19. Application of Differentiation | Rates of Change 1 | Calculus

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AVITECHNOLOGIES

AVITECHNOLOGIES

2 жыл бұрын

There are various applications of derivatives not only in maths and real life but also in other fields like science, engineering, physics, etc. In previous videos, you must have learned to find the derivative of different functions, like, trigonometric functions, implicit functions, logarithm functions, etc.
In this Video, you will learn the use of derivatives with respect to mathematical concepts and in real-life scenarios.
Rate of Change of a Quantity:
This is the general and most important application of derivative. For example, to check the rate of change of the volume of a cube with respect to its decreasing sides, we can use the derivative form as dy/dx. Where dy represents the rate of change of volume of cube and dx represents the change of sides of the cube.

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@user-zg1uf7tg9h
@user-zg1uf7tg9h Ай бұрын
Wow you even teach better than PHD holders thanks sir
@AVITECHNOLOGIES
@AVITECHNOLOGIES Ай бұрын
You're welcome. But me teaching more than PHD holders, I think not.😂
@MartinMusonda-oe1on
@MartinMusonda-oe1on Ай бұрын
❤❤❤❤❤❤ u are a good teacher
@AVITECHNOLOGIES
@AVITECHNOLOGIES Ай бұрын
Thank you very much
@user-er3hf8nb3h
@user-er3hf8nb3h 5 ай бұрын
Very powerful ❤
@InusahAbdulAziz-kc6ee
@InusahAbdulAziz-kc6ee 5 ай бұрын
I'm really enjoying your teaching sir. Thanks 🙏
@AVITECHNOLOGIES
@AVITECHNOLOGIES 5 ай бұрын
You're welcome 😊
@abishaifrimpong8728
@abishaifrimpong8728 4 ай бұрын
Thank you very much sir
@Omori-i-5
@Omori-i-5 Ай бұрын
👌
@fortunefinest
@fortunefinest 3 ай бұрын
You are the best sir
@AVITECHNOLOGIES
@AVITECHNOLOGIES 3 ай бұрын
Thank you very much
@abubacarrdemba2027
@abubacarrdemba2027 5 ай бұрын
Thank you so very much Sir
@AVITECHNOLOGIES
@AVITECHNOLOGIES 5 ай бұрын
You're welcome.
@shamzy460
@shamzy460 2 ай бұрын
How do i find equation of the normal?
@AVITECHNOLOGIES
@AVITECHNOLOGIES Ай бұрын
Get the Gradient, dy/dx of the function at the point and take the negative reciprocal of it. This is because the normal is perpendicular to the tangent. Then use the equation y - y1= m (x - x1), where m is the gradient, which Is the negative reciprocal of dy/dx.
@anjohclinton4609
@anjohclinton4609 2 ай бұрын
@user-ze3qt5lq5h
@user-ze3qt5lq5h 7 ай бұрын
👍
@INDISPENSABLE_DAYSTAR
@INDISPENSABLE_DAYSTAR 4 ай бұрын
My teacher once told me never to be caught unfresh😅😅😅😅. I will not sir😅😅
@AVITECHNOLOGIES
@AVITECHNOLOGIES 4 ай бұрын
Okay. 😂
@abishaifrimpong8728
@abishaifrimpong8728 4 ай бұрын
Thank you very much sir
@AVITECHNOLOGIES
@AVITECHNOLOGIES 4 ай бұрын
You're welcome
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