Cable subjected to Distributed Load Example 3

Cable subjected to Distributed load with non symmetric distribution of the geometry
Calculate the tension at the supports

[@esclipsekr]

you’re better than my static professor

[@ellathebully6064]

Thank you so much... Well explained.☺

[@anotidaishechigiya6773]

wish could subscribe twice lmao😁

[@manishatiwari323]

Thank you so much sir I bow down to you🙏

[@1963rzr]

All the best

[@ghelen5685]

Thank you so much sir, you help a lot 🥺

[@1963rzr]

You are welcome!

[@azari8176]

Thanks a lot ❤❤

[@ZainKhan-cy4sp]

Sir why you take left side distance x and y in F. horizontal

[@petergeorgeednalaga2808]

is the formula same on SI system? say.. N/m..?

[@athenapsychelee7803]

thank you somuchhh!!!!!

[@saqib3s]

Thank you very much

[@1963rzr]

Glad you liked it. Remember to subscribe, like, and share,

[@alysonmohan9855]

Hello, this video helped a lot. Which text book is this from?

[@592chris4]

Hibbeler Structural Analysis

[@jejomaec.7312]

Thank you sir! 🙌

[@stephaniemejia5840]

🤙🤙🤙🤙

[@angielicabalonzo7848]

Lifesaver 😌

[@1963rzr]

@@stephaniemejia5840 you are welcome!

[@1963rzr]

Thanks

[@1963rzr]

You are welcome

[@hanzbobielubapis5166]

ILOVEYOU sooo muchh sir 🤩

[@1963rzr]

:)

[@cjayson38]

How do we find the maximum tension of the cable and also the minimum?

[@1963rzr]

Hi. Hello to you too.

[@ConceptualCalculus]

Maximum tension occurs where the slope of the cable is the steepest (closest to vertical). Minimum tension occurs where the cable is horizontal.

[@maskman2671]

Sir, as you said Fh will be same on both side but i calculuted Fh using right side sag and distance there was lil difference your Fh is 3790 and when i calculated using right side my Fh was 3786. I know its not much difference but its not same. Is this difference negligible. BTW THANKS for video

[@1963rzr]

Sir, Your calculations are either wrong or you didn't use all decimals...Fh is always the same

[@anotidaishechigiya6773]

even if you use all the decimals we not gettin 3790 for the RHS

[@RajivHardeo]

Why did u add 1 to 0.8165?

[@1963rzr]

hello to you too... i added because it must be added. please check the explanation again

[@madscientist4713]

This question came in my paper . I just solved it . Online examination . Thanku so much . This question contain 20 marks . So its for sure . Oh yeah .

[@1963rzr]

Just be sure that you understand it and not just copy it... You are Welcome!

[@berkexan4117]

I saw on other notes that the formula for Fh = wL²/8h instead of wL²/2h ?

[@berkexan4117]

Oh wait i think i got it,some notes would leave L representing the whole length,not the half length; w(L/2)²/2h = wL²/8h

[@mdmizanurmizanur5810]

The name of this books writer?

[@user-ky9ts1wf7y]

hi, at 6:17 you wrote x=25÷(1.08165) but I think that it must be x=25÷(1.8165)

[@1963rzr]

Thanks.... but the results is correct

[@captainseulgi]

What if L is not given?

[@1963rzr]

hello to you too?