#14 : break and continue in C | C Programming for Beginners

[@programizstudios]

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[@hamidabdimurodov7783]

#include int main() { while (1) { int number; printf("Enter a number: "); scanf("%d", &number); if (number >= 0) { printf("Positive value"); break; } if (number % 2 == 0) { printf("Negative Even "); continue; } printf("%d ", number); } return 0; } I did in this way, and it is still working. However, in github the solution is written a slightly different. Is this code right?

[@munasherwizi738]

❤❤❤

[@user-nt4nm4fb3u]

Very well explained, this is what we're struggling when we're start coding as a beginner. Here the basics is covered well, and I'm really grateful for it. This eventually will help most of the enthusiastic learners.

[@awesomeswordsman8231]

you and bro code might be the best coding teachers out there that can explain this 👍

[@vexpomegran9044]

no teacher at university explains these so well🖤🖤🖤

[@harshadatapre2133]

//Can you write a prpgram that takes an input from the user and prints it if the value is a negative odd number? //*If the input value is positive, end the loop with message, 'Positive Value' //*If the input value is negative even, skip the value with message 'Negative Even' #include int main() { int number; while(1) { printf("Enter a number:"); scanf("%d", &number); if(number < 0) { if(number % 2 != 0) { printf("%d ", number); continue; } printf("Negative Even "); continue; } printf("Positive Value"); break; } }

[@devarapallivamsi2981]

thank you by the way at the the end return 0;

[@kothakotasrinivasarao5082]

@@devarapallivamsi2981 why while(1)

[@devarapallivamsi2981]

@@kothakotasrinivasarao5082 here, We need the loop to run without any condition(for the first time). So, we give while(1) which refers to True

[@msreekanth8886]

wtf

[@marusukech.5049]

Answer for Programming Task today #include int main(){ while(1){ int num; printf("Enter a number:"); scanf("%d",&num); if(num < 0){ if((num % 2) != 0){ printf("%d ",num); } else{ printf("Negatif Even "); continue; } } else{ printf("Positif value"); break; } } return 0; }

[@itzmesuhail4948]

I think it wasn't correct plz check it

[@shamsrahmantabish9299]

@@itzmesuhail4948 this is the correct one int main() { while(1) { int number; printf("Enter a number:"); scanf("%d", &number); if (number > 0) { break; } if ((number % 3) != 0){ continue; } printf("%d ", number); } return 0; }

[@bullstefano4352]

@@shamsrahmantabish9299 Did you use the continue function?

[@stealthy_doctor]

this has been a wonderful beginning to C, thank you so much!!! i think the answer is B. continue ? #include int main() { while(1){ int number; printf("Enter a Number: "); scanf("%d",&number); if(number>0){ printf("Positive Value "); break; } if((number%2)!= 0){ printf("%d ",number); continue; } printf("Negative Even "); } return 0; }

[@davradev99]

thanks

[@chitturoyal7750]

09:29 Programming Task #include int main() { int i,j=0; while(j

[@Data2watch]

/*Improved version of your code, Execute it to check*/ #include int main() { label: int i; char choice; printf(" Enter a value: "); scanf("%d",&i); if(i0) { if(i%2==0) printf("Positive even number "); else printf("Positive odd number "); } else { printf("Neither be negitive or positive "); } printf("More numbers?? "); Label: scanf(" %c", &choice); if(choice=='y' || choice=='Y') { goto label; } else if(choice=='n' || choice=='N') { return 1; } else { printf("Answer in Y=Yes or N=No "); goto Label; } return 0; } //Hello

[@OgaPita]

Your explanations are simplified. Thank you!

[@programizstudios]

Q. Which of the following keywords is used to skip the current iteration of a loop ? A. skip B. continue C. break D. loop

[@apurbabera9682]

break

[@apurbabera9682]

Mam please tell me solution Write a C program to add two number using static number ?

[@sujit_ghimire]

@@apurbabera9682 do some research or else drop the course.

[@matthartley2934]

Skip ?

[@harshadatapre2133]

B. continue

[@rythmflow1514]

This video is most valuble for programming beginners ❤️ can you do video for c programming functions ? 🌸😊

[@programizstudios]

Our next video is on C Function. Do check it out on coming Wednesday. Thankyou for Watching !

[@ashutoshurkudkar1080]

Videos are awesome as always 💖

[@programizstudios]

Thankyou

[@b7sh_b7sh]

amazing teacher🥰

[@datuboharry6103]

9:34 #include int main(void) { int a; printf(“Enter number: “); scanf(“%d”, &a); If ( a < 0 && a % 2 == 1) { printf(“%d ”, a); } else if (a > 0) { printf(“Positive Value. ”); break; } else if (a < 0 && a % 2 == 0) { printf(“Negative even. ”); continue; } return (0); }

[@davidjabulani630]

wonderful video

[@yunghan1754]

10:13 to skip current iteration only, not the whole loop, answer should be B.continue

[@lalith_kumar_akhila2411]

Thank you for posting valuable content of C programming..

[@oissimouni7726]

//A Program that takes input and prints if the value is a Negative odd number #include int main(){ while (1){ int number; printf("Enter a number: "); scanf("%d",&number); if (number>0) { printf("Positive Value"); break ; } if (number

[@matthartley2934]

This was super helpful! Thank you.

[@vishalkadkal]

// Online C compiler to run C program online #include int main() { while(1){ int number; printf("Enter the number ="); scanf("%d",&number); if(number>0){ printf(" positive value"); break; } if((number% -2) ==0){ printf("negavtive even "); continue; } printf("%d ",number); } return 0; }

[@pranavsilla]

These videos are very helpful. ThankYou!

[@ScottBisong]

this particular queestion came for my exams

[@crystalsxd]

#include int main() { while (1) { int number; printf("Enter a number: "); scanf("%d", &number); if (number > 0) { printf("Positive Value"); break; } if ((number % 2) ==0) { printf("Negative Even "); continue; } printf("%d ", number); } return 0; } PROGRAMIZ QUIZ ANSWER: B. continue

[@Ech-chatouiMohammed]

great way of explanation , thanks a lot

[@tnk.1608]

My answer: #include int main () { while (1){ sleep(2); int num; printf("Enter value of number: "); scanf("%d", &num); if ( num >=0 ) { printf("Positive value "); break; } if ( ( num % 2) == 0 ) { printf("Negative even "); continue; } printf("Negative odd number: %d ", num); } return 0; }

[@nihatdonmzov4166]

Great video. Thank you

[@zetsubou-chan]

thank you! this helped a lot

[@onic9623]

Option B : Continue ----------------------------------------------------------------------------------------- #include int main () { int num; while (1) { printf(" Enter A Number : "); scanf("%d", &num); if (num < 0) { if (num % 2 == 0) { printf("Negative Even Number"); continue; } else { printf("%d", num); } } else { printf("Positive Number"); break; } } return 0; }

[@vikkyd6707]

Ma'am at 5:53 in one place i=1 and other place i==3 For equal to two sign are used what's the reason ?

[@lalith_kumar_akhila2411]

i=1 here ''='' is assignment operator..means in the box of i we are keeping value ''1''...i==1 means equating i with 1...hope this helps🙂

[@adityajain9439]

Thank you 👍 answer is c

[@whynot.17]

answer is b

[@behailus-tube5024]

programming task #include int main() { int number; printf("enter the number: "); scanf("%d", &number); if(number %2 = 1) { printf(" the value is postive"); } return 0; }

[@FaroOqi_2003]

programming Task #include int main() { while(1){ int number; printf(" Enter a number:"); scanf("%d",&number); if(number>0){ printf("Positive Value"); continue; } if(number

[@vintrixtergunot8064]

programming task #include int main() { while (1){ int number; printf ("Enter a number: "); scanf ("%d", &number); if (number>0){ printf ("Positive Value "); break; } if ((number % 2)== 0){ printf ("Negative Even "); continue; } printf ("%d ", number); } return 0;

[@shrur3527]

Tq so much🙏🙏❤️❤️

[@emmanuelarthur3081]

Great video 🔥🔥🔥

[@devarapallivamsi2981]

thank you programiz team

[@nihatdonmzov4166]

Thank you so much

[@mv8672]

//programming task #include int main() { while(1) { int num; printf("input your num:"); scanf("%d", &num); if(num>0) { printf("positive value"); break; } if((num %2) == 0) { printf("negative even "); continue; } printf("your num is %d ", num); } return 0; }

[@shaheddardas3958]

#include int main() { while(1){ int number; printf("Enter number here:"); scanf("%d",&number); if(number>0){ printf("Positive Value "); break; } if(number%2==0){ printf("Negative Even "); continue; } printf("%d ",number); } return 0; } Quiz answer is B. continue

[@yuvrajbalotiya1064]

Task program of break and continue statement #include //Preprocesssor int main(){ // entry point while (1){ // for While conditions int number; // Declaration of variable printf ("Enter the number : "); // to print the number scanf ("%d", &number); if ( number >= 0){ // for If conditions printf ("Positive value "); break ; } if (( number % 2) >=0 ){ printf ("Negative Even "); continue ; } printf ("%d ", number); // To print the statements } return 0; }

[@SambanaCharmila]

Continue is usedd to skip the current iteration

[@sahalyoosuf]

Thanks a lot guys for your sessions .... thanks @padma

[@gamingnon-stop8167]

QUIZ answer: continue PROGRAMMING TASK : #include #include /* Author - Aryan Phatarpekar Date - Sun 23 Oct 2022 */ main() { // declaring the variables int number; while(1) { // asking user to enter the number printf("Enter a number "); scanf("%d", &number); // checking the condition, if the number is greater than 0 priting the message it is a positive number & breaking the loop. if(number > 0) { printf("%d is a positive number, Please enter a a negative value ", number); break; } /* if the number is less than 0(negative number) than making calculations on that number. dividing that number by 2 with modulus operator(%) and checking the remainder. remainder 0 means it is a -ve even number and continuing the code but remainder is 1 then it is a -ve odd and printing the message it is -ve odd number and breaking the loop. */ else { if(number < 0 && number % 2 == 0) { printf("%d is a negative even ", number); continue; } else { printf("YES ! %d is negative Odd number ", number); break; } } } }

[@ak74u66]

very very good 🤩

[@tshedzanembilwi4572]

She is sooooooo good

[@TechyMom-ft]

Good one

[@rancho121]

Thanks ma'am

[@devarapallivamsi2981]

thank you

[@Sickpisspakh23971]

Thank you!!!

[@karunanithir1510]

Hi, I like to print numbers 1 to 25 in five rows and 5 columns continuously and wish ‘22’ and ‘23’ to be skipped, using the ‘continue’ in a for loop as follows: #include #include int main() { int i,j,n=5; int x=1; for (i=1;i

[@Himerosteam]

Hey, I'm not sure if continue works in this case because you have to print something for the numbers 22 and 23 and if you skip them in the code you also skip the "x++" part. Here is what worked for me, hopefully you can modify it for your needs: //#define _CRT_SECURE_NO_WARNINGS //#include // //int main() //{ // int i, j, n = 5; // int x = 1; // for (i = 1; i

[@ishaangupta2353]

#include int main() { int i,j; int x=1; for (i=1;i

[@lyricsmanprottoy]

answer of quiz: Continue

[@mohammadabdullahaalforhad1375]

Thanks

[@viralfoodies1886]

answer:optiom B (mam)

[@cheftelma8241]

Hi Padma, unfortunately my code for printing positive numbers keeps saying number is undeclared yet it’s the same as yours

[@timothykuria6769]

1 #include 2 3 int main(void) 4 { 5 while(1){ 6 int number; 7 printf("Enter a number: "); 8 scanf("%d", &number); 9 10 if(number < 0 && (number % 2) != 0){ 11 printf("%d ", number); 12 break; 13 } 14 if(number < 0 && (number % 2) == 0){ 15 printf("Negative even "); 16 continue; 17 } 18 printf("Positive value "); 19 } 20 21 return (0); 22 } I used that and works is it okay?

[@zen_zaf]

while (1) { int number ; printf (" Enter a number : ") ; scanf ("%d", &number) ; if ( number > 0) { printf(" Postive value ") ; break ; } if ( number % 2 == 0) { printf(" Negative even : "); continue ; } if ( number % 2 != 0) { printf(" Negative odd : "); continue; } else printf("invalid number : %d ", number); } return 0 ; }

[@barkhadibraahim1023]

#include int main () { while (1) { int number; printf(" enter the number: "); scanf("%d",&number); if(number > 0) { printf(" positive value"); break; } if((number%-2) ==0) { printf(" negative even"); continue; } printf("%d ",number); } return 0; }

[@crafttechindia]

PROGRAMMING TASK SOLUTION int main() { while (1) { int number; printf("Enter a number: "); scanf("%d", &number); if (number > 0) { printf("Number is positive"); break; } if (number < 0 && number % -2 == 0) { printf("Negative even "); continue; } printf("%d ", number); } }

[@ritutomar6268]

Option B (continue)

[@puritykamane8695]

// Online C compiler to run C program online #include int sum = 0; int main() { while (1) { int number; printf("Enter a number: "); scanf("%d", &number); if (number < 0 && number % 2 != 0) { printf("%d ", number); } if (number < 0 && number % 2 == 0){ printf("Negative even "); continue; } if (number >= 0) { printf("positive value"); break; } } return 0; }

[@yogithabale]

opt B - continue

[@rancho121]

Continue

[@balashebjadhav977]

Answer is B) continue

[@b7sh_b7sh]

#include int main() { // Write C code here while(1){ int number; printf("Enter the number: "); scanf("%d", &number); if (number>0){ printf("possitive value"); break; } if (number

[@KageraTanzania]

Answer is B. continue

[@mrwalker8561]

int main() { int x; while(1){ printf(" Enter a number : "); scanf("%d", &x); if (x>0){ printf("Positive Value"); break; } if (x%2 == 0){ printf("Negative even"); continue; } printf("Number %d",x); } return 0; }

[@nuetrkn]

🔥🔥🔥🔥🔥

[@Selcuk._._]

/*Can you write a program that takes an input from the user and prints it if the value is a negative odd number ? • If the input value is positive, end the loop with message, Positive Value. • If the input value is negative even, skip the value with message Negative Even.*/ while (1) { int num; printf("enter number: "); scanf_s("%d", &num); if (num > 0) { printf("Positive Value "); break; } else if (num == 0) { printf("Zero is not even or odd, loop continue "); continue; } else if (num % 2 == 0) { printf("Negative Even "); continue; }else printf("\t\t\t%d ",num); }

[@jokiiex4563]

In 9:00 , do not write a float number 😅

[@franchezke2351]

1 #include 2 int main(void) 3 { 4 while (1) 5 { 6 int number; 7 printf("Enter the number: "); 8 scanf("%d", &number); 9 if (number > 0) 10 { 11 printf("Positive Value "); 12 break; 13 } 14 if (number < 0 && number % 2 == 0) 15 { 16 printf("Negative Even "); 17 continue; 18 } 19 else 20 { 21 printf("%d ", number); 22 } 23 24 } 25 return (0); 26 }

[@Themyth24665]

Perfect bro

[@VarshiniSDevadiga-h5q]

option B continue

[@vinaykumarvinaykumar2006]

My Answer is B # continue

[@sawewfelipe7480]

the answer is C, continue.

[@yadlaaravind811]

Answer:b

[@VictoriaOtunsha]

#include int main() { while(1){ int num; printf("Enter a number: "); scanf("%d", &num); if (num > 0){ printf("Positive Value "); break; } if (num %2== 0){ printf("Negative Even "); continue; } printf("%d ", num); } return 0; }

[@bryanbalantes6486]

//Can you write a prpgram that takes an input from the user and prints it if the value is a negative odd number? //*If the input value is positive, end the loop with message, 'Positive Value' //*If the input value is negative even, skip the value with message 'Negative Even' #include int main(){ while (1) { int number; printf("Enter a number: "); scanf("%d", &number); if(number < 0 && number%2 !=0){ printf("%d ", number); } else if(number < 0 && number%2 ==0){ printf("Negative Even "); }else{ printf("Positive Value "); break; } } return 0; } //Programiz quiz answer B. continue

[@STRANGER-vv2qf]

#include int main() { while(1){ int number; printf(" enter a value:"); scanf("%d",&number); if(number0){ printf("positive value"); break; } if(number

[@furkanakdag7644]

answer is "B"

[@hopeloft]

#include int main() { int number; while (1) { printf("Enter number value: "); scanf("%d", &number); if (number == 0) { break; } if (number > 0) { if (number % 2 == 0) { printf("Positive even number "); } else { printf("Positive odd number "); } } else { if (number % 2 == 0) { printf("Negative even number "); } else { printf("Negative odd number "); } } } return 0; }

[@ahambraba2504]

#include int main(){ int i; while(1){ int i; printf(" Please type a value: "); scanf("%d", &i); if(i >= 0){ printf(" Positive Even "); break; } if(i < 0 && i % 2 != 0){ continue; } printf(" Negative Even "); } return 0; } I find this solution better because there would be no need for continue if you use else or else if

[@racingfan372]

B is correct

[@bullshit485]

The Answer is B, Continue.

[@mohammadabdullahaalforhad1375]

B. Continue

[@seabasschukwu6988]

❤❤❤

[@k.osquared1315]

answer is continue

[@_.narr._.03]

Programming task :- #include int main() { while (1) { int n; printf("Enter any number: "); scanf("%d", &n); if (n >= 0) { printf("Positive value! "); break; } if (n % 2 == 0) { printf("Negative even! "); continue; } } return 0; }

[@aboutouruniverse3834]

Quiz: B

[@NaijaBaronYT]

🙏🏽

[@TheMGIvideos]

int main() { int number; while (1){ printf("Enter a number: "); scanf("%d", &number); if (number > 0) { printf("Positive Value "); break; } else if ((number % 2) == 0){ printf("Negative Even "); continue; } else { printf("%d ", number); } } }

[@bhavanaanu9076]

Option b mam

[@benpalma8322]

#include using namespace std; int main() { while (1) { int value; cout > value; if (value < 0 && value % 2 != 0) { cout

[@VenkataNarisetty-s7m]

Break

[@sunnahboy6223]

while(1){ int number; printf("Enter a number: "); scanf("%d",&number); if(number

[@BharatThakor-bu8pq]

The answer is Continue..

[@HoangDo-yv1yw]

like 👍👍

[@albertamenyah3019]

answer is B.

[@luckev3594]

🤗🤗

[@alanizaguirre4670]

The value of "CHEERIO" 🤣🤣🤣🤣🤣!!

[@davidjabulani630]

int x; while(1){ printf(" Please enter number:"); scanf("%d",&x); if(x>0){ printf("Positive Value"); break; } if((x%3)!=0){ printf("Negative Even"); continue; } printf("%d",x); }

[@manaswini3256]

My frnd tanusri made me shift from Jenny to Padma...Padma>>>>jenny

[@ALONEBOY-es4uc]

Same bro nenu kuda