19.7 Electrolytic Cells | General Chemistry

[@horsegirl9179]

One of my favorite things about these videos is that they are very short for the amount of material covered and yet nothing is ever rushed in the videos either. I am SO GLAD these are made into a video series and not an hour and a half long video I have to search through to find the info I'm looking for. Extremely user friendly!

[@ChadsPrep]

Thanks for the awesome feedback and I'm glad the videos are helping you

[@jahidhossain9867]

Chad, you're a g. Love you my man. Carrying my chem grade right now.

[@ChadsPrep]

Glad the channel is helping you!

[@jahidhossain9867]

@@ChadsPrep the channel is definitely helping a lot. Do you plan on releasing general biology videos in the future?

[@DavidElks-qh2pn]

After 15 days of continuous studying 🎉 i could reach the end of my chem curriculum nd almost the end of the playlist 🥳🥳no words can describe how much grateful i am to you sir. U made me find hope in chemistry ❤

[@ChadsPrep]

Thanks for saying so!

[@yabbadid2120]

Thanks for making these videos! These have been extremely helpful for my final exam.

[@ChadsPrep]

You're welcome - glad to hear it!

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I've liked so many Chad's Prep videos that my thumbs are getting sore.

[@genevieveaiwonegbe2299]

I have my chem final tomorrow, and these videos reduces my stress levels.

[@ChadsPrep]

Glad they are helping - good luck on your final!

[@toolsstop]

How would you write the overall equation for the aqueous electrolysis example?

[@coolkid9206]

How did you figure out that Na+1 got reduced and Br-1 oxidized? Shouldn't the br get reduced because it has a more positive reduction potential? Thank you, love ur vids

[@andgeobaidoos8130]

It is because when NaBr breaks down you get Na+ and Br-. So, if you read the reaction potential chart you'll see that the reduction reaction for Br goes from Br2+2e---> Br- so you would have to do the reverse reaction meaning Br- is oxidized.

[@dalyakorte6052]

Thanks 😊

[@ChadsPrep]

You bet!

[@manav-ty1oj]

Shouldn't the 4OH-> O2 + 2H20 + 4e- reaction (Reduction potential of 0.4, so when OH acts as the reducing agent the oxidizing potential is -0.4) occur at the anode because water dissociates into H+ and OH- and since the anode is positively charged, the OH- would be attracted to it. This is the way our teacher taught it, so I don't know who's right now lol

[@RelaxRailRide]

Nice sir

[@ChadsPrep]

Great!

[@petevenuti7355]

'ionic liquids' & low temp euclectic mixtures.