17 CLAUSIUS INEQUALITY | ENTROPY | THERMODYNAMICS | IIT ADVANCED | JEE MAIN | CHEMISTRY CLASS 11

[@ramanujan4068]

9:00 5th time i got what you meant. You showed a bit misery in words while elaborating. I were craving to hear these line. ' even though the process given in a case is an irreversible one, but there is always another way to reach the same state, in a reversible manner. And from there we calculate ∆S= q(rev) ÷T. Which'd be right, as S is a state function., it doesn't depend on path followed. And we'd get ∆S correct as long as the initial and final states are same in both of the processes(either irreversible or reversible) ' Entrophy change is a definite quantity between two states To reach the other state, you may use irreversible process or any reversible path. But the value of delta S would be same in both of the cases. As it is a state function. Therefore in any cyclic process, ∆S =0 But in an irr cyclic process -cyclic integration of q/T Is a negative value Wherras in a cyclic reversible process, it is 0. Anyone with brainfog like I had, can believe the words, they are 100% correct. Edit : T is the temprature at which the system waas, When thesmall heat q qas poured .

[@Harshitmehta-sb3vu]

Thanks, it literally helped me get the lecture in a go without much confusion

[@quicksilver90-g8h]

If that is the case then why is q irreversible/T less than entropy change even though they follow the same path? By that logic the entropy change should be equal no matter reversible or irreversible. Help me out bro

[@vedanshverma5649]

@@quicksilver90-g8h Because the entropy of irreversible process can't be calculated by q irr÷T.... entropy ki value irr aur reversible mai same ayegi but formula irr alag hoga..rev wala formula nhi use hoga...

[@studyaccount9773]

Exactly and that's why (q)irr /T does not give the value of entropy. Qirr is not all used up in increasing the randomness of the system but a lot is dissipated out etc as change in states comes due to external factors..please correct me where i am wrong

[@ayanagarwaliitdelhi7662]

@punisher6969 this statement is main cherry for the whole cake

[@ayanagarwaliitdelhi7662]

entropy is a state function like internal energy tells the kinetic energy of gaseous molecule translation vibrational rotational entropy tells us about degree of randomness just like change in internal energy change in entropy is also zero in cyclic process from one thermodynamical state to another there are two paths REVERSIBLE AND IRREVERSIBLE (in reversible pressure of gas and external is same while in irreversible is not) there are many process and we can do them through 2 path final state will be same and change in state functions too but not path functions thats why we calculate work for reversible and irreversible as its path function depends on path change in internal energy will be same if two state is same doesnot matter by which path we moved same wth entropy it doesnot matter for entropy change if we reach from path 1 to 2 through reversible or irreversible path but if path is reversible we has a formula to calculate change in entropy its Q/T thats why in a cycle if all process are reversible cyclic summation of Q/T is zero means change in entropy zero but in irreversible process if we do that it will come negative as change is entropy for irreversible can not be calculated through formula its not defined how to calculate change in entropy in an irreversible path from 1 to 2 simply conduct same process through reversible path and calculate Q/T thats entropy change now Qrev/T = Qirrev/T as entropy is same but again entropy for irrev can not be calculated through Qirrev/T and Qrev/T is not eqll to Qirrev/T as Qrev is not eqll to Q irr as Q is path function and depends whether process is reversible or irreversible

[@FAUXVIKINGIITB]

I was able to appreciate the elegance in the derivation, thank you sir. 👍 ✌️

[@iliyanparin_iitism]

Ye sink hai... ye engine hai... aur yaha heat ki barbaadi ho rahi hai.

[@shashankjain917]

😂😂

[@AyushSharma0506]

bade heavy driver ho beta

[@amitsingh2782]

😂😂😂

[@harshapatel7245]

OK... So change in entropy is defined for both irreversible and reversible but can only be calculated by reversible process If I am wrong please correct me...

[@lonamisa6128]

Yup🤘

[@IITian-zy7ks]

entropy is defined for both irreversible and reversible.. we can calculate reversible as well as irreversible process...reversible by intergration of q/t ....irreversible can also be calculated it is not that it is impossible to calculate it unlike internal energy..it can be calculated by some other means but not with the integration of q/t

[@pradeepkumarbhoi9323]

ye that's right,well it's no use now ig

[@khushiaggarwal1659]

5:27

[@neelimakumariamritsar1862]

8:48 sir is ahead of time.... He already knew the trend 4 years before Sir himself is 5 star rated and carry high aura and respect...

[@chandradeep-_-]

It feels amazing probably because the solution of calculating entropy lied in the very basic concept that it is a state function

[@ArRt1719]

2:31 5:40 7:52 8:57 10:14 13:00 15:05

[@ramanujan4068]

Notes for myslef. If the processes are istrml or adbtc type. Then we can directly assume the T to be cnstnt ACCORDNGLY. While looking at q/T 's cyclic integratn . Irrev me.... The question would tell.. .. Basically youll either get A constant T process Or a process with perfectly differentiable and integrable fnctn for Q/T. Like sir derived that expressuon out of Q = U - W integratn Similarily if you think that ,, how does the temp of sys and srndn be at eqm in a rev process,, as the whole universe is too big to change temp..or pressure. .. And that is the reason why, no process is reversible And for the question purposes, thryll make such trivialities convinient for you, they know you are not a Phd stdnt.

[@shilpisingh5484]

Thankuu sirr

[@virajchauhan2141]

wow 😳😳😳😳

[@alphaiitd1]

Brilliant. Thanks sir

[@shrabanibiswas3155]

4:05 sir how did you multipllied inequality

[@label-o-THV]

cross multiplied can be performed when either terms not non zero and +ve quantity

[@gigastein3151]

@@label-o-THV Yes and Temperature is always Positive so it is valid perfectly

[@vivekdhaka2201]

Bas ab thoda si quatum physics aur padh lete hai Zindagi safal ho jaegi😂

[@nerfedthor]

11:28 sir how are we drawing graph for irreversible process

[@IITian-zy7ks]

we cant draw exact curve here it only for understanding

[@Yogesh.kumar9759]

How can we say that efficiency of irr process is less than efficiency of carnot engine plz someone explain it

[@dgaf2008]

bhai sir told this in the previous lectures , he made us note the point that rev adia and isothermal processes are more efficient than irreversible ones , because rev expansion produces more work while rev compression needs less work

[@ishanbajpai173]

jab summation ko integral me convert kiya tab 'q' ki jagah 'dq' hona chahiye......

[@IITian-zy7ks]

yes we can write like that but as sir said q is a path function and we cant actual calculate exact differential of it so in higher studies you will find that but now for simplicity you can use dq

[@senpaibist658]

Maza agaya sir !

[@rekhajha6613]

Sir apne starting lec mai kaha tha ki Change in state function is not a state function. Tab entropy agar state function hai to ΔS to state function nahi hona cahiye. Tab ΔS path pr depend kyu nahi krta?

[@Vijeta-o4l]

Think it like internal energy U and change in internal energy ∆U

[@dgaf2008]

bhai change in state function bhi toh path pe depend nhi krta , ushi lecturer mein sir ne ye bhi bataya tha ( change in state function only depends upon intial and final states

[@sohanbhattacharyya8451]

✅full

[@somilvijay31]

In clausius inequality if 1to 2 rev and 2 to 1 irr then???

[@IITian-zy7ks]

it gives the same result

[@dkdc1882]

👍

[@Kuku-iu5cb]

Thnk

[@aruntejachamalla7465]

🔥 🔥 🔥 🔥 🔥

[@shrikantbodkhe2363]

👍👍🙏🙏🙏🙏

[@thekingishere4260]

"likhenge is baat ko mere tareeke se"