#10: Ternary Operator in C | C Programming for Beginners

[@programizstudios]

🔥Finding it Damn Hard to Understand C Programming? Learn to code-the right way-with interactive lessons, quizzes & challenges. Build a strong programming base; it's IMPORTANT! Try Programiz PRO for Free: bit.ly/master-c-programming

[@AlaskarAbdoul]

/* Can you create a program to check whether a number is odd or eve? > Use a ternary operator to check if the number is odd or even. > If number is odd, print "The number is Odd" > If number is even, print "The number is Even" */ #include int main() { int number; printf("Enter a number: "); scanf("%d", &number); // by using Ternary Operator (number % 2==0) ? printf("The number is Even") : printf("The number is Odd"); }

[@eazyj_c]

thanks

[@zonekenne5329]

did you try doing this operation with the "double" data type? @@eazyj_c

[@user-qq1ze2ml2q]

Thank You!

[@varalakshmidevathi7997]

Thanks

[@hurulaynmuhamedsalimcedarp5770]

Programming Task: #include int main() { int number; printf("Enter a number: "); scanf("%d", &number); (number%2 == 0) ? printf("%d is an even number.", number) : printf("%d is an odd number.", number); return 0; }

[@msreekanth8886]

wtf

[@joechen9498]

#include int main() { int number; printf("Please enter the number:"); scanf("%d", &number); (number%2 == 0) ? printf("Number is an even number"): printf("Number is an odd number"); return 0; }

[@michaelspencer6008]

You did an excellent job explaining the switch statement. I was and am still amazed at how easy you made this so understandable. Please continue teaching us. You have an absolute gift in how you explain these concepts. Thank you sooo much!

[@user-be1qh8iz5u]

hey buddy! How much part of C have you completed to date?

[@rhythmahmed1873]

//Can you create a program to check whether a number is odd or even? //***Use a ternary operator to check if the number is odd or even //***If the number is odd print the number is odd //***If the number is even print the number is even #include int main() { int number; printf("Enter a number: "); scanf("%d", &number); (number % 2==0) ? printf("The number is Even.") : printf("The number is Odd."); return 0; }

[@nuetrkn]

Thank you

[@yasminehey3854]

i did the same thing and it worked but later on i made the ternary as int result=(number % 2==0) ? printf("The number is Even.") : printf("The number is Odd."); but when i print the resut itdoes say in the output whether the number is odd or even but it always adds 13 or 14 i dont understand why there is the "14 or 13 "

[@sanargasimov]

@@yasminehey3854 The program then checks whether 'num' is even or odd using the modulus operator %, and uses the ternary operator to print a message indicating whether the number is even or odd. However, the use of 'printf' in the ternary operator is not recommended because it returns the number of characters printed, not the value of the condition. As a result, the value of result will be 23 or 19, depending on the message printed. A better approach would be to use a separate variable to store the message, and then print that variable and the value of result separately. Here's an updated version of the program: #include int main() { int num = 78; char* message = (num % 2 == 0) ? "Your number is EVEN" : "Your number is ODD"; printf("%s ", message); int result = (num % 2 == 0) ? 0 : 1; printf("%d ", result); return 0; } This program first declares a char* variable named message, and assigns it a string value based on whether num is even or odd. It then uses printf to print message and a newline character. Finally, it declares an int variable named result, and assigns it a value of 0 if num is even or 1 if num is odd. It then uses printf to print result and a newline character.

[@sammuchina8189]

in this part of your code, " (number % 2==0) ? printf("The number is Even.") : printf("The number is Odd."); " what does the % mean kindly🙏

[@muhammadfukii1518]

@@sammuchina8189 % is could be DEVISION or as per our concept REMAINDER

[@SANJAYR-yy1zg]

Answer is option c Result=5>3 ? 5 : 3;

[@rahulc.h2440]

for the quiz, it opts C coz in the if-else statement the if part is evaluated to be true and hence gives 5 so the same principle applies Ternary:- (CONDITION) ? Statement1(Executed when True) : Statement2(Executed when False)

[@abdulazizhabib4441]

it is option c

[@adityasharma3947]

B as we have to print Result = 5 but in C the value of just 5 is will be as output

[@batmanelhakeky]

Your tutorials are so helpful. i learnt switch statement and im now learning tenrary operator. keep the great work up!

[@shohanurrahmanshoron1804]

I tried this in front of my teacher and even he doesn't know about this operator. Thank U❤️❤️❤️

[@shankaradari4741]

Really useful content I really want to thank the teachers who are making the classes

[@sundeepchowdaryattaluri8797]

Thanks for providing this useful and & well content for us.... Code #include int main() { int a; scanf("%d", &a); (a %2 ==0) ? printf("%d is even", a): printf("%d is odd", a); } Ans for Question is C.

[@benchmarkslab2005]

One thing I can't understand bro. Why we used %d is even and %d is odd. If I used without %d it isn't working. But they didn't use %d in age calculator. Plzz explain bro

[@rakesh1045]

#include int main(); { Int number=2; (number % 2 == 0) ? Printf("the number is even") : printf("the number is odd"); return 0 ; }

[@Judyy.Sabryy]

Love it, explantion was clear and straightforward, however, I suggest you also talk about how to implement nested Ternary operators.

[@annettewairimu5542]

how are you doing after 5 months in programming?

[@mdsahil2203]

Thanks for providing " Good quality "content By the way answer is option C

[@shreyasy9164]

why c

[@shreyasy9164]

i think option B is corrrect

[@mandip863]

@@shreyasy9164 yes boss b is ans

[@dhanushs1802]

@@shreyasy9164 in the option B, if you change 5>3 to 3>5 , result will be 0 instead the result should be 3. So C is the answer.

[@monalisabanra2733]

b can also be the answer i checked it

[@qarikhalidwaheed1643]

Thanks for explaining this code simply

[@user-nt4nm4fb3u]

Great explanation as always! Thank you for everyone to make this happen.

[@annettewairimu5542]

how are you doing after two months?

[@sunangashilpakar3672]

Thankyou for explaining it so simply.. was waiting for your video ❤️

[@annettewairimu5542]

how are you doing after two years in programming?

[@kankarlabharath6819]

Mam your explanation is very good and nice, can you make a tutorial videos on Data structures and algorithms in good explanation based on c language.

[@pristinewalek4578]

Beautiful 🤩 Thank you for explaining it so well

[@Ech-chatouiMohammed]

VERY GREAT CONTENT

[@Darkness-898]

PROGRAMMING TASK: #include int main() { int num; printf("Enter number here: "); scanf("%d", &num); (num%2==0)?printf("The number is even."):printf("The number is odd."); return 0; } PROGRAMIZ QUIZ ANSWER: Option(B) 5>3?5:3;

[@laxmanpeddi9714]

(option c)...........cool and clear content by progrmizzzz.....plz keep going......

[@shreyasy9164]

why c??????

[@pretty_you2243]

@@shreyasy9164 5>3? Is a condition. After evaluating the condition, value will be assigned to result variable as either 5 or 3.

[@alirezaz9896]

the best C language tutorial👌👌👌

[@qarikhalidwaheed1643]

It's going super good because of you explaining💞💕

[@light-warrior]

The programming task: #include int main () { int number; printf("Enter a number: "); scanf("%d ", &number); (number % 2 == 0) ? printf("It is an even number ") : printf("It is an odd number "); return 0; } and B is the correct answer.

[@rubakvanitha8164]

Thank you for your happy programming for us🎉

[@eliskaellagalikova3251]

I am going to write a test about this tomorrow🙄but I finally understant🥳

[@amayaamarasinghe5838]

Thank you! The explanation is so useful!!!

[@venkatasumanth3027]

ur way of teaching is exlent.....

[@ahmed_fsi]

Thank you! I didn't think it would be that easy to learn.

[@sayalikhairnar3211]

The great teacher of c programing

[@unruly_ronin]

Subscribed coz you guys are brilliant and have a great presentation style Edit: Answer is C

[@qarikhalidwaheed1643]

❤❤❤thank you for explaining it so easily❤❤❤

[@benjaminhuka7434]

wonderful explaination, thank you!

[@ludowithsanjay]

Thank you🙏 mam. Your teaching quality is awesome👏

[@kam-sc9gs]

Ma'am thank you so much, I really appreciate ur work, and it really help me so much❤

[@yunandaraung2556]

Thank you so much for such wonderful explanation!

[@annettewairimu5542]

how are you doing after 1 year in programming?

[@nihatdonmzov4166]

Great video. Thank you so much

[@seabasschukwu6988]

GREAT EXPLANATION!

[@fountain9886]

#include int main (){ int num ; printf("Enter a number :"); scanf("%d", &num); if ( num % 2 == 0){ printf("The number is even."); } else if (num % 2 != 0){ printf("The number is odd."); } return 0; } it is coded in the common style.

[@clarencelucius9085]

excellent teacher

[@williamowusu7778]

Thanks 👍

[@miarose5382]

was waiting for you mam ... please upload the next video soon

[@Sickpisspakh23971]

Thank you, padma ❤

[@mahoney_tech]

#include int main () { int number = 10; (number % 2 == 0) ? printf("this is even number "): printf("This is odd number"); return 0; }

[@bhavanasai6981]

#include int main() { int num; printf("Enter Num:"); scanf("%d", &num); (num % 2 == 0) ? printf("Number is even") : printf("Number is odd"); return 0; }

[@spoilermedia-h6i]

#include int main() { double num1=1; double num2=3,result; result=1+3; printf("enter the number: "); scanf("%d", &result); (result>=4)? printf("the number is even"):printf("the numer is odd"); return 0; }

[@balashebjadhav977]

The answer is option C)

[@mojo7281]

Programming Task: #include #include int main() { int number; printf("Enter Number: "); scanf("%d", &number); (number % 2==0) ? printf("EVEN #") : printf("ODD #"); return 0; }

[@uppilipavitra9634]

#include int main(){ int a=0; (a%2==0)?printf("the number is even"):printf("the number is odd"); return 0 ; }

[@countrysideshowyaigrock4689]

Thank you very much!!

[@srikanthkotaru515]

// Online C compiler to run C program online #include int main() { // Write C code here int number = 11; int result = (number % 2 == 0) ? printf("it is even") : printf("it is odd"); return 0; }

[@ndikevinetawe8751]

C is the answer

[@naveenperspective]

Option c

[@gogulram2551]

program is #include int main() { int num; printf("enter the number: "); scanf("%d", &num); (num % 2 == 0) ? printf("number is even") : printf("number is odd"); return 0; }

[@JoeMama-zc8ub]

The real MVP

[@buddharatnamanandhar3837]

its going good !!

[@fountain9886]

#include int main () { int num ; printf("Enter your Number :"); scanf("%d", &num); (num%2==0)? printf("Number is Even") : printf("Number is Odd"); return 0; }

[@David_Chijioke]

thanks a lot

[@user-uj8ss9dp7l]

Love it❤

[@haydenawc7189]

i’m learning sm

[@abercharity8023]

// Online C compiler to run C program online #include int main() { int num =25; (num%2)? printf("The numberis odd") : printf("The number is even"); return 0;

[@MagaScampini]

I think the answer is B. Because the condition in the if...Else statement is if (5 > 3) instead of if the result = (5 > 3); for in that case the right answer would be C. Can anyone confirm?

[@onic9623]

Option C : result = 5> 3 ? 5 : 3; ----------------------------------------------------------- #include int main() { int num; printf("Enter A Number: "); scanf("%d", &num); (num % 2 == 0) ? printf("Even") : printf("Odd"); return 0; }

[@bekmirzo9259]

6:20 the answer is C

[@avdeshsingh001]

Thanks ma'am

[@aaronbenjamin3143]

I have a question can I? create a program to integrate into a program like array and basic computer calculator etc. I hope you can answer thank you

[@based1712]

The answer is option B.

[@KarthickShoko]

Option B

[@ebubeanieke2072]

C is the right answer

[@christlike8712]

#include int main() { int num = 4; (num%2==0)? printf("This is an even number"): printf("This is an odd number"); return 0; }

[@subhajitNath0]

good quality 😊

[@zonekenne5329]

why do I get an error when I try to do the operation with a "double" data type. I expected the integer to be converted to double since the double is greater than the int in the ranking

[@AFCOE]

Hello madam. Mind is displaying "number is even" when I haven't insert anything. int number; (number%2==0)? printf("number is even"): printf("number is odd");

[@ejoshtech5358]

How is the flow chart drawn? But is this advisable to use in an exam

[@gayathri0301]

C option for quiz mam

[@raakshas5547]

Mam, aapke liye chand taare tod ke laa sakta hoo.......coding challenge to keya chiz hai ? Ye lo answer.... #include #include int main() { int num; printf("Enter the age "); scanf("%d",&num); (num%2==0)?printf("The number is even"):printf("The number is odd"); return 0; } Aapka 2nd question ka answer hai option B.

[@sara-cq8ev]

// Online C compiler to run C program online #include int main() { int number; printf("enter your number "); scanf("%d",&number); (number %2==0)? printf("num is even") : printf("nub is odd"); return 0; }

[@issabello.]

love it

[@RiyaShorts18]

Correct ans is B

[@jerseyclubbydn153]

#include int main() { int number = 21; (number%2==0) ? printf("Even ") :printf("Odd"); return 0; }

[@ogunlalusarah1138]

good work

[@MercylineNyaboke-b9x]

Nice❤❤❤

[@behailus-tube5024]

programming task int number; printf("Enter a number: "); scanf("%d", &number); int resulte = (number%2 == 0) ? printf(" an even number") : printf(" an odd number");

[@ebbahinnocent2930]

I choose B

[@MeesalaSrilatha-bk2ps]

OptB

[@Mvrck44]

Quizz answer: C

[@xclusiveo.jstudio5359]

#include int main(){ int x= 358; (x % 2 == 0) ? printf("the number is even") : printf("the number is odd"); return 0; }

[@qarikhalidwaheed1643]

Here's my code #include int main() { int num; int ans; printf("Enter Number: "); scanf("%d", &num); ans = num % 2; if (ans == 1) { printf("Number is Odd"); } else { printf("Number is even"); } return 0; }

[@salmanmugharbel]

good

[@jagavardhan576]

Answer for the que?

[@seabasschukwu6988]

the correcr answer is C

[@ravikiranhs8464]

It just shows error in char line

[@mawadasalem5439]

Answer is :b

[@Girma_Chew]

I hope this will be the correct answer, I have tried it on online compiler provided by Programiz. /*This is a program to check whether a number is EVEN or ODD by enquiring an input from a user.*/ #include int main(){ int number; printf("Enter any number! "); scanf("%d", &number); (number%2==0) ? printf("The number %d is Even.",number) : printf("The number %d is Odd.",number); return 0; } //Thank U for helping us.

[@shaikabuzar3495]

answer is c

[@sawewfelipe7480]

answer i s C

[@sayun8848]

Answer is C

[@AniquaIbnatMir-e3b]

The answer is Option (C). result = 5 > 3 ? 5 : 3;

[@phaneendravr900]

how? Please tell me a code