#12 Machine Learning Specialization [Course 1, Week 1, Lesson 3]

[@emmanuelteitelbaum]

My favorite linear regression video of all time!

[@ahmeteren7267]

some npc words💀💀

[@SamuelSibarani-nf9vx]

@@ahmeteren7267 what do you mean?

[@tamaramartinovic]

So well explained, thank you very much!

[@soap4890]

🎯 Key Takeaways for quick navigation: [\[00:01\](kzbin.info/www/bejne/ppaxg6Shm9qej7s)] 🧠 Understanding the cost function: - The section aims to build intuition about the role and behavior of the cost function in linear regression. - A recap emphasizes the objective of finding parameter values \( W \) and \( B \) that minimize the cost function \( J(W, B) \), indicating optimal model performance. - Simplifying the linear regression model to \( f(W, X) = W \times X \) facilitates visualizing the cost function's relationship with parameter \( W \). [\[04:05\](kzbin.info/www/bejne/ppaxg6Shm9qej7s)] 📉 Analyzing the cost function graphically: - Graphical representations of both the linear model \( f(W, X) \) and the cost function \( J(W) \) are examined. - Different values of parameter \( W \) correspond to various straight line fits to the training data, influencing the cost function. - The relationship between parameter \( W \), the linear model fit, and the cost function values is elucidated through graphical analysis. [\[13:47\](kzbin.info/www/bejne/ppaxg6Shm9qej7s)] 📊 Choosing optimal parameter values: - Optimal parameter values \( W \) are selected based on minimizing the cost function \( J(W) \), indicating the best fit of the linear model to the training data. - Graphical analysis demonstrates how the choice of parameter \( W \) affects the fit of the model to the data and the resulting cost function values. - The ultimate goal in linear regression is to identify parameter values that result in the smallest possible cost function value, indicating an accurate model fit. Made with HARPA AItail

[@leogodofnone2706]

Thank you 🙏🏻

[@mithun442]

Understood sir

[@ooxxx]

thank you!

[@nozarlahooti1789]

For the second example would be 4.25/6=0.7, right?

[@quietcorner5989]

so why you calculated J function in the beginning with the same slope which is w=1 ,and then u calculated the value of j function from two different slopes w=1 and w=0.5? in the first one you considered that the actual function and the function of the model prediction had the same slope w=1 so it is normal that the error would be 0!! can you please clarify this i didn t get it. did you suppose in the beginning that the model predition was 100% correct and precise and it mached with the actual function , so the error was 0?

[@Lostverseplays]

In the start yes the model prediction was 100% correct that is why the cost function(J) gave 0 as output as there was no error in prediction, when the slope became 0.5 the model(Function used to predict prices i.e f(x)) was deviated from actual prediction whose error was calculated by J function

[@karthik_0180]

Yes

[@gnull]

i smell calculus

[@TeacherAzkaShehzadi-gf6vb]

date 16

[@YashrajVerma-ni4jn]

😊

[@MikeM-uy6qp]

Huh?