыл бұрын
i did home task of carry but i didnt inderstand how you write 1 as last input of carry circuit can you elaborate it plz?
@nikhilkoditala369
@nikhilkoditala369 8 жыл бұрын
you can see from the k-map of carry out, the values of lat two blocks is 1,i.e., when A and B both are 1's the value of i4=c'+c which is equal to 1. hope this helps
@baldeepsingh1113
@baldeepsingh1113 6 жыл бұрын
how to implement 4 variable function of POS using 4x1 muxF(A,B,C,D)=POS (0,1,4,5,7,8,11,13) using 4x1 multiplexer
@animeshbanerjee4379
@animeshbanerjee4379 6 жыл бұрын
Can u again explain i0=ci ,i1=c1(bar)....why ???
@roosterstudio
@roosterstudio 10 жыл бұрын
Can you explane me... Can we make 4-bit adder with this structure for 1-bit adder?
@roosterstudio
@roosterstudio 10 жыл бұрын
How? Are we connect some outputs or make another true tables?
@roosterstudio
@roosterstudio 10 жыл бұрын
***** Thank you a lot! I understand now :)
@TheAmigodaniel
@TheAmigodaniel 8 жыл бұрын
i could not get the Cout as you described it there is something am missing? Can you explain it?
@NANDANKUMAR-ps3nw
@NANDANKUMAR-ps3nw 7 жыл бұрын
plz explain it for carry
@sanskritijain9700
@sanskritijain9700 4 жыл бұрын
sir how is I3=1 in 4*1 mux of carry output
@zainadiab2699
@zainadiab2699 8 жыл бұрын
how to design a 2-bit binary control adder/subtractor using 2 full adders , 2 NOR gates , and two 2x1 mux
@HabibUrRahman-mu8zf
@HabibUrRahman-mu8zf 5 жыл бұрын
Why can't you use implementation table??
@swarnavanath461
@swarnavanath461 5 жыл бұрын
In case of I3 C(i ) is changing from 1 to 0 i.e. the last two cells How is it 1?
@abhinavbhat6629
@abhinavbhat6629 5 жыл бұрын
Exactly. Did you figure it out yet?
@mdnahidislam1908
@mdnahidislam1908 5 жыл бұрын
My question too.
@aswinp888
@aswinp888 5 жыл бұрын
Yep so u have to take both the cells as we do in normal K map. So Ci +C ̅i=1 by Boolean Algebra Laws
@abdulrahmanhamdan4355
@abdulrahmanhamdan4355 7 жыл бұрын
in carry combinational circuit you represent i0=0 and i3=1,on the other hand in sum circuit you represent them by c and c complement why?
@akashbisht22
@akashbisht22 7 жыл бұрын
because on analyzing the truth table for carry Mux selector inputs (A, B in this case), we found that : When S1= 0 , S0 =0 ; we have 0 in K map, hence i0 = 0 & when S1= 0, S0 = 1 ; we have Cin = 1 in K map, hence i1 = Cin (Same is the case when S1 =1 & S0 =0 & i2 = Cin) & When S1 = 1, S = 1 ; we have Both A' & A = 1 in K map, hence i3 = 1. Hope it helps. :)
@rprvk
@rprvk 6 жыл бұрын
I think I3 is 0 By grouping we get 0
@aradhanakaushal5422
@aradhanakaushal5422 3 жыл бұрын
I did this way .. but out of 5 marks only 3 was given stating u need to draw reduced truth table for this...
@nurulfarhana823
@nurulfarhana823 6 жыл бұрын
Could you show how to do combinational circuit with multiplier of 4 bits
@luking4freedom181
@luking4freedom181 6 жыл бұрын
Thanks curry man
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