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@AlaskarAbdoul Жыл бұрын
/* Can you create a program to check whether a number is odd or eve? > Use a ternary operator to check if the number is odd or even. > If number is odd, print "The number is Odd" > If number is even, print "The number is Even" */ #include int main() { int number; printf("Enter a number: "); scanf("%d", &number); // by using Ternary Operator (number % 2==0) ? printf("The number is Even") : printf("The number is Odd"); }
@eazyj_c11 ай бұрын
thanks
@zonekenne53299 ай бұрын
did you try doing this operation with the "double" data type? @@eazyj_c
@user-qq1ze2ml2q7 ай бұрын
Thank You!
@varalakshmidevathi79972 ай бұрын
Thanks
@hurulaynmuhamedsalimcedarp57702 жыл бұрын
Programming Task: #include int main() { int number; printf("Enter a number: "); scanf("%d", &number); (number%2 == 0) ? printf("%d is an even number.", number) : printf("%d is an odd number.", number); return 0; }
@msreekanth88864 ай бұрын
wtf
@joechen94982 ай бұрын
#include int main() { int number; printf("Please enter the number:"); scanf("%d", &number); (number%2 == 0) ? printf("Number is an even number"): printf("Number is an odd number"); return 0; }
@michaelspencer60082 жыл бұрын
You did an excellent job explaining the switch statement. I was and am still amazed at how easy you made this so understandable. Please continue teaching us. You have an absolute gift in how you explain these concepts. Thank you sooo much!
@user-be1qh8iz5u5 ай бұрын
hey buddy! How much part of C have you completed to date?
@rhythmahmed18732 жыл бұрын
//Can you create a program to check whether a number is odd or even? //***Use a ternary operator to check if the number is odd or even //***If the number is odd print the number is odd //***If the number is even print the number is even #include int main() { int number; printf("Enter a number: "); scanf("%d", &number); (number % 2==0) ? printf("The number is Even.") : printf("The number is Odd."); return 0; }
@nuetrkn Жыл бұрын
Thank you
@yasminehey3854 Жыл бұрын
i did the same thing and it worked but later on i made the ternary as int result=(number % 2==0) ? printf("The number is Even.") : printf("The number is Odd."); but when i print the resut itdoes say in the output whether the number is odd or even but it always adds 13 or 14 i dont understand why there is the "14 or 13 "
@sanargasimov Жыл бұрын
@@yasminehey3854 The program then checks whether 'num' is even or odd using the modulus operator %, and uses the ternary operator to print a message indicating whether the number is even or odd. However, the use of 'printf' in the ternary operator is not recommended because it returns the number of characters printed, not the value of the condition. As a result, the value of result will be 23 or 19, depending on the message printed. A better approach would be to use a separate variable to store the message, and then print that variable and the value of result separately. Here's an updated version of the program: #include int main() { int num = 78; char* message = (num % 2 == 0) ? "Your number is EVEN" : "Your number is ODD"; printf("%s ", message); int result = (num % 2 == 0) ? 0 : 1; printf("%d ", result); return 0; } This program first declares a char* variable named message, and assigns it a string value based on whether num is even or odd. It then uses printf to print message and a newline character. Finally, it declares an int variable named result, and assigns it a value of 0 if num is even or 1 if num is odd. It then uses printf to print result and a newline character.
@sammuchina8189 Жыл бұрын
in this part of your code, " (number % 2==0) ? printf("The number is Even.") : printf("The number is Odd."); " what does the % mean kindly🙏
@muhammadfukii1518 Жыл бұрын
@@sammuchina8189 % is could be DEVISION or as per our concept REMAINDER
@SANJAYR-yy1zg6 ай бұрын
Answer is option c Result=5>3 ? 5 : 3;
@rahulc.h2440 Жыл бұрын
for the quiz, it opts C coz in the if-else statement the if part is evaluated to be true and hence gives 5 so the same principle applies Ternary:- (CONDITION) ? Statement1(Executed when True) : Statement2(Executed when False)
@abdulazizhabib44417 ай бұрын
it is option c
@adityasharma394711 ай бұрын
B as we have to print Result = 5 but in C the value of just 5 is will be as output
@batmanelhakeky11 ай бұрын
Your tutorials are so helpful. i learnt switch statement and im now learning tenrary operator. keep the great work up!
@shohanurrahmanshoron18042 жыл бұрын
I tried this in front of my teacher and even he doesn't know about this operator. Thank U❤️❤️❤️
@shankaradari4741 Жыл бұрын
Really useful content I really want to thank the teachers who are making the classes
@sundeepchowdaryattaluri87972 жыл бұрын
Thanks for providing this useful and & well content for us.... Code #include int main() { int a; scanf("%d", &a); (a %2 ==0) ? printf("%d is even", a): printf("%d is odd", a); } Ans for Question is C.
@benchmarkslab20052 жыл бұрын
One thing I can't understand bro. Why we used %d is even and %d is odd. If I used without %d it isn't working. But they didn't use %d in age calculator. Plzz explain bro
@rakesh1045 Жыл бұрын
#include int main(); { Int number=2; (number % 2 == 0) ? Printf("the number is even") : printf("the number is odd"); return 0 ; }
@Judyy.Sabryy10 ай бұрын
Love it, explantion was clear and straightforward, however, I suggest you also talk about how to implement nested Ternary operators.
@annettewairimu55425 ай бұрын
how are you doing after 5 months in programming?
@mdsahil22032 жыл бұрын
Thanks for providing " Good quality "content By the way answer is option C
@shreyasy91642 жыл бұрын
why c
@shreyasy91642 жыл бұрын
i think option B is corrrect
@mandip8632 жыл бұрын
@@shreyasy9164 yes boss b is ans
@dhanushs18022 жыл бұрын
@@shreyasy9164 in the option B, if you change 5>3 to 3>5 , result will be 0 instead the result should be 3. So C is the answer.
@monalisabanra2733 Жыл бұрын
b can also be the answer i checked it
@qarikhalidwaheed1643 Жыл бұрын
Thanks for explaining this code simply
@user-nt4nm4fb3u7 ай бұрын
Great explanation as always! Thank you for everyone to make this happen.
@annettewairimu55425 ай бұрын
how are you doing after two months?
@sunangashilpakar36722 жыл бұрын
Thankyou for explaining it so simply.. was waiting for your video ❤️
@annettewairimu55425 ай бұрын
how are you doing after two years in programming?
@kankarlabharath68192 жыл бұрын
Mam your explanation is very good and nice, can you make a tutorial videos on Data structures and algorithms in good explanation based on c language.
@pristinewalek45782 жыл бұрын
Beautiful 🤩 Thank you for explaining it so well
@Ech-chatouiMohammed3 күн бұрын
VERY GREAT CONTENT
@Darkness-8983 ай бұрын
PROGRAMMING TASK: #include int main() { int num; printf("Enter number here: "); scanf("%d", &num); (num%2==0)?printf("The number is even."):printf("The number is odd."); return 0; } PROGRAMIZ QUIZ ANSWER: Option(B) 5>3?5:3;
@laxmanpeddi97142 жыл бұрын
(option c)...........cool and clear content by progrmizzzz.....plz keep going......
@shreyasy91642 жыл бұрын
why c??????
@pretty_you2243 Жыл бұрын
@@shreyasy9164 5>3? Is a condition. After evaluating the condition, value will be assigned to result variable as either 5 or 3.
@alirezaz98962 жыл бұрын
the best C language tutorial👌👌👌
@qarikhalidwaheed1643 Жыл бұрын
It's going super good because of you explaining💞💕
@light-warrior7 ай бұрын
The programming task: #include int main () { int number; printf("Enter a number: "); scanf("%d ", &number); (number % 2 == 0) ? printf("It is an even number ") : printf("It is an odd number "); return 0; } and B is the correct answer.
@rubakvanitha816411 ай бұрын
Thank you for your happy programming for us🎉
@eliskaellagalikova3251 Жыл бұрын
I am going to write a test about this tomorrow🙄but I finally understant🥳
@amayaamarasinghe5838 Жыл бұрын
Thank you! The explanation is so useful!!!
@venkatasumanth30272 жыл бұрын
ur way of teaching is exlent.....
@ahmed_fsi2 жыл бұрын
Thank you! I didn't think it would be that easy to learn.
@sayalikhairnar32112 жыл бұрын
The great teacher of c programing
@unruly_ronin11 ай бұрын
Subscribed coz you guys are brilliant and have a great presentation style Edit: Answer is C
@qarikhalidwaheed1643 Жыл бұрын
❤❤❤thank you for explaining it so easily❤❤❤
@benjaminhuka74342 жыл бұрын
wonderful explaination, thank you!
@ludowithsanjay2 жыл бұрын
Thank you🙏 mam. Your teaching quality is awesome👏
@kam-sc9gs8 ай бұрын
Ma'am thank you so much, I really appreciate ur work, and it really help me so much❤
@yunandaraung2556 Жыл бұрын
Thank you so much for such wonderful explanation!
@annettewairimu55425 ай бұрын
how are you doing after 1 year in programming?
@nihatdonmzov4166 Жыл бұрын
Great video. Thank you so much
@seabasschukwu6988 Жыл бұрын
GREAT EXPLANATION!
@fountain9886 Жыл бұрын
#include int main (){ int num ; printf("Enter a number :"); scanf("%d", &num); if ( num % 2 == 0){ printf("The number is even."); } else if (num % 2 != 0){ printf("The number is odd."); } return 0; } it is coded in the common style.
@clarencelucius90857 ай бұрын
excellent teacher
@williamowusu7778 Жыл бұрын
Thanks 👍
@miarose53822 жыл бұрын
was waiting for you mam ... please upload the next video soon
@Sickpisspakh23971 Жыл бұрын
Thank you, padma ❤
@mahoney_tech Жыл бұрын
#include int main () { int number = 10; (number % 2 == 0) ? printf("this is even number "): printf("This is odd number"); return 0; }
@bhavanasai6981Ай бұрын
#include int main() { int num; printf("Enter Num:"); scanf("%d", &num); (num % 2 == 0) ? printf("Number is even") : printf("Number is odd"); return 0; }
@spoilermedia-h6i6 ай бұрын
#include int main() { double num1=1; double num2=3,result; result=1+3; printf("enter the number: "); scanf("%d", &result); (result>=4)? printf("the number is even"):printf("the numer is odd"); return 0; }
#include int main(){ int a=0; (a%2==0)?printf("the number is even"):printf("the number is odd"); return 0 ; }
@countrysideshowyaigrock4689 Жыл бұрын
Thank you very much!!
@srikanthkotaru515 Жыл бұрын
// Online C compiler to run C program online #include int main() { // Write C code here int number = 11; int result = (number % 2 == 0) ? printf("it is even") : printf("it is odd"); return 0; }
@ndikevinetawe87514 ай бұрын
C is the answer
@naveenperspective7 ай бұрын
Option c
@gogulram25512 жыл бұрын
program is #include int main() { int num; printf("enter the number: "); scanf("%d", &num); (num % 2 == 0) ? printf("number is even") : printf("number is odd"); return 0; }
@JoeMama-zc8ub2 жыл бұрын
The real MVP
@buddharatnamanandhar38372 жыл бұрын
its going good !!
@fountain9886 Жыл бұрын
#include int main () { int num ; printf("Enter your Number :"); scanf("%d", &num); (num%2==0)? printf("Number is Even") : printf("Number is Odd"); return 0; }
@David_Chijioke3 ай бұрын
thanks a lot
@user-uj8ss9dp7l3 ай бұрын
Love it❤
@haydenawc71897 ай бұрын
i’m learning sm
@abercharity8023 Жыл бұрын
// Online C compiler to run C program online #include int main() { int num =25; (num%2)? printf("The numberis odd") : printf("The number is even"); return 0;
@MagaScampini5 ай бұрын
I think the answer is B. Because the condition in the if...Else statement is if (5 > 3) instead of if the result = (5 > 3); for in that case the right answer would be C. Can anyone confirm?
@onic9623 Жыл бұрын
Option C : result = 5> 3 ? 5 : 3; ----------------------------------------------------------- #include int main() { int num; printf("Enter A Number: "); scanf("%d", &num); (num % 2 == 0) ? printf("Even") : printf("Odd"); return 0; }
@bekmirzo92594 ай бұрын
6:20 the answer is C
@avdeshsingh001 Жыл бұрын
Thanks ma'am
@aaronbenjamin31432 жыл бұрын
I have a question can I? create a program to integrate into a program like array and basic computer calculator etc. I hope you can answer thank you
@based1712 Жыл бұрын
The answer is option B.
@KarthickShoko2 ай бұрын
Option B
@ebubeanieke20728 ай бұрын
C is the right answer
@christlike8712 Жыл бұрын
#include int main() { int num = 4; (num%2==0)? printf("This is an even number"): printf("This is an odd number"); return 0; }
@subhajitNath02 жыл бұрын
good quality 😊
@zonekenne53299 ай бұрын
why do I get an error when I try to do the operation with a "double" data type. I expected the integer to be converted to double since the double is greater than the int in the ranking
@AFCOE Жыл бұрын
Hello madam. Mind is displaying "number is even" when I haven't insert anything. int number; (number%2==0)? printf("number is even"): printf("number is odd");
@ejoshtech53582 жыл бұрын
How is the flow chart drawn? But is this advisable to use in an exam
@gayathri03013 ай бұрын
C option for quiz mam
@raakshas55472 жыл бұрын
Mam, aapke liye chand taare tod ke laa sakta hoo.......coding challenge to keya chiz hai ? Ye lo answer.... #include #include int main() { int num; printf("Enter the age "); scanf("%d",&num); (num%2==0)?printf("The number is even"):printf("The number is odd"); return 0; } Aapka 2nd question ka answer hai option B.
@sara-cq8ev Жыл бұрын
// Online C compiler to run C program online #include int main() { int number; printf("enter your number "); scanf("%d",&number); (number %2==0)? printf("num is even") : printf("nub is odd"); return 0; }
@issabello. Жыл бұрын
love it
@RiyaShorts18 Жыл бұрын
Correct ans is B
@jerseyclubbydn153 Жыл бұрын
#include int main() { int number = 21; (number%2==0) ? printf("Even ") :printf("Odd"); return 0; }
@ogunlalusarah1138 Жыл бұрын
good work
@MercylineNyaboke-b9x10 ай бұрын
Nice❤❤❤
@behailus-tube50245 ай бұрын
programming task int number; printf("Enter a number: "); scanf("%d", &number); int resulte = (number%2 == 0) ? printf(" an even number") : printf(" an odd number");
@ebbahinnocent29303 ай бұрын
I choose B
@MeesalaSrilatha-bk2ps2 ай бұрын
OptB
@Mvrck4421 күн бұрын
Quizz answer: C
@xclusiveo.jstudio5359 Жыл бұрын
#include int main(){ int x= 358; (x % 2 == 0) ? printf("the number is even") : printf("the number is odd"); return 0; }
@qarikhalidwaheed1643 Жыл бұрын
Here's my code #include int main() { int num; int ans; printf("Enter Number: "); scanf("%d", &num); ans = num % 2; if (ans == 1) { printf("Number is Odd"); } else { printf("Number is even"); } return 0; }
@salmanmugharbel10 ай бұрын
good
@jagavardhan5765 ай бұрын
Answer for the que?
@seabasschukwu6988 Жыл бұрын
the correcr answer is C
@ravikiranhs8464Ай бұрын
It just shows error in char line
@mawadasalem54395 ай бұрын
Answer is :b
@Girma_Chew2 жыл бұрын
I hope this will be the correct answer, I have tried it on online compiler provided by Programiz. /*This is a program to check whether a number is EVEN or ODD by enquiring an input from a user.*/ #include int main(){ int number; printf("Enter any number! "); scanf("%d", &number); (number%2==0) ? printf("The number %d is Even.",number) : printf("The number %d is Odd.",number); return 0; } //Thank U for helping us.