For question at the end: To get 1 for i3, the shaded region that satisfies A=1 & B=1 shows that there are two 1s, if you group them, you can see that Ci changes from 1 to 0, making the answer 1; to help you more, take each 1 alone (generally bad idea), you'll realize you have Ci+Ci' which is equal to 1
@siddhantmeshram40923 жыл бұрын
I don't know who you are or where you live but thank you thank you !
@starkendeavours70723 жыл бұрын
Tysm.
@bhouyem23152 жыл бұрын
thank u sm
@rishavyadav94382 жыл бұрын
Thank you
@satyampatel32442 жыл бұрын
tqsm
@tacoz44298 жыл бұрын
Thank you. You have pretty much saved me from failing the course. :') There is still hope.
@malikhamza22856 жыл бұрын
sir you are the only one reason behind my DLD interest.thanks alot for your service.stay blessed
@abhiramanne96494 жыл бұрын
I will be frank I feel like my lecturer for digital electronics is literally following neso academy.
@ranjeet58063 жыл бұрын
Probably your teacher is the one who's running neso academy.
@saimyousuf21085 жыл бұрын
Best channel to learn digital logic
@reona37135 жыл бұрын
your explanations are better than my prof. Good job
@josuezalazar3 жыл бұрын
The logic to use the full Adder carry output is: i0 = 0, i1 = Cin, i2 = Cin, i3 = 1.
@nandinisharma33602 жыл бұрын
Can you explain me how i3 come 1 it's very confused me 😶
@josuezalazar2 жыл бұрын
@@nandinisharma3360 hey, it's been a while since I studied this. I've just checked it out and I think that i3 = 1 because in the Kmap when A = 1 & B = 1 there're two posible answers. And those answers would be written as Ci or Ci' which equals to 1.
@nandinisharma33602 жыл бұрын
@@josuezalazar then why we written i2 = Ci, why not 1 ?😶
@josuezalazar2 жыл бұрын
@@nandinisharma3360 because in i2 is when A=1 & B=0 and as you can see we have two options. One of them is 0 and the other is 1. We use the option that's 1, and that option occurs when Ci is 1, or in other words, i2 = Ci
@nandinisharma33602 жыл бұрын
@@josuezalazar sorry bt it's very confusing me😶😶😞
@hotaru67657 жыл бұрын
wow! you made my subject DCD interesting.
@kilarisreenivasprasad80303 жыл бұрын
Sir,you are my true and best inspiration.................
@sameerthor11 Жыл бұрын
sir you are a living legend hats off sir
@tabassumhebbalkar8 жыл бұрын
Thanks a ton! your videos are so helpful :)
@alekdanser9 жыл бұрын
Thanks a lot for the videos they're really helpful! Would You mind making one on static hazards and iterative circuits? I find it hard to find a good explanatation regarding those 2 topics anywhere.Thanks again
@mohammadnaseer5413 Жыл бұрын
Good and easy explanation 👍🏻
@johncena83369 жыл бұрын
great stuff man! keep up the good work.
@ajayjadhav-vc5wg8 жыл бұрын
great series of lectures!you are doing good job!
@HaidarTcm8 ай бұрын
Thanks legend, really if i have any course i need help i foud this channel to be the support❤
@xXAIvaNOosXx6 жыл бұрын
you can compare cin with both s and Co , if they cin equals to S or Co then you right the value of I = cin if Cin different with S or Co then you give the value of I C'in. thanks you so much my hero
@mssahin15729 жыл бұрын
Thanks for uploading these videos. They helped me a lot. I have a question. When A = 1 and B =1, how can Cout equal to 1?
@sukhdeepsaini11085 жыл бұрын
we are talking about carry
@hitengupta57935 жыл бұрын
Because when a=1 and when b=1 it gives C & C bar . So there is nothing common so we take it as one.
@mvssguptajagadesh32694 жыл бұрын
@@hitengupta5793 it should be Ci + Complement of Ci = 1. (Ci + Ci' = 1).... That's why it is one .
@goldenSpearton164 жыл бұрын
@@mvssguptajagadesh3269 tqs brother...!!!
@deepakkumrawat83127 жыл бұрын
Thank u a lot.. these videos are very helpful
@priyajitmondal66618 ай бұрын
Thank you much sir❤
@sorryfornoname21573 жыл бұрын
Fuck me. this guy explains this better than the teacher at college where i pay to study (the current education system works guys)
@nitishkumarprajapati60963 жыл бұрын
Thanks Sir😀😀
@riseabovehate94767 жыл бұрын
In an xor gates IC there are four exor gates so output of a xor b can be fed to input of 2nd xor gate with c in the same IC, so in this case also only one IC is required
@legolas4333 жыл бұрын
all videos are great man thx
@samal-satyajit Жыл бұрын
Today is my exam after couple of hours and am watching it now
@pratyushsingh28097 жыл бұрын
when we use b and c as select lines. Den what will be the inputs in terms of A?
@WELLINGTONSIBANDA-t1t8 ай бұрын
what should I consider in choosing a MUX for implementing a particular Boolean function
@hyphenpointhyphen9 жыл бұрын
I wondered till your solution of the hw problem how to derive the value of Ci, so input (last variable) decides what function is used, 00-> 0,11-> 1, Ci Ci'. Thanks for clearing that up.
@DoubleL_Leo2 жыл бұрын
Thank you sir
@sandeepanbhattacharyya8285 жыл бұрын
can we consider S1 and S2 to be B and Cin respectively
@tarunmarisetty28397 жыл бұрын
awesome explaination
@duanoor27672 күн бұрын
When implementing 1 bit full adder using 8X1 mux then in that case we would have three selection lines so we comsider a=s0 and b=s1 and cin =s2 so our output that we calculate from k map would be whole of expression like we will consider threee of the variables?like in 4X1 MUX WE WHEN SELECTION LINES WERE AB then we didnt conder ab and gave output while observing the behaviour of cin..Please,help me to clarify my logic ...am i going on straight direction?
@rishavkashyap3257 жыл бұрын
do we need to connect the select lines of one mux to other ???
@vishwarajendran14836 жыл бұрын
For Carry output, inputs are 0,Ci,Ci,1.
@kuldeeptiwari34246 жыл бұрын
Kaisa Bhai . Mera nhi aaraha h
@vijayanethala49735 жыл бұрын
How did u get that...I got x,ci,ci,x bcz when A=0,B=0 ci changes from 0 to 1
@sadhanasavkare76625 жыл бұрын
@@vijayanethala4973 then ci=1.but in video its ci=0.correction is needed.
@ShaanThorАй бұрын
@kuldeeptiwari3424 bhai easy he batau?
@SomiMm-q1g11 ай бұрын
Thank you
@joshitapapareddy98457 жыл бұрын
Hello sir, How should we apply the same using 8:1 multiplexer? Please reply as soon as possible, thank you!
@sanjukansal82067 жыл бұрын
What if we have to do it by 8×1 MUX? As it contains 3 selectors.
@rohitsayandip67419 жыл бұрын
Thanks a lot man.
@Zuwwar10 жыл бұрын
Dear Nesco, i have a question which is that u said that in case of (4:1 multiplexer) your input would b the Cin and A,B would be your select lines. Now in case of (8:1 multiplexer), i would have 3 select lines that is A,B,Cin. so what would be my input then in case of (8:1 MUX)? Because in this case Cin is also considered as a select line.
@chandumistimer84067 жыл бұрын
Zuwwar Khan Jadoon we can directly give sum as input den
@mukulmohal74929 жыл бұрын
why we have used only A and B as S0 & S1 can we use Cin in place of either A or B
@kunalkadian67926 жыл бұрын
why we dont use bc as select line and then just use A and Acomp as input
@renuka8372 Жыл бұрын
@ShivaKumar-xq8yk6 жыл бұрын
Sir how to implemente the same question with 2 by 1 MUX.....?
@tiboosters96685 жыл бұрын
why not make it with one 8x1 MUX, instead of two 4x1 MUX ?
@tharindukrishan67896 жыл бұрын
Thanks a lot!
@letsbehelpinghands2468 жыл бұрын
thank you so much..
@utkarshshukla2315 жыл бұрын
Suppose s1 = 0 and s0 = 0 for sum then how will Ci's value be taken ... As 1 or as 0 as TT has both at m0 and m1
@khaldounal-nuaimi35945 жыл бұрын
Thank you!
@Caraval8 жыл бұрын
why the last input for the second mux is 1, can you explain it? thanks
@vaibhavahuja40017 жыл бұрын
see the k map, when A and B both are 1, the shaded area has both of the squares as 1, hence I3 is 1.
@deepaksahoo93366 жыл бұрын
Vedprakash Meena thanks dude
@akashdubey91326 жыл бұрын
@Vedprakash Meenalooking for the answer. This is the correct one.
@saurabhraj84776 жыл бұрын
As Ci+~Ci=1
@AshranBaig7 жыл бұрын
how 1 will be there in the input of carry MUX?
@ravimaurya96744 жыл бұрын
Because its Ci + Ci(bar) = 1
@NATANSHROCKS8 жыл бұрын
Sir could you please tell me the answer of the homework question. Thanks
@_cxc_81987 жыл бұрын
thank you so much :D
@sanjanadogga38566 жыл бұрын
Implement a multiplexer using 36 input lines , how many selection lines are needed?
@jackdanksterdawson1127 жыл бұрын
How do u determine the select line variables y did u take a and b why not b and cin
@jackdanksterdawson1127 жыл бұрын
Vedprakash Meena my xams over!!
@yugayadav59063 жыл бұрын
THANKS YOU FOR SUPORTING
@thesorcerer1119 жыл бұрын
Sir I'm a big fan of your videos, but could you please make one on "the implementation of a full adder using 2 4x1 mux". That'd be very helpful.
@thesorcerer1119 жыл бұрын
+Neso Academy Thanks!!
@abudriaz96788 жыл бұрын
but there are already 2 4×1 mux in it 😐
@utsavprabhakar50726 жыл бұрын
What am i missing? This has 2 4*1 mux and this is a full adder? +thesorcerer111 mate did you find the answer?
@chiluvurideepthi68224 жыл бұрын
For the 2nd MUX(For carry) , when A=1,B=1 ,then how the output is 1,by k-map...? And thank you for the video.
@sainadhrahul44503 жыл бұрын
Since Both Minterms are present I3= Ci + Ci ' which is Equal to 1
@_zerox_X2 жыл бұрын
How should we know which mux should we use like here he used 4 x 1 mux
@bhawika9025 жыл бұрын
Thank u
@bjornnct88095 жыл бұрын
Hey how do you design a 1 bit full adder using exnor gates and a mux ? Please respond... I need help
@RadixElektra7 жыл бұрын
ctrl C, for copy ctrl V, for paste,
@studentcommenter58586 жыл бұрын
Did you just assume him to be using a keyboard? He may be using a touchpad and mouse.
@NaveenSword6 жыл бұрын
@@studentcommenter5858 he uses wacom tablet and wacom digital pen.
@justinrosario30535 жыл бұрын
god bless you sir
@VC-kj9yx9 жыл бұрын
what if there is a dont care in k-map
@aqibshafique86718 жыл бұрын
Can we also add Enable in Full adder using Multiplexer ? And enable in in 2:1 Multiplexer ? Why we use Enable in 4:1 Mux special case ? Kindly solve my problem Thanks
@ShubhamSingh-bj3ms8 жыл бұрын
HAFIZ Aqib Shiekh what u want
@shahzaibishaque6 жыл бұрын
Enable is somrthing we use when we want our MUX to give 0 output or 1 by our choice. It is helpful in certain cases e.g in case of 8*1 MUX using 4*1 MUX we use enable to off our one of the two 4*1 MUX
@anastariq8464 Жыл бұрын
what about the i0.....there is no 1 in shaded region when a and b both are zero
@ajaysrivastav54128 жыл бұрын
Can you please tell why I3=1 for "carry" in Kmap ?
@explorewithvikas30194 жыл бұрын
Explain??
@adhishravi205 жыл бұрын
B and ci are the selector variable??
@yugeshvemula80447 жыл бұрын
plz explain about 2 to 1 multiplexer by using 74LS150
@jaswanthsai19175 жыл бұрын
For the last two cases A=1,B=1 then why do we get different ie., Ci, 1
@madhavsaha9628 жыл бұрын
please solve the Boolean function using 8*1 mux please.. thank you.
@gouravmanchanda93019 жыл бұрын
this playlist does not include videos of multiplexer...please upload those videos...
@rebihamounder21858 жыл бұрын
thnx it help full
@sureshdudyala25896 жыл бұрын
Down part is not visible
@ashibindal66449 жыл бұрын
sir can u plz explain how to design 32*1 mux using 8*1 and 4*1 mux
@alagarhari94104 жыл бұрын
Can we select selector variables as per our wish
@ANIKETKUMAR-su1kf8 жыл бұрын
please solve implement of full adder using using 4:1 mux
@Naveenkumar-qu9lk4 жыл бұрын
Sir...if we take select lines different is there any change in answer...?
@aravindosarkar3417 жыл бұрын
Pls make a video that shows how to implement a 4 variable Sop or pos expression using a 8:1 Mux. Suppose the expression is Y(A, B, C, D) = Summation of m(0,2,3,6,8,9,12,14)
@santoshodeyar97362 жыл бұрын
I did that bro
@SahaabMansha Жыл бұрын
sir can we use one 8x1 to make 1 bit full adder
@ankit43766 жыл бұрын
How to determine I3 for carry
@gunduboinadileep9523 Жыл бұрын
if we take BC as selectors it will be more easy I think
@AKJOSHI284 жыл бұрын
Sir, how the value of I4=1 in the case of Carry ???
@Zuwwar10 жыл бұрын
i mean in 8:1 MUX... A,B,Cin these all are your select lines, so what would be your input then?
@Zuwwar10 жыл бұрын
***** So when would it be "0" and when would it be "1" ?
@Zuwwar10 жыл бұрын
***** thanks :)
@TheShahzebrizvi5 жыл бұрын
Can you do a video on ALU
@jamestoh88539 жыл бұрын
How do you get 1 and 0 as the answer?
@Vishtory8 жыл бұрын
+Jason Ramia sir, as for i3 c iz changed from 1 to zero then how could we can take it as 1 ...if smthng changes we dnt take it in account. please explain.
@gunar39397 жыл бұрын
I need to know for last c whose value is 1
@arslanmalik61518 жыл бұрын
i did home task of carry but i didnt inderstand how you write 1 as last input of carry circuit can you elaborate it plz?
@nikhilkoditala3698 жыл бұрын
you can see from the k-map of carry out, the values of lat two blocks is 1,i.e., when A and B both are 1's the value of i4=c'+c which is equal to 1. hope this helps
@baldeepsingh11136 жыл бұрын
how to implement 4 variable function of POS using 4x1 muxF(A,B,C,D)=POS (0,1,4,5,7,8,11,13) using 4x1 multiplexer
@animeshbanerjee43796 жыл бұрын
Can u again explain i0=ci ,i1=c1(bar)....why ???
@roosterstudio10 жыл бұрын
Can you explane me... Can we make 4-bit adder with this structure for 1-bit adder?
@roosterstudio10 жыл бұрын
How? Are we connect some outputs or make another true tables?
@roosterstudio10 жыл бұрын
***** Thank you a lot! I understand now :)
@TheAmigodaniel8 жыл бұрын
i could not get the Cout as you described it there is something am missing? Can you explain it?
@NANDANKUMAR-ps3nw7 жыл бұрын
plz explain it for carry
@sanskritijain97004 жыл бұрын
sir how is I3=1 in 4*1 mux of carry output
@zainadiab26998 жыл бұрын
how to design a 2-bit binary control adder/subtractor using 2 full adders , 2 NOR gates , and two 2x1 mux
@HabibUrRahman-mu8zf5 жыл бұрын
Why can't you use implementation table??
@swarnavanath4615 жыл бұрын
In case of I3 C(i ) is changing from 1 to 0 i.e. the last two cells How is it 1?
@abhinavbhat66295 жыл бұрын
Exactly. Did you figure it out yet?
@mdnahidislam19085 жыл бұрын
My question too.
@aswinp8885 жыл бұрын
Yep so u have to take both the cells as we do in normal K map. So Ci +C ̅i=1 by Boolean Algebra Laws
@abdulrahmanhamdan43557 жыл бұрын
in carry combinational circuit you represent i0=0 and i3=1,on the other hand in sum circuit you represent them by c and c complement why?
@akashbisht227 жыл бұрын
because on analyzing the truth table for carry Mux selector inputs (A, B in this case), we found that : When S1= 0 , S0 =0 ; we have 0 in K map, hence i0 = 0 & when S1= 0, S0 = 1 ; we have Cin = 1 in K map, hence i1 = Cin (Same is the case when S1 =1 & S0 =0 & i2 = Cin) & When S1 = 1, S = 1 ; we have Both A' & A = 1 in K map, hence i3 = 1. Hope it helps. :)
@rprvk6 жыл бұрын
I think I3 is 0 By grouping we get 0
@aradhanakaushal54223 жыл бұрын
I did this way .. but out of 5 marks only 3 was given stating u need to draw reduced truth table for this...
@nurulfarhana8236 жыл бұрын
Could you show how to do combinational circuit with multiplier of 4 bits