+2 Maths Onam Exam | Chapter 5 | Continuity And Differentiability Part 1 | Oneshot | ExamWinner +2

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Exam Winner Plus Two

Exam Winner Plus Two

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@ExamWinnerPlusTwo
@ExamWinnerPlusTwo 3 ай бұрын
Today's Chemistry Live @ 7 PM : kzbin.infoG8S0regCVzE Today's Maths Live @ 9 PM : kzbin.infoL1sJUZwR5BI For +2 Free Class & Notes - chat.whatsapp.com/IOVr1dVbA4ULOgyrm0PV7V Follow Plus Two 2024-25 Channel on Whatsapp - whatsapp.com/channel/0029VaFEkDU6rsQpHT2FeF0I QUICK JOIN EXAM WINNER PLUS TWO UYARE BATCH WHATSAPP " HI " TO 7592092022 OR CLICK HERE : wa.link/md053x
@haridevt1136
@haridevt1136 2 ай бұрын
13:58 Allen sir rocked students shocked 👀
@AdithyanSanthosh-d3i
@AdithyanSanthosh-d3i 3 ай бұрын
13:58 Bro Said " P"word 💀
@abhiiiiiiiiee
@abhiiiiiiiiee 2 ай бұрын
brain rott💀
@CR7-y9e
@CR7-y9e 2 ай бұрын
3:19 continuity 46:05 differentiability 🙂👍🏻
@mathewjoseph1276
@mathewjoseph1276 3 ай бұрын
Enikk maathramano batchil padipuunath kurach manasilaakunnthum ath kazhinj yt class full manasilaakan kaanandathum😅😢
@sreelekshmims5494
@sreelekshmims5494 3 ай бұрын
Enikkum angane thanneya😅 batch il fees koduth keriyitt youtube class kaanum😂
@Nived.S.Anand777
@Nived.S.Anand777 3 ай бұрын
​@@sreelekshmims5494sathyam😂
@Krishnendu-000
@Krishnendu-000 3 ай бұрын
Sathyam, pyq use full ahn
@Nived.S.Anand777
@Nived.S.Anand777 3 ай бұрын
@@Krishnendu-000 actually ath kanan mathram aan subscription eduthirikkane😂
@alveenamaria4130
@alveenamaria4130 2 ай бұрын
Truee.. batchil padippikeneth maths mikaythum manasilakanilaah ytil edukkumba manasilakenend
@SHONEPRASAD456
@SHONEPRASAD456 4 сағат бұрын
23:44 check this Frist before going to class Then you get a surprise 🎉😂
@footballepics9234
@footballepics9234 3 ай бұрын
We got Alex sir saying the p word before gta
@athuul__
@athuul__ 3 ай бұрын
13:59 💀 😭 omg
@Ddfffhhhhibbji
@Ddfffhhhhibbji 3 ай бұрын
😂
@muhammedamilamil174
@muhammedamilamil174 3 ай бұрын
😏🙄
@krishnaunnikrishnan2730
@krishnaunnikrishnan2730 3 ай бұрын
Sir always very thankful for your efforts ❤❤❤ By the way the ans is : 2*Cos(tan(e^2x+3))*Sec²(e^2x+3)*e^2x+3
@rejanibiju8308
@rejanibiju8308 3 ай бұрын
Class starts at 2:44
@aaliyafathimaaswad9b014
@aaliyafathimaaswad9b014 3 ай бұрын
Cos(tan(e^2x+3)) . sec^2(e^2x+3) . e^2x+3 . 2 Thank you sir 💛👍🔥🔥🔥🙏🙏 Super class❤❤full clear ❤❤🔥🔥🔥🔥🔥🔥🔥
@alanpa5536
@alanpa5536 3 ай бұрын
ADIPWOLI CLASS😁❤️ ANSWER = 2Cos ( tan e^2x+3) * sec² (e^ 2x+3) * e^ 2x+3 💀❤️❤️
@Jaycejacob-t4i
@Jaycejacob-t4i 3 ай бұрын
Yes super class 😊
@BLACKCAT-bi3bb
@BLACKCAT-bi3bb 2 ай бұрын
13:58 😅 14:21 💀
@SINAN_NK_2715
@SINAN_NK_2715 13 күн бұрын
Thankyou sir for this wonderful class 😊☺️☺️❤❤❤
@AnanyaAbhinav
@AnanyaAbhinav 3 ай бұрын
dy/dx=cos[tan(e^(2x+3))]*sec²(e^(2x+3)*2[e^(2x+3)] Thankyou Allen Sir🎉❤ for your great effort❤🎉 Thankyou Exam winner family🎉❤
@kamaluddinkamaluddin6455
@kamaluddinkamaluddin6455 3 ай бұрын
Thankyou sir❤️❤️❤️❤️❤️👍🏻👍🏻🔥 Ans: 2cos(tan(e^2x+3))(sec^2+3))(e^2x+3)
@Zimba_505
@Zimba_505 3 ай бұрын
2Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3
@Appus1
@Appus1 24 күн бұрын
I luv u sireee❤😊🎉
@ziluzilu-kk5qk
@ziluzilu-kk5qk 3 ай бұрын
2cos(tan e^2x+3) . Sec^2(e^2x+3) . e^2x+3
@JessySiby-ty7yh
@JessySiby-ty7yh 2 ай бұрын
5:22
@ananyashivadas7811
@ananyashivadas7811 3 ай бұрын
dy/dx=cos[tan(e^(2x+3))]*sec²(e^(2x+3)*2[e^(2x+3)] Thankyou Allen sir.....🎉❤Super class🎉❤
@nithinnithi3001
@nithinnithi3001 3 ай бұрын
Sir poly ❤ 2cos(tan e^2x+3)sec^2(e^2x-3)(e^2x+3)
@Rev_Editz720
@Rev_Editz720 3 ай бұрын
ans; 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3 thanks for this wonderful class sir
@gopikasworid4710
@gopikasworid4710 3 ай бұрын
ANS =COS[TAN(e^2x+3)].sec^2(e^2x+3).(e^2x+3).2 thanks for super class samaya parimithi manasilakkunu sir
@Parvathi-lv6yg
@Parvathi-lv6yg 3 ай бұрын
Ans. = Cos( tan ( e^2x+3))×sec^2(e^2x+3)×e^2x+3
@Strawberryxh
@Strawberryxh 3 ай бұрын
Ans=cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3 ❤️Thanku exam winner❤️
@seenabasheer5763
@seenabasheer5763 3 ай бұрын
22:14 😂
@_allaboutus_431
@_allaboutus_431 3 ай бұрын
Cos(tan(e^2x+3))sec²(e^2x+3)(e^2x+3)×2. Sirr cls valare help full aayirunnu.... Bakki topics nu katta waiting aqnuu❤️🥰
@NihalPp-i1x
@NihalPp-i1x 20 күн бұрын
Bro lasthe ×2 enghaneyaa vann😢
@predatorgaming6969
@predatorgaming6969 3 ай бұрын
2cos(tan(e^(2x++3)))sec²(e^(2x+3))e^(2x+3)
@predatorgaming6969
@predatorgaming6969 3 ай бұрын
52 comments in less than 6 minute Allen sir influence 😂🔥🔥
@sameeraaami2843
@sameeraaami2843 3 ай бұрын
Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3 Good class😍😍
@FaihaFathha
@FaihaFathha Ай бұрын
47:30 smooth operator
@RaseenaAnas...
@RaseenaAnas... 3 ай бұрын
Thankyou Allen sir... For this amazing class❤
@sahalffx
@sahalffx 8 күн бұрын
21:37 😵😵
@kuttapan4070
@kuttapan4070 2 ай бұрын
13:59😵 14:20🙀 22:15💀 24:22☠️ 24:26 ⚰️30:35🪦
@asimahamed._
@asimahamed._ 2 ай бұрын
Bro is cooked
@rexxxxxxxxxxxxxo
@rexxxxxxxxxxxxxo 2 ай бұрын
30:35
@PoornimaTA-ue5bm
@PoornimaTA-ue5bm 2 ай бұрын
What thha😭
@kuttapan4070
@kuttapan4070 2 ай бұрын
​@@rexxxxxxxxxxxxxo👍🏻
@fathimafathimack
@fathimafathimack 2 ай бұрын
Nice class ❤
@mr_benzene786
@mr_benzene786 3 ай бұрын
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3 Thanks allen sir💥
@anisharajeev4289
@anisharajeev4289 3 ай бұрын
Answer =2.Cos[tan (e^2x+3)].Sec^ (e ^ 2 x+3).e ^2x+3
@Jaycejacob-t4i
@Jaycejacob-t4i 3 ай бұрын
Thankyou sir ❤❤😊 Ans =2cos(tan^2x+3).sec²(e^2x+3).e^2x+3
@AnjiAnji-i3v
@AnjiAnji-i3v 3 ай бұрын
dy/dx=2cos(tan(e^x+3)).sec^2(e^2x+3).e^2x+3
@fidharidha9909
@fidharidha9909 3 ай бұрын
Its 2cos(tan e^2x+3).sec²(e^2x+3).e^2x+3
@AdilBijoy-ep5ej
@AdilBijoy-ep5ej 3 ай бұрын
Alen sir power❤🔥 Answer:- 2cos(tan e^2x+3).sec²(e^2x+3).e^2x+3
@sairasakkariya9516
@sairasakkariya9516 3 ай бұрын
Answer: 2 cos (tan e^2x+3) sec²(e^2x+3) × e^2x+3 Thank u Allen sir ❤🙌
@Suryaaa-oq1dq
@Suryaaa-oq1dq 3 ай бұрын
2 cos(tan( e^2x+3))(sec^2(e^2x+3)) (e^2x+3) Crystal clear tnk u Allen sir ❤
@Jaycejacob-t4i
@Jaycejacob-t4i 3 ай бұрын
Yes class is super ❤
@AlanAlanabhilash
@AlanAlanabhilash 3 ай бұрын
2cos(tane^2x+3)*sec²(e^2x+3)*e^2x+3 ❤❤❤❤❤❤❤
@anonymzzz
@anonymzzz 3 ай бұрын
2cos (tan e^2x+3) * sec² (e^2x+3) * e^2x+3 Thankyou❤
@priyaah____123
@priyaah____123 3 ай бұрын
2Cos(tan e^2x+3) Sec²(e^2x+3) e^2x+3 Thank you sir💖for such a nice class
@prettygurl9670
@prettygurl9670 3 ай бұрын
Allen sireeyy thnkuuh so much.....class nannayi manassilaay💗💗💗🤩 Ans:2cos(tan e^2x+3)•sec²(e^2x+3)•e^2x+3👩🏻‍🦯
@subhashvenu4134
@subhashvenu4134 3 ай бұрын
dy/dx=cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
@Adx_cutzz
@Adx_cutzz 3 ай бұрын
Nice class♥️♥️♥️ Ans:2cos(Tan^2x+3).sec²(e^2x+3).e^2x+3
@Kevinmoolan
@Kevinmoolan 3 ай бұрын
dy/dx = 2cos(tan(e^2x+3))×sec^2(e^2x+3)×e^2x+3 Thank youh Allen sireeh
@sarangsr
@sarangsr 3 ай бұрын
2cos(tan(e^(2x+3)))sec^2(e^(2x+3))2e^(2x+3) Sir ithil e yude powerinu braces kodukkande? Like I did?
@Musthafa-o3u
@Musthafa-o3u 3 ай бұрын
Answer:2Cos(tane^2x+3) * sec^2(e^ 2x+3)*e^2x+3❤❤❤🎉🎉🎉 Adipoli class 💪💪❤️❤️❤️💪
@ansanaansar6455
@ansanaansar6455 3 ай бұрын
Ans:cos(tan(e^(2x+3))×sec2(e^(2x+3))×e^(2x+3) ×2 THANKYOU SIR FOR YOU EFFORT❤️
@NihalPp-i1x
@NihalPp-i1x 20 күн бұрын
Lasthe ×2 enghaneya vannenn paranjeruoo
@ansanaansar6455
@ansanaansar6455 20 күн бұрын
​@@NihalPp-i1x e^2x+3 il x nte place il 2x alle.. Appo athinte derivative multiply cheithathann(chain rule)
@ShiraShineKottarathil12032
@ShiraShineKottarathil12032 3 ай бұрын
Ans) dy/dx = 2cos (tan (e^2x+3)) sec² (e^ 2x+3) e^ 2x+3 Thank you so much Sir🔥❤ Baakki portions nale mrning eppozhelm live il edkamo Sir? 💖
@RIO-jw5nx
@RIO-jw5nx 3 ай бұрын
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3 is the ans
@AnjiAnji-i3v
@AnjiAnji-i3v 3 ай бұрын
Thank you sir ❤
@brindat.b2761
@brindat.b2761 3 ай бұрын
Ans: 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3🖤 Thank you sir ❤
@rejilarejila3771
@rejilarejila3771 3 ай бұрын
Thankyou sir❤ Answer:dy/dx =2 cos(tan e^2x+3).sec²(e^2x+3).e^2x+3❤
@shibuvlogs2901
@shibuvlogs2901 3 ай бұрын
Ans=2cos(Tan e^2x+3) . Sec^2(e^2x+3). e^2x+3
@Musthafa-o3u
@Musthafa-o3u 3 ай бұрын
Exam Winner family 💪💪💪💪
@FathimaHiba-rl8pw
@FathimaHiba-rl8pw 3 ай бұрын
Answer-2cos(tane^2X+3). Sec²(e^2X+3) . (e^2X+3) Thank you sir🎉🎉❤❤
@Kalluzzz_77
@Kalluzzz_77 3 ай бұрын
2 Cos (tan(e^2x+3)).Sec²(e^2x+3).(e^2x+3) Thank u Allen Sireyyy .... ✨🫶💗
@RafeekRafee-jm1kb
@RafeekRafee-jm1kb 3 ай бұрын
Cos(tan(e^2x+3))*sec²(e^2x+3)*e^2x+3*2+0 thank you so much sir 🥹
@btswaterbottleofficial6692
@btswaterbottleofficial6692 3 ай бұрын
2cos (tan e^2x+3).sec²(e^2x+3).e^2x+3 is the answer. Thankuu examwinner for the double dhamakka seriess🎉❤❤
@SulaikhaP-dw3vv
@SulaikhaP-dw3vv 3 ай бұрын
Ans=Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3 Nice class❤️
@Ronoman.
@Ronoman. 3 ай бұрын
❤ nice class Ans: 2.e^2x+3.sec²(e^2x+3).cos(tan(e^2x+3)❤❤
@AsinJoseph-wb5zd
@AsinJoseph-wb5zd 3 ай бұрын
dy/dx= cos(tan(e^2x+3))×sec^2(e^2x+3)×(e^2x+3)×2
@fathifathima-n7c
@fathifathima-n7c 3 ай бұрын
Ans=2cos(tan^2x+3).sec^2(e^2x+3).e^2x+3 Seen class thanne❤❤
@Musthafa-o3u
@Musthafa-o3u 3 ай бұрын
Adipoli class ❤❤
@sreekanthvk1071
@sreekanthvk1071 3 ай бұрын
2cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3 ❤ class full on power sir powli😊😊😊😊😊😊❤❤❤❤❤❤❤❤
@NihalEk-jn9mf
@NihalEk-jn9mf 3 ай бұрын
2cos(tane^2x+3).sec^2(e^2x+3).e^2x+3 ❤❤❤ Adipoli siree
@HameemMisbah
@HameemMisbah 3 ай бұрын
Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3.2 Everything crystal clear ❤
@vrindashailesh5718
@vrindashailesh5718 3 ай бұрын
Ans. 2cos (tan e^2x+3) * sec² (e^2x+3) * e ^2x+3 thanku allen sir ❤
@dhdhdJejen-dp8nc
@dhdhdJejen-dp8nc 3 ай бұрын
Ans=2cos(tane^2x+3).sec^2(e^2x+3).e^2x+3 Class is super.......❤
@Mayflower_22
@Mayflower_22 3 ай бұрын
y' = cos(tan(e^(2x) + 3)) * (sec^2(e^(2x) + 3)) * (2e^(2x)) Thanku Allen sir❤️✨
@Sree_lekshmi.S
@Sree_lekshmi.S 3 ай бұрын
Cos[tan(e^2x+3)]sec²(e^2x+3)e^2x × 2
@Jasnasalam-zf4ey
@Jasnasalam-zf4ey 3 ай бұрын
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3 Thankyuuh sirrr for yourr valuable classess🥺🖤🖤
@HadhiFadhi-lp4jr
@HadhiFadhi-lp4jr 3 ай бұрын
Ans:2Cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3 Tnquu sir 🤍
@epiczoro-111
@epiczoro-111 3 ай бұрын
Ans:cos ( tan(e ^ (2x + 3)) * sec(2) * (e ^ (2x + 3)) * e ^ (2x + 3) * 2
@raziteach895
@raziteach895 3 ай бұрын
Answer : dy/dx = 2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
@Aryan....x
@Aryan....x 3 ай бұрын
Tnku allen sireyh 🙂🫶🏼💖 Ans ; 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
@Jaycejacob-t4i
@Jaycejacob-t4i 3 ай бұрын
Yes good class ❤
@arvlog07
@arvlog07 3 ай бұрын
2cos(tan(e^2x+3))sec^2(e^2x+3)(e^2x+3) Useful class ❤❤
@P.SivaPrathap
@P.SivaPrathap 3 ай бұрын
Cos(tan(e^2x+3).sec^x(e^2x+3).2e
@adithyans556
@adithyans556 3 ай бұрын
2cos(tan^2x+3).sec²(e^2x+3).e^2x+3 - ans.
@afthabahmed10
@afthabahmed10 3 ай бұрын
Ans : 2cos(tane"2x+3).sec(e^2x+3).e^2x+3 Nalla cls aayitunnu sir🎉
@AnshirAp
@AnshirAp 3 ай бұрын
2cos( tane^2x+3.sec^2(e^2x+3).e^2x+3 Thankyou allen sir❤❤
@sarangsr
@sarangsr 3 ай бұрын
Thankyou sir ❤ Ans:2cos(tan(e^(2x+3)))sec^2(e^(2x+3))2e^(2x+3)
@messisiiu5000
@messisiiu5000 3 ай бұрын
Ans) 2cos(tan^2x+3).sec²(e^2x+3).e^2x+3. ❤ One of the best class ❤
@prettygurl9670
@prettygurl9670 3 ай бұрын
Allen sireeyy thnkuuh so much.....class nannayi manassilaay💗💗💗🤩 Ans:2cos(tan e^2x+3)•sec²(e^2x+3)•e^2x+3👩🏻‍🦯
@tani__cha_chu
@tani__cha_chu 3 ай бұрын
Answer: 2cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3
@shiba000-m7
@shiba000-m7 3 ай бұрын
2cos(tane^2x+3).sec(e^2x+3).e^2x+3 Thankyou sir ❤
@shiba000-m7
@shiba000-m7 3 ай бұрын
2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3 ❤
@SuryaSiva-jt9jz
@SuryaSiva-jt9jz 3 ай бұрын
2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
@ajileshsaji2025
@ajileshsaji2025 3 ай бұрын
dy/dx =2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
@aswathir.s1258
@aswathir.s1258 3 ай бұрын
dy/dx=cos(tan( e^2x+3)).sec^2(e^2x+3).e^2x+3
@liyalinta
@liyalinta 3 ай бұрын
Thank you sir❤
@Athulyaanilkumar884
@Athulyaanilkumar884 3 ай бұрын
Thank you Sir❤❤❤ Ans: 2cos( tane^2x+3).sec²(e^2x+3).e^2x+3
@manikuttanpillai644
@manikuttanpillai644 3 ай бұрын
cos(tan(e^2x+3)).sec^2(e^2x+3).(e^2x+3).2
@javadc8109
@javadc8109 3 ай бұрын
Ans=2cos(tan e^2x+3)sec²(e^2x+3)e^2x+3 Thankyou exam winner ❤
@sreelakshmi-u1e
@sreelakshmi-u1e 3 ай бұрын
Ans=2cos(tan^2x+3).sec^2(e^2x+3).e^2x+3
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