1400. Construct K Palindrome Strings | leetcode daily challenge | dsa | shashcode | java

[@shashwat_tiwari_st]

like target is 150. Please do like if you have understood the explanation as well as the code!

[@Bhalu-kl7sq]

bhot badhiya solution tha bhaiya maza hi aagya bas aise soch paau to jeevan safal hojayega mera coding mein

[@tarunkumar9177]

Very good explanation bhaiya ❤ But bhaiya ek fix time pr aap video dala kro , chahe list krke chor diya kro, jyada audience recach ati h bhaiya

[@shashwat_tiwari_st]

Ha try whi krte hai

[@shashwat_tiwari_st]

time complexity: N + 26, N is length of string and 26 is total lower case letters.

[@OnstreamGaming]

I heard ecplanation and coded myself , thank you

[@the_AbhishekRanjan]

Awesome sir ji

[@VaibhavSingh_code]

bhaiya Comptetive programming playlist please

[@yugbhatiavlogs2325]

Nice explanation sir ❤

[@opkrchauhan_1]

class Solution { public boolean canConstruct(String s, int k) { if(k>s.length()){ return false; } Mapmap = new HashMap(); for(char c : s.toCharArray()){ map.put(c,map.getOrDefault(c,0)+1); } int count=0; for(Map.Entrymp : map.entrySet()){ if(mp.getValue()%2 !=0){ count++; } } if(count>k){ return false; } return true; } }

[@TarunRaikwar5381]

Great

[@nishith5380]

Nice bayyya

[@patel-up72]

bhaiye Videos Toda Pahle laya karo 9:30

[@aniruddhlaharia1275]

bhai odd wala case nahi samjha agar "cccd" hai input toh fir invalid kyu hua?

[@shashwat_tiwari_st]

@@aniruddhlaharia1275 invalid? jitne odd utne palindrome ye bola. c 3 times hai odd hai d 1 time hai odd hai So 2 odd variables hai toh minimum 2 palindrome bnane hi pdenge.. k>=2 will be valid. k

[@JyotiKumari-fv7hg]

Bhai jda long video mt bno